JEE Main 2018 — 16 Apr Morning (online CBT) (Previous Year Paper)

JEE Main · 2018 · with answers and explanations

questions
89
Total marks
356
Duration
180 minutes
Negative marking
−1

Subjects: Physics · Chemistry · Mathematics

Question 1

Physics · 4 marks · −1

The percentage errors in quantities P, Q, R and S are 0.5%, 1%, 3% and 1.5% respectively in the measurement of a physical quantity A=P3Q2R SA = \frac{P^3Q^2}{\sqrt{R}\,S}. The maximum percentage error in the value of A will be :

  1. A.6.0%
  2. B.7.5%
  3. C.8.5%
  4. D.6.5%

Correct answer: D

Question 2

Physics · 4 marks · −1

Let A⃗=(i^+j^)\vec{A} = (\hat{i} + \hat{j}) and, B⃗=(2i^−j^)\vec{B} = (2\hat{i} - \hat{j}). The magnitude of a coplanar vector C⃗\vec{C} such that A⃗⋅C⃗=B⃗⋅C⃗=A⃗⋅B⃗\vec{A}\cdot\vec{C} = \vec{B}\cdot\vec{C} = \vec{A}\cdot\vec{B}, is given by :

  1. A.109\sqrt{\frac{10}{9}}
  2. B.59\sqrt{\frac{5}{9}}
  3. C.209\sqrt{\frac{20}{9}}
  4. D.912\sqrt{\frac{9}{12}}

Correct answer: B

Question 3

Physics · 4 marks · −1

A body of mass m starts moving from rest along x-axis so that its velocity varies as v=asv = a\sqrt{s} where a is a constant and s is the distance covered by the body. The total work done by all the forces acting on the body in the first t seconds after the start of the motion is :

  1. A.18ma4t2\frac{1}{8}ma^4t^2
  2. B.8ma4t28ma^4t^2
  3. C.4ma4t24ma^4t^2
  4. D.14ma4t2\frac{1}{4}ma^4t^2

Correct answer: A

Question 4

Physics · 4 marks · −1

Two particles of the same mass m are moving in circular orbits because of force, given by F(r)=−16r−r3F(r) = \frac{-16}{r} - r^3. The first particle is at a distance r = 1, and the second, at r = 4. The best estimate for the ratio of kinetic energies of the first and the second particle is closest to :

  1. A.6×10−26\times10^{-2}
  2. B.3×10−33\times10^{-3}
  3. C.10−110^{-1}
  4. D.6×1026\times10^{2}

Correct answer: A

Question 5

Physics · 4 marks · −1

An oscillator of mass M is at rest in its equilibrium position in a potential V=12k(x−X)2V = \frac{1}{2}k(x - X)^2. A particle of mass m comes from right with speed u and collides completely inelastically with M and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after 13 collisions is : (M = 10, m = 5, u = 1, k = 1)

  1. A.13\frac{1}{\sqrt{3}}
  2. B.12\frac{1}{2}
  3. C.23\frac{2}{3}
  4. D.35\sqrt{\frac{3}{5}}

Correct answer: A

Question 6

Physics · 4 marks · −1

Suppose that the angular velocity of rotation of earth is increased. Then, as a consequence :

  1. A.Weight of the object, everywhere on the earth, will increase.
  2. B.Weight of the object, everywhere on the earth, will decrease.
  3. C.There will be no change in weight anywhere on the earth.
  4. D.Except at poles, weight of the object on the earth will decrease.

Correct answer: D

Question 7

Physics · 4 marks · −1

A thin circular disk is in the xy plane as shown in the figure. The ratio of its moment of inertia about z and z' axes will be :

Figure for question 7
  1. A.1 : 3
  2. B.1 : 4
  3. C.1 : 5
  4. D.1 : 2

Correct answer: A

Question 8

Physics · 4 marks · −1

The relative uncertainty in the period of a satellite orbiting around the earth is 10−210^{-2}. If the relative uncertainty in the radius of the orbit is negligible, the relative uncertainty in the mass of the earth is :

  1. A.10−210^{-2}
  2. B.2×10−22\times10^{-2}
  3. C.3×10−23\times10^{-2}
  4. D.6×10−26\times10^{-2}

Correct answer: B

Question 9

Physics · 4 marks · −1

A small soap bubble of radius 4 cm is trapped inside another bubble of radius 6 cm without any contact. Let P2P_2 be the pressure inside the inner bubble and P0P_0, the pressure outside the outer bubble. Radius of another bubble with pressure difference P2−P0P_2 - P_0 between its inside and outside would be :

  1. A.12 cm
  2. B.2.4 cm
  3. C.6 cm
  4. D.4.8 cm

Correct answer: B

Question 10

Physics · 4 marks · −1

One mole of an ideal monoatomic gas is taken along the path ABCA as shown in the PV diagram. The maximum temperature attained by the gas along the path BC is given by :

Figure for question 10
  1. A.2516P0V0R\frac{25}{16}\frac{P_0V_0}{R}
  2. B.258P0V0R\frac{25}{8}\frac{P_0V_0}{R}
  3. C.254P0V0R\frac{25}{4}\frac{P_0V_0}{R}
  4. D.58P0V0R\frac{5}{8}\frac{P_0V_0}{R}

Correct answer: B

Question 11

Physics · 4 marks · −1

Two moles of helium are mixed with n moles of hydrogen. If CPCV=32\frac{C_P}{C_V} = \frac{3}{2} for the mixture, then the value of n is :

  1. A.1
  2. B.3
  3. C.2
  4. D.3/2

Correct answer: C

Question 12

Physics · 4 marks · −1

A particle executes simple harmonic motion and is located at x = a, b and c at times t0t_0, 2t02t_0 and 3t03t_0 respectively. The frequency of the oscillation is :

