BITSAT Practice Set 1

BITSAT · 2026 · with answers and explanations

questions
30
Total marks
89
Duration
180 minutes
Negative marking
−1

Subjects: Physics · Chemistry · Mathematics

Question 1

Physics · 3 marks · −1

A ball is thrown vertically upward with a velocity of 20 m/s from the top of a building 60 m high. The time taken by the ball to reach the ground is (g = 10 m/s²):

  1. A.2 s
  2. B.4 s
  3. C.6 s
  4. D.8 s

Correct answer: C

Explanation: Taking upward as positive: s = -60 m, u = 20 m/s, a = -10 m/s². Using s = ut + ½at²: -60 = 20t - 5t², so 5t² - 20t - 60 = 0, t² - 4t - 12 = 0, (t-6)(t+2) = 0. Since t must be positive, t = 6 s.

Question 2

Physics · 3 marks · −1

A block of mass 5 kg is placed on a rough inclined plane making an angle of 30° with the horizontal. If the coefficient of friction is 1/√3, the acceleration of the block sliding down the plane is (g = 10 m/s²):

  1. A.5 m/s²
  2. B.2.5 m/s²
  3. C.0 m/s²
  4. D.g m/s²

Correct answer: C

Explanation: Along the incline: a = g(sinθ - μcosθ) = 10(sin30° - (1/√3)cos30°) = 10(0.5 - (1/√3)(√3/2)) = 10(0.5 - 0.5) = 0 m/s². The block is in equilibrium on the incline.

Question 3

Physics · 3 marks · −1

A body of mass 4 kg moving with velocity 6 m/s collides with another body of mass 2 kg at rest. If the collision is perfectly inelastic, the kinetic energy lost in the collision is:

  1. A.12 J
  2. B.24 J
  3. C.36 J
  4. D.48 J

Correct answer: B

Explanation: Initial KE = ½(4)(6²) = 72 J. After perfectly inelastic collision, v = m₁u₁/(m₁+m₂) = 4×6/6 = 4 m/s. Final KE = ½(6)(4²) = 48 J. Loss = 72 - 48 = 24 J.

Question 4

Physics · 3 marks · −1

A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of inclination θ. The acceleration of the centre of mass is:

  1. A.gsinθ
  2. B.gsinθ/2
  3. C.2gsinθ/3
  4. D.gsinθ/3

Correct answer: C

Explanation: For a solid cylinder rolling without slipping, a = gsinθ/(1 + I/(MR²)). For a solid cylinder, I = MR²/2, so a = gsinθ/(1 + 1/2) = 2gsinθ/3.

Question 5

Physics · 3 marks · −1

The gravitational potential energy of a body of mass m at a height h above the surface of the Earth (radius R) is -mgR. The escape velocity from height h is (given h = R):

  1. A.vₑ/2
  2. B.vₑ/√2
  3. C.vₑ√2
  4. D.2vₑ

Correct answer: B

Explanation: At height h = R from the surface (distance 2R from centre), escape velocity = √(2GM/(2R)) = √(GM/R) = v_e/√2, where v_e = √(2GM/R) is the escape velocity from the surface.

Question 6

Physics · 3 marks · −1

Three capacitors of 2 μF, 3 μF, and 6 μF are connected in series across a 12 V battery. The charge on each capacitor is:

  1. A.6 μC
  2. B.12 μC
  3. C.24 μC
  4. D.36 μC

Correct answer: B

Explanation: In series, 1/C_eq = 1/2 + 1/3 + 1/6 = (3+2+1)/6 = 1, so C_eq = 1 μF. Charge Q = C_eq × V = 1 × 12 = 12 μC. In series, each capacitor carries the same charge.

Question 7

Physics · 3 marks · −1

A wire of resistance 12 Ω is bent into a circle. The effective resistance between two diametrically opposite points is:

  1. A.12 Ω
  2. B.6 Ω
  3. C.3 Ω
  4. D.1.5 Ω

Correct answer: C

Explanation: The wire becomes two semicircular arcs each of resistance 6 Ω, connected in parallel between the two diametrically opposite points. R_eff = 6×6/(6+6) = 3 Ω.

Question 8

Physics · 3 marks · −1

A circular coil of 200 turns and radius 10 cm carries a current of 2 A. The magnetic field at the centre of the coil is:

  1. A.4π × 10⁻⁴ T
  2. B.8π × 10⁻⁴ T
  3. C.2π × 10⁻⁴ T
  4. D.16π × 10⁻⁴ T

Correct answer: B

Explanation: B = μ₀NI/(2R) = 4π×10⁻⁷ × 200 × 2/(2 × 0.1) = 4π×10⁻⁷ × 2000 = 8π×10⁻⁴ T ≈ 25.1×10⁻⁴ T.

