AIEEE 2007 — 29 Apr Offline Set O (Previous Year Paper)

JEE Main · 2007 · with answers and explanations

questions
116
Total marks
348
Duration
180 minutes
Negative marking
−1

Subjects: Mathematics · Physics · Chemistry

Question 1

Mathematics · 3 marks · −1

In a geometric progression consisting of positive terms, each term equals the sum of the next two terms. Then the common ratio of this progression equals

  1. A.12(1−5)\frac{1}{2}(1-\sqrt{5})
  2. B.125\frac{1}{2}\sqrt{5}
  3. C.5\sqrt{5}
  4. D.12(5−1)\frac{1}{2}(\sqrt{5}-1)

Correct answer: D

Explanation: 1=r+r21=r+r^2, positive root.

Question 2

Mathematics · 3 marks · −1

If sin⁡−1(x5)+csc⁡−1(54)=π2\sin^{-1}\left(\frac{x}{5}\right) + \csc^{-1}\left(\frac{5}{4}\right) = \frac{\pi}{2} then a value of x is

  1. A.1
  2. B.3
  3. C.4
  4. D.5

Correct answer: B

Explanation: sin⁡−1x5=cos⁡−145=sin⁡−135\sin^{-1}\frac x5=\cos^{-1}\frac45=\sin^{-1}\frac35.

Question 3

Mathematics · 3 marks · −1

In the binomial expansion of (a−b)n(a - b)^n, n≥5n \ge 5, the sum of 5th5^{th} and 6th6^{th} terms is zero, then ab\frac{a}{b} equals

  1. A.5n−4\frac{5}{n-4}
  2. B.6n−5\frac{6}{n-5}
  3. C.n−56\frac{n-5}{6}
  4. D.n−45\frac{n-4}{5}

Correct answer: D

Explanation: nC4an−4b4=nC5an−5b5{}^nC_4a^{n-4}b^4={}^nC_5a^{n-5}b^5.

Question 4

Mathematics · 3 marks · −1

The set S = {1, 2, 3, ..., 12} is to be partitioned into three sets A, B, C of equal size. Thus, A∪B∪C=SA\cup B\cup C = S, A∩B=B∩C=A∩C=ϕA\cap B = B\cap C = A\cap C = \phi. The number of ways to partition S is

  1. A.12!3!(4!)3\frac{12!}{3!(4!)^3}
  2. B.12!3!(3!)4\frac{12!}{3!(3!)^4}
  3. C.12!(4!)3\frac{12!}{(4!)^3}
  4. D.12!(3!)4\frac{12!}{(3!)^4}

Correct answer: C

Explanation: Labelled sets A, B, C: (124)(84)\binom{12}{4}\binom84.

Question 5

Mathematics · 3 marks · −1

The largest interval lying in (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) for which the function f(x)=4−x2+cos⁡−1(x2−1)+log⁡(cos⁡x)f(x) = 4^{-x^2} + \cos^{-1}\left(\frac{x}{2} - 1\right) + \log(\cos x) is defined, is

  1. A.[0,π][0, \pi]
  2. B.(−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)
  3. C.[−π4,π2)\left[-\frac{\pi}{4}, \frac{\pi}{2}\right)
  4. D.[0,π2)\left[0, \frac{\pi}{2}\right)

Correct answer: D

Explanation: 0≤x≤40\le x\le4 and cos⁡x>0\cos x>0.

Question 6

Mathematics · 3 marks · −1

A body weighing 13 kg is suspended by two strings 5 m and 12 m long, their other ends being fastened to the extremities of a rod 13 m long. If the rod be so held that the body hangs immediately below the middle point. The tensions in the strings are

  1. A.12 kg and 13 kg
  2. B.5 kg and 5 kg
  3. C.5 kg and 12 kg
  4. D.5 kg and 13 kg

Correct answer: C

Explanation: The strings meet at a right angle (5-12-13 triangle). Resolving along each string: the tension in each string equals the weight component along it, 13⋅513=513\cdot\frac{5}{13}=5 kg and 13⋅1213=1213\cdot\frac{12}{13}=12 kg.

Question 7

Mathematics · 3 marks · −1

A pair of fair dice is thrown independently three times. The probability of getting a score of exactly 9 twice is

  1. A.1/729
  2. B.8/9
  3. C.8/729
  4. D.8/243

Correct answer: D

Explanation: (32)(19)289\binom32\left(\frac19\right)^2\frac89.

Question 8

Mathematics · 3 marks · −1

Consider a family of circles which are passing through the point (-1, 1) and are tangent to x-axis. If (h, k) are the co-ordinates of the centre of the circles, then the set of values of k is given by the interval

  1. A.0<k<120 < k < \frac{1}{2}
  2. B.k≥12k \ge \frac{1}{2}
  3. C.−12≤k≤12-\frac{1}{2} \le k \le \frac{1}{2}
  4. D.k≤12k \le \frac{1}{2}

Correct answer: B

Explanation: h2+2h−2k+2=0h^2+2h-2k+2=0 real in h: k≥12k\ge\frac12.

Question 9

Mathematics · 3 marks · −1

Let L be the line of intersection of the planes 2x+3y+z=12x + 3y + z = 1 and x+3y+2z=2x + 3y + 2z = 2. If L makes an angle α\alpha with the positive x-axis, then cos⁡α\cos\alpha equals

  1. A.13\frac{1}{\sqrt{3}}
  2. B.12\frac{1}{2}
  3. C.1
  4. D.12\frac{1}{\sqrt{2}}

Correct answer: A

Explanation: Direction (3,−3,3)(3,-3,3).

Question 10

Mathematics · 3 marks · −1

The differential equation of all circles passing through the origin and having their centres on the x-axis is

  1. A.x2=y2+xydydxx^2 = y^2 + xy\frac{dy}{dx}
  2. B.x2=y2+3xydydxx^2 = y^2 + 3xy\frac{dy}{dx}
  3. C.y2=x2+2xydydxy^2 = x^2 + 2xy\frac{dy}{dx}
  4. D.y2=x2−2xydydxy^2 = x^2 - 2xy\frac{dy}{dx}

Correct answer: C

Explanation: Eliminate g from x2+y2+2gx=0x^2+y^2+2gx=0.

Question 11

Mathematics · 3 marks · −1

If p and q are positive real numbers such that p2+q2=1p^2 + q^2 = 1, then the maximum value of (p + q) is

  1. A.2
  2. B.1/2
  3. C.12\frac{1}{\sqrt{2}}
  4. D.2\sqrt{2}

Correct answer: D

Explanation: (p+q)2≤2(p2+q2)(p+q)^2\le2(p^2+q^2).

Question 12

Mathematics · 3 marks · −1

A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (= a) subtends an angle of 60∘60^\circ at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30∘30^\circ. The height of the tower is

  1. A.2a3\frac{2a}{\sqrt{3}}
  2. B.2a32a\sqrt{3}
  3. C.a3\frac{a}{\sqrt{3}}
  4. D.a3a\sqrt{3}

Correct answer: C

Explanation: Radius = a; h=atan⁡30∘h=a\tan30^\circ.

Question 13

Mathematics · 3 marks · −1

The sum of the series 20C0−20C1+20C2−20C3+⋯+20C10{}^{20}C_0 - {}^{20}C_1 + {}^{20}C_2 - {}^{20}C_3 + \dots + {}^{20}C_{10} is

  1. A.−20C10-{}^{20}C_{10}
  2. B.1220C10\frac{1}{2}{}^{20}C_{10}
  3. C.0
  4. D.20C10{}^{20}C_{10}

Correct answer: B

Explanation: By symmetry of the alternating sum (1−1)20=0(1-1)^{20}=0.

