JEE Main 2024 — 27 Jan Shift 1 (Previous Year Paper)

JEE Main · 2024 · with answers and explanations

questions
89
Total marks
296
Duration
180 minutes
Negative marking
−1

Subjects: Mathematics · Physics · Chemistry

Question 1

Mathematics · 4 marks · −1

Consider the function f(x)={a(7x−12−x2)b ∣x2−7x+12∣,x<32sin⁡(x−3)x−[x],x>3b,x=3f(x)=\begin{cases}\dfrac{a(7x-12-x^2)}{b\,|x^2-7x+12|}, & x<3\\[4pt] 2^{\frac{\sin(x-3)}{x-[x]}}, & x>3\\[4pt] b, & x=3\end{cases} where [x][x] denotes the greatest integer less than or equal to xx. If SS denotes the set of all ordered pairs (a,b)(a,b) such that f(x)f(x) is continuous at x=3x=3, then the number of elements in SS is :

  1. A.2
  2. B.Infinitely many
  3. C.4
  4. D.1

Correct answer: D

Explanation: For x→3−x\to3^-, x2−7x+12=(x−3)(x−4)>0x^2-7x+12=(x-3)(x-4)>0 and 7x−12−x2=−(x−3)(x−4)7x-12-x^2=-(x-3)(x-4), so LHL =−a/b=-a/b. For x→3+x\to3^+, x−[x]=x−3x-[x]=x-3, so RHL =21=2=2^1=2. Continuity: b=2b=2, a=−4a=-4; exactly one pair.

Question 2

Mathematics · 4 marks · −1

The distance, of the point (7,−2,11)(7,-2,11) from the line x−61=y−40=z−83\frac{x-6}{1}=\frac{y-4}{0}=\frac{z-8}{3} along the line x−52=y−1−3=z−56\frac{x-5}{2}=\frac{y-1}{-3}=\frac{z-5}{6}, is:

  1. A.12
  2. B.14
  3. C.21
  4. D.18

Correct answer: B

Explanation: Point (7+2t,−2−3t,11+6t)(7+2t,-2-3t,11+6t) meets the first line when y=4y=4, i.e. t=−2t=-2, giving (3,4,−1)(3,4,-1) which lies on it. Distance =∣t∣4+9+36=14=|t|\sqrt{4+9+36}=14.

Question 3

Mathematics · 4 marks · −1

If the shortest distance of the parabola y2=4xy^2=4x from the centre of the circle x2+y2−4x−16y+64=0x^2+y^2-4x-16y+64=0 is dd, then d2d^2 is equal to :

  1. A.36
  2. B.20
  3. C.24
  4. D.16

Correct answer: B

Explanation: Centre (2,8)(2,8). Normal at (t2,2t)(t^2,2t): y=−tx+2t+t3y=-tx+2t+t^3 through (2,8)(2,8) gives t3=8t^3=8, t=2t=2, foot (4,4)(4,4). d2=4+16=20d^2=4+16=20.

Question 4

Mathematics · 4 marks · −1

If (a,b)(a,b) be the orthocentre of the triangle whose vertices are (1,2)(1,2), (2,3)(2,3) and (3,1)(3,1), and I1=∫abxsin⁡(4x−x2) dxI_1=\int_a^b x\sin(4x-x^2)\,dx, I2=∫absin⁡(4x−x2) dxI_2=\int_a^b \sin(4x-x^2)\,dx, then 36I1I236\frac{I_1}{I_2} is equal to:

  1. A.88
  2. B.72
  3. C.66
  4. D.80

Correct answer: B

Explanation: Orthocentre (5/3,7/3)(5/3,7/3), so a+b=4a+b=4. Since 4x−x24x-x^2 is symmetric about x=2x=2, I1=a+b2I2=2I2I_1=\frac{a+b}{2}I_2=2I_2; 36⋅2=7236\cdot2=72.

Question 5

Mathematics · 4 marks · −1

The portion of the line 4x+5y=204x+5y=20 in the first quadrant is trisected by the lines L1L_1 and L2L_2 passing through the origin. The tangent of an angle between the lines L1L_1 and L2L_2 is :

  1. A.85\frac{8}{5}
  2. B.25\frac{2}{5}
  3. C.2541\frac{25}{41}
  4. D.3041\frac{30}{41}

Correct answer: D

Explanation: Trisection points (10/3,4/3)(10/3,4/3) and (5/3,8/3)(5/3,8/3); slopes 2/52/5 and 8/58/5; tan⁡θ=6/51+16/25=3041\tan\theta=\frac{6/5}{1+16/25}=\frac{30}{41}.

