JEE Main 2019 — 8 Apr Shift 2 (Previous Year Paper)

JEE Main · 2019 · with answers and explanations

questions
85
Total marks
340
Duration
180 minutes
Negative marking
−1

Subjects: Physics · Chemistry · Mathematics

Question 1

Physics · 4 marks · −1

If Surface tension (S), Moment of Inertia (I) and Planck's constant (h), were to be taken as the fundamental units, the dimensional formula for linear momentum would be:

  1. A.S1/2I1/2h0S^{1/2}I^{1/2}h^0
  2. B.S3/2I1/2h0S^{3/2}I^{1/2}h^0
  3. C.S1/2I3/2h−1S^{1/2}I^{3/2}h^{-1}
  4. D.S1/2I1/2h−1S^{1/2}I^{1/2}h^{-1}

Correct answer: A

Question 2

Physics · 4 marks · −1

Let ∣A⃗1∣=3|\vec{A}_1| = 3, ∣A⃗2∣=5|\vec{A}_2| = 5 and ∣A⃗1+A⃗2∣=5|\vec{A}_1 + \vec{A}_2| = 5. The value of (2A⃗1+3A⃗2)⋅(3A⃗1−2A⃗2)(2\vec{A}_1 + 3\vec{A}_2)\cdot(3\vec{A}_1 - 2\vec{A}_2) is:

  1. A.−99.5
  2. B.−106.5
  3. C.−112.5
  4. D.−118.5

Correct answer: D

Question 3

Physics · 4 marks · −1

A body of mass m1m_1 moving with an unknown velocity of v1i^v_1\hat{i}, undergoes a collinear collision with a body of mass m2m_2 moving with a velocity v2i^v_2\hat{i}. After collision, m1m_1 and m2m_2 move with velocities of v3i^v_3\hat{i} and v4i^v_4\hat{i}, respectively. If m2=0.5m1m_2 = 0.5m_1 and v3=0.5v1v_3 = 0.5v_1, then v1v_1 is:

  1. A.v4−v2v_4 - v_2
  2. B.v4−v22v_4 - \dfrac{v_2}{2}
  3. C.v4+v2v_4 + v_2
  4. D.v4−v24v_4 - \dfrac{v_2}{4}

Correct answer: A

Question 4

Physics · 4 marks · −1

A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity (see figure). Both roll without slipping all throughout. The two climb maximum heights hsphh_{sph} and hcylh_{cyl} on the incline. The ratio hsphhcyl\dfrac{h_{sph}}{h_{cyl}} is given by:

Figure for question 4
  1. A.1
  2. B.25\dfrac{2}{\sqrt{5}}
  3. C.1415\dfrac{14}{15}
  4. D.45\dfrac{4}{5}

Correct answer: C

Question 5

Physics · 4 marks · −1

A uniform rectangular thin sheet ABCD of mass M has length a and breadth b, as shown in the figure. If the shaded portion HBGO is cut-off, the coordinates of the centre of mass of the remaining portion will be:

Figure for question 5
  1. A.(5a12,5b12)\left(\dfrac{5a}{12}, \dfrac{5b}{12}\right)
  2. B.(5a3,5b3)\left(\dfrac{5a}{3}, \dfrac{5b}{3}\right)
  3. C.(3a4,3b4)\left(\dfrac{3a}{4}, \dfrac{3b}{4}\right)
  4. D.(2a3,2b3)\left(\dfrac{2a}{3}, \dfrac{2b}{3}\right)

Correct answer: A

Question 6

Physics · 4 marks · −1

A rocket has to be launched from earth in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher, what should be the minimum energy that the launcher should have if the same rocket is to be launched from the surface of the moon? Assume that the density of the earth and the moon are equal and that the earth's volume is 64 times the volume of the moon.

  1. A.E64\dfrac{E}{64}
  2. B.E32\dfrac{E}{32}
  3. C.E16\dfrac{E}{16}
  4. D.E4\dfrac{E}{4}

Correct answer: C

Question 7

Physics · 4 marks · −1

Young's moduli of two wires A and B are in the ratio 7 : 4. Wire A is 2 m long and has radius R. Wire B is 1.5 m long and has radius 2 mm. If the two wires stretch by the same length for a given load, then the value of R is close to:

  1. A.1.3 mm
  2. B.1.5 mm
  3. C.1.7 mm
  4. D.1.9 mm

Correct answer: C

Question 8

Physics · 4 marks · −1

The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by:

Figure for question 8
  1. A.d a c b
  2. B.a d b c
  3. C.a d c b
  4. D.d a b c

Correct answer: D

Question 9

Physics · 4 marks · −1

The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to: [Boltzmann Constant kB=1.38×10−23k_B = 1.38\times10^{-23} J/K, Avogadro Number NA=6.02×1026N_A = 6.02\times10^{26} /kg, Radius of Earth: 6.4×1066.4\times10^6 m, Gravitational acceleration on Earth = 10 m s−2^{-2}]

  1. A.800 K
  2. B.650 K
  3. C.10410^4 K
  4. D.3×1053\times10^5 K

Correct answer: C

Question 10

Physics · 4 marks · −1

A damped harmonic oscillator has a frequency of 5 oscillations per second. The amplitude drops to half its value for every 10 oscillations. The time it will take to drop to 11000\dfrac{1}{1000} of the original amplitude is close to:

  1. A.100 s
  2. B.50 s
  3. C.20 s
  4. D.10 s

Correct answer: C

Question 11

Physics · 4 marks · −1

An electric dipole is formed by two equal and opposite charges q with separation d. The charges have same mass m. It is kept in a uniform electric field E. If it is slightly rotated from its equilibrium orientation, then its angular frequency ω\omega is:

  1. A.qE2md\sqrt{\dfrac{qE}{2md}}
  2. B.2qEmd\sqrt{\dfrac{2qE}{md}}
  3. C.qEmd\sqrt{\dfrac{qE}{md}}
  4. D.2qEmd2\sqrt{\dfrac{qE}{md}}

Correct answer: B

Question 12

Physics · 4 marks · −1

A parallel plate capacitor has 1 μF capacitance. One of its two plates is given +2 μC charge and the other plate, +4 μC charge. The potential difference developed across the capacitor is:

  1. A.1 V
  2. B.5 V
  3. C.2 V
  4. D.3 V

Correct answer: A

Question 13

Physics · 4 marks · −1

A positive point charge is released from rest at a distance r0r_0 from a positive line charge with uniform density. The speed (vv) of the point charge, as a function of instantaneous distance r from line charge, is proportional to:

Figure for question 13
  1. A.v∝ln⁡(rr0)v \propto \ln\left(\dfrac{r}{r_0}\right)
  2. B.v∝(rr0)v \propto \left(\dfrac{r}{r_0}\right)
  3. C.v∝ln⁡(rr0)v \propto \sqrt{\ln\left(\dfrac{r}{r_0}\right)}
  4. D.v∝e+r/r0v \propto e^{+r/r_0}

Correct answer: C

Question 14

Physics · 4 marks · −1

The electric field in a region is given by E⃗=(Ax+B)i^\vec{E} = (Ax + B)\hat{i}, where E is in N C−1^{-1} and x is in metres. The values of constants are A = 20 SI unit and B = 10 SI unit. If the potential at x = 1 is V1V_1 and that at x = −5 is V2V_2, then V1−V2V_1 - V_2 is:

  1. A.−520 V
  2. B.320 V
  3. C.180 V
  4. D.−48 V

Correct answer: C

Question 15

Physics · 4 marks · −1

A cell of internal resistance r drives current through an external resistance R. The power delivered by the cell to the external resistance will be maximum when:

  1. A.R = 1000 r
  2. B.R = 0.001 r
  3. C.R = r
  4. D.R = 2r

Correct answer: C

Question 16

Physics · 4 marks · −1

In the figure shown, what is the current (in Ampere) drawn from the battery? You are given: R1=15 ΩR_1 = 15\ \Omega, R2=10 ΩR_2 = 10\ \Omega, R3=20 ΩR_3 = 20\ \Omega, R4=5 ΩR_4 = 5\ \Omega, R5=25 ΩR_5 = 25\ \Omega, R6=30 ΩR_6 = 30\ \Omega, E = 15 V

Figure for question 16
  1. A.9/32
  2. B.13/24
  3. C.20/3
  4. D.7/18

Correct answer: A

Question 17

Physics · 4 marks · −1

Two very long, straight, and insulated wires are kept at 90° angle from each other in xy-plane as shown in the figure. These wires carry currents of equal magnitude I, whose directions are shown in the figure. The net magnetic field at point P will be:

Figure for question 17
  1. A.μ0I2πd(x^+y^)\dfrac{\mu_0 I}{2\pi d}(\hat{x} + \hat{y})
  2. B.−μ0I2πd(x^+y^)-\dfrac{\mu_0 I}{2\pi d}(\hat{x} + \hat{y})
  3. C.+μ0Iπd(z^)+\dfrac{\mu_0 I}{\pi d}(\hat{z})
  4. D.Zero

Correct answer: D

Question 18

Physics · 4 marks · −1

Two magnetic dipoles X and Y are placed at a separation d, with their axes perpendicular to each other. The dipole moment of Y is twice that of X. A particle of charge q is passing through their mid-point P, at angle θ=45°\theta = 45° with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant? (d is much larger than the dimensions of the dipole)

Figure for question 18
  1. A.(μ04π)2M(d/2)3×qv\left(\dfrac{\mu_0}{4\pi}\right)\dfrac{2M}{(d/2)^3}\times qv
  2. B.(μ04π)M(d/2)3×qv\left(\dfrac{\mu_0}{4\pi}\right)\dfrac{M}{(d/2)^3}\times qv
  3. C.0
  4. D.2(μ04π)M(d/2)3×qv\sqrt{2}\left(\dfrac{\mu_0}{4\pi}\right)\dfrac{M}{(d/2)^3}\times qv

Correct answer: C

Question 19

Physics · 4 marks · −1

A circuit connected to an ac source of emf e=e0sin⁡(100t)e = e_0\sin(100t) with t in seconds, gives a phase difference of π4\dfrac{\pi}{4} between the emf e and current i. Which of the following circuits will exhibit this?

  1. A.RC circuit with R = 1 kΩ and C = 1 μF
  2. B.RC circuit with R = 1 kΩ and C = 10 μF
  3. C.RL circuit with R = 1 kΩ and L = 10 mH
  4. D.RL circuit with R = 1 kΩ and L = 1 mH

Correct answer: B

Question 20

Physics · 4 marks · −1

The magnetic field of an electromagnetic wave is given by: B⃗=1.6×10−6cos⁡(2×107z+6×1015t)(2i^+j^) Wbm2\vec{B} = 1.6\times10^{-6}\cos(2\times10^7 z + 6\times10^{15} t)(2\hat{i} + \hat{j})\ \dfrac{\text{Wb}}{\text{m}^2}. The associated electric field will be:

  1. A.E⃗=4.8×102cos⁡(2×107z+6×1015t)(−i^+2j^) Vm\vec{E} = 4.8\times10^2\cos(2\times10^7 z + 6\times10^{15} t)(-\hat{i} + 2\hat{j})\ \frac{\text{V}}{\text{m}}
  2. B.E⃗=4.8×102cos⁡(2×107z−6×1015t)(−2j^+i^) Vm\vec{E} = 4.8\times10^2\cos(2\times10^7 z - 6\times10^{15} t)(-2\hat{j} + \hat{i})\ \frac{\text{V}}{\text{m}}
  3. C.E⃗=4.8×102cos⁡(2×107z+6×1015t)(i^−2j^) Vm\vec{E} = 4.8\times10^2\cos(2\times10^7 z + 6\times10^{15} t)(\hat{i} - 2\hat{j})\ \frac{\text{V}}{\text{m}}
  4. D.E⃗=4.8×102cos⁡(2×107z−6×1015t)(2i^+j^) Vm\vec{E} = 4.8\times10^2\cos(2\times10^7 z - 6\times10^{15} t)(2\hat{i} + \hat{j})\ \frac{\text{V}}{\text{m}}

Correct answer: A

Question 21

Physics · 4 marks · −1

A convex lens (of focal length 20 cm) and a concave mirror, having their principal axes along the same lines, are kept 80 cm apart from each other. The concave mirror is to the right of the convex lens. When an object is kept at a distance of 30 cm to the left of the convex lens, its image remains at the same position even if the concave mirror is removed. The maximum distance of the object for which this concave mirror, by itself would produce a virtual image would be:

  1. A.30 cm
  2. B.25 cm
  3. C.20 cm
  4. D.10 cm

Correct answer: D

Question 22

Physics · 4 marks · −1

Calculate the limit of resolution of a telescope objective having a diameter of 200 cm, if it has to detect light of wavelength 500 nm coming from a star.

  1. A.152.5×10−9152.5\times10^{-9} radian
  2. B.457.5×10−9457.5\times10^{-9} radian
  3. C.610×10−9610\times10^{-9} radian
  4. D.305×10−9305\times10^{-9} radian

Correct answer: D

Question 23

Physics · 4 marks · −1

A nucleus A, with a finite de-broglie wavelength λA\lambda_A, undergoes spontaneous fission into two nuclei B and C of equal mass. B flies in the same direction as that of A, while C flies in the opposite direction with a velocity equal to half of that of B. The de-Broglie wavelengths λB\lambda_B and λC\lambda_C of B and C are respectively:

  1. A.2λA,λA2\lambda_A, \lambda_A
  2. B.λA,2λA\lambda_A, 2\lambda_A
  3. C.λA2,λA\dfrac{\lambda_A}{2}, \lambda_A
  4. D.λA,λA2\lambda_A, \dfrac{\lambda_A}{2}

Correct answer: C

Question 24

Physics · 4 marks · −1

The ratio of mass densities of nuclei of 40^{40}Ca and 16^{16}O is close to:

  1. A.0.1
  2. B.5
  3. C.2
  4. D.1

Correct answer: D

Question 25

Physics · 4 marks · −1

A common emitter amplifier circuit, built using an npn transistor, is shown in the figure. Its dc current gain is 250, RC=1R_C = 1 kΩ and VCC=10V_{CC} = 10 V. What is the minimum base current for VCEV_{CE} to reach saturation?

Figure for question 25
  1. A.10 μA
  2. B.40 μA
  3. C.7 μA
  4. D.100 μA

Correct answer: B

Question 26

Physics · 4 marks · −1

In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70 m, then the minimum height of the transmitting antenna should be: (Radius of the Earth = 6.4×1066.4\times10^6 m).

  1. A.40 m
  2. B.32 m
  3. C.51 m
  4. D.20 m

Correct answer: B

Question 27

Physics · 4 marks · −1

In the circuit shown, a four-wire potentiometer is made of a 400 cm long wire, which extends between A and B. The resistance per unit length of the potentiometer wire is r = 0.01 Ω/cm. If an ideal voltmeter is connected as shown with jockey J at 50 cm from end A, the expected reading of the voltmeter will be:

Figure for question 27
  1. A.0.25 V
  2. B.0.20 V
  3. C.0.50 V
  4. D.0.75 V

Correct answer: A

Question 28

Physics · 4 marks · −1

In a simple pendulum experiment for determination of acceleration due to gravity (g), time taken for 20 oscillations is measured by using a watch of 1 second least count. The mean value of time taken comes out to be 30 s. The length of pendulum is measured by using a meter scale of least count 1 mm and the value obtained is 55.0 cm. The percentage error in the determination of g is close to:

  1. A.0.2 %
  2. B.0.7 %
  3. C.3.5 %
  4. D.6.8 %

Correct answer: D

Question 29

Chemistry · 4 marks · −1

The structure of Nylon-6 is:

  1. A.[−C∥O−(CH2)5−N∣H−]n\left[-\overset{O}{\overset{\|}{C}}-(CH_2)_5-\overset{H}{\overset{|}{N}}-\right]_n
  2. B.[−C∥O−(CH2)6−N∣H−]n\left[-\overset{O}{\overset{\|}{C}}-(CH_2)_6-\overset{H}{\overset{|}{N}}-\right]_n
  3. C.[−(CH2)4−C∥O−N∣H−]n\left[-(CH_2)_4-\overset{O}{\overset{\|}{C}}-\overset{H}{\overset{|}{N}}-\right]_n
  4. D.[−(CH2)6−C∥O−N∣H−]n\left[-(CH_2)_6-\overset{O}{\overset{\|}{C}}-\overset{H}{\overset{|}{N}}-\right]_n

Correct answer: A

Question 30

Chemistry · 4 marks · −1

The major product obtained in the following reaction is: a benzene ring bearing −NH2-NH_2, an ortho −COCH3-COCH_3 and a −CN-CN group (ortho to the acetyl) →(ii) Pd/C/H2(i) CHCl3/KOH\xrightarrow[\text{(ii) Pd/C/H}_2]{\text{(i) CHCl}_3\text{/KOH}}

