Agriculture University Entrance Practice Set 1

Agriculture University Entrance · 2026 · with answers and explanations

questions
30
Total marks
120
Duration
150 minutes
Negative marking
−1

Subjects: Agriculture · Biology · Chemistry · Physics · Mathematics

Question 1

Agriculture · 4 marks · −1

Which of the following is the most important cereal crop of India in terms of area under cultivation?

  1. A.Wheat
  2. B.Rice
  3. C.Maize
  4. D.Barley

Correct answer: B

Explanation: Rice has the largest area under cultivation among cereal crops in India, covering approximately 44 million hectares. India is the second largest producer of rice in the world after China.

Question 2

Agriculture · 4 marks · −1

Laterite soils are predominantly found in areas with:

  1. A.Cold and dry climate
  2. B.High temperature and heavy rainfall
  3. C.Temperate and moderate rainfall
  4. D.Arid and hot desert conditions

Correct answer: B

Explanation: Laterite soils are formed in tropical and subtropical regions with high temperature and heavy rainfall. Intense leaching removes silica and bases, leaving behind iron and aluminium oxides that give these soils their characteristic red colour. They are found in the Western Ghats, eastern coast, and parts of northeast India.

Question 3

Agriculture · 4 marks · −1

The biological control agent Trichogramma is a parasitoid of:

  1. A.Adult beetles
  2. B.Lepidopteran eggs
  3. C.Soil nematodes
  4. D.Weed seeds

Correct answer: B

Explanation: Trichogramma is a tiny wasp (egg parasitoid) that lays its eggs inside the eggs of lepidopteran pests (moths and butterflies), including stem borers, bollworms, and fruit borers. It is the most widely used biological control agent in agriculture worldwide.

Question 4

Agriculture · 4 marks · −1

A sprinkler irrigation system is most suitable for:

  1. A.Paddy fields with standing water
  2. B.Undulating terrain with uneven slopes
  3. C.Heavy clay soils only
  4. D.Greenhouse cultivation only

Correct answer: B

Explanation: Sprinkler irrigation is most suitable for undulating (uneven) terrain where surface irrigation methods like flood or furrow irrigation cannot distribute water uniformly. The sprinkler system applies water through the air as spray, mimicking rainfall, and can be used on slopes.

Question 5

Agriculture · 4 marks · −1

Rinderpest in cattle is caused by:

  1. A.Bacteria
  2. B.Virus
  3. C.Fungus
  4. D.Protozoan

Correct answer: B

Explanation: Rinderpest (cattle plague) was caused by the Rinderpest virus (Morbillivirus, family Paramyxoviridae). It was declared globally eradicated in 2011 by FAO and OIE — only the second disease (after smallpox) to be completely eradicated.

Question 6

Agriculture · 4 marks · −1

Which micronutrient deficiency causes 'Khaira disease' in rice?

  1. A.Iron
  2. B.Zinc
  3. C.Manganese
  4. D.Boron

Correct answer: B

Explanation: Khaira disease of rice is caused by zinc deficiency. Symptoms include dusty brown spots on leaves, stunted growth, and delayed maturity. It is common in alkaline and calcareous soils where zinc availability is low. Application of zinc sulphate (ZnSO₄) at 25 kg/ha corrects the deficiency.

Question 7

Biology · 4 marks · −1

Apical dominance in plants is controlled by the hormone:

  1. A.Gibberellin
  2. B.Auxin
  3. C.Ethylene
  4. D.Abscisic acid

Correct answer: B

Explanation: Auxin, produced in the apical bud, inhibits the growth of lateral buds, a phenomenon known as apical dominance. When the apical bud is removed (decapitation), auxin supply decreases and lateral buds begin to grow, resulting in bushy plant growth.

Question 8

Biology · 4 marks · −1

Nephridia are the excretory organs of:

  1. A.Insects
  2. B.Earthworms
  3. C.Fish
  4. D.Frogs

Correct answer: B

Explanation: Nephridia are the excretory organs of annelids (segmented worms) such as earthworms. They filter waste products from the coelomic fluid and blood, functioning analogously to kidneys in vertebrates. Each segment typically has a pair of nephridia.

Question 9

Biology · 4 marks · −1

Crossing over during meiosis occurs between:

  1. A.Sister chromatids of the same chromosome
  2. B.Non-sister chromatids of homologous chromosomes
  3. C.Two non-homologous chromosomes
  4. D.DNA and RNA molecules

Correct answer: B

Explanation: Crossing over is the exchange of genetic material between non-sister chromatids of homologous chromosomes during the pachytene stage of prophase I of meiosis. It results in genetic recombination and increases genetic variation in offspring.