Question 6

Mathematics · 4 marks · −1

Let a1,a2,…,a10a_1,a_2,\ldots,a_{10} be 10 observations such that ∑k=110ak=50\sum_{k=1}^{10}a_k=50 and ∑∀k<jak⋅aj=1100\sum_{\forall k<j}a_k\cdot a_j=1100. Then the standard deviation of a1,a2,…,a10a_1,a_2,\ldots,a_{10} is equal to:

  1. A.5
  2. B.10
  3. C.5\sqrt{5}
  4. D.115\sqrt{115}

Correct answer: C

Explanation: ∑ak2=502−2(1100)=300\sum a_k^2=50^2-2(1100)=300; variance =30−25=5=30-25=5; SD =5=\sqrt5.

Question 7

Mathematics · 4 marks · −1

n−1Cr=(k2−8) nCr+1{}^{n-1}C_r=(k^2-8)\,{}^{n}C_{r+1} if and only if:

  1. A.23<k<332\sqrt{3}<k<3\sqrt{3}
  2. B.23<k≤322\sqrt{3}<k\le3\sqrt{2}
  3. C.22<k<232\sqrt{2}<k<2\sqrt{3}
  4. D.22<k≤32\sqrt{2}<k\le3

Correct answer: D

Explanation: k2−8=r+1n∈(0,1]k^2-8=\frac{r+1}{n}\in(0,1], so 8<k2≤98<k^2\le9, i.e. 22<k≤32\sqrt2<k\le3.

Question 8

Mathematics · 4 marks · −1

The number of common terms in the progressions 4,9,14,19,…4,9,14,19,\ldots up to 25th25^{th} term and 3,6,9,12,…3,6,9,12,\ldots up to 37th37^{th} term is:

  1. A.9
  2. B.7
  3. C.5
  4. D.8

Correct answer: B

Explanation: Last terms 124 and 111. Common terms are ≡9(mod15)\equiv 9 \pmod{15}: 9,24,…,999,24,\ldots,99 — 7 terms.

Question 9

Mathematics · 4 marks · −1

The length of the chord of the ellipse x225+y216=1\frac{x^2}{25}+\frac{y^2}{16}=1, whose mid-point is (1,25)\left(1,\frac{2}{5}\right), is equal to:

  1. A.17415\frac{\sqrt{1741}}{5}
  2. B.20095\frac{\sqrt{2009}}{5}
  3. C.16915\frac{\sqrt{1691}}{5}
  4. D.15415\frac{\sqrt{1541}}{5}

Correct answer: C

Explanation: Chord T=S1T=S_1: 8x+5y=108x+5y=10. Substituting gives 4x2−8x−15=04x^2-8x-15=0, ∣x1−x2∣=19|x_1-x_2|=\sqrt{19}, slope −8/5-8/5, length =19⋅895=16915=\sqrt{19}\cdot\frac{\sqrt{89}}{5}=\frac{\sqrt{1691}}{5}.

Question 10

Mathematics · 4 marks · −1

If the shortest distance between the lines x−41=y+12=z−3\frac{x-4}{1}=\frac{y+1}{2}=\frac{z}{-3} and x−λ2=y+14=z−2−5\frac{x-\lambda}{2}=\frac{y+1}{4}=\frac{z-2}{-5} is 65\frac{6}{\sqrt5}, then the sum of all possible values of λ\lambda is:

  1. A.7
  2. B.5
  3. C.8
  4. D.10

Correct answer: C

Explanation: d1×d2=(2,−1,0)d_1\times d_2=(2,-1,0); ∣2(λ−4)∣5=65⇒λ=7,1\frac{|2(\lambda-4)|}{\sqrt5}=\frac{6}{\sqrt5}\Rightarrow\lambda=7,1; sum 8.

Question 11

Mathematics · 4 marks · −1

Let S={1,2,3,…,10}S=\{1,2,3,\ldots,10\}. Suppose MM is the set of all the subsets of SS, then the relation R={(A,B):A∩B≠ϕ; A,B∈M}R=\{(A,B):A\cap B\ne\phi;\ A,B\in M\} is:

  1. A.symmetric and reflexive only
  2. B.symmetric only
  3. C.reflexive only
  4. D.symmetric and transitive only

Correct answer: B

Explanation: Not reflexive (ϕ∩ϕ=ϕ\phi\cap\phi=\phi), symmetric, not transitive.

Question 12

Mathematics · 4 marks · −1

If a=lim⁡x→01+1+x4−2x4a=\lim_{x\to0}\frac{\sqrt{1+\sqrt{1+x^4}}-\sqrt2}{x^4} and b=lim⁡x→0sin⁡2x2−1+cos⁡xb=\lim_{x\to0}\frac{\sin^2x}{\sqrt2-\sqrt{1+\cos x}}, then the value of ab3ab^3 is:

  1. A.32
  2. B.36
  3. C.25
  4. D.30

Correct answer: A

Explanation: a=28a=\frac{\sqrt2}{8}, b=42b=4\sqrt2; ab3=28⋅1282=32ab^3=\frac{\sqrt2}{8}\cdot128\sqrt2=32.

