AIEEE 2008 — 27 Apr Offline Set C-5 (Previous Year Paper)

JEE Main · 2008 · with answers and explanations

questions
98
Total marks
294
Duration
180 minutes
Negative marking
−1

Subjects: Mathematics · Chemistry · Physics

Question 1

Mathematics · 3 marks · −1

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60∘60^\circ. He moves away from the pole along the line BC to a point D such that CD = 7 m. From D the angle of elevation of the point A is 45∘45^\circ. Then the height of the pole is

  1. A.732⋅13−1\frac{7\sqrt{3}}{2}\cdot\frac{1}{\sqrt{3}-1} m
  2. B.732(3+1)\frac{7\sqrt{3}}{2}(\sqrt{3}+1) m
  3. C.732(3−1)\frac{7\sqrt{3}}{2}(\sqrt{3}-1) m
  4. D.732⋅13+1\frac{7\sqrt{3}}{2}\cdot\frac{1}{\sqrt{3}+1}

Correct answer: B

Explanation: x3=7+x⇒x=73−1x\sqrt3=7+x\Rightarrow x=\frac{7}{\sqrt3-1}; AB=732(3+1)AB=\frac{7\sqrt3}{2}(\sqrt3+1) m.

Question 2

Mathematics · 3 marks · −1

It is given that the events A and B are such that P(A)=14P(A) = \frac{1}{4}, P(A∣B)=12P(A|B) = \frac{1}{2} and P(B∣A)=23P(B|A) = \frac{2}{3}. Then P(B) is

  1. A.16\frac{1}{6}
  2. B.13\frac{1}{3}
  3. C.23\frac{2}{3}
  4. D.12\frac{1}{2}

Correct answer: B

Explanation: P(A∩B)=23⋅14=16=12P(B)P(A\cap B)=\frac23\cdot\frac14=\frac16=\frac12P(B).

Question 3

Mathematics · 3 marks · −1

A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then P(A∪B)P(A\cup B) is

  1. A.35\frac{3}{5}
  2. B.0
  3. C.1
  4. D.25\frac{2}{5}

Correct answer: C

Explanation: A∪BA\cup B is the whole sample space.

Question 4

Mathematics · 3 marks · −1

A focus of an ellipse is at the origin. The directrix is the line x = 4 and the eccentricity is 1/2. Then the length of the semi-major axis is

  1. A.83\frac{8}{3}
  2. B.23\frac{2}{3}
  3. C.43\frac{4}{3}
  4. D.53\frac{5}{3}

Correct answer: A

Explanation: Focus-directrix distance ae−ae=3a2=4\frac ae-ae=\frac{3a}{2}=4.

Question 5

Mathematics · 3 marks · −1

A parabola has the origin as its focus and the line x = 2 as the directrix. Then the vertex of the parabola is at

  1. A.(0, 2)
  2. B.(1, 0)
  3. C.(0, 1)
  4. D.(2, 0)

Correct answer: B

Explanation: Midpoint of focus and directrix foot.

Question 6

Mathematics · 3 marks · −1

The point diametrically opposite to the point P(1, 0) on the circle x2+y2+2x+4y−3=0x^2 + y^2 + 2x + 4y - 3 = 0 is

  1. A.(3, -4)
  2. B.(-3, 4)
  3. C.(-3, -4)
  4. D.(3, 4)

Correct answer: C

Explanation: Centre (-1, -2) is the midpoint.

Question 7

Mathematics · 3 marks · −1

Let f:N→Yf : N \to Y be a function defined as f(x)=4x+3f(x) = 4x + 3, where Y={y∈N:y=4x+3 for some x∈N}Y = \{y \in N : y = 4x + 3 \text{ for some } x \in N\}. Show that f is invertible and its inverse is

  1. A.g(y)=3y+43g(y) = \frac{3y+4}{3}
  2. B.g(y)=4+y+34g(y) = 4 + \frac{y+3}{4}
  3. C.g(y)=y+34g(y) = \frac{y+3}{4}
  4. D.g(y)=y−34g(y) = \frac{y-3}{4}

Correct answer: D

Explanation: Solve y=4x+3y=4x+3.

Question 8

Mathematics · 3 marks · −1

The conjugate of a complex number is 1i−1\frac{1}{i-1}. Then the complex number is

  1. A.−1i−1\frac{-1}{i-1}
  2. B.1i+1\frac{1}{i+1}
  3. C.−1i+1\frac{-1}{i+1}
  4. D.1i−1\frac{1}{i-1}

Correct answer: C

Explanation: Replace i by -i: 1−i−1\frac{1}{-i-1}.

Question 9

Mathematics · 3 marks · −1

Let R be the real line. Consider the following subsets of the plane R×RR\times R. S={(x,y):y=x+1 and 0<x<2}S = \{(x, y) : y = x + 1 \text{ and } 0 < x < 2\}, T={(x,y):x−y is an integer}T = \{(x, y) : x - y \text{ is an integer}\}. Which one of the following is true?

  1. A.neither S nor T is an equivalence relation on R
  2. B.both S and T are equivalence relations on R
  3. C.S is an equivalence relation on R but T is not
  4. D.T is an equivalence relation on R but S is not

Correct answer: D

Explanation: T is reflexive, symmetric, transitive; S is not reflexive.

Question 10

Mathematics · 3 marks · −1

The perpendicular bisector of the line segment joining P(1, 4) and Q(k, 3) has y-intercept -4. Then a possible value of k is

  1. A.1
  2. B.2
  3. C.-2
  4. D.-4

Correct answer: D

Explanation: Bisector y−72=(k−1)(x−k+12)y-\frac72=(k-1)\left(x-\frac{k+1}{2}\right) at x = 0 gives k2=16k^2=16.

Question 11

Mathematics · 3 marks · −1

The solution of the differential equation dydx=x+yx\frac{dy}{dx} = \frac{x+y}{x} satisfying the condition y(1) = 1 is

  1. A.y=ln⁡x+xy = \ln x + x
  2. B.y=xln⁡x+x2y = x\ln x + x^2
  3. C.y=xe(x−1)y = xe^{(x-1)}
  4. D.y=xln⁡x+xy = x\ln x + x

Correct answer: D

Explanation: y=vxy=vx: v=ln⁡x+1v=\ln x+1.

Question 12

Mathematics · 3 marks · −1

The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then which one of the following gives possible values of a and b?

  1. A.a = 0, b = 7
  2. B.a = 5, b = 2
  3. C.a = 1, b = 6
  4. D.a = 3, b = 4

Correct answer: D

Explanation: a+b=7a+b=7, (a−6)2+(b−6)2=13⇒a2+b2=25(a-6)^2+(b-6)^2=13\Rightarrow a^2+b^2=25: {3, 4}.

Question 13

Mathematics · 3 marks · −1

The vector a⃗=αi^+2j^+βk^\vec{a} = \alpha\hat{i} + 2\hat{j} + \beta\hat{k} lies in the plane of the vectors b⃗=i^+j^\vec{b} = \hat{i} + \hat{j} and c⃗=j^+k^\vec{c} = \hat{j} + \hat{k} and bisects the angle between b⃗\vec{b} and c⃗\vec{c}. Then which one of the following gives possible values of α\alpha and β\beta?