  1. A.12πt0cos⁡−1(a+c2b)\frac{1}{2\pi t_0}\cos^{-1}\left(\frac{a+c}{2b}\right)
  2. B.12πt0cos⁡−1(a+b2c)\frac{1}{2\pi t_0}\cos^{-1}\left(\frac{a+b}{2c}\right)
  3. C.12πt0cos⁡−1(2a+3cb)\frac{1}{2\pi t_0}\cos^{-1}\left(\frac{2a+3c}{b}\right)
  4. D.12πt0cos⁡−1(a+2b3c)\frac{1}{2\pi t_0}\cos^{-1}\left(\frac{a+2b}{3c}\right)

Correct answer: A

Question 13

Physics · 4 marks · −1

Two sitar strings, A and B, playing the note 'Dha' are slightly out of tune and produce beats of frequency 5 Hz. The tension of the string B is slightly increased and the beat frequency is found to decrease by 3 Hz. If the frequency of A is 425 Hz, the original frequency of B is :

  1. A.430 Hz
  2. B.420 Hz
  3. C.428 Hz
  4. D.422 Hz

Correct answer: B

Question 14

Physics · 4 marks · −1

Two identical conducting spheres A and B, carry equal charge. They are separated by a distance much larger than their diameters, and the force between them is F. A third identical conducting sphere, C, is uncharged. Sphere C is first touched to A, then to B, and then removed. As a result, the force between A and B would be equal to :

  1. A.F
  2. B.3F4\frac{3F}{4}
  3. C.3F8\frac{3F}{8}
  4. D.F2\frac{F}{2}

Correct answer: C

Question 15

Physics · 4 marks · −1

A heating element has a resistance of 100 Ω\Omega at room temperature. When it is connected to a supply of 220 V, a steady current of 2 A passes in it and temperature is 500°C more than room temperature. What is the temperature coefficient of resistance of the heating element ?

  1. A.0.5×10−40.5\times10^{-4} °C−1^{-1}
  2. B.5×10−45\times10^{-4} °C−1^{-1}
  3. C.1×10−41\times10^{-4} °C−1^{-1}
  4. D.2×10−42\times10^{-4} °C−1^{-1}

Correct answer: D

Question 16

Physics · 4 marks · −1

A galvanometer with its coil resistance 25 Ω\Omega requires a current of 1 mA for its full deflection. In order to construct an ammeter to read up to a current of 2 A, the approximate value of the shunt resistance should be :

  1. A.2.5×10−3 Ω2.5\times10^{-3}\,\Omega
  2. B.1.25×10−2 Ω1.25\times10^{-2}\,\Omega
  3. C.1.25×10−3 Ω1.25\times10^{-3}\,\Omega
  4. D.2.5×10−2 Ω2.5\times10^{-2}\,\Omega

Correct answer: B

Question 17

Physics · 4 marks · −1

In the following circuit, the switch S is closed at t = 0. The charge on the capacitor C1C_1 as a function of time will be given by (Ceq=C1C2C1+C2)\left(C_{eq} = \frac{C_1C_2}{C_1+C_2}\right)

Figure for question 17
  1. A.C1E[1−exp⁡(−tR/C1)]C_1E\left[1 - \exp(-tR/C_1)\right]
  2. B.C2E[1−exp⁡(−t/RC2)]C_2E\left[1 - \exp(-t/RC_2)\right]
  3. C.CeqE[1−exp⁡(−t/RCeq)]C_{eq}E\left[1 - \exp(-t/RC_{eq})\right]
  4. D.CeqEexp⁡(−t/RCeq)C_{eq}E\exp(-t/RC_{eq})

Correct answer: C

Question 18

Physics · 4 marks · −1

A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity ω\omega, the maximum e.m.f. induced in the coil will be :

  1. A.3nBAω3nBA\omega
  2. B.32nBAω\frac{3}{2}nBA\omega
  3. C.nBAωnBA\omega
  4. D.12nBAω\frac{1}{2}nBA\omega

Correct answer: C

Question 19

Physics · 4 marks · −1

A charge q is spread uniformly over an insulated loop of radius r. If it is rotated with an angular velocity ω\omega with respect to normal axis then the magnetic moment of the loop is :

  1. A.qωr2q\omega r^2
  2. B.43qωr2\frac{4}{3}q\omega r^2
  3. C.32qωr2\frac{3}{2}q\omega r^2
  4. D.12qωr2\frac{1}{2}q\omega r^2

Correct answer: D

Question 20

Physics · 4 marks · −1

A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90%, the output current would be :

  1. A.50 A
  2. B.45 A
  3. C.25 A
  4. D.20 A

Correct answer: B

Question 21

Physics · 4 marks · −1

A plane electromagnetic wave of wavelength λ\lambda has an intensity I. It is propagating along the positive Y-direction. The allowed expressions for the electric and magnetic fields are given by :

  1. A.E⃗=2Iϵ0ccos⁡[2πλ(y−ct)]k^\vec{E} = \sqrt{\frac{2I}{\epsilon_0 c}}\cos\left[\frac{2\pi}{\lambda}(y - ct)\right]\hat{k} ; B⃗=+1cE i^\vec{B} = +\frac{1}{c}E\,\hat{i}
  2. B.E⃗=2Iϵ0ccos⁡[2πλ(y+ct)]k^\vec{E} = \sqrt{\frac{2I}{\epsilon_0 c}}\cos\left[\frac{2\pi}{\lambda}(y + ct)\right]\hat{k} ; B⃗=1cE i^\vec{B} = \frac{1}{c}E\,\hat{i}
  3. C.E⃗=Iϵ0ccos⁡[2πλ(y−ct)]k^\vec{E} = \sqrt{\frac{I}{\epsilon_0 c}}\cos\left[\frac{2\pi}{\lambda}(y - ct)\right]\hat{k} ; B⃗=1cE i^\vec{B} = \frac{1}{c}E\,\hat{i}
  4. D.E⃗=Iϵ0ccos⁡[2πλ(y−ct)]i^\vec{E} = \sqrt{\frac{I}{\epsilon_0 c}}\cos\left[\frac{2\pi}{\lambda}(y - ct)\right]\hat{i} ; B⃗=1cE k^\vec{B} = \frac{1}{c}E\,\hat{k}