Question 14

Mathematics · 3 marks · −1

If ∣z+4∣≤3|z + 4| \le 3, then the maximum value of ∣z+1∣|z + 1| is

  1. A.4
  2. B.10
  3. C.6
  4. D.0

Correct answer: C

Explanation: ∣z+1∣≤∣z+4∣+3≤6|z+1|\le|z+4|+3\le6.

Question 15

Mathematics · 3 marks · −1

The resultant of two forces P N and 3 N is a force of 7 N. If the direction of 3 N force were reversed, the resultant would be 19\sqrt{19} N. The value of P is

  1. A.5 N
  2. B.6 N
  3. C.3 N
  4. D.4 N

Correct answer: A

Explanation: Adding 49=P2+9+6Pcos⁡θ49=P^2+9+6P\cos\theta and 19=P2+9−6Pcos⁡θ19=P^2+9-6P\cos\theta: P=5P=5.

Question 16

Mathematics · 3 marks · −1

If D=∣11111+x1111+y∣D = \begin{vmatrix} 1 & 1 & 1 \\ 1 & 1+x & 1 \\ 1 & 1 & 1+y \end{vmatrix} for x≠0x \ne 0, y≠0y \ne 0 then D is

  1. A.divisible by neither x nor y
  2. B.divisible by both x and y
  3. C.divisible by x but not y
  4. D.divisible by y but not x

Correct answer: B

Explanation: D=xyD=xy.

Question 17

Mathematics · 3 marks · −1

For the hyperbola x2cos⁡2α−y2sin⁡2α=1\frac{x^2}{\cos^2\alpha} - \frac{y^2}{\sin^2\alpha} = 1, which of the following remains constant when α\alpha varies?

  1. A.eccentricity
  2. B.directrix
  3. C.abscissae of vertices
  4. D.abscissae of foci

Correct answer: D

Explanation: a2+b2=1a^2+b^2=1, foci at (±1,0)(\pm1,0).

Question 18

Mathematics · 3 marks · −1

If a line makes an angle of π4\frac{\pi}{4} with the positive directions of each of x-axis and y-axis, then the angle that the line makes with the positive direction of the z-axis is

  1. A.π6\frac{\pi}{6}
  2. B.π3\frac{\pi}{3}
  3. C.π4\frac{\pi}{4}
  4. D.π2\frac{\pi}{2}

Correct answer: D

Explanation: n2=1−12−12=0n^2=1-\frac12-\frac12=0.

Question 19

Mathematics · 3 marks · −1

A value of C for which the conclusion of Mean Value Theorem holds for the function f(x)=log⁡exf(x) = \log_ex on the interval [1, 3] is

  1. A.2log⁡3e2\log_3e
  2. B.12log⁡e3\frac{1}{2}\log_e3
  3. C.log⁡3e\log_3e
  4. D.log⁡e3\log_e3

Correct answer: A

Explanation: 1c=ln⁡32\frac1c=\frac{\ln3}{2}.

Question 20

Mathematics · 3 marks · −1

The function f(x)=tan⁡−1(sin⁡x+cos⁡x)f(x) = \tan^{-1}(\sin x + \cos x) is an increasing function in

  1. A.(π4,π2)\left(\frac{\pi}{4}, \frac{\pi}{2}\right)
  2. B.(−π2,π4)\left(-\frac{\pi}{2}, \frac{\pi}{4}\right)
  3. C.(0,π2)\left(0, \frac{\pi}{2}\right)
  4. D.(−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

Correct answer: B

Explanation: f′∝cos⁡x−sin⁡x>0f'\propto\cos x-\sin x>0 on (−π2,π4)(-\frac\pi2,\frac\pi4).

Question 21

Mathematics · 3 marks · −1

Let A=[55αα0α5α005]A = \begin{bmatrix} 5 & 5\alpha & \alpha \\ 0 & \alpha & 5\alpha \\ 0 & 0 & 5 \end{bmatrix}. If ∣A2∣=25|A^2| = 25, then ∣α∣|\alpha| equals

  1. A.525^2
  2. B.1
  3. C.1/5
  4. D.5

Correct answer: C

Explanation: ∣A∣=25α|A|=25\alpha, ∣A2∣=625α2=25|A^2|=625\alpha^2=25.

Question 22

Mathematics · 3 marks · −1

The sum of the series 12!−13!+14!−…\frac{1}{2!} - \frac{1}{3!} + \frac{1}{4!} - \dots upto infinity is

  1. A.e−2e^{-2}
  2. B.e−1e^{-1}
  3. C.e−1/2e^{-1/2}
  4. D.e1/2e^{1/2}

Correct answer: B

Explanation: e−1=1−1+12!−13!+…e^{-1}=1-1+\frac1{2!}-\frac1{3!}+\dots.

Question 23

Mathematics · 3 marks · −1

If u^\hat{u} and v^\hat{v} are unit vectors and θ\theta is the acute angle between them, then 2u^×3v^2\hat{u}\times3\hat{v} is a unit vector for

  1. A.exactly two values of θ\theta
  2. B.more than two values of θ\theta
  3. C.no value of θ\theta
  4. D.exactly one value of θ\theta

Correct answer: D

Explanation: 6sin⁡θ=16\sin\theta=1.

Question 24

Mathematics · 3 marks · −1

A particle just clears a wall of height b at distance a and strikes the ground at a distance c from the point of projection. The angle of projection is

  1. A.tan⁡−1bac\tan^{-1}\frac{b}{ac}
  2. B.45∘45^\circ
  3. C.tan⁡−1bca(c−a)\tan^{-1}\frac{bc}{a(c-a)}
  4. D.tan⁡−1bca\tan^{-1}\frac{bc}{a}

Correct answer: C

Explanation: b=atan⁡α(1−ac)b=a\tan\alpha\left(1-\frac ac\right).

Question 25

Mathematics · 3 marks · −1

The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls combined is 50. The percentage of boys in the class is

  1. A.40
  2. B.20
  3. C.80
  4. D.60

Correct answer: C

Explanation: 52x+42y=50(x+y)⇒x=4y52x+42y=50(x+y)\Rightarrow x=4y.

Question 26

Mathematics · 3 marks · −1

The equation of a tangent to the parabola y2=8xy^2 = 8x is y=x+2y = x + 2. The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is

  1. A.(-1, 1)
  2. B.(0, 2)
  3. C.(2, 4)
  4. D.(-2, 0)

Correct answer: D

Explanation: Perpendicular tangents meet on the directrix x = -2.

Question 27

Mathematics · 3 marks · −1

If (2, 3, 5) is one end of a diameter of the sphere x2+y2+z2−6x−12y−2z+20=0x^2 + y^2 + z^2 - 6x - 12y - 2z + 20 = 0, then the coordinates of the other end of the diameter are

  1. A.(4, 9, -3)
  2. B.(4, -3, 3)
  3. C.(4, 3, 5)
  4. D.(4, 3, -3)

Correct answer: A

Explanation: Centre (3, 6, 1).

Question 28

Mathematics · 3 marks · −1

Let a⃗=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, b⃗=i^−j^+2k^\vec{b} = \hat{i} - \hat{j} + 2\hat{k} and c⃗=xi^+(x−2)j^−k^\vec{c} = x\hat{i} + (x-2)\hat{j} - \hat{k}. If the vector c⃗\vec{c} lies in the plane of a⃗\vec{a} and b⃗\vec{b}, then x equals

  1. A.0
  2. B.1
  3. C.-4
  4. D.-2

Correct answer: D

Explanation: Scalar triple product zero: 2x+4=02x+4=0.