Figure for question 30
  1. A.Ring bearing −NHCHCl2-NHCHCl_2, −CH(OH)CH3-CH(OH)CH_3 and −CN-CN
  2. B.Ring bearing −NHCH3-NHCH_3, −COCH3-COCH_3 and −CN-CN
  3. C.Ring bearing −NHCH3-NHCH_3, −CH(OH)CH3-CH(OH)CH_3 and −CH2NH2-CH_2NH_2
  4. D.Ring bearing −NHCH3-NHCH_3, −CH(OH)CH3-CH(OH)CH_3 and −CN-CN

Correct answer: C

Question 31

Chemistry · 4 marks · −1

Polysubstitution is a major drawback in:

  1. A.Friedel Craft's alkylation
  2. B.Friedel Craft's acylation
  3. C.Acetylation of aniline
  4. D.Reimer Tiemann reaction

Correct answer: A

Question 32

Chemistry · 4 marks · −1

Fructose and glucose can be distinguished by:

  1. A.Fehling's test
  2. B.Benedict's test
  3. C.Barfoed's test
  4. D.Seliwanoff's test

Correct answer: D

Question 33

Chemistry · 4 marks · −1

The major product obtained in the following reaction is: OHC−CH(CH3)−CH2−CH2−CH2−CO−CH3OHC-CH(CH_3)-CH_2-CH_2-CH_2-CO-CH_3 (2-methyl-6-oxoheptanal) →NaOH, Δ\xrightarrow{NaOH,\ \Delta}

Figure for question 33
  1. A.1-(3-Methylcyclopent-2-en-1-yl)ethan-1-one: cyclopentene ring with the acetyl group on an sp3 ring carbon and CH3 on a ring alkene carbon
  2. B.1-(3-Methylcyclopent-1-en-1-yl)ethan-1-one: cyclopentene ring with the acetyl group on a ring alkene carbon (C1=C2) and CH3 on the sp3 carbon C3 next to C2
  3. C.1-Methyl-2-methylenecyclopentane-1-carbaldehyde: cyclopentane bearing CH3 and CHO on the same carbon, with an exocyclic =CH2 on the adjacent carbon
  4. D.1,2-Dimethylcyclopent-2-ene-1-carbaldehyde: cyclopentene bearing CH3 and CHO on the same sp3 carbon, and CH3 on the adjacent alkene carbon

Correct answer: B

Question 34

Chemistry · 4 marks · −1

The major product of the following reaction is: 4-chlorotoluene →(2) H2O, Δ(1) Cl2/hν\xrightarrow[\text{(2) H}_2\text{O, }\Delta]{\text{(1) Cl}_2/h\nu}

  1. A.4−ClC6H4CH2OH4-ClC_6H_4CH_2OH
  2. B.4−ClC6H4CHO4-ClC_6H_4CHO
  3. C.4−ClC6H4CHCl24-ClC_6H_4CHCl_2
  4. D.4−ClC6H4CO2H4-ClC_6H_4CO_2H

Correct answer: B

Question 35

Chemistry · 4 marks · −1

The major product of the following reaction is: 3−(CH3)2CH−C6H4−CH2−CO−CH2−CH2Cl3-(CH_3)_2CH-C_6H_4-CH_2-CO-CH_2-CH_2Cl (a meta-isopropylbenzyl ketone bearing a 2-chloroethyl group) →(2) Conc. H2SO4/Δ(1) tBuOK\xrightarrow[\text{(2) Conc. H}_2\text{SO}_4/\Delta]{\text{(1) }^t\text{BuOK}}

Figure for question 35
  1. A.An indan-2-one (five-membered ketone ring fused to benzene) bearing a methyl on the ring carbon next to the benzene and the isopropyl group on the benzene ring next to the ring fusion
  2. B.A 2-tetralone (six-membered ketone ring fused to benzene) with the isopropyl group on the benzene ring next to the ring fusion
  3. C.An indan-2-one bearing a methyl on the ring carbon next to the benzene and the isopropyl group on the benzene ring away from the ring fusion
  4. D.A 2-tetralone with the isopropyl group on the benzene ring away from the ring fusion (para to the new C-C bond)

Correct answer: D

Question 36

Chemistry · 4 marks · −1

Which of the following compounds will show the maximum 'enol' content?

  1. A.CH3COCH2COCH3CH_3COCH_2COCH_3
  2. B.CH3COCH2COOC2H5CH_3COCH_2COOC_2H_5
  3. C.CH3COCH3CH_3COCH_3
  4. D.CH3COCH2CONH2CH_3COCH_2CONH_2

Correct answer: A

Question 37

Chemistry · 4 marks · −1

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

  1. A.CH3O−CH=CH2CH_3O-CH=CH_2
  2. B.F3C−CH=CH2F_3C-CH=CH_2
  3. C.Cl−CH=CH2Cl-CH=CH_2
  4. D.H2N−CH=CH2H_2N-CH=CH_2

Correct answer: B

Question 38

Chemistry · 4 marks · −1

The IUPAC symbol for the element with atomic number 119 would be:

  1. A.une
  2. B.uun
  3. C.unh
  4. D.uue

Correct answer: D

Question 39

Chemistry · 4 marks · −1

The Mond process is used for the:

  1. A.extraction of Zn
  2. B.extraction of Mo
  3. C.purification of Ni
  4. D.purification of Zr and Ti

Correct answer: C

Question 40

Chemistry · 4 marks · −1

The strength of 11.2 volume solution of H2_2O2_2 is: [Given that molar mass of H = 1 g mol−1^{-1} and O = 16 g mol−1^{-1}]

  1. A.13.6%
  2. B.3.4%
  3. C.1.7%
  4. D.34%

Correct answer: B

Question 41

Chemistry · 4 marks · −1

The covalent alkaline earth metal halide (X = Cl, Br, I) is:

  1. A.BeX2BeX_2
  2. B.MgX2MgX_2
  3. C.CaX2CaX_2
  4. D.SrX2SrX_2

Correct answer: A

Question 42

Chemistry · 4 marks · −1

The correct statement about ICl5_5 and ICl4−_4^- is:

  1. A.both are isostructural.
  2. B.ICl5ICl_5 is trigonal bipyramidal and ICl4−ICl_4^- is tetrahedral.
  3. C.ICl5ICl_5 is square pyramidal and ICl4−ICl_4^- is square planar.
  4. D.ICl5ICl_5 is square pyramidal and ICl4−ICl_4^- is tetrahedral.