  1. A.α=2,β=2\alpha = 2, \beta = 2
  2. B.α=1,β=2\alpha = 1, \beta = 2
  3. C.α=2,β=1\alpha = 2, \beta = 1
  4. D.α=1,β=1\alpha = 1, \beta = 1

Correct answer: D

Explanation: a⃗∥b^+c^∝(1,2,1)\vec a\parallel\hat b+\hat c\propto(1,2,1).

Question 14

Mathematics · 3 marks · −1

The non-zero vectors a⃗\vec{a}, b⃗\vec{b} and c⃗\vec{c} are related by a⃗=8b⃗\vec{a} = 8\vec{b} and c⃗=−7b⃗\vec{c} = -7\vec{b}. Then the angle between a⃗\vec{a} and c⃗\vec{c} is

  1. A.0
  2. B.π/4\pi/4
  3. C.π/2\pi/2
  4. D.π\pi

Correct answer: D

Explanation: a⃗\vec a and c⃗\vec c are antiparallel.

Question 15

Mathematics · 3 marks · −1

The line passing through the points (5, 1, a) and (3, b, 1) crosses the yz-plane at the point (0,172,−132)\left(0, \frac{17}{2}, \frac{-13}{2}\right). Then

  1. A.a = 2, b = 8
  2. B.a = 4, b = 6
  3. C.a = 6, b = 4
  4. D.a = 8, b = 2

Correct answer: C

Explanation: λ=−52\lambda=-\frac52 at x = 0 gives b = 4, a = 6.

Question 16

Mathematics · 3 marks · −1

If the straight lines x−1k=y−22=z−33\frac{x-1}{k} = \frac{y-2}{2} = \frac{z-3}{3} and x−23=y−3k=z−12\frac{x-2}{3} = \frac{y-3}{k} = \frac{z-1}{2} intersect at a point, then the integer k is equal to

  1. A.-5
  2. B.5
  3. C.2
  4. D.-2

Correct answer: A

Explanation: Coplanarity: 2k2+5k−25=0⇒k=−52k^2+5k-25=0\Rightarrow k=-5 (integer).

Question 17

Mathematics · 3 marks · −1

Statement-1: For every natural number n≥2n \ge 2, 11+12+⋯+1n>n\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + \dots + \frac{1}{\sqrt{n}} > \sqrt{n}. Statement-2: For every natural number n≥2n \ge 2, n(n+1)<n+1\sqrt{n(n+1)} < n + 1.

  1. A.Statement-1 is false, Statement-2 is true
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
  4. D.Statement-1 is true, Statement-2 is false

Correct answer: C

Explanation: Both are provable (induction / AM-GM), but Statement-2 is not what makes Statement-1 true.

Question 18

Mathematics · 3 marks · −1

Let A be a 2×22\times2 matrix with real entries. Let I be the 2×22\times2 identity matrix. Denote by tr(A), the sum of diagonal entries of A. Assume that A2=IA^2 = I. Statement-1: If A≠IA \ne I and A≠−IA \ne -I, then det A = -1. Statement-2: If A≠IA \ne I and A≠−IA \ne -I, then tr(A)≠0tr(A) \ne 0.

  1. A.Statement-1 is false, Statement-2 is true
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
  4. D.Statement-1 is true, Statement-2 is false

Correct answer: D

Explanation: Such A has a=−da=-d, so det⁡A=−1\det A=-1 and trA=0tr A=0.

Question 19

Mathematics · 3 marks · −1

Statement-1: ∑r=0n(r+1) nCr=(n+2)2n−1\sum_{r=0}^{n}(r+1)\,{}^nC_r = (n+2)2^{n-1}. Statement-2: ∑r=0n(r+1) nCrxr=(1+x)n+nx(1+x)n−1\sum_{r=0}^{n}(r+1)\,{}^nC_rx^r = (1+x)^n + nx(1+x)^{n-1}.

  1. A.Statement-1 is false, Statement-2 is true
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
  4. D.Statement-1 is true, Statement-2 is false

Correct answer: B

Explanation: Put x = 1 in Statement-2: 2n+n2n−1=(n+2)2n−12^n+n2^{n-1}=(n+2)2^{n-1}.

Question 20

Mathematics · 3 marks · −1

Let p be the statement 'x is an irrational number', q be the statement 'y is a transcendental number', and r be the statement 'x is a rational number iff y is a transcendental number'. Statement-1: r is equivalent to either q or p. Statement-2: r is equivalent to ∼(p↔∼q)\sim(p \leftrightarrow \sim q).

  1. A.Statement-1 is false, Statement-2 is true
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
  4. D.Statement-1 is true, Statement-2 is false

Correct answer: D

Explanation: r≡∼p↔qr\equiv\sim p\leftrightarrow q, i.e. exactly one of p, q (Statement-1 true); ∼(p↔∼q)≡p↔q\sim(p\leftrightarrow\sim q)\equiv p\leftrightarrow q (false).

Question 21

Mathematics · 3 marks · −1

In a shop there are five types of ice-creams available. A child buys six ice-creams. Statement-1: The number of different ways the child can buy the six ice-creams is 10C5{}^{10}C_5. Statement-2: The number of different ways the child can buy the six ice-creams is equal to the number of different ways of arranging 6 A's and 4 B's in a row.

  1. A.Statement-1 is false, Statement-2 is true
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
  4. D.Statement-1 is true, Statement-2 is false

Correct answer: A

Explanation: Count =(104)=210≠(105)=\binom{10}{4}=210\ne\binom{10}{5}; Statement-2 (stars and bars) is true.

Question 22

Mathematics · 3 marks · −1

The first two terms of a geometric progression add up to 12. The sum of the third and the fourth terms is 48. If the terms of the geometric progression are alternately positive and negative, then the first term is

  1. A.-4
  2. B.-12
  3. C.12
  4. D.4

Correct answer: B

Explanation: r2=4r^2=4, r=−2r=-2, a(1+r)=12⇒a=−12a(1+r)=12\Rightarrow a=-12.

Question 23

Mathematics · 3 marks · −1

Suppose the cubic x3−px+qx^3 - px + q has three distinct real roots where p > 0 and q > 0. Then which one of the following holds?

  1. A.The cubic has minima at p3\sqrt{\frac{p}{3}} and maxima at −p3-\sqrt{\frac{p}{3}}
  2. B.The cubic has minima at −p3-\sqrt{\frac{p}{3}} and maxima at p3\sqrt{\frac{p}{3}}
  3. C.The cubic has minima at both p3\sqrt{\frac{p}{3}} and −p3-\sqrt{\frac{p}{3}}
  4. D.The cubic has maxima at both p3\sqrt{\frac{p}{3}} and −p3-\sqrt{\frac{p}{3}}

Correct answer: A

Explanation: f′′=6xf''=6x.

Question 24

Mathematics · 3 marks · −1

How many real solutions does the equation x7+14x5+16x3+30x−560=0x^7 + 14x^5 + 16x^3 + 30x - 560 = 0 have?

  1. A.7
  2. B.1
  3. C.3
  4. D.5

Correct answer: B

Explanation: Strictly increasing polynomial of odd degree.

Question 25

Mathematics · 3 marks · −1

The statement p→(q→p)p \to (q \to p) is equivalent to

  1. A.p→(p→q)p \to (p \to q)
  2. B.p→(p∨q)p \to (p \vee q)
  3. C.p→(p∧q)p \to (p \wedge q)
  4. D.p→(p↔q)p \to (p \leftrightarrow q)

Correct answer: B

Explanation: Both are tautologies.