Question 29

Mathematics · 3 marks · −1

Let A(h, k), B(1, 1) and C(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 1, then the set of values which 'k' can take is given by

  1. A.{1, 3}
  2. B.{0, 2}
  3. C.{-1, 3}
  4. D.{-3, -2}

Correct answer: C

Explanation: 12⋅1⋅∣k−1∣=1\frac12\cdot1\cdot|k-1|=1.

Question 30

Mathematics · 3 marks · −1

Let P = (-1, 0), Q = (0, 0) and R = (3,33)(3, 3\sqrt{3}) be three points. The equation of the bisector of the angle PQR is

  1. A.3x+y=0\sqrt{3}x + y = 0
  2. B.x+32y=0x + \frac{\sqrt{3}}{2}y = 0
  3. C.32x+y=0\frac{\sqrt{3}}{2}x + y = 0
  4. D.x+3y=0x + \sqrt{3}y = 0

Correct answer: A

Explanation: QR at 60∘60^\circ, QP at 180∘180^\circ: bisector at 120∘120^\circ, y=−3xy=-\sqrt3x.

Question 31

Mathematics · 3 marks · −1

If one of the lines of my2+(1−m2)xy−mx2=0my^2 + (1 - m^2)xy - mx^2 = 0 is a bisector of the angle between the lines xy = 0, then m is

  1. A.-1/2
  2. B.-2
  3. C.1
  4. D.2

Correct answer: C

Explanation: Substituting y=±xy=\pm x gives m2=1m^2=1; option 1 lists m=1m=1.

Question 32

Mathematics · 3 marks · −1

Let F(x)=f(x)+f(1x)F(x) = f(x) + f\left(\frac{1}{x}\right), where f(x)=∫1xlog⁡t1+tdtf(x) = \int_1^x\frac{\log t}{1+t}dt. Then F(e) equals

  1. A.12\frac{1}{2}
  2. B.0
  3. C.1
  4. D.2

Correct answer: A

Explanation: F(e)=∫1eln⁡ttdt=12F(e)=\int_1^e\frac{\ln t}{t}dt=\frac12.

Question 33

Mathematics · 3 marks · −1

Let f:R→Rf : R \to R be a function defined by f(x)=min⁡{x+1,∣x∣+1}f(x) = \min\{x + 1, |x| + 1\}. Then which of the following is true?

  1. A.f(x)≥1f(x) \ge 1 for all x∈Rx \in R
  2. B.f(x) is not differentiable at x = 1
  3. C.f(x) is differentiable everywhere
  4. D.f(x) is not differentiable at x = 0

Correct answer: C

Explanation: f(x)=x+1f(x)=x+1 everywhere.

Question 34

Mathematics · 3 marks · −1

The function f:R∼{0}→Rf : R \sim \{0\} \to R given by f(x)=1x−2e2x−1f(x) = \frac{1}{x} - \frac{2}{e^{2x}-1} can be made continuous at x = 0 by defining f(0) as

  1. A.2
  2. B.-1
  3. C.0
  4. D.1

Correct answer: D

Explanation: Limit is 1.

Question 35

Mathematics · 3 marks · −1

∫dxcos⁡x+3sin⁡x\int\frac{dx}{\cos x + \sqrt{3}\sin x} equals

  1. A.12log⁡tan⁡(x2+π12)+c\frac{1}{2}\log\tan\left(\frac{x}{2}+\frac{\pi}{12}\right)+c
  2. B.12log⁡tan⁡(x2−π12)+c\frac{1}{2}\log\tan\left(\frac{x}{2}-\frac{\pi}{12}\right)+c
  3. C.log⁡tan⁡(x2+π12)+c\log\tan\left(\frac{x}{2}+\frac{\pi}{12}\right)+c
  4. D.log⁡tan⁡(x2−π12)+c\log\tan\left(\frac{x}{2}-\frac{\pi}{12}\right)+c

Correct answer: A

Explanation: 12∫sec⁡(x−π3)dx\frac12\int\sec(x-\frac\pi3)dx.

Question 36

Mathematics · 3 marks · −1

The area enclosed between the curves y2=xy^2 = x and y=∣x∣y = |x| is

  1. A.2/3
  2. B.1
  3. C.1/6
  4. D.1/3

Correct answer: C

Explanation: ∫01(x−x)dx\int_0^1(\sqrt x-x)dx.

Question 37

Mathematics · 3 marks · −1

If the difference between the roots of the equation x2+ax+1=0x^2 + ax + 1 = 0 is less than 5\sqrt{5}, then the set of possible values of a is

  1. A.(-3, 3)
  2. B.(−3,∞)(-3, \infty)
  3. C.(3,∞)(3, \infty)
  4. D.(−∞,−3)(-\infty, -3)

Correct answer: A

Explanation: a2−4<5a^2-4<5 (with real roots, ∣a∣≥2|a|\ge2; the intended answer is (-3, 3)).

Question 38

Physics · 3 marks · −1

The displacement of an object attached to a spring and executing simple harmonic motion is given by x=2×10−2cos⁡πtx = 2\times10^{-2}\cos\pi t metres. The time at which the maximum speed first occurs is

  1. A.0.5 s
  2. B.0.75 s
  3. C.0.125 s
  4. D.0.25 s

Correct answer: A

Explanation: ∣v∣∝∣sin⁡πt∣|v|\propto|\sin\pi t|, max at t=0.5t=0.5 s.

Question 39

Physics · 3 marks · −1

In an a.c. circuit the voltage applied is E=E0sin⁡ωtE = E_0\sin\omega t. The resulting current in the circuit is I=I0sin⁡(ωt−π2)I = I_0\sin\left(\omega t - \frac{\pi}{2}\right). The power consumption in the circuit is given by

  1. A.P=E0I02P = \frac{E_0I_0}{\sqrt{2}}
  2. B.P = zero
  3. C.P=E0I02P = \frac{E_0I_0}{2}
  4. D.P=2E0I0P = \sqrt{2}E_0I_0

Correct answer: B

Explanation: cos⁡ϕ=0\cos\phi=0.

Question 40

Physics · 3 marks · −1

An electric charge 10−3 μ10^{-3}\,\muC is placed at the origin (0, 0) of X-Y co-ordinate system. Two points A and B are situated at (2,2)(\sqrt{2}, \sqrt{2}) and (2, 0) respectively. The potential difference between the points A and B will be

  1. A.9 volt
  2. B.zero
  3. C.2 volt
  4. D.4.5 volt

Correct answer: B

Explanation: Both at distance 2.

Question 41

Physics · 3 marks · −1

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

  1. A.1
  2. B.2
  3. C.14\frac{1}{4}
  4. D.12\frac{1}{2}

Correct answer: D

Explanation: 12QVQV\frac{\frac12QV}{QV}.

Question 42

Physics · 3 marks · −1

An ideal coil of 10H is connected in series with a resistance of 5 Ω5\,\Omega and a battery of 5V. 2 second after the connection is made the current flowing in amperes in the circuit is

  1. A.(1 - e)
  2. B.e
  3. C.e−1e^{-1}
  4. D.(1−e−1)(1 - e^{-1})

Correct answer: D

Explanation: τ=2\tau=2 s, i0=1i_0=1 A.

Question 43

Physics · 3 marks · −1

A long straight wire of radius 'a' caries a steady current i. The current is uniformly distributed across its cross section. The ratio of the magnetic field at a2\frac{a}{2} and 2a is

  1. A.14\frac{1}{4}
  2. B.4
  3. C.1
  4. D.12\frac{1}{2}

Correct answer: C

Explanation: Both equal μ0i4πa\frac{\mu_0i}{4\pi a}.