Question 10

Biology · 4 marks · −1

The term 'biodiversity hotspot' was coined by:

  1. A.Charles Darwin
  2. B.Norman Myers
  3. C.E.O. Wilson
  4. D.Paul Ehrlich

Correct answer: B

Explanation: Norman Myers coined the term 'biodiversity hotspot' in 1988. A hotspot must have at least 1,500 endemic plant species and must have lost at least 70% of its primary vegetation. India has four hotspots: Western Ghats, Eastern Himalayas, Indo-Burma, and Sundaland.

Question 11

Biology · 4 marks · −1

The blood group system in humans is determined by:

  1. A.Haemoglobin concentration in plasma
  2. B.Antigens on the surface of red blood cells
  3. C.Number of white blood cells
  4. D.Shape of platelets

Correct answer: B

Explanation: The ABO blood group system is determined by the presence of specific antigens (glycoproteins) on the surface of red blood cells. The gene has three alleles (IA, IB, and i) that determine which antigens are present, resulting in four blood groups: A, B, AB, and O.

Question 12

Biology · 4 marks · −1

PCR (Polymerase Chain Reaction) was developed by:

  1. A.James Watson
  2. B.Kary Mullis
  3. C.Frederick Sanger
  4. D.Herbert Boyer

Correct answer: B

Explanation: Kary Mullis developed the Polymerase Chain Reaction (PCR) technique in 1983 and was awarded the Nobel Prize in Chemistry in 1993. PCR allows amplification of specific DNA sequences in vitro using Taq polymerase (from Thermus aquaticus).

Question 13

Chemistry · 4 marks · −1

The molarity of a solution containing 4 g of NaOH (molar mass = 40 g/mol) dissolved in 500 mL of solution is:

  1. A.0.1 M
  2. B.0.2 M
  3. C.0.4 M
  4. D.1.0 M

Correct answer: B

Explanation: Molarity (M) = moles of solute / volume of solution in litres. Moles of NaOH = 4/40 = 0.1 mol. Volume = 500 mL = 0.5 L. Molarity = 0.1/0.5 = 0.2 M.

Question 14

Chemistry · 4 marks · −1

Which of the following is the strongest acid?

  1. A.HF
  2. B.HCl
  3. C.HBr
  4. D.HI

Correct answer: D

Explanation: Among the halogen acids (HF, HCl, HBr, HI), HI is the strongest acid because the H–I bond is the weakest (largest atomic size of iodine) and dissociates most easily in water. Bond strength decreases down the group: HF > HCl > HBr > HI, but acid strength follows the opposite trend.

Question 15

Chemistry · 4 marks · −1

The functional group present in acetic acid (CH₃COOH) is:

  1. A.Hydroxyl (–OH)
  2. B.Aldehyde (–CHO)
  3. C.Carboxyl (–COOH)
  4. D.Amino (–NH₂)

Correct answer: C

Explanation: Acetic acid (CH₃COOH) contains the carboxyl group (–COOH), which is the functional group characteristic of carboxylic acids. It consists of a carbonyl group (C=O) bonded to a hydroxyl group (–OH).

Question 16

Chemistry · 4 marks · −1

The reaction of an alcohol with a carboxylic acid in the presence of an acid catalyst produces:

  1. A.An aldehyde
  2. B.A ketone
  3. C.An ester
  4. D.An ether

Correct answer: C

Explanation: The reaction of an alcohol with a carboxylic acid (in the presence of an acid catalyst like H₂SO₄) is called esterification. It produces an ester and water. For example, ethanol + acetic acid → ethyl acetate + water.

Question 17

Chemistry · 4 marks · −1

The number of valence electrons in a carbon atom is:

  1. A.2
  2. B.4
  3. C.6
  4. D.8

Correct answer: B

Explanation: Carbon (atomic number 6) has the electronic configuration 1s² 2s² 2p², giving it 4 valence electrons in its outermost shell (2s² 2p²). These 4 valence electrons enable carbon to form four covalent bonds.

Question 18

Physics · 4 marks · −1

A car accelerates uniformly from rest to 72 km/h in 10 seconds. Its acceleration is:

  1. A.1 m/s²
  2. B.2 m/s²
  3. C.7.2 m/s²
  4. D.20 m/s²

Correct answer: B

Explanation: First convert 72 km/h to m/s: 72 × (1000/3600) = 20 m/s. Acceleration = (v − u)/t = (20 − 0)/10 = 2 m/s².

Question 19

Physics · 4 marks · −1

The SI unit of specific heat capacity is:

  1. A.J/kg
  2. B.J/(kg·K)
  3. C.W/(m·K)
  4. D.cal/g

Correct answer: B

Explanation: Specific heat capacity is the heat required to raise the temperature of 1 kg of a substance by 1 K (or 1°C). Its SI unit is J/(kg·K), also written as J kg⁻¹ K⁻¹.