Correct answer: A

Question 22

Physics · 4 marks · −1

A ray of light is incident at an angle of 60∘60^\circ on one face of a prism of angle 30∘30^\circ. The emergent ray of light makes an angle of 30∘30^\circ with incident ray. The angle made by the emergent ray with second face of prism will be :

  1. A.0∘0^\circ
  2. B.90∘90^\circ
  3. C.45∘45^\circ
  4. D.30∘30^\circ

Correct answer: B

Question 23

Physics · 4 marks · −1

Unpolarized light of intensity I is incident on a system of two polarizers, A followed by B. The intensity of emergent light is I/2. If a third polarizer C is placed between A and B, the intensity of emergent light is reduced to I/3. The angle between the polarizers A and C is θ\theta. Then :

  1. A.cos⁡θ=(23)1/2\cos\theta = \left(\frac{2}{3}\right)^{1/2}
  2. B.cos⁡θ=(23)1/4\cos\theta = \left(\frac{2}{3}\right)^{1/4}
  3. C.cos⁡θ=(13)1/2\cos\theta = \left(\frac{1}{3}\right)^{1/2}
  4. D.cos⁡θ=(13)1/4\cos\theta = \left(\frac{1}{3}\right)^{1/4}

Correct answer: B

Question 24

Physics · 4 marks · −1

The de-Broglie wavelength (λB)(\lambda_B) associated with the electron orbiting in the second excited state of hydrogen atom is related to that in the ground state (λG)(\lambda_G) by :

  1. A.λB=2λG\lambda_B = 2\lambda_G
  2. B.λB=3λG\lambda_B = 3\lambda_G
  3. C.λB=λG/2\lambda_B = \lambda_G/2
  4. D.λB=λG/3\lambda_B = \lambda_G/3

Correct answer: B

Question 25

Physics · 4 marks · −1

Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths λN\lambda_N, λA\lambda_A respectively. The ratio λNλA\frac{\lambda_N}{\lambda_A} is closest to :

  1. A.10−610^{-6}
  2. B.10
  3. C.10−1010^{-10}
  4. D.10−110^{-1}

Correct answer: A

Question 26

Physics · 4 marks · −1

At some instant, a radioactive sample S1S_1 having an activity 5 μ\muCi has twice the number of nuclei as another sample S2S_2 which has an activity of 10 μ\muCi. The half lives of S1S_1 and S2S_2 are :

  1. A.20 years and 5 years, respectively
  2. B.20 years and 10 years, respectively
  3. C.5 years and 20 years, respectively
  4. D.10 years and 20 years, respectively

Correct answer: A

Question 27

Physics · 4 marks · −1

In the given circuit, the current through zener diode is :

Figure for question 27
  1. A.5.5 mA
  2. B.6.7 mA
  3. C.2.5 mA
  4. D.3.3 mA

Correct answer: D

Question 28

Physics · 4 marks · −1

A carrier wave of peak voltage 14 V is used for transmitting a message signal. The peak voltage of modulating signal given to achieve a modulation index of 80% will be :

  1. A.7 V
  2. B.28 V
  3. C.11.2 V
  4. D.22.4 V

Correct answer: C

Question 29

Physics · 4 marks · −1

In a circuit for finding the resistance of a galvanometer by half deflection method, a 6 V battery and a high resistance of 11 kΩ\Omega are used. The figure of merit of the galvanometer is 60 μ\muA/division. In the absence of shunt resistance, the galvanometer produces a deflection of θ=9\theta = 9 divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of θ/2\theta/2, is closest to :

  1. A.550 Ω\Omega
  2. B.220 Ω\Omega
  3. C.55 Ω\Omega
  4. D.110 Ω\Omega

Correct answer: D

Question 30

Physics · 4 marks · −1

The end correction of a resonance column is 1 cm. If the shortest length resonating with the tuning fork is 10 cm, the next resonating length should be :

  1. A.28 cm
  2. B.32 cm
  3. C.36 cm
  4. D.40 cm

Correct answer: B

Question 31

Chemistry · 4 marks · −1

An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are : (Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023×10236.023\times10^{23} mol−1^{-1})

  1. A.6.023×10206.023\times10^{20}
  2. B.6.023×1096.023\times10^{9}
  3. C.6.023×10216.023\times10^{21}
  4. D.6.023×10236.023\times10^{23}

Correct answer: A

Question 32

Chemistry · 4 marks · −1

The gas phase reaction 2NO2(g)→N2O4(g)2NO_2(g) \rightarrow N_2O_4(g) is an exothermic reaction. The decomposition of N2O4N_2O_4, in equilibrium mixture of NO2(g)NO_2(g) and N2O4(g)N_2O_4(g), can be increased by :

  1. A.lowering the temperature.
  2. B.increasing the pressure.
  3. C.addition of an inert gas at constant volume.
  4. D.addition of an inert gas at constant pressure.

Correct answer: D

Question 33

Chemistry · 4 marks · −1

Assuming ideal gas behaviour, the ratio of density of ammonia to that of hydrogen chloride at same temperature and pressure is : (Atomic wt. of Cl = 35.5 u)

  1. A.1.46
  2. B.0.46
  3. C.1.64
  4. D.0.64

Correct answer: B

Question 34

Chemistry · 4 marks · −1

When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p-aminophenol produced is :

  1. A.9.81 g
  2. B.10.9 g
  3. C.98.1 g
  4. D.109.0 g

Correct answer: A

Question 35

Chemistry · 4 marks · −1

For which of the following processes, ΔS\Delta S is negative ?