Question 44

Physics · 3 marks · −1

A current I flows along the length of an infinitely long, straight, thin walled pipe. Then

  1. A.the magnetic field is zero only on the axis of the pipe
  2. B.the magnetic field is different at different points inside the pipe
  3. C.the magnetic field at any point inside the pipe is zero
  4. D.the magnetic field at all points inside the pipe is the same, but not zero

Correct answer: C

Explanation: Ampere's law: no enclosed current.

Question 45

Physics · 3 marks · −1

If MOM_O is the mass of an oxygen isotope 8O17_8O^{17}, MpM_p and MNM_N are the masses of a proton and a neutron respectively, the nuclear binding energy of the isotope is

  1. A.(MO−8Mp)c2(M_O - 8M_p)c^2
  2. B.(MO−8Mp−9MN)c2(M_O - 8M_p - 9M_N)c^2
  3. C.MOc2M_Oc^2
  4. D.(MO−17MN)c2(M_O - 17M_N)c^2

Correct answer: B

Explanation: The binding energy is (8Mp+9MN−MO)c2(8M_p+9M_N-M_O)c^2; option 2 is its negative (the intended answer).

Question 46

Physics · 3 marks · −1

In gamma ray emission from a nucleus

  1. A.both the neutron number and the proton number change
  2. B.there is no change in the proton number and the neutron number.
  3. C.only the neutron number changes
  4. D.only the proton number changes

Correct answer: B

Explanation: Gamma emission is de-excitation only.

Question 47

Physics · 3 marks · −1

If in a p-n junction diode, a square input signal of 10V is applied as shown. Then the output signal across RLR_L will be

Figure for question 47
  1. A.Waveform (1): square pulse 0 to 10 V
  2. B.Waveform (2): negative pulse to -10 V
  3. C.Waveform (3): negative pulse to -5 V
  4. D.Waveform (4): positive pulse +5 V only

Correct answer: D

Explanation: The forward-biased half (+5 V) passes, the -5 V half is blocked.

Question 48

Physics · 3 marks · −1

Photon of frequency ν\nu has a momentum associated with it. If c is the velocity of light, the momentum is

  1. A.ν/c\nu/c
  2. B.hνch\nu c
  3. C.hν/c2h\nu/c^2
  4. D.hν/ch\nu/c

Correct answer: D

Explanation: p=hλp=\frac{h}{\lambda}.

Question 49

Physics · 3 marks · −1

The velocity of a particle is v=v0+gt+ft2v = v_0 + gt + ft^2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is

  1. A.v0+2g+3fv_0 + 2g + 3f
  2. B.v0+g/2+f/3v_0 + g/2 + f/3
  3. C.v0+g+fv_0 + g + f
  4. D.v0+g/2+fv_0 + g/2 + f

Correct answer: B

Explanation: Integrate.

Question 50

Physics · 3 marks · −1

For the given uniform square lamina ABCD, whose centre is O,

Figure for question 50
  1. A.2IAC=IEF\sqrt{2}I_{AC} = I_{EF}
  2. B.IAD=3IEFI_{AD} = 3I_{EF}
  3. C.IAC=IEFI_{AC} = I_{EF}
  4. D.IAC=2IEFI_{AC} = \sqrt{2}I_{EF}

Correct answer: C

Explanation: By the perpendicular axis theorem and symmetry, all in-plane axes through O have equal moments.

Question 51

Physics · 3 marks · −1

A point mass oscillates along the x-axis according to the law x=x0cos⁡(ωt−π/4)x = x_0\cos(\omega t - \pi/4). If the acceleration of the particle is written as a=Acos⁡(ωt+δ)a = A\cos(\omega t + \delta)

  1. A.A=x0A = x_0, δ=−π/4\delta = -\pi/4
  2. B.A=x0ω2A = x_0\omega^2, δ=π/4\delta = \pi/4
  3. C.A=x0ω2A = x_0\omega^2, δ=−π/4\delta = -\pi/4
  4. D.A=x0ω2A = x_0\omega^2, δ=3π/4\delta = 3\pi/4

Correct answer: D

Explanation: a=−ω2x=x0ω2cos⁡(ωt−π4+π)a=-\omega^2x=x_0\omega^2\cos(\omega t-\frac\pi4+\pi).

Question 52

Physics · 3 marks · −1

Charges are placed on the vertices of a square as shown. Let E⃗\vec{E} be the electric field and V the potential at the centre. If the charges on A and B are interchanged with those on D and C respectively, then

Figure for question 52
  1. A.E⃗\vec{E} remains unchanged, V changes
  2. B.Both E⃗\vec{E} and V change
  3. C.E⃗\vec{E} and V remains unchanged
  4. D.E⃗\vec{E} changes, V remains unchanged

Correct answer: D

Explanation: Swapping reverses the field direction; the potential (sum of q/r) stays zero.

Question 53

Physics · 3 marks · −1

The half-life period of a radio-active element X is same as the mean life time of another radio-active element Y. Initially they have the same number of atoms. Then

  1. A.X will decay faster than Y
  2. B.Y will decay faster than X
  3. C.X and Y have same decay rate initially
  4. D.X and Y decay at same rate always

Correct answer: B

Explanation: λY=λX0.693>λX\lambda_Y=\frac{\lambda_X}{0.693}>\lambda_X.

Question 54

Physics · 3 marks · −1

A Carnot engine, having an efficiency of η=1/10\eta = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

  1. A.99 J
  2. B.90 J
  3. C.1 J
  4. D.100 J

Correct answer: B

Explanation: COP =T2T1−T2=9=\frac{T_2}{T_1-T_2}=9.

Question 55

Physics · 3 marks · −1

Carbon, silicon and germanium have four valence electrons each. At room temperature which one of the following statements is most appropriate?

  1. A.The number of free conduction electrons is significant in C but small in Si and Ge.
  2. B.The number of free conduction electrons is negligible small in all the three.
  3. C.The number of free electrons for conduction is significant in all the three.
  4. D.The number of free electrons for conduction is significant only in Si and Ge but small in C.

Correct answer: D

Explanation: Diamond has a large band gap.

Question 56

Physics · 3 marks · −1

A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields E⃗\vec{E} and B⃗\vec{B} with a velocity v⃗\vec{v} perpendicular to both E⃗\vec{E} and B⃗\vec{B}, and comes out without any change in magnitude or direction of v⃗\vec{v}. Then

  1. A.v⃗=E⃗×B⃗/B2\vec{v} = \vec{E}\times\vec{B}/B^2
  2. B.v⃗=B⃗×E⃗/B2\vec{v} = \vec{B}\times\vec{E}/B^2
  3. C.v⃗=E⃗×B⃗/E2\vec{v} = \vec{E}\times\vec{B}/E^2
  4. D.v⃗=B⃗×E⃗/E2\vec{v} = \vec{B}\times\vec{E}/E^2

Correct answer: A

Explanation: E⃗+v⃗×B⃗=0\vec E+\vec v\times\vec B=0.

Question 57

Physics · 3 marks · −1

The potential at a point x (measured in μ\mum) due to some charges situated on the x-axis is given by V(x)=20/(x2−4)V(x) = 20/(x^2 - 4) Volts. The electric field E at x = 4 μ\mum is given by

  1. A.5/3 Volt/μ\mum and in the -ve x direction
  2. B.5/3 Volt/μ\mum and in the +ve x direction
  3. C.10/9 Volt/μ\mum and in the -ve x direction
  4. D.10/9 Volt/μ\mum and in the +ve x direction

Correct answer: D

Explanation: E=−V′=40x(x2−4)2=160144E=-V'=\frac{40x}{(x^2-4)^2}=\frac{160}{144}.