Question 26

Mathematics · 3 marks · −1

The value of cot⁡(csc⁡−153+tan⁡−123)\cot\left(\csc^{-1}\frac{5}{3} + \tan^{-1}\frac{2}{3}\right) is

  1. A.617\frac{6}{17}
  2. B.317\frac{3}{17}
  3. C.417\frac{4}{17}
  4. D.517\frac{5}{17}

Correct answer: A

Explanation: tan⁡−134+tan⁡−123=tan⁡−1176\tan^{-1}\frac34+\tan^{-1}\frac23=\tan^{-1}\frac{17}{6}.

Question 27

Mathematics · 3 marks · −1

The differential equation of the family of circles with fixed radius 5 units and centre on the line y = 2 is

  1. A.(x−2)y′2=25−(y−2)2(x-2)y'^2 = 25 - (y-2)^2
  2. B.(y−2)y′2=25−(y−2)2(y-2)y'^2 = 25 - (y-2)^2
  3. C.(y−2)2y′2=25−(y−2)2(y-2)^2y'^2 = 25 - (y-2)^2
  4. D.(x−2)2y′2=25−(y−2)2(x-2)^2y'^2 = 25 - (y-2)^2

Correct answer: C

Explanation: Eliminate h: x−h=−(y−2)y′x-h=-(y-2)y'.

Question 28

Mathematics · 3 marks · −1

Let I=∫01sin⁡xxdxI = \int_0^1\frac{\sin x}{\sqrt{x}}dx and J=∫01cos⁡xxdxJ = \int_0^1\frac{\cos x}{\sqrt{x}}dx. Then which one of the following is true?

  1. A.I>23I > \frac{2}{3} and J>2J > 2
  2. B.I<23I < \frac{2}{3} and J<2J < 2
  3. C.I<23I < \frac{2}{3} and J>2J > 2
  4. D.I>23I > \frac{2}{3} and J<2J < 2

Correct answer: B

Explanation: sin⁡x<x\sin x<x, cos⁡x<1\cos x<1.

Question 29

Mathematics · 3 marks · −1

The area of the plane region bounded by the curves x+2y2=0x + 2y^2 = 0 and x+3y2=1x + 3y^2 = 1 is equal to

  1. A.53\frac{5}{3}
  2. B.13\frac{1}{3}
  3. C.23\frac{2}{3}
  4. D.43\frac{4}{3}

Correct answer: D

Explanation: 2∫01(1−y2)dy=432\int_0^1(1-y^2)dy=\frac43.

Question 30

Mathematics · 3 marks · −1

The value of 2∫sin⁡x dxsin⁡(x−π4)\sqrt{2}\int\frac{\sin x\,dx}{\sin\left(x - \frac{\pi}{4}\right)} is

  1. A.x+log⁡∣cos⁡(x−π4)∣+cx + \log\left|\cos\left(x - \frac{\pi}{4}\right)\right| + c
  2. B.x−log⁡∣sin⁡(x−π4)∣+cx - \log\left|\sin\left(x - \frac{\pi}{4}\right)\right| + c
  3. C.x+log⁡∣sin⁡(x−π4)∣+cx + \log\left|\sin\left(x - \frac{\pi}{4}\right)\right| + c
  4. D.x−log⁡∣cos⁡(x−π4)∣+cx - \log\left|\cos\left(x - \frac{\pi}{4}\right)\right| + c

Correct answer: C

Explanation: Write sin⁡x=sin⁡(x−π4+π4)\sin x=\sin(x-\frac\pi4+\frac\pi4).

Question 31

Mathematics · 3 marks · −1

How many different words can be formed by jumbling the letters in the word MISSISSIPPI in which no two S are adjacent?

  1. A.8⋅6C4⋅7C48\cdot{}^6C_4\cdot{}^7C_4
  2. B.6⋅7⋅8C46\cdot7\cdot{}^8C_4
  3. C.6⋅8⋅7C46\cdot8\cdot{}^7C_4
  4. D.7⋅6C4⋅8C47\cdot{}^6C_4\cdot{}^8C_4

Correct answer: D

Explanation: Arrange MIIIIPP: 7!4!2!=105=7⋅6C4\frac{7!}{4!2!}=105=7\cdot{}^6C_4; choose 4 of 8 gaps for S.

Question 32

Mathematics · 3 marks · −1

Let a, b, c be any real numbers. Suppose that there are real numbers x, y, z not all zero such that x=cy+bzx = cy + bz, y=az+cxy = az + cx and z=bx+ayz = bx + ay. Then a2+b2+c2+2abca^2 + b^2 + c^2 + 2abc is equal to

  1. A.2
  2. B.-1
  3. C.0
  4. D.1

Correct answer: D

Explanation: Determinant zero gives a2+b2+c2+2abc=1a^2+b^2+c^2+2abc=1.

Question 33

Mathematics · 3 marks · −1

Let A be a square matrix all of whose entries are integers. Then which one of the following is true?

  1. A.If det A = ±1\pm1, then A−1A^{-1} exists but all its entries are not necessarily integers
  2. B.If det A ≠±1\ne \pm1, then A−1A^{-1} exists and all its entries are non-integers
  3. C.If det A = ±1\pm1, then A−1A^{-1} exists and all its entries are integers
  4. D.If det A = ±1\pm1, then A−1A^{-1} need not exist

Correct answer: C

Explanation: A−1=±adjAA^{-1}=\pm\text{adj}A has integer entries.

Question 34

Mathematics · 3 marks · −1

The quadratic equations x2−6x+a=0x^2 - 6x + a = 0 and x2−cx+6=0x^2 - cx + 6 = 0 have one root in common. The other roots of the first and second equations are integers in the ratio 4 : 3. Then the common root is

  1. A.1
  2. B.4
  3. C.3
  4. D.2

Correct answer: D

Explanation: Roots α,4β\alpha,4\beta and α,3β\alpha,3\beta: αβ=2\alpha\beta=2, a=8a=8, roots 2 and 4; integer condition gives α=2\alpha=2.

Question 35

Chemistry · 3 marks · −1

The organic chloro compound, which shows complete stereochemical inversion during a SN2S_N2 reaction, is

  1. A.(C2H5)2CHCl(C_2H_5)_2CHCl
  2. B.(CH3)3CCl(CH_3)_3CCl
  3. C.(CH3)2CHCl(CH_3)_2CHCl
  4. D.CH3ClCH_3Cl

Correct answer: D

Explanation: Least hindered substrate.

Question 36

Chemistry · 3 marks · −1

Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is diazotised and then heated with cuprous bromide. The reaction mixture so formed contains

  1. A.mixture of o- and p-bromotoluenes
  2. B.mixture of o- and p-dibromobenzenes
  3. C.mixture of o- and p-bromoanilines
  4. D.mixture of o- and m-bromotoluenes

Correct answer: A

Explanation: o/p-nitrotoluene, then toluidines, then Sandmeyer bromination.

Question 37

Chemistry · 3 marks · −1

The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)]NO2[E(en)_2(C_2O_4)]NO_2 (where (en) is ethylene diamine) are, respectively,

  1. A.6 and 2
  2. B.4 and 2
  3. C.4 and 3
  4. D.6 and 3

Correct answer: D

Explanation: Three bidentate ligands; charge balance gives +3.