  1. A.H2(g)→2H(g)H_2(g) \rightarrow 2H(g)
  2. B.N2(g,1 atm)→N2(g,5 atm)N_2(g, 1\text{ atm}) \rightarrow N_2(g, 5\text{ atm})
  3. C.C(diamond) →\rightarrow C(graphite)
  4. D.N2(g,273 K)→N2(g,300 K)N_2(g, 273\text{ K}) \rightarrow N_2(g, 300\text{ K})

Correct answer: B

Question 36

Chemistry · 4 marks · −1

Which one of the following is not a property of physical adsorption ?

  1. A.Higher the pressure, more the adsorption
  2. B.Lower the temperature, more the adsorption
  3. C.Greater the surface area, more the adsorption
  4. D.Unilayer adsorption occurs

Correct answer: D

Question 37

Chemistry · 4 marks · −1

If 50% of a reaction occurs in 100 second and 75% of the reaction occurs in 200 second, the order of this reaction is :

  1. A.Zero
  2. B.1
  3. C.2
  4. D.3

Correct answer: B

Question 38

Chemistry · 4 marks · −1

Which of the following statements is false ?

  1. A.Photon has momentum as well as wavelength.
  2. B.Splitting of spectral lines in electrical field is called Stark effect.
  3. C.Rydberg constant has unit of energy.
  4. D.Frequency of emitted radiation from a black body goes from a lower wavelength to higher wavelength as the temperature increases.

Correct answer: D

Question 39

Chemistry · 4 marks · −1

At 320 K, a gas A2A_2 is 20% dissociated to A(g). The standard free energy change at 320 K and 1 atm in J mol−1^{-1} is approximately : (R = 8.314 J K−1^{-1} mol−1^{-1}; ln 2 = 0.693; ln 3 = 1.098)

  1. A.4763
  2. B.2068
  3. C.1844
  4. D.4281

Correct answer: A

Question 40

Chemistry · 4 marks · −1

The incorrect statement is :

  1. A.Cu2+Cu^{2+} salts give red coloured borax bead test in reducing flame.
  2. B.Cu2+Cu^{2+} and Ni2+Ni^{2+} ions give black precipitate with H2SH_2S in presence of HCl solution.
  3. C.Ferric ion gives blood red colour with potassium thiocyanate.
  4. D.Cu2+Cu^{2+} ion gives chocolate coloured precipitate with potassium ferrocyanide solution.

Correct answer: B

Question 41

Chemistry · 4 marks · −1

The incorrect geometry is represented by :

  1. A.BF3BF_3 - trigonal planar
  2. B.H2OH_2O - bent
  3. C.NF3NF_3 - trigonal planar
  4. D.AsF5AsF_5 - trigonal bipyramidal

Correct answer: C

Question 42

Chemistry · 4 marks · −1

In Wilkinson's catalyst, the hybridization of central metal ion and its shape are respectively :

  1. A.sp3dsp^3d, trigonal bipyramidal
  2. B.sp3sp^3, tetrahedral
  3. C.dsp2dsp^2, square planar
  4. D.d2sp3d^2sp^3, octahedral

Correct answer: C

Question 43

Chemistry · 4 marks · −1

Among the oxides of nitrogen : N2O3N_2O_3, N2O4N_2O_4 and N2O5N_2O_5 ; the molecule(s) having nitrogen-nitrogen bond is/are :

  1. A.Only N2O5N_2O_5
  2. B.N2O3N_2O_3 and N2O5N_2O_5
  3. C.N2O4N_2O_4 and N2O5N_2O_5
  4. D.N2O3N_2O_3 and N2O4N_2O_4

Correct answer: D

Question 44

Chemistry · 4 marks · −1

Which of the following complexes will show geometrical isomerism ?

  1. A.aquachlorobis(ethylenediamine)cobalt(II) chloride
  2. B.pentaaquachlorochromium(III) chloride
  3. C.potassium amminetrichloroplatinate(II)
  4. D.potassium tris(oxalato)chromate(III)

Correct answer: A

Question 45

Chemistry · 4 marks · −1

In a complexometric titration of metal ion with ligand M(Metal ion) + L(Ligand) →\rightarrow C(Complex) end point is estimated spectrophotometrically (through light absorption). If 'M' and 'C' do not absorb light and only 'L' absorbs, then the titration plot between absorbed light (A) versus volume of ligand 'L' (V) would look like :

Figure for question 45
  1. A.Graph (1): A decreases linearly with V to a minimum at the end point, then increases linearly (V-shaped)
  2. B.Graph (2): A stays constant (flat, near zero) up to the end point, then increases linearly
  3. C.Graph (3): A increases linearly to a maximum at the end point, then decreases linearly (inverted V)
  4. D.Graph (4): A decreases linearly up to the end point, then stays constant

Correct answer: B

Question 46

Chemistry · 4 marks · −1

In the extraction of copper from its sulphide ore, metal is finally obtained by the oxidation of cuprous sulphide with :

  1. A.Fe2O3Fe_2O_3
  2. B.Cu2OCu_2O
  3. C.SO2SO_2
  4. D.CO

Correct answer: B

Question 47

Chemistry · 4 marks · −1

Which of the following conversions involves change in both shape and hybridisation ?