Question 58

Physics · 3 marks · −1

Which of the following transitions in hydrogen atoms emit photons of highest frequency?

  1. A.n = 2 to n = 6
  2. B.n = 6 to n = 2
  3. C.n = 2 to n = 1
  4. D.n = 1 to n = 2

Correct answer: C

Explanation: Largest emitted energy gap.

Question 59

Physics · 3 marks · −1

A block of mass 'm' is connected to another block of mass 'M' by a spring (massless) of spring constant 'k'. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force 'F' starts acting on the block of mass 'M' to pull it. Find the force on the block of mass 'm'

  1. A.mFM\frac{mF}{M}
  2. B.(M+m)Fm\frac{(M+m)F}{m}
  3. C.mF(m+M)\frac{mF}{(m+M)}
  4. D.MF(m+M)\frac{MF}{(m+M)}

Correct answer: C

Explanation: Intended: when both move with common acceleration, Fm=mFm+MF_m=\frac{mF}{m+M}.

Question 60

Physics · 3 marks · −1

Two lenses of power -15 D and +5 D are in contact with each other. The focal length of the combination is

  1. A.-20 cm
  2. B.-10 cm
  3. C.+20 cm
  4. D.+10 cm

Correct answer: B

Explanation: P = -10 D.

Question 61

Physics · 3 marks · −1

One end of a thermally insulated rod is kept at a temperature T1T_1 and the other at T2T_2. The rod is composed of two sections of lengths ℓ1\ell_1 and ℓ2\ell_2 and thermal conductivities k1k_1 and k2k_2 respectively. The temperature at the interface of the two sections is

Figure for question 61
  1. A.(k2ℓ2T1+k1ℓ1T2)/(k1ℓ1+k2ℓ2)(k_2\ell_2T_1 + k_1\ell_1T_2)/(k_1\ell_1 + k_2\ell_2)
  2. B.(k2ℓ1T1+k1ℓ2T2)/(k2ℓ1+k1ℓ2)(k_2\ell_1T_1 + k_1\ell_2T_2)/(k_2\ell_1 + k_1\ell_2)
  3. C.(k1ℓ2T1+k2ℓ1T2)/(k1ℓ2+k2ℓ1)(k_1\ell_2T_1 + k_2\ell_1T_2)/(k_1\ell_2 + k_2\ell_1)
  4. D.(k1ℓ1T1+k2ℓ2T2)/(k1ℓ1+k2ℓ2)(k_1\ell_1T_1 + k_2\ell_2T_2)/(k_1\ell_1 + k_2\ell_2)

Correct answer: C

Explanation: Equal heat currents: k1(T1−T)ℓ1=k2(T−T2)ℓ2\frac{k_1(T_1-T)}{\ell_1}=\frac{k_2(T-T_2)}{\ell_2}.

Question 62

Physics · 3 marks · −1

A sound absorber attenuates the sound level by 20 dB. The intensity decreases by a factor of

  1. A.1000
  2. B.10000
  3. C.10
  4. D.100

Correct answer: D

Explanation: 20 dB = factor 100.

Question 63

Physics · 3 marks · −1

If CpC_p and CvC_v denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

  1. A.Cp−Cv=R/28C_p - C_v = R/28
  2. B.Cp−Cv=R/14C_p - C_v = R/14
  3. C.Cp−Cv=RC_p - C_v = R
  4. D.Cp−Cv=28RC_p - C_v = 28R

Correct answer: A

Explanation: Per unit mass: RM\frac RM.

Question 64

Physics · 3 marks · −1

A charged particle moves through a magnetic field perpendicular to its direction. Then

  1. A.the momentum changes but the kinetic energy is constant
  2. B.both momentum and kinetic energy of the particle are not constant
  3. C.both, momentum and kinetic energy of the particle are constant
  4. D.kinetic energy changes but the momentum is constant

Correct answer: A

Explanation: Magnetic force does no work.

Question 65

Physics · 3 marks · −1

Two identical conducting wires AOB and COD are placed at right angles to each other. The wire AOB carries an electric current I1I_1 and COD carries a current I2I_2. The magnetic field on a point lying at a distance 'd' from O, in a direction perpendicular to the plane of the wires AOB and COD, will be given by

  1. A.μ02π(I1+I2d)1/2\frac{\mu_0}{2\pi}\left(\frac{I_1+I_2}{d}\right)^{1/2}
  2. B.μ02πd(I12+I22)1/2\frac{\mu_0}{2\pi d}(I_1^2+I_2^2)^{1/2}
  3. C.μ02πd(I1+I2)\frac{\mu_0}{2\pi d}(I_1+I_2)
  4. D.μ02πd(I12+I22)\frac{\mu_0}{2\pi d}(I_1^2+I_2^2)

Correct answer: B

Explanation: Perpendicular fields add in quadrature.

Question 66

Physics · 3 marks · −1

The resistance of a wire is 5 ohm at 50∘50^\circC and 6 ohm at 100∘100^\circC. The resistance of the wire at 0∘0^\circC will be

  1. A.2 ohm
  2. B.1 ohm
  3. C.4 ohm
  4. D.3 ohm

Correct answer: C

Explanation: Linear: 1 ohm per 50∘50^\circC.

Question 67

Physics · 3 marks · −1

A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volts. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is

  1. A.12(K−1)CV2\frac{1}{2}(K-1)CV^2
  2. B.CV2(K−1)/KCV^2(K-1)/K
  3. C.(K−1)CV2(K-1)CV^2
  4. D.zero

Correct answer: D

Explanation: The system returns to its initial state.

Question 68

Physics · 3 marks · −1

If gEg_E and gmg_m are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio electronic charge on the moonelectronic charge on the earth\frac{\text{electronic charge on the moon}}{\text{electronic charge on the earth}} to be

  1. A.1
  2. B.0
  3. C.gE/gmg_E/g_m
  4. D.gm/gEg_m/g_E

Correct answer: A

Explanation: Electronic charge is universal.

Question 69

Physics · 3 marks · −1

A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs coincide. The centre of mass of the new disc is α/R\alpha/R from the centre of the bigger disc. The value of α\alpha is

  1. A.1/3
  2. B.1/2
  3. C.1/6
  4. D.1/4

Correct answer: A

Explanation: Interpreting the distance as αR\alpha R: 3M4αR=M4R\frac{3M}{4}\alpha R=\frac M4R.

Question 70

Physics · 3 marks · −1

A round uniform body of radius R, mass M and moment of inertia 'I', rolls down (without slipping) an inclined plane making an angle θ\theta with the horizontal. Then its acceleration is

  1. A.gsin⁡θ1+I/MR2\frac{g\sin\theta}{1+I/MR^2}
  2. B.gsin⁡θ1+MR2/I\frac{g\sin\theta}{1+MR^2/I}
  3. C.gsin⁡θ1−I/MR2\frac{g\sin\theta}{1-I/MR^2}
  4. D.gsin⁡θ1−MR2/I\frac{g\sin\theta}{1-MR^2/I}

Correct answer: A

Explanation: Standard rolling result.

Question 71

Physics · 3 marks · −1

Angular momentum of the particle rotating with a central force is constant due to

  1. A.Constant Force
  2. B.Constant linear momentum.
  3. C.Zero Torque
  4. D.Constant Torque

Correct answer: C

Explanation: Central force exerts no torque.

