JEE Main 2021 — 17 Mar Shift 1 (Previous Year Paper)

JEE Main · 2021 · with answers and explanations

questions
90
Total marks
300
Duration
180 minutes
Negative marking
−1

Subjects: Physics · Chemistry · Mathematics

Question 1

Physics · 4 marks · −1

A car accelerates from rest at a constant rate α\alpha for some time after which it decelerates at a constant rate β\beta to come to rest. If the total time elapsed is t seconds, the total distance travelled is:

  1. A.2αβ(α+β)t2\frac{2\alpha\beta}{(\alpha+\beta)}t^2
  2. B.αβ2(α+β)t2\frac{\alpha\beta}{2(\alpha+\beta)}t^2
  3. C.4αβ(α+β)t2\frac{4\alpha\beta}{(\alpha+\beta)}t^2
  4. D.αβ4(α+β)t2\frac{\alpha\beta}{4(\alpha+\beta)}t^2

Correct answer: B

Explanation: vmax=αβtα+βv_{max}=\frac{\alpha\beta t}{\alpha+\beta}, distance =12vmaxt=\frac12v_{max}t.

Question 2

Physics · 4 marks · −1

A modern grand-prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed v. If the coefficient of static friction between the tyres and the track is μs\mu_s, then the magnitude of negative lift FLF_L acting downwards on the car is: (Assume forces on the four tyres are identical and g = acceleration due to gravity)

Figure for question 2
  1. A.m(v2μsR+g)m\left(\frac{v^2}{\mu_sR}+g\right)
  2. B.m(g−v2μsR)m\left(g-\frac{v^2}{\mu_sR}\right)
  3. C.m(v2μsR−g)m\left(\frac{v^2}{\mu_sR}-g\right)
  4. D.−m(g+v2μsR)-m\left(g+\frac{v^2}{\mu_sR}\right)

Correct answer: C

Explanation: μs(mg+FL)=mv2R\mu_s(mg+F_L)=\frac{mv^2}{R}.

Question 3

Physics · 4 marks · −1

A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is:

  1. A.2400 J
  2. B.1600 J
  3. C.3200 J
  4. D.1800 J

Correct answer: A

Explanation: η=0.5\eta=0.5.

Question 4

Physics · 4 marks · −1

A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5 A. The magnetic flux density produced by the solenoid is: (permeability of free space =4π×10−7=4\pi\times10^{-7} H/m)

  1. A.10−4π10^{-4}\pi T
  2. B.2×10−3π2\times10^{-3}\pi T
  3. C.π5\frac\pi5 T
  4. D.π\pi T

Correct answer: D

Explanation: B=μ0μrnI=4π×10−7×500×1000×5=πB=\mu_0\mu_rnI=4\pi\times10^{-7}\times500\times1000\times5=\pi T.

Question 5

Physics · 4 marks · −1

A current of 10 A exists in a wire of crosssectional area of 5 mm2^2 with a drift velocity of 2×10−32\times10^{-3} ms−1^{-1}. The number of free electrons in each cubic meter of the wire is ________.

  1. A.2×1062\times10^6
  2. B.1×10231\times10^{23}
  3. C.625×1025625\times10^{25}
  4. D.2×10252\times10^{25}

Correct answer: C

Explanation: n=IeAvd=6.25×1027n=\frac{I}{eAv_d}=6.25\times10^{27}.

Question 6

Physics · 4 marks · −1

A mass M hangs on a massless rod of length l which rotates at a constant angular frequency. The mass M moves with steady speed in a circular path of constant radius. Assume that the system is in steady circular motion with constant angular velocity ω\omega. The angular momentum of M about point A is LAL_A which lies in the positive z direction and the angular momentum of M about point B is LBL_B. The correct statement for this system is:

Figure for question 6
  1. A.LAL_A and LBL_B are both constant in magnitude and direction
  2. B.LAL_A is constant, both in magnitude and direction
  3. C.LBL_B is constant, both in magnitude and direction
  4. D.LBL_B is constant in direction with varying magnitude

Correct answer: B

Question 7

Physics · 4 marks · −1

An AC current is given by I=I1sin⁡ωt+I2cos⁡ωtI=I_1\sin\omega t+I_2\cos\omega t. A hot wire ammeter will give a reading:

  1. A.I1+I22\frac{I_1+I_2}{\sqrt2}
  2. B.I1+I222\frac{I_1+I_2}{2\sqrt2}
  3. C.I12+I222\sqrt{\frac{I_1^2+I_2^2}{2}}
  4. D.I12−I222\sqrt{\frac{I_1^2-I_2^2}{2}}

Correct answer: C

Question 8

Physics · 4 marks · −1

A polyatomic ideal gas has 24 vibrational modes. What is the value of γ\gamma?

  1. A.10.3
  2. B.1.30
  3. C.1.03
  4. D.1.37

Correct answer: C

Explanation: f=3+3+2×24=54f=3+3+2\times24=54, γ=1+254≈1.03\gamma=1+\frac2{54}\approx1.03.