  1. A.NH3→NH4+NH_3 \rightarrow NH_4^+
  2. B.CH4→C2H6CH_4 \rightarrow C_2H_6
  3. C.H2O→H3O+H_2O \rightarrow H_3O^+
  4. D.BF3→BF4−BF_3 \rightarrow BF_4^-

Correct answer: D

Question 48

Chemistry · 4 marks · −1

A group 13 element 'X' reacts with chlorine gas to produce a compound XCl3XCl_3. XCl3XCl_3 is electron deficient and easily reacts with NH3NH_3 to form Cl3X←NH3Cl_3X \leftarrow NH_3 adduct; however, XCl3XCl_3 does not dimerize. X is :

  1. A.B
  2. B.Al
  3. C.Ga
  4. D.In

Correct answer: A

Question 49

Chemistry · 4 marks · −1

When XO2XO_2 is fused with an alkali metal hydroxide in presence of an oxidizing agent such as KNO3KNO_3; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. X is :

  1. A.Ti
  2. B.V
  3. C.Cr
  4. D.Mn

Correct answer: D

Question 50

Chemistry · 4 marks · −1

The major product of the following reaction is : C6H5−CH=CHCH3→HBrC_6H_5-CH=CHCH_3 \xrightarrow{HBr}

Figure for question 50
  1. A.C6H5−CH(Br)CH2CH3C_6H_5-CH(Br)CH_2CH_3
  2. B.C6H5−CH2CH(Br)CH3C_6H_5-CH_2CH(Br)CH_3
  3. C.C6H5−CH2CH2CH2BrC_6H_5-CH_2CH_2CH_2Br
  4. D.pp-Br−C6H4−CH=CHCH3Br-C_6H_4-CH=CHCH_3 (ring-brominated)

Correct answer: A

Question 51

Chemistry · 4 marks · −1

For standardizing NaOH solution, which of the following is used as a primary standard ?

  1. A.Ferrous Ammonium Sulfate
  2. B.dil. HCl
  3. C.Oxalic acid
  4. D.Sodium tetraborate

Correct answer: C

Question 52

Chemistry · 4 marks · −1

The most polar compound among the following is :

Figure for question 52
  1. A.1-Fluoro-3-(1-fluoroethylidene)cyclohex-1-ene, geometric isomer drawn in option (1) (exocyclic F drawn to the right, pointing up)
  2. B.1,4-Difluoro-3-(propan-2-ylidene)cyclohex-1-ene (ring vinylic F plus an sp3^3 C-F, exocyclic =C(CH3)2=C(CH_3)_2)
  3. C.1-Fluoro-3-(1-fluoroethylidene)cyclohex-1-ene, the other geometric isomer (exocyclic F drawn pointing down)
  4. D.1-Methyl-3-(propan-2-ylidene)cyclohex-1-ene (no fluorine)

Correct answer: A

Question 53

Chemistry · 4 marks · −1

The correct match between items of List - I and List - II is : List - I: (A) Phenelzine (B) Chloroxylenol (C) Uracil (D) Ranitidine. List - II: (P) Pyrimidine (Q) Furan (R) Hydrazine (S) Phenol

  1. A.(A)-(R), (B)-(S), (C)-(P), (D)-(Q)
  2. B.(A)-(S), (B)-(R), (C)-(P), (D)-(Q)
  3. C.(A)-(S), (B)-(R), (C)-(Q), (D)-(P)
  4. D.(A)-(R), (B)-(S), (C)-(Q), (D)-(P)

Correct answer: A

Question 54

Chemistry · 4 marks · −1

Among the following, the incorrect statement is :

  1. A.Maltose and lactose has 1,4-glycosidic linkage.
  2. B.Sucrose and amylose has 1,2-glycosidic linkage.
  3. C.Cellulose and amylose has 1,4-glycosidic linkage.
  4. D.Lactose contains β\beta-D-galactose and β\beta-D-glucose.

Correct answer: B

Question 55

Chemistry · 4 marks · −1

Which of the following compounds will most readily be dehydrated to give alkene under acidic condition ?

  1. A.1-Pentanol
  2. B.4-Hydroxypentan-2-one
  3. C.3-Hydroxypentan-2-one
  4. D.2-Hydroxycyclopentanone

Correct answer: B

Question 56

Chemistry · 4 marks · −1

Products A and B formed in the following reactions are respectively : pp-HO3S−C6H4−N+H3 CH3COO−+HNO2→A→C6H5NH2BHO_3S-C_6H_4-\overset{+}{N}H_3\ CH_3CO\overset{-}{O} + HNO_2 \rightarrow A \xrightarrow{C_6H_5NH_2} B

Figure for question 56
  1. A.A = pp-HO3S−C6H4−N=N−COCH3HO_3S-C_6H_4-N=N-COCH_3 ; B = pp-HO3S−C6H4−N=N−C6H5HO_3S-C_6H_4-N=N-C_6H_5
  2. B.A = pp-HO3S−C6H4−N=N−COCH3HO_3S-C_6H_4-N=N-COCH_3 ; B = HO3S−C6H4−NH−C6H4−NH2HO_3S-C_6H_4-NH-C_6H_4-NH_2
  3. C.A = pp-HO3S−C6H4−N=N−OCOCH3HO_3S-C_6H_4-N=N-OCOCH_3 ; B = pp-HO3S−C6H4−N=N−NH−C6H5HO_3S-C_6H_4-N=N-NH-C_6H_5
  4. D.A = pp-HO3S−C6H4−N=N−OCOCH3HO_3S-C_6H_4-N=N-OCOCH_3 ; B = pp-HO3S−C6H4−N=N−C6H4−NH2HO_3S-C_6H_4-N=N-C_6H_4-NH_2 (pp-amino azo compound)

Correct answer: D

Question 57

Chemistry · 4 marks · −1

The major product B formed in the following reaction sequence is : pp-MeO−C6H4−CHO→(ii) H2O(i) C2H5MgBrA→HClBMeO-C_6H_4-CHO \xrightarrow[\text{(ii) } H_2O]{\text{(i) } C_2H_5MgBr} A \xrightarrow{HCl} B