Correct answer: C

Question 43

Chemistry · 4 marks · −1

The ion that has sp3^3d2^2 hybridization for the central atom, is:

  1. A.[BrF2]−[BrF_2]^-
  2. B.[ICl4]−[ICl_4]^-
  3. C.[IF6]−[IF_6]^-
  4. D.[ICl2]−[ICl_2]^-

Correct answer: B

Question 44

Chemistry · 4 marks · −1

The statement that is INCORRECT about the interstitial compounds is:

  1. A.they have high melting points.
  2. B.they are very hard.
  3. C.they have metallic conductivity.
  4. D.they are chemically reactive.

Correct answer: D

Question 45

Chemistry · 4 marks · −1

The compound that inhibits the growth of tumors is:

  1. A.cis-[Pt(Cl)2(NH3)2][Pt(Cl)_2(NH_3)_2]
  2. B.trans-[Pt(Cl)2(NH3)2][Pt(Cl)_2(NH_3)_2]
  3. C.cis-[Pd(Cl)2(NH3)2][Pd(Cl)_2(NH_3)_2]
  4. D.trans-[Pd(Cl)2(NH3)2][Pd(Cl)_2(NH_3)_2]

Correct answer: A

Question 46

Chemistry · 4 marks · −1

The maximum prescribed concentration of copper in drinking water is:

  1. A.0.5 ppm
  2. B.0.05 ppm
  3. C.3 ppm
  4. D.5 ppm

Correct answer: C

Question 47

Chemistry · 4 marks · −1

The percentage composition of carbon by mole in methane is:

  1. A.25%
  2. B.75%
  3. C.20%
  4. D.80%

Correct answer: C

Question 48

Chemistry · 4 marks · −1

Consider the bcc unit cells of the solids 1 and 2 with the position of atoms as shown below. The radius of atom B is twice that of atom A. The unit cell edge length is 50% more in solid 2 than in 1. What is the approximate packing efficiency in solid 2?

Figure for question 48
  1. A.90%
  2. B.75%
  3. C.65%
  4. D.45%

Correct answer: A

Question 49

Chemistry · 4 marks · −1

If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ\lambda, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be: (Assume kinetic energy of ejected photoelectron to be very high in comparison to work function):

  1. A.12λ\dfrac{1}{2}\lambda
  2. B.23λ\dfrac{2}{3}\lambda
  3. C.34λ\dfrac{3}{4}\lambda
  4. D.49λ\dfrac{4}{9}\lambda

Correct answer: D

Question 50

Chemistry · 4 marks · −1

Among the following molecules/ions, C22−C_2^{2-}, N22−N_2^{2-}, O22−O_2^{2-}, O2O_2 which one is diamagnetic and has the shortest bond length?

  1. A.O22−O_2^{2-}
  2. B.C22−C_2^{2-}
  3. C.N22−N_2^{2-}
  4. D.O2O_2

Correct answer: B

Question 51

Chemistry · 4 marks · −1

5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV=28C_V = 28 J K−1^{-1} mol−1^{-1}, calculate ΔU\Delta U and ΔpV\Delta pV for this process. (R = 8.0 J K−1^{-1} mol−1^{-1})

  1. A.ΔU=14\Delta U = 14 kJ; Δ(pV)=18\Delta(pV) = 18 kJ
  2. B.ΔU=14\Delta U = 14 J; Δ(pV)=0.8\Delta(pV) = 0.8 J
  3. C.ΔU=14\Delta U = 14 kJ; Δ(pV)=4\Delta(pV) = 4 kJ
  4. D.ΔU=2.8\Delta U = 2.8 kJ; Δ(pV)=0.8\Delta(pV) = 0.8 kJ

Correct answer: C

Question 52

Chemistry · 4 marks · −1

For the solution of the gases w, x, y and z in water at 298 K, the Henry's law constants (KHK_H) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is:

Figure for question 52
  1. A.Plot of partial pressure vs mole fraction of water: four nearly horizontal lines starting at different heights on the pressure axis, rising slightly, in order w (lowest), x, y, z (highest)
  2. B.Plot of partial pressure vs mole fraction of water: four parallel rising straight lines, labelled w, x, y, z
  3. C.Plot of partial pressure vs mole fraction of water: four straight lines falling from different intercepts on the pressure axis towards the x-axis, steepest for z, then y, x, w
  4. D.Plot of partial pressure vs mole fraction of water: lines starting on the pressure axis, w and x falling, y and z nearly horizontal

Correct answer: C

Question 53

Chemistry · 4 marks · −1

For the following reactions, equilibrium constants are given: S(s)+O2(g)⇌SO2(g)S(s) + O_2(g) \rightleftharpoons SO_2(g); K1=1052K_1 = 10^{52}; 2S(s)+3O2(g)⇌2SO3(g)2S(s) + 3O_2(g) \rightleftharpoons 2SO_3(g); K2=10129K_2 = 10^{129}. The equilibrium constant for the reaction, 2SO2(g)+O2(g)⇌2SO3(g)2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) is:

  1. A.107710^{77}
  2. B.1018110^{181}
  3. C.1015410^{154}
  4. D.102510^{25}

Correct answer: D

Question 54

Chemistry · 4 marks · −1

Calculate the standard cell potential (in V) of the cell in which following reaction takes place: Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s)Fe^{2+}(aq) + Ag^+(aq) \rightarrow Fe^{3+}(aq) + Ag(s). Given that EAg+/Ago=xE^o_{Ag^+/Ag} = x V, EFe2+/Feo=yE^o_{Fe^{2+}/Fe} = y V, EFe3+/Feo=zE^o_{Fe^{3+}/Fe} = z V

  1. A.x−yx - y
  2. B.x−zx - z
  3. C.x+y−zx + y - z
  4. D.x+2y−3zx + 2y - 3z

Correct answer: D

Question 55

Chemistry · 4 marks · −1

For a reaction scheme A→k1B→k2CA \xrightarrow{k_1} B \xrightarrow{k_2} C, if the rate of formation of B is set to be zero then the concentration of B is given by:

  1. A.(k1k2)[A]\left(\dfrac{k_1}{k_2}\right)[A]
  2. B.(k1+k2)[A](k_1 + k_2)[A]
  3. C.(k1−k2)[A](k_1 - k_2)[A]
  4. D.k1k2[A]k_1k_2[A]

Correct answer: A

Question 56

Chemistry · 4 marks · −1

0.27 g of a long chain fatty acid was dissolved in 100 cm3^3 of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer? [Density of fatty acid = 0.9 g cm−3^{-3}; π=3\pi = 3]

  1. A.10−410^{-4} m
  2. B.10−610^{-6} m
  3. C.10−210^{-2} m
  4. D.10−810^{-8} m

Correct answer: B

Question 57

Mathematics · 4 marks · −1

Let f(x)=axf(x) = a^x (a>0)(a > 0) be written as f(x)=f1(x)+f2(x)f(x) = f_1(x) + f_2(x), where f1(x)f_1(x) is an even function and f2(x)f_2(x) is an odd function. Then f1(x+y)+f1(x−y)f_1(x + y) + f_1(x - y) equals:

  1. A.2f1(x)f1(y)2f_1(x)f_1(y)
  2. B.2f1(x+y)f1(x−y)2f_1(x+y)f_1(x-y)
  3. C.2f1(x)f2(y)2f_1(x)f_2(y)
  4. D.2f1(x+y)f2(x−y)2f_1(x+y)f_2(x-y)

Correct answer: A

Question 58

Mathematics · 4 marks · −1

If z=32+i2z = \dfrac{\sqrt{3}}{2} + \dfrac{i}{2} (i=−1)(i = \sqrt{-1}), then (1+iz+z5+iz8)9(1 + iz + z^5 + iz^8)^9 is equal to:

  1. A.1
  2. B.−1
  3. C.(−1+2i)9(-1 + 2i)^9
  4. D.0

Correct answer: B

Question 59

Mathematics · 4 marks · −1

The number of integral values of m for which the equation (1+m2)x2−2(1+3m)x+(1+8m)=0(1 + m^2)x^2 - 2(1 + 3m)x + (1 + 8m) = 0 has no real root is:

  1. A.2
  2. B.3
  3. C.infinitely many
  4. D.1

Correct answer: C

Question 60

Mathematics · 4 marks · −1

Let the numbers 2, b, c be in an A.P. and A=[1112bc4b2c2]A = \begin{bmatrix} 1 & 1 & 1 \\ 2 & b & c \\ 4 & b^2 & c^2 \end{bmatrix}. If det(A) ∈[2,16]\in [2, 16], then c lies in the interval:

  1. A.[3,2+23/4][3, 2 + 2^{3/4}]
  2. B.[4, 6]
  3. C.[2, 3)
  4. D.(2+23/4,4)(2 + 2^{3/4}, 4)

Correct answer: B

Question 61

Mathematics · 4 marks · −1

If the system of linear equations x−2y+kz=1x - 2y + kz = 1, 2x+y+z=22x + y + z = 2, 3x−y−kz=33x - y - kz = 3 has a solution (x, y, z), z≠0z \ne 0, then (x, y) lies on the straight line whose equation is:

  1. A.4x−3y−1=04x - 3y - 1 = 0
  2. B.3x−4y−1=03x - 4y - 1 = 0
  3. C.3x−4y−4=03x - 4y - 4 = 0
  4. D.4x−3y−4=04x - 3y - 4 = 0

Correct answer: D

Question 62

Mathematics · 4 marks · −1

The number of four-digit numbers strictly greater than 4321 that can be formed using the digits 0, 1, 2, 3, 4, 5 (repetition of digits is allowed) is:

  1. A.310
  2. B.360
  3. C.288
  4. D.306

Correct answer: A

Question 63

Mathematics · 4 marks · −1

If three distinct numbers a, b, c are in G.P. and the equations ax2+2bx+c=0ax^2 + 2bx + c = 0 and dx2+2ex+f=0dx^2 + 2ex + f = 0 have a common root, then which one of the following statements is correct?

  1. A.d, e, f are in G.P.
  2. B.d, e, f are in A.P.
  3. C.da,eb,fc\dfrac{d}{a}, \dfrac{e}{b}, \dfrac{f}{c} are in G.P.
  4. D.da,eb,fc\dfrac{d}{a}, \dfrac{e}{b}, \dfrac{f}{c} are in A.P.