Question 9

Physics · 4 marks · −1

When two soap bubbles of radii a and b (b > a) coalesce, the radius of curvature of common surface is:

  1. A.abb−a\frac{ab}{b-a}
  2. B.aba+b\frac{ab}{a+b}
  3. C.b−aab\frac{b-a}{ab}
  4. D.a+bab\frac{a+b}{ab}

Correct answer: A

Question 10

Physics · 4 marks · −1

A triangular plate is shown. A force F⃗=4i^−3j^\vec F=4\hat i-3\hat j is applied at point P. The torque at point P with respect to point 'O' and 'Q' are:

Figure for question 10
  1. A.−15−203-15-20\sqrt3, 15−20315-20\sqrt3
  2. B.15+20315+20\sqrt3, 15−20315-20\sqrt3
  3. C.15−20315-20\sqrt3, 15+20315+20\sqrt3
  4. D.−15+203-15+20\sqrt3, 15+20315+20\sqrt3

Correct answer: A

Explanation: About O: 5(−3)−53(4)=−15−2035(-3)-5\sqrt3(4)=-15-20\sqrt3; about Q: (−5)(−3)−53(4)=15−203(-5)(-3)-5\sqrt3(4)=15-20\sqrt3 (N cm).

Question 11

Physics · 4 marks · −1

Two identical metal wires of thermal conductivities K1K_1 and K2K_2 respectively are connected in series. The effective thermal conductivity of the combination is:

  1. A.K1K2K1+K2\frac{K_1K_2}{K_1+K_2}
  2. B.2K1K2K1+K2\frac{2K_1K_2}{K_1+K_2}
  3. C.K1+K22K1K2\frac{K_1+K_2}{2K_1K_2}
  4. D.K1+K2K1K2\frac{K_1+K_2}{K_1K_2}

Correct answer: B

Question 12

Physics · 4 marks · −1

A boy is rolling a 0.5 kg ball on the frictionless floor with the speed of 20 ms−1^{-1}. The ball gets deflected by an obstacle on the way. After deflection it moves with 5% of its initial kinetic energy. What is the speed of the ball now?

  1. A.1.00 ms−1^{-1}
  2. B.4.47 ms−1^{-1}
  3. C.14.41 ms−1^{-1}
  4. D.19.0 ms−1^{-1}

Correct answer: B

Question 13

Physics · 4 marks · −1

The thickness at the centre of a plano convex lens is 3 mm and the diameter is 6 cm. If the speed of light in the material of the lens is 2×1082\times10^8 ms−1^{-1}. The focal length of the lens is ________.

  1. A.30 cm
  2. B.15 cm
  3. C.1.5 cm
  4. D.0.30 cm

Correct answer: A

Explanation: R≈r22t=15R\approx\frac{r^2}{2t}=15 cm, μ=1.5\mu=1.5, f=Rμ−1=30f=\frac{R}{\mu-1}=30 cm.

Question 14

Physics · 4 marks · −1

Which level of the single ionized carbon has the same energy as the ground state energy of hydrogen atom?

  1. A.1
  2. B.4
  3. C.6
  4. D.8

Correct answer: C

Question 15

Physics · 4 marks · −1

Two ideal polyatomic gases at temperatures T1T_1 and T2T_2 are mixed so that there is no loss of energy. If F1F_1 and F2F_2, m1m_1 and m2m_2, n1n_1 and n2n_2 be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is:

  1. A.n1F1T1+n2F2T2n1+n2\frac{n_1F_1T_1+n_2F_2T_2}{n_1+n_2}
  2. B.n1F1T1+n2F2T2F1+F2\frac{n_1F_1T_1+n_2F_2T_2}{F_1+F_2}
  3. C.n1F1T1+n2F2T2n1F1+n2F2\frac{n_1F_1T_1+n_2F_2T_2}{n_1F_1+n_2F_2}
  4. D.n1T1+n2T2n1+n2\frac{n_1T_1+n_2T_2}{n_1+n_2}

Correct answer: C

Question 16

Physics · 4 marks · −1

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal?

  1. A.x=±Ax=\pm A
  2. B.x=0x=0
  3. C.x=±A2x=\pm\frac{A}{\sqrt2}
  4. D.x=A2x=\frac A2

Correct answer: C

Question 17

Physics · 4 marks · −1

The output of the given combination gates represents:

Figure for question 17
  1. A.AND Gate
  2. B.NOR Gate
  3. C.NAND Gate
  4. D.XOR Gate

Correct answer: C

Explanation: Y=Aˉ+Bˉ‾‾=Aˉ+Bˉ=AB‾Y=\overline{\overline{\bar A+\bar B}}=\bar A+\bar B=\overline{AB}: NAND.

Question 18

Physics · 4 marks · −1

An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is: (c being the velocity of light)

  1. A.(E2m)1/2\left(\frac{E}{2m}\right)^{1/2}
  2. B.c(2mE)1/2c(2mE)^{1/2}
  3. C.1c(2mE)1/2\frac1c\left(\frac{2m}{E}\right)^{1/2}
  4. D.1c(E2m)1/2\frac1c\left(\frac{E}{2m}\right)^{1/2}

Correct answer: D

Question 19

Physics · 4 marks · −1

The vernier scale used for measurement has a positive zero error of 0.2 mm. If while taking a measurement it was noted that '0' on the vernier scale lies between 8.5 cm and 8.6 cm, vernier coincidence is 6, then the correct value of measurement is ________ cm. (least count = 0.01 cm)

  1. A.8.58 cm
  2. B.8.56 cm
  3. C.8.54 cm
  4. D.8.36 cm

Correct answer: C

Explanation: 8.5+0.06−0.02=8.548.5+0.06-0.02=8.54 cm.