Question 72

Physics · 3 marks · −1

A 2 kg block slides on a horizontal floor with a speed of 4 m/s. It strikes a uncompressed spring, and compresses it till the block is motionless. The kinetic friction force is 15 N and spring constant is 10,000 N/m. The spring compresses by

  1. A.5.5 cm
  2. B.2.5 cm
  3. C.11.0 cm
  4. D.8.5 cm

Correct answer: A

Explanation: 16=5000x2+15x⇒x≈0.05516=5000x^2+15x\Rightarrow x\approx0.055 m.

Question 73

Physics · 3 marks · −1

A particle is projected at 60∘60^\circ to the horizontal with a kinetic energy K. The kinetic energy at the highest point is

  1. A.K
  2. B.Zero
  3. C.K/2
  4. D.K/4

Correct answer: D

Explanation: cos⁡260∘=14\cos^260^\circ=\frac14.

Question 74

Physics · 3 marks · −1

In a Young's double slit experiment the intensity at a point where the path difference is λ6\frac{\lambda}{6} (λ\lambda being the wavelength of the light used) is I. If I0I_0 denotes the maximum intensity, II0\frac{I}{I_0} is equal to

  1. A.12\frac{1}{\sqrt{2}}
  2. B.32\frac{\sqrt{3}}{2}
  3. C.1/2
  4. D.3/4

Correct answer: D

Explanation: ϕ=π3\phi=\frac\pi3, cos⁡2π6=34\cos^2\frac\pi6=\frac34.

Question 75

Physics · 3 marks · −1

Two springs, of force constants k1k_1 and k2k_2, are connected to a mass m as shown. The frequency of oscillation of the mass is f. If both k1k_1 and k2k_2 are made four times their original values, the frequency of oscillation becomes

Figure for question 75
  1. A.f/2
  2. B.f/4
  3. C.4f
  4. D.2f

Correct answer: D

Explanation: Parallel combination: f∝k1+k2f\propto\sqrt{k_1+k_2}.

Question 76

Physics · 3 marks · −1

When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf Q = 36 cal. W along the path ibf is

Figure for question 76
  1. A.6 cal
  2. B.16 cal
  3. C.66 cal
  4. D.14 cal

Correct answer: A

Explanation: ΔU=30\Delta U=30 cal; W=36−30W=36-30.

Question 77

Physics · 3 marks · −1

A particle of mass m executes simple harmonic motion with amplitude 'a' and frequency 'ν\nu'. The average kinetic energy during its motion from the position of equilibrium to the end is

  1. A.π2ma2ν2\pi^2ma^2\nu^2
  2. B.14π2ma2ν2\frac{1}{4}\pi^2ma^2\nu^2
  3. C.4π2ma2ν24\pi^2ma^2\nu^2
  4. D.2π2ma2ν22\pi^2ma^2\nu^2

Correct answer: A

Explanation: Time average 14ma2ω2=π2ma2ν2\frac14ma^2\omega^2=\pi^2ma^2\nu^2.

Question 78

Chemistry · 3 marks · −1

The energies of activation for forward and reverse reactions for A2+B2⇌2ABA_2 + B_2 \rightleftharpoons 2AB are 180 kJ mol−1^{-1} and 200 kJ mol−1^{-1} respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol−1^{-1}. The enthalpy change of the reaction (A2+B2→2AB)(A_2 + B_2 \rightarrow 2AB) in the presence of catalyst will be (in kJ mol−1^{-1})

  1. A.300
  2. B.120
  3. C.280
  4. D.20

Correct answer: D

Explanation: ΔH=Ef−Eb=80−100=−20\Delta H=E_f-E_b=80-100=-20 kJ/mol, unchanged by the catalyst; the magnitude 20 is offered.

Question 79

Chemistry · 3 marks · −1

The cell, Zn∣Zn2+(1M)∣∣Cu2+(1M)∣CuZn|Zn^{2+}(1M)||Cu^{2+}(1M)|Cu (Ecell∘=1.10E^\circ_{cell} = 1.10 V), was allowed to be completely discharged at 298 K. The relative concentration of Zn2+Zn^{2+} to Cu2+Cu^{2+} ([Zn2+][Cu2+])\left(\frac{[Zn^{2+}]}{[Cu^{2+}]}\right) is

  1. A.antilog (24.08)
  2. B.37.3
  3. C.1037.310^{37.3}
  4. D.9.65×1049.65\times10^4

Correct answer: C

Explanation: E=0⇒log⁡Q=2⋅1.100.0591=37.3E=0\Rightarrow\log Q=\frac{2\cdot1.10}{0.0591}=37.3.

Question 80

Chemistry · 3 marks · −1

The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is

  1. A.4.5
  2. B.2.5
  3. C.9.5
  4. D.7.0

Correct answer: C

Explanation: pH = pKa = 4.5.

Question 81

Chemistry · 3 marks · −1

Consider the reaction, 2A+B→2A + B \rightarrow Products. When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

  1. A.L mol−1^{-1} s−1^{-1}
  2. B.no unit
  3. C.mol L−1^{-1} s−1^{-1}
  4. D.s−1^{-1}

Correct answer: A

Explanation: First order in each: overall second order.

Question 82

Chemistry · 3 marks · −1

Identify the incorrect statement among the following

  1. A.d-Block elements show irregular and erratic chemical properties among themselves
  2. B.La and Lu have partially filled d orbitals and no other partially filled orbitals
  3. C.The chemistry of various lanthanoids is very similar
  4. D.4f and 5f orbitals are equally shielded

Correct answer: D

Explanation: 4f is more shielded than 5f.

Question 83

Chemistry · 3 marks · −1

Which one of the following has a square planar geometry?

  1. A.[CoCl4]2−[CoCl_4]^{2-}
  2. B.[FeCl4]2−[FeCl_4]^{2-}
  3. C.[NiCl4]2−[NiCl_4]^{2-}
  4. D.[PtCl4]2−[PtCl_4]^{2-}

Correct answer: D

Explanation: 5d Pt2+Pt^{2+} complexes are square planar.

Question 84

Chemistry · 3 marks · −1

Which of the following molecules is expected to rotate the plane of plane polarized light?

Figure for question 84
  1. A.D-glyceraldehyde (Fischer projection: CHO, H-C-OH, CH2OH)
  2. B.3-pentanethiol (CH3CH2CH(SH)CH2CH3CH_3CH_2CH(SH)CH_2CH_3)
  3. C.meso-1,2-diphenylethane-1,2-diamine
  4. D.Glycine (H2NCH2COOHH_2NCH_2COOH)

Correct answer: A

Explanation: Only glyceraldehyde is chiral.

Question 85

Chemistry · 3 marks · −1

The secondary structure of a protein refers to

  1. A.α\alpha-helical backbone
  2. B.hydrophobic interactions
  3. C.sequence of α\alpha-amino acids
  4. D.fixed configuration of the polypeptide backbone

Correct answer: A

Explanation: H-bonded helices/sheets.

Question 86

Chemistry · 3 marks · −1

Which of the following reactions will yield 2, 2-dibromopropane?

  1. A.CH3−C≡CH+2HBr→CH_3-C\equiv CH + 2HBr \rightarrow
  2. B.CH3CH=CHBr+HBr→CH_3CH=CHBr + HBr \rightarrow
  3. C.CH≡CH+2HBr→CH\equiv CH + 2HBr \rightarrow
  4. D.CH3−CH=CH2+HBr→CH_3-CH=CH_2 + HBr \rightarrow

Correct answer: A

Explanation: Markovnikov addition twice to propyne.