Correct answer: D

Question 64

Mathematics · 4 marks · −1

The sum ∑k=120k12k\displaystyle\sum_{k=1}^{20} k\frac{1}{2^k} is equal to:

  1. A.2−112192 - \dfrac{11}{2^{19}}
  2. B.2−212202 - \dfrac{21}{2^{20}}
  3. C.1−112201 - \dfrac{11}{2^{20}}
  4. D.2−32172 - \dfrac{3}{2^{17}}

Correct answer: A

Question 65

Mathematics · 4 marks · −1

Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be a differentiable function satisfying f′(3)+f′(2)=0f'(3) + f'(2) = 0. Then lim⁡x→0(1+f(3+x)−f(3)1+f(2−x)−f(2))1x\displaystyle\lim_{x\to 0}\left(\frac{1 + f(3 + x) - f(3)}{1 + f(2 - x) - f(2)}\right)^{\frac{1}{x}} is equal to:

  1. A.e
  2. B.1
  3. C.e−1e^{-1}
  4. D.e2e^2

Correct answer: B

Question 66

Mathematics · 4 marks · −1

If f(1)=1f(1) = 1, f′(1)=3f'(1) = 3, then the derivative of f(f(f(x)))+(f(x))2f(f(f(x))) + (f(x))^2 at x=1x = 1 is:

  1. A.9
  2. B.12
  3. C.15
  4. D.33

Correct answer: D

Question 67

Mathematics · 4 marks · −1

Let f:[−1,3]→Rf: [-1, 3] \rightarrow \mathbb{R} be defined as f(x)={∣x∣+[x],−1≤x<1x+∣x∣,1≤x<2x+[x],2≤x≤3,f(x) = \begin{cases} |x| + [x], & -1 \le x < 1 \\ x + |x|, & 1 \le x < 2 \\ x + [x], & 2 \le x \le 3, \end{cases} where [t] denotes the greatest integer less than or equal to t. Then, f is discontinuous at:

  1. A.only one point
  2. B.only two points
  3. C.only three points
  4. D.four or more points

Correct answer: C

Question 68

Mathematics · 4 marks · −1

The height of a right circular cylinder of maximum volume inscribed in a sphere of radius 3 is:

  1. A.233\dfrac{2}{3}\sqrt{3}
  2. B.232\sqrt{3}
  3. C.6\sqrt{6}
  4. D.3\sqrt{3}

Correct answer: B

Question 69

Mathematics · 4 marks · −1

If ∫dxx3(1+x6)2/3=xf(x)(1+x6)13+C\displaystyle\int \frac{dx}{x^3(1 + x^6)^{2/3}} = xf(x)(1 + x^6)^{\frac{1}{3}} + C where C is a constant of integration, then the function f(x) is equal to:

  1. A.−16x3-\dfrac{1}{6x^3}
  2. B.−12x2-\dfrac{1}{2x^2}
  3. C.−12x3-\dfrac{1}{2x^3}
  4. D.3x2\dfrac{3}{x^2}

Correct answer: C

Question 70

Mathematics · 4 marks · −1

Let f(x)=∫0xg(t) dtf(x) = \displaystyle\int_0^x g(t)\,dt, where g is a non-zero even function. If f(x+5)=g(x)f(x + 5) = g(x), then ∫0xf(t) dt\displaystyle\int_0^x f(t)\,dt equals:

  1. A.∫x+55g(t) dt\displaystyle\int_{x+5}^{5} g(t)\,dt
  2. B.∫5x+5g(t) dt\displaystyle\int_{5}^{x+5} g(t)\,dt
  3. C.2∫5x+5g(t) dt2\displaystyle\int_{5}^{x+5} g(t)\,dt
  4. D.5∫x+55g(t) dt5\displaystyle\int_{x+5}^{5} g(t)\,dt

Correct answer: A

Question 71

Mathematics · 4 marks · −1

Let S(α)={(x,y):y2≤x, 0≤x≤α}S(\alpha) = \{(x, y) : y^2 \le x,\ 0 \le x \le \alpha\} and A(α)A(\alpha) is area of the region S(α)S(\alpha). If for a λ\lambda, 0<λ<40 < \lambda < 4, A(λ):A(4)=2:5A(\lambda) : A(4) = 2 : 5, then λ\lambda equals:

  1. A.4(425)134\left(\dfrac{4}{25}\right)^{\frac{1}{3}}
  2. B.4(25)134\left(\dfrac{2}{5}\right)^{\frac{1}{3}}
  3. C.2(25)132\left(\dfrac{2}{5}\right)^{\frac{1}{3}}
  4. D.2(425)132\left(\dfrac{4}{25}\right)^{\frac{1}{3}}

Correct answer: A

Question 72

Mathematics · 4 marks · −1

Given that the slope of the tangent to a curve y=y(x)y = y(x) at any point (x, y) is 2yx2\dfrac{2y}{x^2}. If the curve passes through the centre of the circle x2+y2−2x−2y=0x^2 + y^2 - 2x - 2y = 0, then its equation is:

  1. A.xlog⁡e∣y∣=2(x−1)x\log_e|y| = 2(x - 1)
  2. B.xlog⁡e∣y∣=x−1x\log_e|y| = x - 1
  3. C.xlog⁡e∣y∣=−2(x−1)x\log_e|y| = -2(x - 1)
  4. D.x2log⁡e∣y∣=−2(x−1)x^2\log_e|y| = -2(x - 1)

Correct answer: A

Question 73

Mathematics · 4 marks · −1

The tangent and the normal lines at the point (3,1)(\sqrt{3}, 1) to the circle x2+y2=4x^2 + y^2 = 4 and the x-axis form a triangle. The area of this triangle (in square units) is:

  1. A.43\dfrac{4}{\sqrt{3}}
  2. B.13\dfrac{1}{3}
  3. C.13\dfrac{1}{\sqrt{3}}
  4. D.23\dfrac{2}{\sqrt{3}}

Correct answer: D

Question 74

Mathematics · 4 marks · −1

Suppose that the points (h, k), (1, 2) and (−3, 4) lie on the line L1L_1. If a line L2L_2 passing through the points (h, k) and (4, 3) is perpendicular to L1L_1, then kh\dfrac{k}{h} equals:

  1. A.13\dfrac{1}{3}
  2. B.3
  3. C.0
  4. D.−17-\dfrac{1}{7}

Correct answer: A

Question 75

Mathematics · 4 marks · −1

The tangent to the parabola y2=4xy^2 = 4x at the point where it intersects the circle x2+y2=5x^2 + y^2 = 5 in the first quadrant, passes through the point:

  1. A.(−13,43)\left(-\dfrac{1}{3}, \dfrac{4}{3}\right)
  2. B.(−14,12)\left(-\dfrac{1}{4}, \dfrac{1}{2}\right)
  3. C.(34,74)\left(\dfrac{3}{4}, \dfrac{7}{4}\right)
  4. D.(14,34)\left(\dfrac{1}{4}, \dfrac{3}{4}\right)

Correct answer: C

Question 76

Mathematics · 4 marks · −1

In an ellipse, with centre at the origin, if the difference of the lengths of major axis and minor axis is 10 and one of the foci is at (0,53)(0, 5\sqrt{3}), then the length of its latus rectum is:

  1. A.8
  2. B.10
  3. C.5
  4. D.6

Correct answer: C

Question 77

Mathematics · 4 marks · −1

If the eccentricity of the standard hyperbola passing through the point (4, 6) is 2, then the equation of the tangent to the hyperbola at (4, 6) is:

  1. A.3x−2y=03x - 2y = 0
  2. B.2x−y−2=02x - y - 2 = 0
  3. C.2x−3y+10=02x - 3y + 10 = 0
  4. D.x−2y+8=0x - 2y + 8 = 0

Correct answer: B

Question 78

Mathematics · 4 marks · −1

The vector equation of the plane through the line of intersection of the planes x+y+z=1x + y + z = 1 and 2x+3y+4z=52x + 3y + 4z = 5 which is perpendicular to the plane x−y+z=0x - y + z = 0 is:

  1. A.r⃗×(i^+k^)+2=0\vec{r}\times(\hat{i} + \hat{k}) + 2 = 0
  2. B.r⃗×(i^−k^)+2=0\vec{r}\times(\hat{i} - \hat{k}) + 2 = 0
  3. C.r⃗⋅(i^−k^)−2=0\vec{r}\cdot(\hat{i} - \hat{k}) - 2 = 0
  4. D.r⃗⋅(i^−k^)+2=0\vec{r}\cdot(\hat{i} - \hat{k}) + 2 = 0

Correct answer: D

Question 79

Mathematics · 4 marks · −1

If a point R(4, y, z) lies on the line segment joining the points P(2, −3, 4) and Q(8, 0, 10), then the distance of R from the origin is:

  1. A.53\sqrt{53}
  2. B.2142\sqrt{14}
  3. C.2212\sqrt{21}
  4. D.6

Correct answer: B

Question 80

Mathematics · 4 marks · −1

Let a⃗=3i^+2j^+xk^\vec{a} = 3\hat{i} + 2\hat{j} + x\hat{k} and b⃗=i^−j^+k^\vec{b} = \hat{i} - \hat{j} + \hat{k}, for some real x. Then ∣a⃗×b⃗∣=r|\vec{a}\times\vec{b}| = r is possible if:

  1. A.0<r≤320 < r \le \sqrt{\dfrac{3}{2}}
  2. B.32<r≤332\sqrt{\dfrac{3}{2}} < r \le 3\sqrt{\dfrac{3}{2}}
  3. C.332<r<5323\sqrt{\dfrac{3}{2}} < r < 5\sqrt{\dfrac{3}{2}}
  4. D.r≥532r \ge 5\sqrt{\dfrac{3}{2}}

Correct answer: D

Question 81

Mathematics · 4 marks · −1

A student scores the following marks in five tests: 45, 54, 41, 57, 43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is:

  1. A.1003\dfrac{100}{3}
  2. B.103\dfrac{10}{3}
  3. C.103\dfrac{10}{\sqrt{3}}
  4. D.1003\dfrac{100}{\sqrt{3}}

Correct answer: C

Question 82

Mathematics · 4 marks · −1

The minimum number of times one has to toss a fair coin so that the probability of observing at least one head is at least 90% is:

  1. A.2
  2. B.3
  3. C.4
  4. D.5

Correct answer: C

Question 83

Mathematics · 4 marks · −1

If the lengths of the sides of a triangle are in A.P. and the greatest angle is double the smallest, then a ratio of lengths of the sides of this triangle is:

  1. A.5 : 6 : 7
  2. B.5 : 9 : 13
  3. C.4 : 5 : 6
  4. D.3 : 4 : 5

Correct answer: C

Question 84

Mathematics · 4 marks · −1

Two vertical poles of heights, 20 m and 80 m stand apart on a horizontal plane. The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other, from this horizontal plane is:

  1. A.12
  2. B.15
  3. C.16
  4. D.18

Correct answer: C

Question 85

Mathematics · 4 marks · −1

Which one of the following statements is not a tautology?

  1. A.(p∧q)→p(p \wedge q) \rightarrow p
  2. B.p→(p∨q)p \rightarrow (p \vee q)
  3. C.(p∨q)→(p∨(∼q))(p \vee q) \rightarrow (p \vee (\sim q))
  4. D.(p∧q)→(∼p)∨q(p \wedge q) \rightarrow (\sim p) \vee q

Correct answer: C

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