Question 20

Physics · 4 marks · −1

If an electron is moving in the nthn^{th} orbit of the hydrogen atom, then its velocity (vnv_n) for the nthn^{th} orbit is given as:

  1. A.vn∝n2v_n\propto n^2
  2. B.vn∝nv_n\propto n
  3. C.vn∝1n2v_n\propto\frac1{n^2}
  4. D.vn∝1nv_n\propto\frac1n

Correct answer: D

Question 21

Physics · 4 marks

For VHF signal broadcasting, ________ km2^2 of maximum service area will be covered by an antenna tower of height 30 m, if the receiving antenna is placed at ground. Let radius of the earth be 6400 km. (Round off to the Nearest Integer) (Take π\pi as 3.14)

Correct answer: 1206

Explanation: π(2Rh)=3.14×2×6400×0.03≈1206\pi(2Rh)=3.14\times2\times6400\times0.03\approx1206 km2^2.

Question 22

Physics · 4 marks

If 2.5×10−62.5\times10^{-6} N average force is exerted by a light wave on a non-reflecting surface of 30 cm2^2 area during 40 minutes of time span, the energy flux of light just before it falls on the surface is ________ W/cm2^2. (Round off to the Nearest Integer) (Assume complete absorption and normal incidence conditions are there)

Correct answer: 25

Explanation: I=FcA=2.5×10−6×3×10830=25I=\frac{Fc}{A}=\frac{2.5\times10^{-6}\times3\times10^8}{30}=25 W/cm2^2.

Question 23

Physics · 4 marks

Four identical rectangular plates with length, l=2l=2 cm and breadth, b=32b=\frac32 cm are arranged as shown in figure. The equivalent capacitance between A and C is xε0d\frac{x\varepsilon_0}{d}. The value of x is ________. (Round off to the Nearest Integer)

Figure for question 23

Correct answer: 2

Explanation: A–B is C0C_0 in series with (B–C parallel C–D, since D=B) 2C02C_0: 23C0\frac23C_0 with C0=3ε0dC_0=\frac{3\varepsilon_0}{d} (area 3 cm2^2), giving x = 2.

Question 24

Physics · 4 marks

The equivalent resistance of series combination of two resistors is 's'. When they are connected in parallel, the equivalent resistance is 'p'. If s = np, then the minimum value for n is ________. (Round off to the Nearest Integer)

Correct answer: 4

Explanation: n=(R1+R2)2R1R2≥4n=\frac{(R_1+R_2)^2}{R_1R_2}\ge4.

Question 25

Physics · 4 marks

A parallel plate capacitor whose capacitance C is 14 pF is charged by a battery to a potential difference V = 12 V between its plates. The charging battery is now disconnected and a porcelin plate with k = 7 is inserted between the plates, then the plate would oscillate back and forth between the plates with a constant mechanical energy of ________ pJ. (Assume no friction)

Correct answer: 864

Explanation: U1=1008U_1=1008 pJ, U2=U1/7=144U_2=U_1/7=144 pJ; difference 864 pJ.

Question 26

Physics · 4 marks

The radius in kilometer to which the present radius of earth (R = 6400 km) to be compressed so that the escape velocity is increased 10 times is ________.

Correct answer: 64

Explanation: ve∝R−1/2v_e\propto R^{-1/2}: R/100=64R/100=64 km.

Question 27

Physics · 4 marks

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is ________. (Assuming the acceleration to be uniform).

Correct answer: 728

Explanation: Mean 1680 rpm = 28 rps; 28×26=72828\times26=728.

Question 28

Physics · 4 marks

Consider two identical springs each of spring constant k and negligible mass compared to the mass M as shown. Fig. 1 shows one of them and Fig. 2 shows their series combination. The ratios of time period of oscillation of the two SHM is TbTa=x\frac{T_b}{T_a}=\sqrt x, where value of x is ________. (Round off to the Nearest Integer)

Figure for question 28

Correct answer: 2

Explanation: keq=k/2k_{eq}=k/2: Tb/Ta=2T_b/T_a=\sqrt2.

Question 29

Physics · 4 marks

The following bodies, (1) a ring (2) a disc (3) a solid cylinder (4) a solid sphere, of same mass 'm' and radius 'R' are allowed to roll down without slipping simultaneously from the top of the inclined plane. The body which will reach first at the bottom of the inclined plane is ________. [Mark the body as per their respective numbering given in the question]

Figure for question 29

Correct answer: 4

Explanation: Smallest k^2/R^2 (solid sphere) arrives first: 4.

Question 30

Physics · 4 marks

Two blocks (m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is 37\frac37. Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is ________ N. (Round off to the Nearest Integer) [Take g as 9.8 ms−2^{-2}]

Figure for question 30

Correct answer: 21

Explanation: amax=μg=4.2a_{max}=\mu g=4.2 m s−2^{-2}; F=5×4.2=21F=5\times4.2=21 N.

Question 31

Chemistry · 4 marks · −1

A central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is:

  1. A.planar triangular
  2. B.T-shaped
  3. C.see-saw
  4. D.trigonal pyramidal

Correct answer: B

Question 32

Chemistry · 4 marks · −1

A colloidal system consisting of a gas dispersed in a solid is called a/an:

  1. A.aerosol
  2. B.solid sol
  3. C.foam
  4. D.gel

Correct answer: B

Question 33

Chemistry · 4 marks · −1

The absolute value of the electron gain enthalpy of halogens satisfies:

  1. A.F > Cl > Br > I
  2. B.Cl > F > Br > I
  3. C.Cl > Br > F > I
  4. D.I > Br > Cl > F

Correct answer: B

Question 34

Chemistry · 4 marks · −1

The point of intersection and sudden increase in the slope, in the diagram given below, respectively, indicates:

Figure for question 34
  1. A.ΔG<0\Delta G<0 and decomposition of the metal oxide
  2. B.ΔG>0\Delta G>0 and decomposition of the metal oxide
  3. C.ΔG=0\Delta G=0 and melting or boiling point of the metal oxide
  4. D.ΔG=0\Delta G=0 and reduction of the metal oxide

Correct answer: C

Question 35

Chemistry · 4 marks · −1

The INCORRECT statement(s) about heavy water is (are) (A) used as a moderator in nuclear reactor (B) obtained as a by-product in fertilizer industry (C) used for the study of reaction mechanism (D) has a higher dielectric constant than water. Choose the correct answer from the options given below:

  1. A.(C) only
  2. B.(B) only
  3. C.(D) only
  4. D.(B) and (D) only

Correct answer: C

Question 36

Chemistry · 4 marks · −1

The correct order of conductivity of ions in water is:

  1. A.Cs+^+ > Rb+^+ > K+^+ > Na+^+
  2. B.Na+^+ > K+^+ > Rb+^+ > Cs+^+
  3. C.K+^+ > Na+^+ > Cs+^+ > Rb+^+
  4. D.Rb+^+ > Na+^+ > K+^+ > Li+^+

Correct answer: A

Question 37

Chemistry · 4 marks · −1

Which of the following compound CANNOT act as a Lewis base?

  1. A.ClF3_3
  2. B.PCl5_5
  3. C.NF3_3
  4. D.SF4_4

Correct answer: B

Question 38

Chemistry · 4 marks · −1

What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25, in it's aqueous solution?

  1. A.5.0
  2. B.5.26
  3. C.5.92
  4. D.zero

Correct answer: C

Question 39

Chemistry · 4 marks · −1

Given below are two statements: Statement I: Potassium permanganate on heating at 573 K forms potassium manganate. Statement II: Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature. In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both statement I and statement II are false
  2. B.Both statement I and statement II are true
  3. C.Statement I is true but statement II is false
  4. D.Statement I is false but statement II is true

Correct answer: C

Question 40

Chemistry · 4 marks · −1

Reducing smog is a mixture of:

  1. A.Smoke, fog and O3_3
  2. B.Smoke, fog and SO2_2
  3. C.Smoke, fog and N2_2O3_3
  4. D.Smoke, fog and CH2_2=CH–CHO

Correct answer: B

Question 41

Chemistry · 4 marks · −1

Given below are two statements: Statement I: Retardation factor (RfR_f) can be measured in meter/centimeter. Statement II: RfR_f value of a compound remains constant in all solvents. Choose the most appropriate answer from the options given below:

  1. A.Both statement I and statement II are true
  2. B.Both statement I and statement II are false
  3. C.Statement I is true but statement II is false
  4. D.Statement I is false but statement II is true

Correct answer: B

Question 42

Chemistry · 4 marks · −1

Which of the following is an aromatic compound?

Figure for question 42
  1. A.cyclopentadiene (neutral)
  2. B.cyclopentadienyl anion
  3. C.cyclopentadienyl cation
  4. D.a cyclopentadiene drawn with two negative charges (dianion)

Correct answer: B

Question 43

Chemistry · 4 marks · −1

1-methyl-1-vinylcyclohexane →HBr, CCl4\xrightarrow{\text{HBr, CCl}_4} A (Major Product). Product "A" in the above chemical reaction is:

Figure for question 43
  1. A.1-(2-bromoethyl)-1-methylcyclohexane
  2. B.1-bromo-1,2-dimethylcyclohexane
  3. C.1-bromo-1-isopropylcyclohexane
  4. D.1-(1-bromoethyl)-2-methylcyclohexane type (Br on side-chain CH, CH3 on adjacent ring carbon)

Correct answer: C

Question 44

Chemistry · 4 marks · −1

Chlorobenzene + NaOH →\rightarrow sodium phenoxide. The above reaction requires which of the following reaction conditions?

  1. A.623 K, Cu, 300 atm
  2. B.573 K, Cu, 300 atm
  3. C.623 K, 300 atm
  4. D.573 K, 300 atm

Correct answer: C

Question 45

Chemistry · 4 marks · −1

Mesityl oxide is a common name of:

  1. A.4-Methyl pent-3-en-2-one
  2. B.2,4-Dimethyl pentan-3-one
  3. C.2-Methyl cyclohexanone
  4. D.3-Methyl cyclohexane carbaldehyde

Correct answer: A

Question 46

Chemistry · 4 marks · −1

Hoffmann bromomide degradation of benzamide gives product A, which upon heating with CHCl3_3 and NaOH gives product B. The structures of A and B are:

  1. A.A = 4-bromobenzamide; B = 4-bromo-2-formylbenzamide
  2. B.A = aniline; B = phenyl isocyanide (C6H5NC)
  3. C.A = 4-bromoaniline; B = 2-amino-5-bromobenzaldehyde
  4. D.A = aniline; B = 2-aminobenzaldehyde

Correct answer: B

Question 47

Chemistry · 4 marks · −1

Ethyl acetoacetate CH3COCH2COOC2H5→Ethylene Glycol, H+\mathrm{CH_3COCH_2COOC_2H_5}\xrightarrow{\text{Ethylene Glycol, H}^+} A (Major Product). The product "A" in the above reaction is:

  1. A.hemiacetal: CH3C(OH)(OCH2CH2OH)CH2COOC2H5
  2. B.2-methyl-1,3-dioxolane-2-acetic acid (ketal with free COOH)
  3. C.3-ethoxy-3-hydroxycyclobutanone
  4. D.ethyl 2-methyl-1,3-dioxolane-2-acetate (ketal, ester retained)

Correct answer: D

Question 48

Chemistry · 4 marks · −1

Which of the following reaction is an example of ammonolysis?