Question 38

Chemistry · 3 marks · −1

Identify the wrong statements in the following:

  1. A.Chlorofluorocarbons are responsible for ozone layer depletion
  2. B.Greenhouse effect is responsible for global warming
  3. C.Ozone layer does not permit infrared radiation from the sun to reach the earth
  4. D.Acid rains is mostly because of oxides of nitrogen and sulphur

Correct answer: C

Explanation: Ozone absorbs UV, not IR.

Question 39

Chemistry · 3 marks · −1

Phenol, when it first reacts with concentrated sulphuric acid and then with concentrated nitric acid, gives

  1. A.2,4,6-trinitrobenzene
  2. B.o-nitrophenol
  3. C.p-nitrophenol
  4. D.nitrobenzene

Correct answer: B

Explanation: Sulphonation blocks the para position; nitration goes ortho (the SO3H is later lost).

Question 40

Chemistry · 3 marks · −1

In the following sequence of reactions, the alkene affords the compound 'B': CH3CH=CHCH3→O3A→H2O/ZnBCH_3CH=CHCH_3 \xrightarrow{O_3} A \xrightarrow{H_2O/Zn} B. The compound B is

  1. A.CH3CH2CHOCH_3CH_2CHO
  2. B.CH3COCH3CH_3COCH_3
  3. C.CH3CH2COCH3CH_3CH_2COCH_3
  4. D.CH3CHOCH_3CHO

Correct answer: D

Explanation: Reductive ozonolysis of 2-butene.

Question 41

Chemistry · 3 marks · −1

Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids, the main reason being

  1. A.4f orbitals more diffused than the 5f orbitals
  2. B.lesser energy difference between 5f and 6d than between 4f and 5d orbitals
  3. C.more energy difference between 5f and 6d than between 4f and 5d orbitals
  4. D.more reactive nature of the actinoids than the lanthanoids

Correct answer: B

Explanation: Comparable 5f/6d energies.

Question 42

Chemistry · 3 marks · −1

In which of the following octahedral complexes of Co (at. no. 27), will the magnitude of Δo\Delta_o be the highest?

  1. A.[Co(CN)6]3−[Co(CN)_6]^{3-}
  2. B.[Co(C2O4)3]3−[Co(C_2O_4)_3]^{3-}
  3. C.[Co(H2O)6]3+[Co(H_2O)_6]^{3+}
  4. D.[Co(NH3)6]3+[Co(NH_3)_6]^{3+}

Correct answer: A

Explanation: CN−CN^- is the strongest-field ligand.

Question 43

Chemistry · 3 marks · −1

At 80∘80^\circC, the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at 80∘80^\circC and 1 atm pressure, the amount of 'A' in the mixture is (1 atm = 760 mm Hg)

  1. A.52 mol percent
  2. B.34 mol percent
  3. C.48 mol percent
  4. D.50 mol percent

Correct answer: D

Explanation: 760=520x+1000(1−x)⇒x=0.5760=520x+1000(1-x)\Rightarrow x=0.5.

Question 44

Chemistry · 3 marks · −1

For a reaction 12A→2B\frac{1}{2}A \rightarrow 2B, rate of disappearance of 'A' is related to the rate of appearance of 'B' by the expression

  1. A.−d[A]dt=12d[B]dt-\frac{d[A]}{dt} = \frac{1}{2}\frac{d[B]}{dt}
  2. B.−d[A]dt=14d[B]dt-\frac{d[A]}{dt} = \frac{1}{4}\frac{d[B]}{dt}
  3. C.−d[A]dt=d[B]dt-\frac{d[A]}{dt} = \frac{d[B]}{dt}
  4. D.−d[A]dt=4d[B]dt-\frac{d[A]}{dt} = 4\frac{d[B]}{dt}

Correct answer: B

Explanation: −2d[A]dt=12d[B]dt-2\frac{d[A]}{dt}=\frac12\frac{d[B]}{dt}.

Question 45

Chemistry · 3 marks · −1

The equilibrium constants KP1K_{P_1} and KP2K_{P_2} for the reactions X⇌2YX \rightleftharpoons 2Y and Z⇌P+QZ \rightleftharpoons P + Q, respectively are in the ratio of 1 : 9. If the degree of dissociation of X and Z be equal then the ratio of total pressure at these equilibria is

  1. A.1 : 36
  2. B.1 : 1
  3. C.1 : 3
  4. D.1 : 9

Correct answer: A

Explanation: 4P1P2=19\frac{4P_1}{P_2}=\frac19.

Question 46

Chemistry · 3 marks · −1

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below: 12Cl2(g)→12ΔdissH∘Cl(g)→ΔegH∘Cl−(g)→ΔhydH∘Cl−(aq)\frac{1}{2}Cl_2(g) \xrightarrow{\frac{1}{2}\Delta_{diss}H^\circ} Cl(g) \xrightarrow{\Delta_{eg}H^\circ} Cl^-(g) \xrightarrow{\Delta_{hyd}H^\circ} Cl^-(aq). The energy involved in the conversion of 12Cl2(g)\frac{1}{2}Cl_2(g) to Cl−(aq)Cl^-(aq) (using the data, ΔdissHCl2∘=240\Delta_{diss}H^\circ_{Cl_2} = 240 kJ mol−1^{-1}, ΔegHCl∘=−349\Delta_{eg}H^\circ_{Cl} = -349 kJ mol−1^{-1}, ΔhydHCl−∘=−381\Delta_{hyd}H^\circ_{Cl^-} = -381 kJ mol−1^{-1}) will be

  1. A.+152+152 kJ mol−1^{-1}
  2. B.−610-610 kJ mol−1^{-1}
  3. C.−850-850 kJ mol−1^{-1}
  4. D.+120+120 kJ mol−1^{-1}

Correct answer: B

Explanation: 120−349−381=−610120-349-381=-610 kJ/mol.

Question 47

Chemistry · 3 marks · −1

Bakelite is obtained from phenol by reacting with

  1. A.(CH2OH)2(CH_2OH)_2
  2. B.CH3CHOCH_3CHO
  3. C.CH3COCH3CH_3COCH_3
  4. D.HCHO

Correct answer: D

Explanation: Phenol-formaldehyde resin.

Question 48

Chemistry · 3 marks · −1

For the following three reactions a, b and c, equilibrium constants are given: a. CO(g)+H2O(g)⇌CO2(g)+H2(g)CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g); K1K_1 b. CH4(g)+H2O(g)⇌CO(g)+3H2(g)CH_4(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g); K2K_2 c. CH4(g)+2H2O(g)⇌CO2(g)+4H2(g)CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g); K3K_3. Which of the following relations is correct?

  1. A.K1K2=K3K_1\sqrt{K_2} = K_3
  2. B.K2K3=K1K_2K_3 = K_1
  3. C.K3=K1K2K_3 = K_1K_2
  4. D.K3K23=K12K_3K_2^3 = K_1^2

Correct answer: C

Explanation: c = a + b.

Question 49

Chemistry · 3 marks · −1

The absolute configuration of tartaric acid drawn as HO2C−CH(OH)−CH(OH)−CO2HHO_2C-CH(OH)-CH(OH)-CO_2H with the C1-OH on a hashed bond and the C2-OH on a wedged bond (see figure) is

Figure for question 49
  1. A.S, S
  2. B.R, R
  3. C.R, S
  4. D.S, R

Correct answer: B

Explanation: Assigning CIP priorities (OH > CO2H > CH(OH) > H) at each centre gives R at both.