Question 20

Physics · 4 marks · −1

The phenomenon of splitting of white light into its component colours by a prism is called:

  1. A.Diffraction
  2. B.Interference
  3. C.Dispersion
  4. D.Polarisation

Correct answer: C

Explanation: Dispersion is the splitting of white light into its constituent colours (VIBGYOR) when it passes through a prism. This occurs because different wavelengths of light travel at different speeds in the glass, resulting in different angles of refraction.

Question 21

Physics · 4 marks · −1

The magnetic field inside a long solenoid is:

  1. A.Zero everywhere
  2. B.Uniform and along the axis
  3. C.Strongest at the ends
  4. D.Radially outward

Correct answer: B

Explanation: The magnetic field inside a long solenoid is uniform (constant in magnitude and direction) throughout the interior, directed along the axis. It is given by B = μ₀nI, where n is the number of turns per unit length and I is the current. Outside the solenoid, the field is negligibly small.

Question 22

Physics · 4 marks · −1

The radioactive isotope Carbon-14 is used for dating objects up to approximately:

  1. A.500 years
  2. B.5,000 years
  3. C.50,000 years
  4. D.5 million years

Correct answer: C

Explanation: Carbon-14 has a half-life of approximately 5,730 years. Radiocarbon dating is effective for organic materials up to about 50,000 years old. Beyond that, the remaining C-14 is too little to measure accurately.

Question 23

Mathematics · 4 marks · −1

If log₁₀ 2 = 0.3010, then log₁₀ 8 is:

  1. A.0.6020
  2. B.0.9030
  3. C.2.4080
  4. D.3.0100

Correct answer: B

Explanation: Since 8 = 2³, log₁₀ 8 = log₁₀ 2³ = 3 × log₁₀ 2 = 3 × 0.3010 = 0.9030.

Question 24

Mathematics · 4 marks · −1

The value of sin 30° + cos 60° is:

  1. A.0
  2. B.1/2
  3. C.1
  4. D.√3

Correct answer: C

Explanation: sin 30° = 1/2 and cos 60° = 1/2. Therefore, sin 30° + cos 60° = 1/2 + 1/2 = 1.

Question 25

Mathematics · 4 marks · −1

The distance between the points (2, 3) and (5, 7) is:

  1. A.3
  2. B.4
  3. C.5
  4. D.7

Correct answer: C

Explanation: Distance = √[(x₂−x₁)² + (y₂−y₁)²] = √[(5−2)² + (7−3)²] = √[9 + 16] = √25 = 5 units.

Question 26

Mathematics · 4 marks · −1

The derivative of sin x with respect to x is:

  1. A.−cos x
  2. B.cos x
  3. C.tan x
  4. D.−sin x

Correct answer: B

Explanation: The derivative of sin x with respect to x is cos x. This is one of the fundamental differentiation rules: d/dx(sin x) = cos x, derived from the limit definition of the derivative.

Question 27

Mathematics · 4 marks · −1

The median of the data set {3, 7, 2, 9, 5} is:

  1. A.3
  2. B.5
  3. C.7
  4. D.5.2

Correct answer: B

Explanation: To find the median, arrange the data in ascending order: {2, 3, 5, 7, 9}. Since there are 5 values (odd number), the median is the middle value, which is 5.

Question 28

Agriculture · 4 marks · −1

Green manuring involves incorporating which type of crop into the soil?

  1. A.Cereal crop at maturity
  2. B.Leguminous crop while still green
  3. C.Dried grass and straw
  4. D.Fruit tree prunings

Correct answer: B

Explanation: Green manuring involves growing a leguminous crop (such as dhaincha, sunhemp, or sesbania) and ploughing it into the soil while still green. This adds organic matter and nitrogen (fixed by Rhizobium in root nodules) to improve soil fertility.

Question 29

Mathematics · 4 marks · −1

If nCr denotes the number of combinations of n things taken r at a time, then 5C2 equals:

  1. A.5
  2. B.10
  3. C.20
  4. D.25

Correct answer: B

Explanation: 5C2 = 5! / (2! × 3!) = (5 × 4) / (2 × 1) = 20/2 = 10.

Question 30

Physics · 4 marks · −1

The half-life of a radioactive substance is 20 minutes. What fraction of the substance remains after 60 minutes?

  1. A.1/2
  2. B.1/4
  3. C.1/8
  4. D.1/16

Correct answer: C

Explanation: After each half-life, half the substance remains. In 60 minutes there are 60/20 = 3 half-lives. Fraction remaining = (1/2)³ = 1/8.

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