  1. A.C6H5COCl+C6H5NH2→C6H5CONHC6H5\mathrm{C_6H_5COCl+C_6H_5NH_2\rightarrow C_6H_5CONHC_6H_5}
  2. B.C6H5CH2CN→[H]C6H5CH2CH2NH2\mathrm{C_6H_5CH_2CN\xrightarrow{[H]}C_6H_5CH_2CH_2NH_2}
  3. C.C6H5CH2Cl+NH3→C6H5CH2NH2\mathrm{C_6H_5CH_2Cl+NH_3\rightarrow C_6H_5CH_2NH_2}
  4. D.C6H5NH2→HClC6H5N+H3Cl−\mathrm{C_6H_5NH_2\xrightarrow{HCl}C_6H_5\overset{+}{N}H_3Cl^-}

Correct answer: C

Question 49

Chemistry · 4 marks · −1

With respect to drug-enzyme interaction, identify the wrong statement.

  1. A.Competitive inhibitor binds to the enzyme's active site
  2. B.Allosteric inhibitor changes the enzyme's active site
  3. C.Allosteric inhibitor competes with the enzyme's active site
  4. D.Non-Competitive inhibitor binds to the allosteric site

Correct answer: C

Question 50

Chemistry · 4 marks · −1

Which of the following is correct structure of tyrosine?

Figure for question 50
  1. A.H2N-CH(COOH)-CH2-C6H4-OH with OH meta
  2. B.H2N-CH(COOH)-CH2CH2-C6H4-OH with OH meta
  3. C.H2N-CH(COOH)-CH2-C6H4-OH with OH para
  4. D.H2N-CH(COOH)-CH2CH2-C6H4-OH with OH para

Correct answer: C

Question 51

Chemistry · 4 marks

The mole fraction of a solute in a 100 molal aqueous solution is ________ ×10−2\times10^{-2}. (Round off to the Nearest Integer). [Given: Atomic masses: H: 1.0 u, O: 16.0 u]

Correct answer: 64

Explanation: 100100+55.5≈0.64\frac{100}{100+55.5}\approx0.64.

Question 52

Chemistry · 4 marks

The pressure exerted by a non-reactive gaseous mixture of 6.4 g of methane and 8.8 g of carbon dioxide in a 10 L vessel at 27°C is ________ kPa. (Round off to the Nearest Integer). [Assume gases are ideal, R = 8.314 J mol−1^{-1} K−1^{-1}; Atomic masses: C: 12.0 u, H: 1.0 u, O: 16.0 u]

Correct answer: 150

Explanation: 0.6 mol: P=0.6×8.314×3000.01≈150P=\frac{0.6\times8.314\times300}{0.01}\approx150 kPa.

Question 53

Chemistry · 4 marks

A certain orbital has n = 4 and mL=−3m_L=-3. The number of radial nodes in this orbital is ________. (Round off to the Nearest Integer).

Correct answer: 0

Explanation: l=3l=3: n−l−1=0n-l-1=0.

Question 54

Chemistry · 4 marks

The standard enthalpies of formation of Al2_2O3_3 and CaO are −1675-1675 kJ mol−1^{-1} and −635-635 kJ mol−1^{-1} respectively. For the reaction 3CaO+2Al→3Ca+Al2O3\mathrm{3CaO+2Al\rightarrow3Ca+Al_2O_3} the standard reaction enthalpy ΔrH0\Delta_rH^0 = ________ kJ. (Round off to the Nearest Integer).

Correct answer: 230

Explanation: −1675+1905=230-1675+1905=230 kJ.

Question 55

Chemistry · 4 marks

The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is ________ ×10−5\times10^{-5} mol dm−3^{-3}. (Round off to the Nearest Integer). [Given: Henry\'s law constant = KH=8.0×104K_H=8.0\times10^4 kPa for O2_2. Density of water with dissolved oxygen = 1.0 kg dm−3^{-3}]

Correct answer: 25

Explanation: Mole fraction x=p/KH=2.5×10−4x=p/K_H=2.5\times10^{-4}; the official answer 25 treats this as 25×10−525\times10^{-5} (i.e. equates mole fraction with the requested quantity). A strict conversion to mol dm−3^{-3} (×55.5\times55.5) would give about 1388.

Question 56

Chemistry · 4 marks

0.01 moles of a weak acid HA (Ka=2.0×10−6K_a=2.0\times10^{-6}) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is ________ ×10−5\times10^{-5} (Round off to the Nearest Integer). [Neglect volume change on adding HA. Assume degree of dissociation <<1]

Correct answer: 2

Explanation: α=Ka/[H+]=2×10−5\alpha=K_a/[H^+]=2\times10^{-5}.

Question 57

Chemistry · 4 marks

15 mL of aqueous solution of Fe2+^{2+} in acidic medium completely reacted with 20 mL of 0.03 M aqueous Cr2_2O72−_7^{2-}. The molarity of the Fe2+^{2+} solution is ________ ×10−2\times10^{-2} M. (Round off to the Nearest Integer).

Correct answer: 24

Explanation: 6×0.66\times0.6 mmol / 15 mL = 0.24 M.

Question 58

Chemistry · 4 marks

For a certain first order reaction 32% of the reactant is left after 570 s. The rate constant of this reaction is ________ ×10−3\times10^{-3} s−1^{-1}. (Round off to the Nearest Integer). [Given: log⁡102=0.301\log_{10}2=0.301, ln 10 = 2.303]

Correct answer: 2

Explanation: k=ln⁡(1/0.32)570≈2×10−3k=\frac{\ln(1/0.32)}{570}\approx2\times10^{-3}.