Question 50

Chemistry · 3 marks · −1

The electrophile, E⊕E^\oplus attacks the benzene ring to generate the intermediate σ\sigma-complex. Of the following, which σ\sigma-complex is of lowest energy?

Figure for question 50
  1. A.sigma-complex of nitrobenzene with E at the para position
  2. B.sigma-complex of benzene (no substituent)
  3. C.sigma-complex of nitrobenzene with E at the ortho position
  4. D.sigma-complex of nitrobenzene with E at the meta position

Correct answer: B

Explanation: −NO2-NO_2 destabilises every arenium ion, so the unsubstituted one is lowest in energy.

Question 51

Chemistry · 3 marks · −1

α\alpha-D-(+)-glucose and β\beta-D-(+)-glucose are

  1. A.conformers
  2. B.epimers
  3. C.anomers
  4. D.enantiomers

Correct answer: C

Explanation: They differ at C1 (anomeric carbon).

Question 52

Chemistry · 3 marks · −1

Standard entropy of X2X_2, Y2Y_2 and XY3XY_3 are 60, 40 and 50 JK−1^{-1}mol−1^{-1}, respectively. For the reaction, 12X2+32Y2→XY3\frac{1}{2}X_2 + \frac{3}{2}Y_2 \rightarrow XY_3, ΔH=−30\Delta H = -30 kJ, to be at equilibrium, the temperature will be

  1. A.1250 K
  2. B.500 K
  3. C.750 K
  4. D.1000 K

Correct answer: C

Explanation: ΔS=−40\Delta S=-40; T=3000040T=\frac{30000}{40}.

Question 53

Chemistry · 3 marks · −1

Four species are listed below: i. HCO3−HCO_3^- ii. H3O+H_3O^+ iii. HSO4−HSO_4^- iv. HSO3FHSO_3F. Which one of the following is the correct sequence of their acid strength?

  1. A.iv < ii < iii < i
  2. B.ii < iii < i < iv
  3. C.i < iii < ii < iv
  4. D.iii < i < iv < ii

Correct answer: C

Explanation: HSO3FHSO_3F (superacid) > H3O+H_3O^+ > HSO4−HSO_4^- > HCO3−HCO_3^-.

Question 54

Chemistry · 3 marks · −1

Which one of the following constitutes a group of the isoelectronic species?

  1. A.C22−C_2^{2-}, O2−O_2^-, CO, NO
  2. B.NO+NO^+, C22−C_2^{2-}, CN−CN^-, N2N_2
  3. C.CN−CN^-, N2N_2, O22−O_2^{2-}, C22−C_2^{2-}
  4. D.N2N_2, O2−O_2^-, NO+NO^+, CO

Correct answer: B

Explanation: All have 14 electrons.

Question 55

Chemistry · 3 marks · −1

Which one of the following pairs of species have the same bond order?

  1. A.CN−CN^- and NO+NO^+
  2. B.CN−CN^- and CN+CN^+
  3. C.O2−O_2^- and CN−CN^-
  4. D.NO+NO^+ and CN+CN^+

Correct answer: A

Explanation: Both isoelectronic with N2N_2, bond order 3.

Question 56

Chemistry · 3 marks · −1

The ionization enthalpy of hydrogen atom is 1.312×1061.312\times10^6 J mol−1^{-1}. The energy required to excite the electron in the atom from n = 1 to n = 2 is

  1. A.8.51×1058.51\times10^5 J mol−1^{-1}
  2. B.6.56×1056.56\times10^5 J mol−1^{-1}
  3. C.7.56×1057.56\times10^5 J mol−1^{-1}
  4. D.9.84×1059.84\times10^5 J mol−1^{-1}

Correct answer: D

Explanation: 34⋅1.312×106\frac34\cdot1.312\times10^6.

Question 57

Chemistry · 3 marks · −1

Which one of the following is the correct statement?

  1. A.Boric acid is a protonic acid
  2. B.Beryllium exhibits coordination number of six
  3. C.Chlorides of both beryllium and aluminium have bridged chloride structures in solid phase
  4. D.B2H6⋅2NH3B_2H_6\cdot2NH_3 is known as 'inorganic benzene'

Correct answer: C

Explanation: (BeCl2)n(BeCl_2)_n chains and Al2Cl6Al_2Cl_6 dimers are chloride bridged.

Question 58

Chemistry · 3 marks · −1

Given ECr3+/Cr∘=−0.72E^\circ_{Cr^{3+}/Cr} = -0.72 V, EFe2+/Fe∘=−0.42E^\circ_{Fe^{2+}/Fe} = -0.42 V. The potential for the cell Cr∣Cr3+(0.1 M)∣∣Fe2+(0.01 M)∣FeCr|Cr^{3+}(0.1\ M)||Fe^{2+}(0.01\ M)|Fe is

  1. A.0.26 V
  2. B.0.399 V
  3. C.-0.339 V
  4. D.-0.26 V

Correct answer: A

Explanation: 0.30−0.05916log⁡(0.1)2(0.01)3=0.260.30-\frac{0.0591}{6}\log\frac{(0.1)^2}{(0.01)^3}=0.26 V.

Question 59

Chemistry · 3 marks · −1

Amount of oxalic acid present in a solution can be determined by its titration with KMnO4KMnO_4 solution in the presence of H2SO4H_2SO_4. The titration gives unsatisfactory result when carried out in the presence of HCl, because HCl

  1. A.gets oxidised by oxalic acid to chlorine
  2. B.furnishes H+H^+ ions in addition to those from oxalic acid
  3. C.reduces permanganate to Mn2+Mn^{2+}
  4. D.oxidises oxalic acid to carbon dioxide and water

Correct answer: C

Explanation: HCl consumes permanganate.

Question 60

Chemistry · 3 marks · −1

The vapour pressure of water at 20∘20^\circC is 17.5 mm Hg. If 18 g of glucose (C6H12O6)(C_6H_{12}O_6) is added to 178.2 g of water at 20∘20^\circC, the vapour pressure of the resulting solution will be

  1. A.17.675 mm Hg
  2. B.15.750 mm Hg
  3. C.16.500 mm Hg
  4. D.17.325 mm Hg

Correct answer: D

Explanation: xsolute=0.01x_{solute}=0.01: 17.5⋅0.9917.5\cdot0.99.

Question 61

Chemistry · 3 marks · −1

Among the following substituted silanes the one which will give rise to cross linked silicone polymer on hydrolysis is

  1. A.R4SiR_4Si
  2. B.RSiCl3RSiCl_3
  3. C.R2SiCl2R_2SiCl_2
  4. D.R3SiClR_3SiCl

Correct answer: B

Explanation: Trifunctional RSi(OH)3RSi(OH)_3 cross-links.

Question 62

Chemistry · 3 marks · −1

In context with the industrial preparation of hydrogen from water gas (CO+H2)(CO + H_2), which of the following is the correct statement?