Question 87

Chemistry · 3 marks · −1

In the chemical reaction, CH3CH2NH2+CHCl3+3KOH→(A)+(B)+3H2OCH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (A) + (B) + 3H_2O, the compound (A) and (B) are respectively

  1. A.C2H5CNC_2H_5CN and 3KCl
  2. B.CH3CH2CONH2CH_3CH_2CONH_2 and 3KCl
  3. C.C2H5NCC_2H_5NC and K2CO3K_2CO_3
  4. D.C2H5NCC_2H_5NC and 3KCl

Correct answer: D

Explanation: Carbylamine reaction.

Question 88

Chemistry · 3 marks · −1

The reaction of toluene with Cl2Cl_2 in presence of FeCl3FeCl_3 gives predominantly

  1. A.benzoyl chloride
  2. B.benzyl chloride
  3. C.o-and p-chlorotoluene
  4. D.m-chlorotoluene

Correct answer: C

Explanation: Ring chlorination, o/p directed.

Question 89

Chemistry · 3 marks · −1

Presence of a nitro group in a benzene ring

  1. A.activates the ring towards electrophilic substitution
  2. B.renders the ring basic
  3. C.deactivates the ring towards nucleophilic substitution
  4. D.deactivates the ring towards electrophilic substitution

Correct answer: D

Explanation: -M/-I withdrawal.

Question 90

Chemistry · 3 marks · −1

In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

  1. A.C2→C2+C_2 \rightarrow C_2^+
  2. B.NO→NO+NO \rightarrow NO^+
  3. C.O2→O2+O_2 \rightarrow O_2^+
  4. D.N2→N2+N_2 \rightarrow N_2^+

Correct answer: B

Explanation: NO loses an antibonding electron and becomes diamagnetic.

Question 91

Chemistry · 3 marks · −1

The actinoids exhibits more number of oxidation states in general than the lanthanoids. This is because

  1. A.the 5f orbitals are more buried than the 4f orbitals
  2. B.there is a similarity between 4f and 5f orbitals in their angular part of the wave function
  3. C.the actinoids are more reactive than the lanthanoids
  4. D.the 5f orbitals extend further from the nucleus than the 4f orbitals

Correct answer: D

Explanation: 5f are less buried.

Question 92

Chemistry · 3 marks · −1

Equal masses of methane and oxygen are mixed in an empty container at 25∘25^\circC. The fraction of the total pressure exerted by oxygen is

  1. A.23\frac{2}{3}
  2. B.13×273298\frac{1}{3}\times\frac{273}{298}
  3. C.13\frac{1}{3}
  4. D.12\frac{1}{2}

Correct answer: C

Explanation: Mole fraction 1/321/32+1/16\frac{1/32}{1/32+1/16}.

Question 93

Chemistry · 3 marks · −1

A 5.25 % solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol−1^{-1}) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0 g cm−3^{-3}, molar mass of the substance will be

  1. A.90.0 g mol−1^{-1}
  2. B.115.0 g mol−1^{-1}
  3. C.105.0 g mol−1^{-1}
  4. D.210.0 g mol−1^{-1}

Correct answer: D

Explanation: 5.25M=1.560\frac{5.25}{M}=\frac{1.5}{60}.

Question 94

Chemistry · 3 marks · −1

Assuming that water vapour is an ideal gas, the internal energy (ΔU\Delta U) when 1 mol of water is vapourised at 1 bar pressure and 100∘100^\circC, (Given: Molar enthalpy of vapourization of water at 1 bar and 373 K = 41 kJ mol−1^{-1} and R = 8.3 J mol−1^{-1}K−1^{-1}) will be

  1. A.4.100 kJ mol−1^{-1}
  2. B.3.7904 kJ mol−1^{-1}
  3. C.37.904 kJ mol−1^{-1}
  4. D.41.00 kJ mol−1^{-1}

Correct answer: C

Explanation: ΔU=41−8.3×10−3⋅373\Delta U=41-8.3\times10^{-3}\cdot373.

Question 95

Chemistry · 3 marks · −1

In a saturated solution of the sparingly soluble strong electrolyte AgIO3AgIO_3 (Molecular mass = 283) the equilibrium which sets in is AgIO3(s)⇌Ag+(aq)+IO3−(aq)AgIO_3(s) \rightleftharpoons Ag^+(aq) + IO_3^-(aq). If the solubility product constant KspK_{sp} of AgIO3AgIO_3 at a given temperature is 1.0×10−81.0\times10^{-8}, what is the mass of AgIO3AgIO_3 contained in 100 ml of its saturated solution?

  1. A.28.3×10−228.3\times10^{-2} g
  2. B.2.83×10−32.83\times10^{-3} g
  3. C.1.0×10−71.0\times10^{-7} g
  4. D.1.0×10−41.0\times10^{-4} g

Correct answer: B

Explanation: s=10−4s=10^{-4} M; 10−510^{-5} mol in 100 mL.

Question 96

Chemistry · 3 marks · −1

A radioactive element gets spilled over the floor of a room. Its half-life period is 30 days. If the initial activity is ten times the permissible value, after how many days will it be safe to enter the room?

  1. A.1000 days
  2. B.300 days
  3. C.10 days
  4. D.100 days

Correct answer: D

Explanation: t=30log⁡210≈100t=30\log_210\approx100 days.

Question 97

Chemistry · 3 marks · −1

Which one of the following conformation of cyclohexane is chiral?

  1. A.Twist boat
  2. B.Rigid
  3. C.Chair
  4. D.Boat

Correct answer: A

Explanation: Twist-boat has no mirror plane.

Question 98

Chemistry · 3 marks · −1

Which of the following is the correct order of decreasing SN2S_N2 reactivity? (X = a halogen)

  1. A.RCH2X>R3CX>R2CHXRCH_2X > R_3CX > R_2CHX
  2. B.RCH2X>R2CHX>R3CXRCH_2X > R_2CHX > R_3CX
  3. C.R3CX>R2CHX>RCH2XR_3CX > R_2CHX > RCH_2X
  4. D.R2CHX>R3CX>RCH2XR_2CHX > R_3CX > RCH_2X

Correct answer: B

Explanation: Steric hindrance.

Question 99

Chemistry · 3 marks · −1

In the following sequence of reactions, CH3CH2OH→P+I2A→Mg/etherB→HCHOC→H2ODCH_3CH_2OH \xrightarrow{P + I_2} A \xrightarrow{Mg/ether} B \xrightarrow{HCHO} C \xrightarrow{H_2O} D the compound 'D' is

  1. A.butanal
  2. B.n-butyl alcohol
  3. C.n-propyl alcohol
  4. D.propanal

Correct answer: C

Explanation: C2H5MgI+HCHO→CH3CH2CH2OHC_2H_5MgI+HCHO\rightarrow CH_3CH_2CH_2OH.

Question 100

Chemistry · 3 marks · −1

Which of the following sets of quantum numbers represents the highest energy of an atom?

  1. A.n = 3, l = 2, m = 1, s = +1/2
  2. B.n = 3, l = 2, m = 1, s = +1/2
  3. C.n = 4, l = 0, m = 0, s = +1/2
  4. D.n = 3, l = 0, m = 0, s = +1/2

Correct answer: B

Explanation: 3d (n + l = 5) is higher than 4s (4 + 0).

Question 101

Chemistry · 3 marks · −1

Which of the following hydrogen bonds is the strongest?

  1. A.O-H.......N
  2. B.F-H.......F
  3. C.O-H.......O
  4. D.O-H.......F

Correct answer: B

Explanation: F is the most electronegative.