Question 9

Physics · 3 marks · −1

A concave mirror of focal length 20 cm produces a real image that is three times the size of the object. The object distance is:

  1. A.20 cm
  2. B.80/3 cm
  3. C.40 cm
  4. D.60 cm

Correct answer: B

Explanation: For a real image, magnification m = -3 (inverted). m = -v/u, so v = 3u. Using mirror formula 1/v + 1/u = 1/f with sign convention (u = -x, v = -3x, f = -20): -1/(3x) - 1/x = -1/20, so 4/(3x) = 1/20, x = 80/3 ≈ 26.67 cm.

Question 10

Physics · 3 marks · −1

In a common-emitter transistor amplifier, the input resistance is 1 kΩ, the output resistance is 5 kΩ, and the current gain (β) is 100. The voltage gain of the amplifier is:

  1. A.100
  2. B.200
  3. C.500
  4. D.1000

Correct answer: C

Explanation: Voltage gain A_v = β × (R_out/R_in) = 100 × (5000/1000) = 500.

Question 11

Chemistry · 3 marks · −1

How many moles of oxygen are present in 64 g of O₂?

  1. A.1
  2. B.2
  3. C.3
  4. D.4

Correct answer: B

Explanation: Molar mass of O₂ = 32 g/mol. Number of moles = 64/32 = 2 moles.

Question 12

Chemistry · 3 marks · −1

The maximum number of electrons that can be accommodated in the 3d subshell is:

  1. A.6
  2. B.8
  3. C.10
  4. D.14

Correct answer: C

Explanation: For d subshell, l = 2 and m_l ranges from -2 to +2 giving 5 orbitals. Each orbital holds 2 electrons, so the maximum is 5 × 2 = 10 electrons.

Question 13

Chemistry · 3 marks · −1

Among BF₃, NH₃, NF₃, and BCl₃, the molecules with zero dipole moment are:

  1. A.BF₃ and NH₃
  2. B.NH₃ and NF₃
  3. C.BF₃ and BCl₃
  4. D.BF₃ and NF₃

Correct answer: C

Explanation: BF₃ and BCl₃ are trigonal planar (sp² hybridised) with 120° bond angles, so their individual bond dipoles cancel out giving zero net dipole moment. NH₃ and NF₃ are pyramidal with lone pairs, giving non-zero dipole moments.

Question 14

Chemistry · 3 marks · −1

The pH of a 0.001 M HCl solution is:

  1. A.1
  2. B.2
  3. C.3
  4. D.4

Correct answer: C

Explanation: HCl is a strong acid that completely dissociates. [H⁺] = 0.001 = 10⁻³ M. pH = -log[H⁺] = -log(10⁻³) = 3.

Question 15

Chemistry · 3 marks · −1

The standard enthalpy of formation of CO₂(g) is -393.5 kJ/mol. The enthalpy change when 24 g of carbon (graphite) is completely burnt in excess oxygen is:

  1. A.-393.5 kJ
  2. B.-787.0 kJ
  3. C.-196.75 kJ
  4. D.-1574 kJ

Correct answer: B

Explanation: Moles of C = 24/12 = 2 mol. The reaction C(s) + O₂(g) → CO₂(g) releases 393.5 kJ/mol. For 2 mol: ΔH = 2 × (-393.5) = -787 kJ.

Question 16

Chemistry · 3 marks · −1

In the electrochemical series, the metal that is the strongest reducing agent is:

  1. A.Sodium
  2. B.Potassium
  3. C.Lithium
  4. D.Caesium

Correct answer: C

Explanation: In the electrochemical series, lithium (Li) has the most negative standard reduction potential (E° = -3.04 V), making it the strongest reducing agent among common metals.

Question 17

Chemistry · 3 marks · −1

The element that shows the maximum number of allotropes in the p-block is:

  1. A.Sulphur
  2. B.Carbon
  3. C.Phosphorus
  4. D.Tin

Correct answer: B

Explanation: Carbon shows the maximum number of allotropes among p-block elements, including diamond, graphite, fullerenes (C₆₀), carbon nanotubes, graphene, and amorphous carbon.

Question 18

Chemistry · 3 marks · −1

The IUPAC name of the complex [Co(NH₃)₅Cl]Cl₂ is:

  1. A.Pentaamminechloridocobalt(III) chloride
  2. B.Chloridopentaamminecobalt(III) chloride
  3. C.Pentaamminechloridocobalt(II) chloride
  4. D.Pentachloridoamminecobalt(III) chloride

Correct answer: A

Explanation: The complex cation has 5 NH₃ (pentaammine) and 1 Cl⁻ (chlorido) ligands coordinated to Co³⁺. Following IUPAC nomenclature: anionic ligands first alphabetically, then neutral ligands. Name: pentaamminechloridocobalt(III) chloride.