Figure for question 57
  1. A.pp-Cl−C6H4−CH2CH(Cl)CH3Cl-C_6H_4-CH_2CH(Cl)CH_3
  2. B.pp-MeO−C6H4−CH(Cl)CH2CH3MeO-C_6H_4-CH(Cl)CH_2CH_3
  3. C.pp-MeO−C6H4−CH=CHCH3MeO-C_6H_4-CH=CHCH_3
  4. D.pp-MeO−C6H4−CH2CH=CH2MeO-C_6H_4-CH_2CH=CH_2

Correct answer: B

Question 58

Chemistry · 4 marks · −1

The major product of the following reaction is : [(E)-hex-3-ene chain with Br on C-2 (wedge) and NH2NH_2 on C-5 (hashed), treated with KOH (SN2S_N2)]

Figure for question 58
  1. A.Hex-3-ene chain drawn with H2NH_2N on a bold wedge at the left end carbon and OH on a bold wedge at the right end carbon
  2. B.Chain drawn with OH on a bold wedge at the left end carbon and NH2NH_2 on a hashed bond at the right end carbon (same drawing as the substrate with Br replaced by OH)
  3. C.Chain drawn with H2NH_2N on a bold wedge at the left end carbon and OH on a hashed bond at the right end carbon
  4. D.Chain drawn with OH on a hashed bond at the left end carbon and NH2NH_2 on a bold wedge at the right end carbon

Correct answer: C

Question 59

Chemistry · 4 marks · −1

The major product of the following reaction is : 3-methoxyphenol →(ii) H2SO4, heat(i) OHC CH2COCl\xrightarrow[\text{(ii) } H_2SO_4,\ \text{heat}]{\text{(i) } OHC\,CH_2COCl}

Figure for question 59
  1. A.7-Methoxy-2H-chromen-2-one (7-methoxycoumarin)
  2. B.7-Methoxy-4H-chromen-4-one (7-methoxychromone)
  3. C.5-Methoxy-2H-chromen-2-one (5-methoxycoumarin)
  4. D.5-Methoxy-4H-chromen-4-one (5-methoxychromone)

Correct answer: A

Question 60

Mathematics · 4 marks · −1

Let N\mathbb{N} denote the set of all natural numbers. Define two binary relations on N\mathbb{N} as R1={(x,y)∈N×N:2x+y=10}R_1 = \{(x, y) \in \mathbb{N}\times\mathbb{N} : 2x + y = 10\} and R2={(x,y)∈N×N:x+2y=10}R_2 = \{(x, y) \in \mathbb{N}\times\mathbb{N} : x + 2y = 10\}. Then :

  1. A.Range of R1R_1 is {2,4,8}\{2, 4, 8\}.
  2. B.Range of R2R_2 is {1,2,3,4}\{1, 2, 3, 4\}.
  3. C.Both R1R_1 and R2R_2 are symmetric relations.
  4. D.Both R1R_1 and R2R_2 are transitive relations.

Correct answer: B

Question 61

Mathematics · 4 marks · −1

Let p, q and r be real numbers (p≠q,r≠0)(p \ne q, r \ne 0), such that the roots of the equation 1x+p+1x+q=1r\frac{1}{x+p} + \frac{1}{x+q} = \frac{1}{r} are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :

  1. A.p2+q22\frac{p^2+q^2}{2}
  2. B.p2+q2p^2 + q^2
  3. C.2(p2+q2)2(p^2 + q^2)
  4. D.p2+q2+r2p^2 + q^2 + r^2

Correct answer: B

Question 62

Mathematics · 4 marks · −1

The least positive integer n for which (1+i31−i3)n=1\left(\frac{1+i\sqrt{3}}{1-i\sqrt{3}}\right)^n = 1, is :

  1. A.2
  2. B.3
  3. C.5
  4. D.6

Correct answer: B

Question 63

Mathematics · 4 marks · −1

Let A=[100110111]A = \begin{bmatrix}1 & 0 & 0\\ 1 & 1 & 0\\ 1 & 1 & 1\end{bmatrix} and B=A20B = A^{20}. Then the sum of the elements of the first column of B is :

  1. A.210
  2. B.211
  3. C.231
  4. D.251

Correct answer: C

Question 64

Mathematics · 4 marks · −1

The number of values of k for which the system of linear equations, (k+2)x+10y=k(k + 2)x + 10y = k, kx+(k+3)y=k−1kx + (k + 3)y = k - 1 has no solution, is :

  1. A.1
  2. B.2
  3. C.3
  4. D.infinitely many

Correct answer: A

Question 65

Mathematics · 4 marks · −1

The number of numbers between 2,000 and 5,000 that can be formed with the digits 0, 1, 2, 3, 4 (repetition of digits is not allowed) and are multiple of 3 is :

  1. A.24
  2. B.30
  3. C.36
  4. D.48

Correct answer: B

Question 66

Mathematics · 4 marks · −1

The coefficient of x2x^2 in the expansion of the product (2−x2)⋅((1+2x+3x2)6+(1−4x2)6)(2 - x^2)\cdot\left((1 + 2x + 3x^2)^6 + (1 - 4x^2)^6\right) is :

  1. A.107
  2. B.106
  3. C.108
  4. D.155

Correct answer: B

Question 67

Mathematics · 4 marks · −1

Let 1x1,1x2,…,1xn\frac{1}{x_1}, \frac{1}{x_2}, \ldots, \frac{1}{x_n} (xi≠0(x_i \ne 0 for i=1,2,…,n)i = 1, 2, \ldots, n) be in A.P. such that x1=4x_1 = 4 and x21=20x_{21} = 20. If n is the least positive integer for which xn>50x_n > 50, then ∑i=1n(1xi)\sum_{i=1}^{n}\left(\frac{1}{x_i}\right) is equal to :