Question 59

Chemistry · 4 marks

The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction of 1 mol of 'A' with excess of AgNO3_3 in aqueous medium gives ________ mol(s) of Ag. (Round off to the Nearest Integer).

Correct answer: 4

Question 60

Chemistry · 4 marks

Benzene →HNO3/H2SO4\xrightarrow{\text{HNO}_3/\text{H}_2\text{SO}_4} nitrobenzene. In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ________ %. (Round off to the Nearest Integer). (Given atomic mass: C: 12.0 u, H: 1.0 u, O: 16.0 u, N: 14.0 u)

Correct answer: 80

Explanation: Theoretical 6.15 g: 80%.

Question 61

Mathematics · 4 marks · −1

In a school, there are three types of games to be played. Some of the students play two types of games, but none play all the three games. Which Venn diagrams can justify the above statement?

Figure for question 61
  1. A.P and Q
  2. B.P and R
  3. C.Q and R
  4. D.None of these

Correct answer: D

Question 62

Mathematics · 4 marks · −1

The area of the triangle with vertices A(z)A(z), B(iz)B(iz) and C(z+iz)C(z+iz) is:

  1. A.12∣z+iz∣2\frac12|z+iz|^2
  2. B.12∣z∣2\frac12|z|^2
  3. C.12\frac12
  4. D.1

Correct answer: B

Question 63

Mathematics · 4 marks · −1

If A=(0sin⁡αsin⁡α0)A=\begin{pmatrix}0&\sin\alpha\\\sin\alpha&0\end{pmatrix} and det⁡(A2−12I)=0\det\left(A^2-\frac12I\right)=0, then a possible value of α\alpha is:

  1. A.π4\frac\pi4
  2. B.π3\frac\pi3
  3. C.π6\frac\pi6
  4. D.π2\frac\pi2

Correct answer: A

Question 64

Mathematics · 4 marks · −1

The system of equations kx+y+z=1kx+y+z=1, x+ky+z=kx+ky+z=k and x+y+zk=k2x+y+zk=k^2 has no solution if k is equal to:

  1. A.0
  2. B.1
  3. C.−1
  4. D.−2

Correct answer: D

Question 65

Mathematics · 4 marks · −1

Team 'A' consists of 7 boys and n girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to:

  1. A.2
  2. B.4
  3. C.5
  4. D.6

Correct answer: B

Explanation: 28+6n=5228+6n=52.

Question 66

Mathematics · 4 marks · −1

If the fourth term in the expansion of (x+xlog⁡2x)7(x+x^{\log_2x})^7 is 4480, then the value of x where x∈Nx\in\mathbb{N} is equal to:

  1. A.1
  2. B.2
  3. C.3
  4. D.4

Correct answer: B

Question 67

Mathematics · 4 marks · −1

The value of 4+15+14+15+14+…∞4+\cfrac{1}{5+\cfrac{1}{4+\cfrac{1}{5+\cfrac{1}{4+\dots\infty}}}} is:

  1. A.2+25302+\frac25\sqrt{30}
  2. B.2+45302+\frac4{\sqrt5}\sqrt{30}
  3. C.5+25305+\frac25\sqrt{30}
  4. D.4+45304+\frac4{\sqrt5}\sqrt{30}

Correct answer: A

Explanation: y=4+y5y+1⇒5y2−20y−4=0y=4+\frac{y}{5y+1}\Rightarrow5y^2-20y-4=0.

Question 68

Mathematics · 4 marks · −1

If cot⁡−1(α)=cot⁡−12+cot⁡−18+cot⁡−118+cot⁡−132+…\cot^{-1}(\alpha)=\cot^{-1}2+\cot^{-1}8+\cot^{-1}18+\cot^{-1}32+\dots upto 100 terms, then α\alpha is:

  1. A.1.00
  2. B.1.01
  3. C.1.02
  4. D.1.03

Correct answer: B

Explanation: cot⁡−12n2=tan⁡−1(2n+1)−tan⁡−1(2n−1)\cot^{-1}2n^2=\tan^{-1}(2n+1)-\tan^{-1}(2n-1): sum =tan⁡−1201−tan⁡−11=cot⁡−1202200=\tan^{-1}201-\tan^{-1}1=\cot^{-1}\frac{202}{200}.

Question 69

Mathematics · 4 marks · −1

The inverse of y=5log⁡xy=5^{\log x} is:

  1. A.x=51log⁡yx=5^{\frac1{\log y}}
  2. B.x=y1log⁡5x=y^{\frac1{\log5}}
  3. C.x=5log⁡yx=5^{\log y}
  4. D.x=ylog⁡5x=y^{\log5}

Correct answer: B

Question 70

Mathematics · 4 marks · −1

The value of lim⁡x→0+cos⁡−1(x−[x]2)⋅sin⁡−1(x−[x]2)x−x3\lim_{x\to0^+}\frac{\cos^{-1}(x-[x]^2)\cdot\sin^{-1}(x-[x]^2)}{x-x^3}, where [x] denotes the greatest integer ≤x\le x is:

  1. A.π4\frac\pi4
  2. B.0
  3. C.π2\frac\pi2
  4. D.π\pi

Correct answer: C

Question 71

Mathematics · 4 marks · −1

Which of the following statements is incorrect for the function g(α)g(\alpha) for α∈R\alpha\in\mathbb{R} such that g(α)=∫π/6π/3sin⁡αxcos⁡αx+sin⁡αxdxg(\alpha)=\int_{\pi/6}^{\pi/3}\frac{\sin^\alpha x}{\cos^\alpha x+\sin^\alpha x}dx

  1. A.g(α)g(\alpha) is a strictly increasing function
  2. B.g(α)g(\alpha) is a strictly decreasing function
  3. C.g(α)g(\alpha) has an inflection point at α=−12\alpha=-\frac12
  4. D.g(α)g(\alpha) is an even function

Correct answer: D

Explanation: By x→π2−xx\to\frac\pi2-x, g(α)=π12g(\alpha)=\frac{\pi}{12} for every α\alpha (constant).