Question 19

Chemistry · 3 marks · −1

The number of isomers possible for the alkene C₄H₈ is:

  1. A.2
  2. B.3
  3. C.4
  4. D.5

Correct answer: B

Explanation: C₄H₈ (butene) has three structural isomers: but-1-ene (CH₂=CHCH₂CH₃), but-2-ene (CH₃CH=CHCH₃), and 2-methylpropene ((CH₃)₂C=CH₂). But-2-ene has cis and trans forms, so total = 4 stereoisomers, but 3 structural isomers.

Question 20

Chemistry · 3 marks · −1

Which of the following amino acids is NOT essential for the human body?

  1. A.Valine
  2. B.Leucine
  3. C.Alanine
  4. D.Isoleucine

Correct answer: C

Explanation: Alanine is a non-essential amino acid as the human body can synthesise it. Valine, leucine, and isoleucine are all essential amino acids that must be obtained from the diet.

Question 21

Mathematics · 3 marks · −1

If A = {1, 2, 3, 4} and B = {3, 4, 5, 6}, then A ∩ B is:

  1. A.{1, 2, 3, 4, 5, 6}
  2. B.{3, 4}
  3. C.{1, 2, 5, 6}
  4. D.{1, 2}

Correct answer: B

Explanation: The intersection A ∩ B contains elements common to both sets. Common elements are 3 and 4. So A ∩ B = {3, 4}.

Question 22

Mathematics · 3 marks · −1

If one root of the equation x² - 5x + k = 0 is 2, then the value of k is:

  1. A.4
  2. B.5
  3. C.6
  4. D.7

Correct answer: C

Explanation: Substituting x = 2: (2)² - 5(2) + k = 0, so 4 - 10 + k = 0, giving k = 6.

Question 23

Mathematics · 3 marks · −1

The coefficient of x³ in the expansion of (1 + x)¹ is:

  1. A.56
  2. B.84
  3. C.120
  4. D.126

Correct answer: B

Explanation: Using binomial theorem, the coefficient of x³ in (1+x)⁹ is C(9,3) = 9!/(3!6!) = (9×8×7)/(3×2×1) = 84.

Question 24

Mathematics · 2 marks

The sum of the first 20 terms of the arithmetic progression 3, 7, 11, 15, ... is:

  1. A.780
  2. B.820
  3. C.860
  4. D.900

Correct answer: B

Explanation: First term a = 3, common difference d = 4. S₂₀ = (20/2)[2(3) + (20−1)(4)] = 10[6 + 76] = 10 × 82 = 820.

Question 25

Mathematics · 3 marks · −1

The value of sin²(π/6) + cos²(π/3) + tan²(π/4) is:

  1. A.1
  2. B.3/2
  3. C.2
  4. D.5/2

Correct answer: B

Explanation: sin(π/6) = 1/2, cos(π/3) = 1/2, tan(π/4) = 1. So sin²(π/6) + cos²(π/3) + tan²(π/4) = 1/4 + 1/4 + 1 = 3/2.

Question 26

Mathematics · 3 marks · −1

The slope of the line passing through the points (2, 3) and (5, 9) is:

  1. A.1
  2. B.2
  3. C.3
  4. D.1/2

Correct answer: B

Explanation: Slope m = (y₂ - y₁)/(x₂ - x₁) = (9 - 3)/(5 - 2) = 6/3 = 2.

Question 27

Mathematics · 3 marks · −1

The value of lim(x→0) (sin 5x)/(3x) is:

  1. A.1
  2. B.3/5
  3. C.5/3
  4. D.0

Correct answer: C

Explanation: lim(x→0) sin(5x)/(3x) = lim(x→0) [sin(5x)/(5x)] × (5x/3x) = 1 × 5/3 = 5/3.

Question 28

Mathematics · 3 marks · −1

The value of ∫₀² (3x² + 2x) dx is:

  1. A.8
  2. B.10
  3. C.12
  4. D.14

Correct answer: C

Explanation: ∫(3x² + 2x)dx = x³ + x². Evaluating from 0 to 2: [2³ + 2²] - [0] = 8 + 4 = 12.

Question 29

Mathematics · 3 marks · −1

A bag contains 5 red and 3 blue balls. If two balls are drawn at random without replacement, the probability that both are red is:

  1. A.5/14
  2. B.5/8
  3. C.25/64
  4. D.10/28

Correct answer: A

Explanation: P(both red) = (5/8) × (4/7) = 20/56 = 5/14.

Question 30

Mathematics · 3 marks · −1

If A is a square matrix of order 3 such that |A| = 5, then |2A| is:

  1. A.10
  2. B.20
  3. C.40
  4. D.80

Correct answer: C

Explanation: |kA| = kⁿ|A| for a matrix of order n. So |2A| = 2³ × |A| = 8 × 5 = 40.

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