  1. A.18\frac{1}{8}
  2. B.3
  3. C.138\frac{13}{8}
  4. D.134\frac{13}{4}

Correct answer: D

Question 68

Mathematics · 4 marks · −1

The sum of the first 20 terms of the series 1+32+74+158+3116+…1 + \frac{3}{2} + \frac{7}{4} + \frac{15}{8} + \frac{31}{16} + \ldots, is :

  1. A.38+121938 + \frac{1}{2^{19}}
  2. B.38+122038 + \frac{1}{2^{20}}
  3. C.39+122039 + \frac{1}{2^{20}}
  4. D.39+121939 + \frac{1}{2^{19}}

Correct answer: A

Question 69

Mathematics · 4 marks · −1

lim⁡x→0(27+x)1/3−39−(27+x)2/3\lim_{x\to0}\frac{(27+x)^{1/3} - 3}{9 - (27+x)^{2/3}} equals :

  1. A.13\frac{1}{3}
  2. B.−13-\frac{1}{3}
  3. C.−16-\frac{1}{6}
  4. D.16\frac{1}{6}

Correct answer: C

Question 70

Mathematics · 4 marks · −1

If the function f defined as f(x)=1x−k−1e2x−1f(x) = \frac{1}{x} - \frac{k-1}{e^{2x}-1}, x≠0x \ne 0, is continuous at x=0x = 0, then the ordered pair (k,f(0))(k, f(0)) is equal to :

  1. A.(3, 2)
  2. B.(3, 1)
  3. C.(2, 1)
  4. D.(13,2)\left(\frac{1}{3}, 2\right)

Correct answer: B

Question 71

Mathematics · 4 marks · −1

If x=2cosec−1tx = \sqrt{2^{\text{cosec}^{-1}t}} and y=2sec⁡−1ty = \sqrt{2^{\sec^{-1}t}} (∣t∣≥1)(|t| \ge 1), then dydx\frac{dy}{dx} is equal to :

  1. A.yx\frac{y}{x}
  2. B.xy\frac{x}{y}
  3. C.−yx-\frac{y}{x}
  4. D.−xy-\frac{x}{y}

Correct answer: C

Question 72

Mathematics · 4 marks · −1

Let M and m be respectively the absolute maximum and the absolute minimum values of the function, f(x)=2x3−9x2+12x+5f(x) = 2x^3 - 9x^2 + 12x + 5 in the interval [0, 3]. Then M−mM - m is equal to :

  1. A.5
  2. B.9
  3. C.4
  4. D.1

Correct answer: B

Question 73

Mathematics · 4 marks · −1

If ∫tan⁡x1+tan⁡x+tan⁡2xdx=x−KAtan⁡−1(Ktan⁡x+1A)+C\int\frac{\tan x}{1 + \tan x + \tan^2 x}dx = x - \frac{K}{\sqrt{A}}\tan^{-1}\left(\frac{K\tan x + 1}{\sqrt{A}}\right) + C, (C is a constant of integration), then the ordered pair (K, A) is equal to :

  1. A.(2, 1)
  2. B.(−2,3)(-2, 3)
  3. C.(2, 3)
  4. D.(−2,1)(-2, 1)

Correct answer: C

Question 74

Mathematics · 4 marks · −1

If f(x)=∫0xt(sin⁡x−sin⁡t) dtf(x) = \int_0^x t(\sin x - \sin t)\,dt then :

  1. A.f′′′(x)+f′′(x)=sin⁡xf'''(x) + f''(x) = \sin x
  2. B.f′′′(x)+f′′(x)−f′(x)=cos⁡xf'''(x) + f''(x) - f'(x) = \cos x
  3. C.f′′′(x)+f′(x)=cos⁡x−2xsin⁡xf'''(x) + f'(x) = \cos x - 2x\sin x
  4. D.f′′′(x)−f′′(x)=cos⁡x−2xsin⁡xf'''(x) - f''(x) = \cos x - 2x\sin x

Correct answer: C

Question 75

Mathematics · 4 marks · −1

If the area of the region bounded by the curves, y=x2y = x^2, y=1xy = \frac{1}{x} and the lines y=0y = 0 and x=tx = t (t>1)(t > 1) is 1 sq. unit, then t is equal to :

  1. A.e3/2e^{3/2}
  2. B.43\frac{4}{3}
  3. C.32\frac{3}{2}
  4. D.e2/3e^{2/3}

Correct answer: D

Question 76

Mathematics · 4 marks · −1

The differential equation representing the family of ellipses having foci either on the x-axis or on the y-axis, centre at the origin and passing through the point (0, 3) is :

  1. A.xyy′′+x(y′)2−yy′=0xyy'' + x(y')^2 - yy' = 0
  2. B.x+yy′′=0x + yy'' = 0
  3. C.xyy′+y2−9=0xyy' + y^2 - 9 = 0
  4. D.xyy′−y2+9=0xyy' - y^2 + 9 = 0

Correct answer: D

Question 77

Mathematics · 4 marks · −1

The locus of the point of intersection of the lines, 2x−y+42k=0\sqrt{2}x - y + 4\sqrt{2}k = 0 and 2kx+ky−42=0\sqrt{2}kx + ky - 4\sqrt{2} = 0 (k is any non-zero real parameter), is :

  1. A.an ellipse whose eccentricity is 13\frac{1}{\sqrt{3}}.
  2. B.an ellipse with length of its major axis 828\sqrt{2}.
  3. C.a hyperbola whose eccentricity is 3\sqrt{3}.
  4. D.a hyperbola with length of its transverse axis 828\sqrt{2}.