Question 72

Mathematics · 4 marks · −1

Which of the following is true for y(x) that satisfies the differential equation dydx=xy−1+x−y\frac{dy}{dx}=xy-1+x-y; y(0)=0y(0)=0:

  1. A.y(1)=e−12−1y(1)=e^{-\frac12}-1
  2. B.y(1)=e12−1y(1)=e^{\frac12}-1
  3. C.y(1)=e12−e−12y(1)=e^{\frac12}-e^{-\frac12}
  4. D.y(1)=1y(1)=1

Correct answer: A

Explanation: dyy+1=(x−1)dx\frac{dy}{y+1}=(x-1)dx.

Question 73

Mathematics · 4 marks · −1

In a triangle PQR, the co-ordinates of the points P and Q are (−2,4)(-2,4) and (4,−2)(4,-2) respectively. If the equation of the perpendicular bisector of PR is 2x−y+2=02x-y+2=0, then the centre of the circumcircle of the ΔPQR\Delta PQR is:

  1. A.(1, 4)
  2. B.(0, 2)
  3. C.(−1, 0)
  4. D.(−2, −2)

Correct answer: D

Explanation: Perpendicular bisector of PQ is y=xy=x; with 2x−y+2=02x-y+2=0: (−2,−2)(-2,-2).

Question 74

Mathematics · 4 marks · −1

The line 2x−y+1=02x-y+1=0 is a tangent to the circle at the point (2, 5) and the centre of the circle lies on x−2y=4x-2y=4. Then, the radius of the circle is:

  1. A.535\sqrt3
  2. B.545\sqrt4
  3. C.454\sqrt5
  4. D.353\sqrt5

Correct answer: D

Explanation: Centre (8,2)(8,2), r=45r=\sqrt{45}.

Question 75

Mathematics · 4 marks · −1

Choose the incorrect statement about the two circles whose equations are given below: x2+y2−10x−10y+41=0x^2+y^2-10x-10y+41=0 and x2+y2−16x−10y+80=0x^2+y^2-16x-10y+80=0

  1. A.Circles have two intersection points.
  2. B.Both circles pass through the centre of each other.
  3. C.Both circles' centres lie inside region of one another.
  4. D.Distance between two centres is the average of radii of both the circles.

Correct answer: C

Question 76

Mathematics · 4 marks · −1

The equation of the plane which contains the y-axis and passes through the point (1, 2, 3) is:

  1. A.3x+z=63x+z=6
  2. B.x+3z=10x+3z=10
  3. C.x+3z=0x+3z=0
  4. D.3x−z=03x-z=0

Correct answer: D

Question 77

Mathematics · 4 marks · −1

If the Boolean expression (p⇒q)⇔(q∗(∼p))(p\Rightarrow q)\Leftrightarrow(q*(\sim p)) is a tautology, then the Boolean expression p∗(∼q)p*(\sim q) is equivalent to:

  1. A.p⇒qp\Rightarrow q
  2. B.p⇒∼qp\Rightarrow\sim q
  3. C.q⇒pq\Rightarrow p
  4. D.∼q⇒p\sim q\Rightarrow p

Correct answer: C

Question 78

Mathematics · 4 marks · −1

Let a⃗=2i^−3j^+4k^\vec a=2\hat i-3\hat j+4\hat k and b⃗=7i^+j^−6k^\vec b=7\hat i+\hat j-6\hat k. If r⃗×a⃗=r⃗×b⃗\vec r\times\vec a=\vec r\times\vec b, r⃗⋅(i^+2j^+k^)=−3\vec r\cdot(\hat i+2\hat j+\hat k)=-3, then r⃗⋅(2i^−3j^+k^)\vec r\cdot(2\hat i-3\hat j+\hat k) is equal to:

  1. A.8
  2. B.10
  3. C.12
  4. D.13

Correct answer: C

Explanation: r⃗=λ(a⃗−b⃗)=λ(−5,−4,10)\vec r=\lambda(\vec a-\vec b)=\lambda(-5,-4,10), λ=1\lambda=1: value 12.

Question 79

Mathematics · 4 marks · −1

Two dices are rolled. If both dices have six faces numbered 1, 2, 3, 5, 7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:

  1. A.512\frac5{12}
  2. B.49\frac49
  3. C.1736\frac{17}{36}
  4. D.12\frac12

Correct answer: C

Question 80

Mathematics · 4 marks · −1

The sum of possible values of x for tan⁡−1(x+1)+cot⁡−1(1x−1)=tan⁡−1(831)\tan^{-1}(x+1)+\cot^{-1}\left(\frac1{x-1}\right)=\tan^{-1}\left(\frac8{31}\right) is:

  1. A.−334-\frac{33}4
  2. B.−324-\frac{32}4
  3. C.−314-\frac{31}4
  4. D.−304-\frac{30}4

Correct answer: B

Explanation: Taking the principal value cot⁡−11x−1=π+tan⁡−1(x−1)\cot^{-1}\frac1{x-1}=\pi+\tan^{-1}(x-1) for x<1x<1: the tangent equation gives 4x2+31x−8=04x^2+31x-8=0, but only x=−8x=-8 satisfies the original equation (x=14x=\frac14 gives an angle exceeding π\pi). Sum =−8=−324=-8=-\frac{32}{4}.