  1. A.CO and H2H_2 are fractionally separated using differences in their densities
  2. B.CO is removed by absorption in aqueous Cu2Cl2Cu_2Cl_2 solution
  3. C.H2H_2 is removed through occlusion with Pd
  4. D.CO is oxidised to CO2CO_2 with steam in the presence of a catalyst followed by absorption of CO2CO_2 in alkali

Correct answer: D

Explanation: Water-gas shift then CO2CO_2 scrubbing.

Question 63

Chemistry · 3 marks · −1

In a compound atoms of element Y from ccp lattice and those of element X occupy 2/3rd2/3^{rd} of tetrahedral voids. The formula of the compound will be

  1. A.X4Y3X_4Y_3
  2. B.X2Y3X_2Y_3
  3. C.X2YX_2Y
  4. D.X3Y4X_3Y_4

Correct answer: A

Explanation: Y = 4, X = 23⋅8\frac23\cdot8.

Question 64

Chemistry · 3 marks · −1

Gold numbers of protective colloids A, B, C and D are 0.50, 0.01, 0.10 and 0.005, respectively. The correct order of their protective powers is

  1. A.D < A < C < B
  2. B.C < B < D < A
  3. C.A < C < B < D
  4. D.B < D < A < C

Correct answer: C

Explanation: Protective power is inverse of gold number.

Question 65

Chemistry · 3 marks · −1

The hydrocarbon which can react with sodium in liquid ammonia is

  1. A.CH3CH2CH2C≡CCH2CH2CH3CH_3CH_2CH_2C\equiv CCH_2CH_2CH_3
  2. B.CH3CH2C≡CHCH_3CH_2C\equiv CH
  3. C.CH3CH=CHCH3CH_3CH=CHCH_3
  4. D.CH3CH2C≡CCH2CH3CH_3CH_2C\equiv CCH_2CH_3

Correct answer: B

Explanation: Terminal alkyne has an acidic H.

Question 66

Chemistry · 3 marks · −1

The treatment of CH3MgXCH_3MgX with CH3C≡C−HCH_3C\equiv C-H produces

  1. A.CH3−CH=CH2CH_3-CH=CH_2
  2. B.CH3C≡C−CH3CH_3C\equiv C-CH_3
  3. C.CH3−CH=CH−CH3CH_3-CH=CH-CH_3
  4. D.CH4CH_4

Correct answer: D

Explanation: Acid-base: the acetylenic H protonates the Grignard.

Question 67

Chemistry · 3 marks · −1

The pKapK_a of a weak acid, HA, is 4.80. The pKbpK_b of a weak base, BOH, is 4.78. The pH of an aqueous solution of the corresponding salt, BA, will be

  1. A.9.58
  2. B.4.79
  3. C.7.01
  4. D.9.22

Correct answer: C

Explanation: pH=7+4.80−4.782=7.01pH=7+\frac{4.80-4.78}{2}=7.01.

Question 68

Physics · 3 marks · −1

Wave property of electrons implies that they will show diffraction effects. Davisson and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see in figure). Electrons accelerated by potential V are diffracted from a crystal. If d = 1 Å and i = 30∘30^\circ, V should be about (h=6.6×10−34h = 6.6\times10^{-34} Js, me=9.1×10−31m_e = 9.1\times10^{-31} kg, e=1.6×10−19e = 1.6\times10^{-19} C)

Figure for question 68
  1. A.2000 V
  2. B.50 V
  3. C.500 V
  4. D.1000 V

Correct answer: B

Explanation: λ=2dcos⁡i=1.73\lambda=2d\cos i=1.73 Å =12.27V=\frac{12.27}{\sqrt V} Å ⇒V≈50\Rightarrow V\approx50 V.

Question 69

Physics · 3 marks · −1

Wave property of electrons implies that they will show diffraction effects. Davisson and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see in figure). In an experiment, electrons are made to pass through a narrow slit of width 'd' comparable to their de Broglie wavelength. They are detected on a screen at a distance 'D' from the slit (see figure). Which of the following graph can be expected to represent the number of electrons 'N' detected as a function of the detector position 'y' (y = 0 corresponds to the middle of the slit)?

Figure for question 69
  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)
  4. D.Graph (4)

Correct answer: D

Explanation: Single-slit diffraction: central maximum wider than d with side lobes.

Question 70

Physics · 3 marks · −1

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 kms−1^{-1}, the escape velocity from the surface of the planet would be

  1. A.1.1 kms−1^{-1}
  2. B.11 kms−1^{-1}
  3. C.110 kms−1^{-1}
  4. D.0.11 kms−1^{-1}

Correct answer: C

Explanation: v∝M/Rv\propto\sqrt{M/R}: factor 10.

Question 71

Physics · 3 marks · −1

A spherical solid ball of volume V is made of a material of density ρ1\rho_1. It is falling through a liquid of density ρ2\rho_2 (ρ2<ρ1)(\rho_2 < \rho_1). Assume that the liquid applies a viscous force on the ball that is proportional to the square of its speed v, i.e., Fviscous=−kv2F_{viscous} = -kv^2 (k>0)(k > 0). The terminal speed of the ball is

  1. A.Vg(ρ1−ρ2)k\sqrt{\frac{Vg(\rho_1-\rho_2)}{k}}
  2. B.Vgρ1k\frac{Vg\rho_1}{k}
  3. C.Vgρ1k\sqrt{\frac{Vg\rho_1}{k}}
  4. D.Vg(ρ1−ρ2)k\frac{Vg(\rho_1-\rho_2)}{k}

Correct answer: A

Explanation: kv2=Vg(ρ1−ρ2)kv^2=Vg(\rho_1-\rho_2).

Question 72

Physics · 3 marks · −1

Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer. The value of the unknown resistor R is

Figure for question 72
  1. A.13.75 Ω13.75\,\Omega
  2. B.220 Ω220\,\Omega
  3. C.110 Ω110\,\Omega
  4. D.55 Ω55\,\Omega

Correct answer: B

Explanation: 5520=R80\frac{55}{20}=\frac{R}{80}.

Question 73

Physics · 3 marks · −1

A thin rod of length 'L' is lying along the x-axis with its ends at x = 0 and x = L. Its linear density (mass/length) varies with x as k(xL)nk\left(\frac{x}{L}\right)^n, where n can be zero or any positive number. If the position xCMx_{CM} of the centre of mass of the rod is plotted against 'n', which of the following graphs best approximates the dependence of xCMx_{CM} on n?

Figure for question 73
  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)
  4. D.Graph (4)

Correct answer: A

Explanation: xCM=n+1n+2Lx_{CM}=\frac{n+1}{n+2}L: starts at L2\frac L2 and rises towards L.

Question 74

Physics · 3 marks · −1

While measuring the speed of sound by performing a resonance column experiment, a student gets the first resonance condition at a column length of 18 cm during winter. Repeating the same experiment during summer, she measures the column length to be x cm for the second resonance. Then

  1. A.18 > x
  2. B.x > 54
  3. C.54 > x > 36
  4. D.36 > x > 18

Correct answer: B

Explanation: Second resonance is 3 times the first; higher summer temperature increases the speed, so x>54x>54.

Question 75

Physics · 3 marks · −1

The dimension of magnetic field in M, L, T and C (Coulomb) is given as

  1. A.MLT−1C−1MLT^{-1}C^{-1}
  2. B.MT2C−2MT^2C^{-2}
  3. C.MT−1C−1MT^{-1}C^{-1}
  4. D.MT−2C−1MT^{-2}C^{-1}

Correct answer: C

Explanation: B=FqvB=\frac{F}{qv}.