Question 102

Chemistry · 3 marks · −1

In the reaction, 2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g)2Al(s) + 6HCl(aq) \rightarrow 2Al^{3+}(aq) + 6Cl^-(aq) + 3H_2(g),

  1. A.6 L HCl(aq) is consumed for every 3L H2H_2(g) produced
  2. B.33.6 L H2H_2(g) is produced regardless of temperature and pressure for every mole Al that reacts
  3. C.67.2 L H2H_2(g) at STP is produced for every mole Al that reacts
  4. D.11.2 L H2H_2(g) at STP is produced for every mole HCl(aq) consumed

Correct answer: D

Explanation: 0.5 mol H2H_2 per mol HCl.

Question 103

Chemistry · 3 marks · −1

Regular use of which of the following fertilizer increases the acidity of soil?

  1. A.Potassium nitrate
  2. B.Urea
  3. C.Superphosphate of lime
  4. D.Ammonium sulphate

Correct answer: D

Explanation: NH4+NH_4^+ hydrolysis.

Question 104

Chemistry · 3 marks · −1

Identify the correct statement regarding a spontaneous process

  1. A.For a spontaneous process in an isolated system, the change in entropy is positive
  2. B.Endothermic processes are never spontaneous
  3. C.Exothermic processes are always spontaneous
  4. D.Lowering of energy in the reaction process is the only criterion for spontaneity

Correct answer: A

Explanation: Second law.

Question 105

Chemistry · 3 marks · −1

Which of the following nuclear reactions will generate an isotope?

  1. A.neutron particle emission
  2. B.positron emission
  3. C.α\alpha-particle emission
  4. D.β\beta-particle emission

Correct answer: A

Explanation: Z unchanged.

Question 106

Chemistry · 3 marks · −1

The equivalent conductances of two strong electrolytes at infinite dilution in H2OH_2O (where ions move freely through a solution) at 25∘25^\circC are given below: ΛCH3COONa∘=91.0\Lambda^\circ_{CH_3COONa} = 91.0 S cm2^2/equiv, ΛHCl∘=426.2\Lambda^\circ_{HCl} = 426.2 S cm2^2/equiv. What additional information/quantity one needs to calculate Λ∘\Lambda^\circ of an aqueous solution of acetic acid?

  1. A.Λ∘\Lambda^\circ of NaCl
  2. B.Λ∘\Lambda^\circ of CH3COOKCH_3COOK
  3. C.The limiting equivalent conductance of H+H^+ (λH+∘\lambda^\circ_{H^+})
  4. D.Λ∘\Lambda^\circ of chloroacetic acid (ClCH2COOHClCH_2COOH)

Correct answer: A

Explanation: Kohlrausch: ΛAcOH=ΛAcONa+ΛHCl−ΛNaCl\Lambda_{AcOH}=\Lambda_{AcONa}+\Lambda_{HCl}-\Lambda_{NaCl}.

Question 107

Chemistry · 3 marks · −1

Which one of the following is the strongest base in aqueous solution?

  1. A.Trimethylamine
  2. B.Aniline
  3. C.Dimethylamine
  4. D.Methylamine

Correct answer: C

Explanation: In water: 2° > 1° > 3° for methylamines.

Question 108

Chemistry · 3 marks · −1

The compound formed as a result of oxidation of ethyl benzene by KMnO4KMnO_4 is

  1. A.benzophenone
  2. B.acetophenone
  3. C.benzoic acid
  4. D.benzyl alcohol

Correct answer: C

Explanation: Side-chain oxidation.

Question 109

Chemistry · 3 marks · −1

The IUPAC name of the compound shown (skeletal: a seven-carbon chain with two methyls on C4 and an ethyl on C3) is

Figure for question 109
  1. A.1, 1-diethyl-2,2-dimethylpentane
  2. B.4, 4-dimethyl-5, 5-diethylpentane
  3. C.5, 5-diethyl-4, 4-diemthylpentane
  4. D.3-ethyl-4, 4-dimethylheptane

Correct answer: D

Explanation: Longest chain seven carbons.

Question 110

Chemistry · 3 marks · −1

Which of the following species exhibits the diamagnetic behaviour?

  1. A.O22−O_2^{2-}
  2. B.O2+O_2^+
  3. C.O2O_2
  4. D.NO

Correct answer: A

Explanation: 18 electrons, all paired.

Question 111

Chemistry · 3 marks · −1

The stability of dihalides of Si, Ge, Sn and Pb increases steadily in the sequence

  1. A.GeX2≪SiX2≪SnX2≪PbX2GeX_2 \ll SiX_2 \ll SnX_2 \ll PbX_2
  2. B.SiX2≪GeX2≪PbX2≪SnX2SiX_2 \ll GeX_2 \ll PbX_2 \ll SnX_2
  3. C.SiX2≪GeX2≪SnX2≪PbX2SiX_2 \ll GeX_2 \ll SnX_2 \ll PbX_2
  4. D.PbX2≪SnX2≪GeX2≪SiX2PbX_2 \ll SnX_2 \ll GeX_2 \ll SiX_2

Correct answer: C

Explanation: Inert pair effect.

Question 112

Chemistry · 3 marks · −1

The charge/size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, K+K^+, Ca2+Ca^{2+}, Mg2+Mg^{2+}, Be2+Be^{2+}?

  1. A.Mg2+,Be2+,K+,Ca2+Mg^{2+}, Be^{2+}, K^+, Ca^{2+}
  2. B.Be2+,K+,Ca2+,Mg2+Be^{2+}, K^+, Ca^{2+}, Mg^{2+}
  3. C.K+,Ca2+,Mg2+,Be2+K^+, Ca^{2+}, Mg^{2+}, Be^{2+}
  4. D.Ca2+,Mg2+,Be2+,K+Ca^{2+}, Mg^{2+}, Be^{2+}, K^+

Correct answer: C

Explanation: Increasing charge/size.

Question 113

Chemistry · 3 marks · −1

The density (in g mL−1^{-1}) of a 3.60 M sulphuric acid solution that is 29% H2SO4H_2SO_4 (Molar mass = 98 g mol−1^{-1}) by mass will be

  1. A.1.64
  2. B.1.88
  3. C.1.22
  4. D.1.45

Correct answer: C

Explanation: d=3.6⋅980.29⋅1000d=\frac{3.6\cdot98}{0.29\cdot1000}.

Question 114

Chemistry · 3 marks · −1

The first and second dissociation constants of an acid H2AH_2A are 1.0×10−51.0\times10^{-5} and 5.0×10−105.0\times10^{-10} respectively. The overall dissociation constant of the acid will be

  1. A.5.0×10−55.0\times10^{-5}
  2. B.5.0×10155.0\times10^{15}
  3. C.5.0×10−155.0\times10^{-15}
  4. D.0.0×1050.0\times10^{5}

Correct answer: C

Explanation: K=K1K2K=K_1K_2.

Question 115

Chemistry · 3 marks · −1

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K. The vapour pressure of propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be

  1. A.350
  2. B.300
  3. C.700
  4. D.360

Correct answer: A

Explanation: 290=0.4⋅200+0.6P290=0.4\cdot200+0.6P.

Question 116

Chemistry · 3 marks · −1

In conversion of lime-stone to lime, CaCO3(s)→CaO(s)+CO2(g)CaCO_3(s) \rightarrow CaO(s) + CO_2(g) the values of ΔH∘\Delta H^\circ and ΔS∘\Delta S^\circ are +179.1 kJ mol−1^{-1} and 160.2 J/K respectively at 298 K and 1 bar. Assuming that ΔH∘\Delta H^\circ do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is

  1. A.1008 K
  2. B.1200 K
  3. C.845 K
  4. D.1118 K

Correct answer: D

Explanation: T=179100160.2T=\frac{179100}{160.2}.

View all papers — JEE Main

Practice this paper with a timer

Attempt it online, get scored instantly, and see which subjects are costing you marks.

Start practising free