Question 81

Mathematics · 4 marks

The maximum value of z in the following equation z=6xy+y2z=6xy+y^2, where 3x+4y≤1003x+4y\le100 and 4x+3y≤754x+3y\le75 for x≥0x\ge0 and y≥0y\ge0 is ________.

Correct answer: 904

Question 82

Mathematics · 4 marks

If A=[230−1]A=\begin{bmatrix}2&3\\0&-1\end{bmatrix}, then the value of det⁡(A4)+det⁡(A10−(Adj(2A))10)\det(A^4)+\det(A^{10}-(\mathrm{Adj}(2A))^{10}) is equal to ________.

Correct answer: 16

Question 83

Mathematics · 4 marks

If (2021)3762(2021)^{3762} is divided by 17, then the remainder is ________.

Correct answer: 4

Explanation: 2021≡−22021\equiv-2; 28≡1(mod17)2^8\equiv1\pmod{17}, 3762≡2(mod8)3762\equiv2\pmod8: remainder 4.

Question 84

Mathematics · 4 marks

If the function f(x)=cos⁡(sin⁡x)−cos⁡xx4f(x)=\frac{\cos(\sin x)-\cos x}{x^4} is continuous at each point in its domain and f(0)=1kf(0)=\frac1k, then k is ________.

Correct answer: 6

Explanation: Numerator ≈x46\approx\frac{x^4}{6}: k=6k=6.

Question 85

Mathematics · 4 marks

If [·] represents the greatest integer function, then the value of ∣∫0π/2[[x2]−cos⁡x]dx∣\left|\int_0^{\sqrt{\pi/2}}\left[[x^2]-\cos x\right]dx\right| is ________.

Correct answer: 1

Explanation: Integrand is −1-1 on (0,1)(0,1) and 00 on (1,π/2)(1,\sqrt{\pi/2}): value 1.

Question 86

Mathematics · 4 marks

The minimum distance between any two points P1P_1 and P2P_2 while considering point P1P_1 on one circle and point P2P_2 on the other circle for the given circles' equations x2+y2−10x−10y+41=0x^2+y^2-10x-10y+41=0, x2+y2−24x−10y+160=0x^2+y^2-24x-10y+160=0 is ________.

Correct answer: 1

Explanation: Centres 7 apart, radii 3 and 3: 1.

Question 87

Mathematics · 4 marks

If the equation of the plane passing through the line of intersection of the planes 2x−7y+4z−3=02x-7y+4z-3=0, 3x−5y+4z+11=03x-5y+4z+11=0 and the point (−2,1,3)(-2,1,3) is ax+by+cz−7=0ax+by+cz-7=0, then the value of 2a+b+c−72a+b+c-7 is ________.

Correct answer: 4

Explanation: Plane 15x−47y+28z−7=015x-47y+28z-7=0: 30−47+28−7=430-47+28-7=4.

Question 88

Mathematics · 4 marks

Let there be three independent events E1E_1, E2E_2 and E3E_3. The probability that only E1E_1 occurs is α\alpha, only E2E_2 occurs is β\beta and only E3E_3 occurs is γ\gamma. Let 'p' denote the probability of none of events occurs that satisfies the equations (α−2β)p=αβ(\alpha-2\beta)p=\alpha\beta and (β−3γ)p=2βγ(\beta-3\gamma)p=2\beta\gamma. All the given probabilities are assumed to lie in the interval (0, 1). Then, Probability of occurrence of E1Probability of occurrence of E3\frac{\text{Probability of occurrence of }E_1}{\text{Probability of occurrence of }E_3} is equal to ________.

Correct answer: 6

Question 89

Mathematics · 4 marks

If f(x)=sin⁡(cos⁡−1(1−22x1+22x))f(x)=\sin\left(\cos^{-1}\left(\frac{1-2^{2x}}{1+2^{2x}}\right)\right) and its first derivative with respect to x is −balog⁡e2-\frac ba\log_e2 when x=1x=1, where a and b are integers, then the minimum value of ∣a2−b2∣|a^2-b^2| is ________.

Correct answer: 481

Explanation: f=2t1+t2f=\frac{2t}{1+t^2}, t=2xt=2^x; f(ˊ1)=−1225ln⁡2f\'(1)=-\frac{12}{25}\ln2: 625−144=481625-144=481.

Question 90

Mathematics · 4 marks

If a⃗=αi^+βj^+3k^\vec a=\alpha\hat i+\beta\hat j+3\hat k, b⃗=−βi^−αj^−k^\vec b=-\beta\hat i-\alpha\hat j-\hat k and c⃗=i^−2j^−k^\vec c=\hat i-2\hat j-\hat k such that a⃗⋅b⃗=1\vec a\cdot\vec b=1 and b⃗⋅c⃗=−3\vec b\cdot\vec c=-3, then 13((a⃗×b⃗)⋅c⃗)\frac13((\vec a\times\vec b)\cdot\vec c) is equal to ________.

Correct answer: 2

Explanation: α=−1,β=2\alpha=-1,\beta=2; [a⃗ b⃗ c⃗]=6[\vec a\,\vec b\,\vec c]=6, answer 2.

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