Question 76

Physics · 3 marks · −1

Consider a uniform square plate of side 'a' and mass 'm'. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

  1. A.56ma2\frac{5}{6}ma^2
  2. B.112ma2\frac{1}{12}ma^2
  3. C.712ma2\frac{7}{12}ma^2
  4. D.23ma2\frac{2}{3}ma^2

Correct answer: D

Explanation: ma26+ma22\frac{ma^2}{6}+m\frac{a^2}{2}.

Question 77

Physics · 3 marks · −1

A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00 ms−1^{-1}. The magnitude of its momentum is recorded as

  1. A.17.6 kg ms−1^{-1}
  2. B.17.565 kg ms−1^{-1}
  3. C.17.56 kg ms−1^{-1}
  4. D.17.57 kg ms−1^{-1}

Correct answer: A

Explanation: Three significant figures.

Question 78

Physics · 3 marks · −1

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range

  1. A.200 J - 500 J
  2. B.2×1052\times10^5 J - 3×1053\times10^5 J
  3. C.20,000 J - 50,000 J
  4. D.2,000 J - 5,000 J

Correct answer: D

Explanation: 12⋅60⋅102≈3000\frac12\cdot60\cdot10^2\approx3000 J.

Question 79

Physics · 3 marks · −1

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is 'd'. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant k1=3k_1 = 3 and thickness d3\frac{d}{3} while the other one has dielectric constant k2=6k_2 = 6 and thickness 2d3\frac{2d}{3}. Capacitance of the capacitor is now

  1. A.1.8 pF
  2. B.45 pF
  3. C.40.5 pF
  4. D.20.25 pF

Correct answer: C

Explanation: C=Aϵ0d/9+d/9=4.5C0C=\frac{A\epsilon_0}{d/9+d/9}=4.5C_0.

Question 80

Physics · 3 marks · −1

Statement-1: Energy is released when heavy nuclei undergo fission or light nuclei undergo fusion. Statement-2: For heavy nuclei, binding energy per nucleon increases with increasing Z while for light nuclei it decreases with increasing Z.

  1. A.Statement-1 is false, Statement-2 is true.
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is correct explanation for Statement-1.
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  4. D.Statement-1 is true, Statement-2 is False.

Correct answer: D

Explanation: Binding energy per nucleon decreases with Z for heavy nuclei and increases for light nuclei, so Statement-2 is false.

Question 81

Physics · 3 marks · −1

Statement-1: For a mass M kept at the centre of a cube of side 'a', the flux of gravitational field passing through its sides is 4πGM4\pi GM. Statement-2: If the direction of a field due to a point source is radial and its dependence on the distance 'r' for the source is given as 1/r21/r^2, its flux through a closed surface depends only on the strength of the source enclosed by the surface and not on the size or shape of the surface

  1. A.Statement-1 is false, Statement-2 is true.
  2. B.Statement-1 is true, Statement-2 is true; Statement-2 is correct explanation for Statement-1.
  3. C.Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  4. D.Statement-1 is true, Statement-2 is False.

Correct answer: B

Explanation: Gauss's law for gravity.

Question 82

Physics · 3 marks · −1

A jar filled with two non mixing liquids 1 and 2 having densities ρ1\rho_1 and ρ2\rho_2 respectively. A solid ball, made of a material of density ρ3\rho_3, is dropped in the jar. It comes to equilibrium in the position shown in the figure. Which of the following is true for ρ1\rho_1, ρ2\rho_2 and ρ3\rho_3?

Figure for question 82
  1. A.ρ3<ρ1<ρ2\rho_3 < \rho_1 < \rho_2
  2. B.ρ1>ρ3>ρ2\rho_1 > \rho_3 > \rho_2
  3. C.ρ1<ρ2<ρ3\rho_1 < \rho_2 < \rho_3
  4. D.ρ1<ρ3<ρ2\rho_1 < \rho_3 < \rho_2

Correct answer: D

Explanation: Liquid 1 floats on liquid 2, the ball sits at the interface.

Question 83

Physics · 3 marks · −1

Consider a block of conducting material of resistivity 'ρ\rho' shown in the figure. Current 'I' enters at 'A' and leaves from 'D'. We apply superposition principle to find voltage 'ΔV\Delta V' developed between 'B' and 'C'. The calculation is done in the following steps: (i) Take current 'I' entering from 'A' and assume it to spread over a hemispherical surface in the block. (ii) Calculate field E(r) at distance 'r' from A by using Ohm's law E=ρjE = \rho j, where j is the current per unit area at 'r'. (iii) From the 'r' dependence of E(r), obtain the potential V(r) at r. (iv) Repeat (i), (ii) and (iii) for current 'I' leaving 'D' and superpose results for 'A' and 'D'. For current entering at A, the electric field at a distance 'r' from A is

Figure for question 83
  1. A.ρI8πr2\frac{\rho I}{8\pi r^2}
  2. B.ρIr2\frac{\rho I}{r^2}
  3. C.ρI2πr2\frac{\rho I}{2\pi r^2}
  4. D.ρI4πr2\frac{\rho I}{4\pi r^2}

Correct answer: C

Explanation: j=I2πr2j=\frac{I}{2\pi r^2} over a hemisphere.

Question 84

Physics · 3 marks · −1

A student measures the focal length of convex lens by putting an object pin at a distance 'u' from the lens and measuring the distance 'v' of the image pin. The graph between 'u' and 'v' plotted by the student should look like

Figure for question 84
  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)
  4. D.Graph (4)

Correct answer: C

Explanation: 1v−1u=1f\frac1v-\frac1u=\frac1f with u negative: a rectangular hyperbola in the second quadrant.

Question 85

Physics · 3 marks · −1

A block of mass 0.50 kg is moving with a speed of 2.00 m/s on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

  1. A.0.16 J
  2. B.1.00 J
  3. C.0.67 J
  4. D.0.34 J

Correct answer: C

Explanation: v=23v=\frac23; loss 1−13=0.671-\frac13=0.67 J.

Question 86

Physics · 3 marks · −1

A capillary tube (A) is dipped in water. Another identical tube (B) is dipped in a soap water solution. Which of the following shows the relative nature of the liquid columns in the two tubes?

Figure for question 86
  1. A.Figure (1)
  2. B.Figure (2)
  3. C.Figure (3)
  4. D.Figure (4)

Correct answer: C

Explanation: Both concave menisci; soap solution (lower surface tension) rises less.

Question 87

Physics · 3 marks · −1

Suppose an electron is attracted towards the origin by a force k/r where 'k' is a constant and 'r' is the distance of the electron from the origin. By applying Bohr model to this system, the radius of the nthn^{th} orbital of the electron is found to be 'rnr_n' and the kinetic energy of the electron to be 'TnT_n'. Then which of the following is true?

  1. A.Tn∝1/n2T_n \propto 1/n^2, rn∝n2r_n \propto n^2
  2. B.TnT_n independent of n, rn∝nr_n \propto n
  3. C.Tn∝1/nT_n \propto 1/n, rn∝nr_n \propto n
  4. D.Tn∝1/nT_n \propto 1/n, rn∝n2r_n \propto n^2

Correct answer: B

Explanation: mv2=kmv^2=k constant; mvr=nh2π⇒r∝nmvr=\frac{nh}{2\pi}\Rightarrow r\propto n.