Correct answer: D

Question 78

Mathematics · 4 marks · −1

If a circle C, whose radius is 3, touches externally the circle, x2+y2+2x−4y−4=0x^2 + y^2 + 2x - 4y - 4 = 0 at the point (2, 2), then the length of the intercept cut by this circle C, on the x-axis is equal to :

  1. A.252\sqrt{5}
  2. B.323\sqrt{2}
  3. C.5\sqrt{5}
  4. D.232\sqrt{3}

Correct answer: A

Question 79

Mathematics · 4 marks · −1

Let P be a point on the parabola, x2=4yx^2 = 4y. If the distance of P from the centre of the circle, x2+y2+6x+8=0x^2 + y^2 + 6x + 8 = 0 is minimum, then the equation of the tangent to the parabola at P, is :

  1. A.x+4y−2=0x + 4y - 2 = 0
  2. B.x−y+3=0x - y + 3 = 0
  3. C.x+y+1=0x + y + 1 = 0
  4. D.x+2y=0x + 2y = 0

Correct answer: C

Question 80

Mathematics · 4 marks · −1

If the length of the latus rectum of an ellipse is 4 units and the distance between a focus and its nearest vertex on the major axis is 32\frac{3}{2} units, then its eccentricity is :

  1. A.12\frac{1}{2}
  2. B.13\frac{1}{3}
  3. C.23\frac{2}{3}
  4. D.19\frac{1}{9}

Correct answer: B

Question 81

Mathematics · 4 marks · −1

The sum of the intercepts on the coordinate axes of the plane passing through the point (−2,−2,2)(-2, -2, 2) and containing the line joining the points (1,−1,2)(1, -1, 2) and (1,1,1)(1, 1, 1), is :

  1. A.4
  2. B.−4-4
  3. C.−8-8
  4. D.12

Correct answer: B

Question 82

Mathematics · 4 marks · −1

If the angle between the lines, x2=y2=z1\frac{x}{2} = \frac{y}{2} = \frac{z}{1} and 5−x−2=7y−14p=z−34\frac{5-x}{-2} = \frac{7y-14}{p} = \frac{z-3}{4} is cos⁡−1(23)\cos^{-1}\left(\frac{2}{3}\right), then p is equal to :

  1. A.72\frac{7}{2}
  2. B.27\frac{2}{7}
  3. C.−74-\frac{7}{4}
  4. D.−47-\frac{4}{7}

Correct answer: A

Question 83

Mathematics · 4 marks · −1

Let a⃗=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, c⃗=j^−k^\vec{c} = \hat{j} - \hat{k} and a vector b⃗\vec{b} be such that a⃗×b⃗=c⃗\vec{a}\times\vec{b} = \vec{c} and a⃗⋅b⃗=3\vec{a}\cdot\vec{b} = 3. Then ∣b⃗∣|\vec{b}| equals :

  1. A.113\frac{11}{3}
  2. B.113\frac{11}{\sqrt{3}}
  3. C.113\sqrt{\frac{11}{3}}
  4. D.113\frac{\sqrt{11}}{3}

Correct answer: C

Question 84

Mathematics · 4 marks · −1

The mean and the standard deviation (s.d.) of five observations are 9 and 0, respectively. If one of the observations is changed such that the mean of the new set of five observations becomes 10, then their s.d. is :

  1. A.0
  2. B.1
  3. C.2
  4. D.4

Correct answer: C

Question 85

Mathematics · 4 marks · −1

Let A, B and C be three events, which are pair-wise independent and E‾\overline{E} denotes the complement of an event E. If P(A∩B∩C)=0P(A\cap B\cap C) = 0 and P(C)>0P(C) > 0, then P[(A‾∩B‾) ∣ C]P\left[(\overline{A}\cap\overline{B})\,|\,C\right] is equal to :

  1. A.P(A‾)−P(B)P(\overline{A}) - P(B)
  2. B.P(A)+P(B‾)P(A) + P(\overline{B})
  3. C.P(A‾)−P(B‾)P(\overline{A}) - P(\overline{B})
  4. D.P(A‾)+P(B‾)P(\overline{A}) + P(\overline{B})

Correct answer: A

Question 86

Mathematics · 4 marks · −1

Two different families A and B are blessed with equal number of children. There are 3 tickets to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is 112\frac{1}{12}, then the number of children in each family is :

  1. A.3
  2. B.4
  3. C.5
  4. D.6

Correct answer: C

Question 87

Mathematics · 4 marks · −1

If an angle A of a ΔABC\Delta ABC satisfies 5cos⁡A+3=05\cos A + 3 = 0, then the roots of the quadratic equation, 9x2+27x+20=09x^2 + 27x + 20 = 0 are :

  1. A.sec⁡A\sec A, cot⁡A\cot A
  2. B.sin⁡A\sin A, sec⁡A\sec A
  3. C.sec⁡A\sec A, tan⁡A\tan A
  4. D.tan⁡A\tan A, cos⁡A\cos A

Correct answer: C

Question 88

Mathematics · 4 marks · −1

A man on the top of a vertical tower observes a car moving at a uniform speed towards the tower on a horizontal road. If it takes 18 min. for the angle of depression of the car to change from 30∘30^\circ to 45∘45^\circ; then after this, the time taken (in min.) by the car to reach the foot of the tower, is :

  1. A.9(1+3)9(1+\sqrt{3})
  2. B.18(1+3)18(1+\sqrt{3})
  3. C.18(3−1)18(\sqrt{3}-1)
  4. D.92(3−1)\frac{9}{2}(\sqrt{3}-1)

Correct answer: A

Question 89

Mathematics · 4 marks · −1

If p→(∼p∨∼q)p \rightarrow (\sim p \vee \sim q) is false, then the truth values of p and q are respectively :

  1. A.F, F
  2. B.T, F
  3. C.F, T
  4. D.T, T

Correct answer: D

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