Question 88

Physics · 3 marks · −1

A wave travelling along the x-axis is described by the equation y(x,t)=0.005cos⁡(αx−βt)y(x, t) = 0.005\cos(\alpha x - \beta t). If the wavelength and the time period of the wave are 0.08 m and 2.0 s, respectively, then α\alpha and β\beta in appropriate units are

  1. A.α=25.00π\alpha = 25.00\pi, β=π\beta = \pi
  2. B.α=0.08π\alpha = \frac{0.08}{\pi}, β=2.0π\beta = \frac{2.0}{\pi}
  3. C.α=0.04π\alpha = \frac{0.04}{\pi}, β=1.0π\beta = \frac{1.0}{\pi}
  4. D.α=12.50π\alpha = 12.50\pi, β=π2.0\beta = \frac{\pi}{2.0}

Correct answer: A

Explanation: α=2π0.08\alpha=\frac{2\pi}{0.08}, β=2π2\beta=\frac{2\pi}{2}.

Question 89

Physics · 3 marks · −1

Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross sectional area A = 10 cm2^2 and length = 20 cm. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is (μ0=4π×10−7\mu_0 = 4\pi\times10^{-7} Tm A−1^{-1})

  1. A.2.4π×10−52.4\pi\times10^{-5} H
  2. B.4.8π×10−44.8\pi\times10^{-4} H
  3. C.4.8π×10−54.8\pi\times10^{-5} H
  4. D.2.4π×10−42.4\pi\times10^{-4} H

Correct answer: D

Explanation: M=μ0N1N2AℓM=\frac{\mu_0N_1N_2A}{\ell}.

Question 90

Physics · 3 marks · −1

In the circuit below, A and B represent two inputs and C represents the output. The circuit represents

Figure for question 90
  1. A.NOR gate
  2. B.AND gate
  3. C.NAND gate
  4. D.OR gate

Correct answer: D

Explanation: Diode OR: output high if either input high.

Question 91

Physics · 3 marks · −1

A body is at rest at x = 0. At t = 0, it starts moving in the positive x-direction with a constant acceleration. At the same instant another body passes through x = 0 moving in the positive x-direction with a constant speed. The position of the first body is given by x1(t)x_1(t) after time 't' and that of the second body by x2(t)x_2(t) after the same time interval. Which of the following graphs correctly describes (x1−x2)(x_1 - x_2) as a function of time 't'?

Figure for question 91
  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)
  4. D.Graph (4)

Correct answer: B

Explanation: x1−x2=12at2−vtx_1-x_2=\frac12at^2-vt: dips below zero then rises (parabola through origin).

Question 92

Physics · 3 marks · −1

An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment distance are measured by

  1. A.a vernier scale provided on the microscope
  2. B.a standard laboratory scale
  3. C.a meter scale provided on the microscope
  4. D.a screw gauge provided on the microscope

Correct answer: A

Explanation: Travelling microscope readings use its vernier.

Question 93

Physics · 3 marks · −1

A thin spherical shell of radius R has charge Q spread uniformly over its surface. Which of the following graphs most closely represents the electric field E(r) produced by the shell in the range 0≤r<∞0 \le r < \infty, where r is the distance from the centre of the shell?

Figure for question 93
  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)
  4. D.Graph (4)

Correct answer: A

Explanation: Zero inside, jumps at R, then falls as 1/r21/r^2.

Question 94

Physics · 3 marks · −1

A 5V battery with internal resistance 2 Ω2\,\Omega and a 2V battery with internal resistance 1 Ω1\,\Omega are connected to a 10 Ω10\,\Omega resistor as shown in the figure. The current in the 10 Ω10\,\Omega resistor is

Figure for question 94
  1. A.0.27 A P2P_2 to P1P_1
  2. B.0.03 A P1P_1 to P2P_2
  3. C.0.03 A P2P_2 to P1P_1
  4. D.0.27 A P1P_1 to P2P_2

Correct answer: C

Explanation: Millman: VP2−VP1=5/2−2/11/2+1/10+1≈0.31V_{P_2}-V_{P_1}=\frac{5/2-2/1}{1/2+1/10+1}\approx0.31 V; I≈0.03I\approx0.03 A from P2P_2 to P1P_1.

Question 95

Physics · 3 marks · −1

A horizontal overhead power line is at a height of 4m from the ground and carries a current of 100 A from east to west. The magnetic field directly below it on the ground is (μ0=4π×10−7\mu_0 = 4\pi\times10^{-7} T m A−1^{-1})

  1. A.2.5×10−72.5\times10^{-7} T southward
  2. B.5×10−65\times10^{-6} T northward
  3. C.5×10−65\times10^{-6} T southward
  4. D.2.5×10−72.5\times10^{-7} northward

Correct answer: C

Explanation: B=μ0I2πr=5×10−6B=\frac{\mu_0I}{2\pi r}=5\times10^{-6} T; right-hand rule gives south.

Question 96

Physics · 3 marks · −1

Relative permittivity and permeability of a material are ϵr\epsilon_r and μr\mu_r, respectively. Which of the following values of these quantities are allowed for a diamagnetic material?

  1. A.ϵr=0.5\epsilon_r = 0.5, μr=1.5\mu_r = 1.5
  2. B.ϵr=1.5\epsilon_r = 1.5, μr=0.5\mu_r = 0.5
  3. C.ϵr=0.5\epsilon_r = 0.5, μr=0.5\mu_r = 0.5
  4. D.ϵr=1.5\epsilon_r = 1.5, μr=1.5\mu_r = 1.5

Correct answer: B

Explanation: Diamagnetic: μr<1\mu_r<1; ϵr>1\epsilon_r>1 for a material.

Question 97

Physics · 3 marks · −1

Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, it is found that the screw gauge has a zero error of -0.03 mm while measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is

  1. A.3.32 mm
  2. B.3.73 mm
  3. C.3.67 mm
  4. D.3.38 mm

Correct answer: D

Explanation: 3+35⋅0.01+0.03=3.383+35\cdot0.01+0.03=3.38 mm.

Question 98

Physics · 3 marks · −1

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V1V_1 and contains ideal gas at pressure P1P_1 and temperature T1T_1. The other chamber has volume V2V_2 and contains ideal gas at pressure P2P_2 and temperature T2T_2. If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be

  1. A.T1T2(P1V1+P2V2)P1V1T2+P2V2T1\frac{T_1T_2(P_1V_1+P_2V_2)}{P_1V_1T_2+P_2V_2T_1}
  2. B.P1V1T1+P2V2T2P1V1+P2V2\frac{P_1V_1T_1+P_2V_2T_2}{P_1V_1+P_2V_2}
  3. C.P1V1T2+P2V2T1P1V1+P2V2\frac{P_1V_1T_2+P_2V_2T_1}{P_1V_1+P_2V_2}
  4. D.T1T2(P1V1+P2V2)P1V1T1+P2V2T2\frac{T_1T_2(P_1V_1+P_2V_2)}{P_1V_1T_1+P_2V_2T_2}

Correct answer: A

Explanation: Internal energy conserved: (n1+n2)T=n1T1+n2T2(n_1+n_2)T=n_1T_1+n_2T_2 with n=PVRTn=\frac{PV}{RT}.

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