Question 13

Mathematics · 4 marks · −1

If ∫0113+x+1+x dx=a+b2+c3\int_0^1\frac{1}{\sqrt{3+x}+\sqrt{1+x}}\,dx=a+b\sqrt2+c\sqrt3, where a,b,ca,b,c are rational numbers, then 2a+3b−4c2a+3b-4c is equal to:

  1. A.4
  2. B.8
  3. C.7
  4. D.10

Correct answer: B

Explanation: Rationalise: 12∫01(3+x−1+x)dx=3−232−3\frac12\int_0^1(\sqrt{3+x}-\sqrt{1+x})dx=3-\frac{2}{3}\sqrt2-\sqrt3; 2a+3b−4c=6−2+4=82a+3b-4c=6-2+4=8.

Question 14

Mathematics · 4 marks · −1

Consider the matrix f(x)=[cos⁡x−sin⁡x0sin⁡xcos⁡x0001]f(x)=\begin{bmatrix}\cos x&-\sin x&0\\\sin x&\cos x&0\\0&0&1\end{bmatrix}. Given below are two statements: Statement I: f(−x)f(-x) is the inverse of the matrix f(x)f(x). Statement II: f(x)f(y)=f(x+y)f(x)f(y)=f(x+y). In the light of the above statements, choose the correct answer from the options given below:

  1. A.Both Statement I and Statement II are true
  2. B.Statement I is false but Statement II is true
  3. C.Both Statement I and Statement II are false
  4. D.Statement I is true but Statement II is false

Correct answer: A

Explanation: ff is a rotation matrix: f(x)f(y)=f(x+y)f(x)f(y)=f(x+y) and f(x)f(−x)=f(0)=If(x)f(-x)=f(0)=I.

Question 15

Mathematics · 4 marks · −1

The function f:N−{1}→Nf:\mathbb{N}-\{1\}\to\mathbb{N}; defined by f(n)=f(n)= the highest prime factor of nn, is :

  1. A.both one-one and onto
  2. B.onto only
  3. C.neither one-one nor onto
  4. D.one-one only

Correct answer: C

Explanation: f(2)=f(4)f(2)=f(4) (not one-one); range contains only primes (not onto).

Question 16

Mathematics · 4 marks · −1

Let a⃗=i^+2j^+k^\vec a=\hat i+2\hat j+\hat k, b⃗=3(i^−j^+k^)\vec b=3(\hat i-\hat j+\hat k). Let c⃗\vec c be the vector such that a⃗×c⃗=b⃗\vec a\times\vec c=\vec b and a⃗⋅c⃗=3\vec a\cdot\vec c=3. Then a⃗⋅((c⃗×b⃗)−b⃗−c⃗)\vec a\cdot\left((\vec c\times\vec b)-\vec b-\vec c\right) is equal to:

  1. A.24
  2. B.36
  3. C.32
  4. D.20

Correct answer: A

Explanation: a⃗⋅(c⃗×b⃗)=(a⃗×c⃗)⋅b⃗=∣b⃗∣2=27\vec a\cdot(\vec c\times\vec b)=(\vec a\times\vec c)\cdot\vec b=|\vec b|^2=27, a⃗⋅b⃗=0\vec a\cdot\vec b=0, a⃗⋅c⃗=3\vec a\cdot\vec c=3: 27−0−3=2427-0-3=24.

Question 17

Mathematics · 4 marks · −1

If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n(1-3x+10x^2)^n and B denotes the sum of all the coefficients in the expansion of (1+x2)n(1+x^2)^n, then:

  1. A.A=B3A=B^3
  2. B.A=3BA=3B
  3. C.B=A3B=A^3
  4. D.3A=B3A=B

Correct answer: A

Explanation: A=8nA=8^n, B=2nB=2^n, so A=B3A=B^3.

Question 18

Mathematics · 4 marks · −1

Four distinct points (2k,3k)(2k,3k), (1,0)(1,0), (0,1)(0,1) and (0,0)(0,0) lie on a circle for kk equal to :

  1. A.313\frac{3}{13}
  2. B.513\frac{5}{13}
  3. C.113\frac{1}{13}
  4. D.213\frac{2}{13}

Correct answer: B

Explanation: Circle x2+y2−x−y=0x^2+y^2-x-y=0; 13k2=5k⇒k=5/1313k^2=5k\Rightarrow k=5/13.

Question 19

Mathematics · 4 marks · −1

Let x=x(t)x=x(t) and y=y(t)y=y(t) be solutions of the differential equations dxdt+ax=0\frac{dx}{dt}+ax=0 and dydt+by=0\frac{dy}{dt}+by=0 respectively, a,b∈Ra,b\in\mathbb{R}. Given that x(0)=2x(0)=2; y(0)=1y(0)=1 and 3y(1)=2x(1)3y(1)=2x(1). The value of tt, for which x(t)=y(t)x(t)=y(t), is:

  1. A.log⁡4/32\log_{4/3}2
  2. B.log⁡43\log_4 3
  3. C.log⁡2/32\log_{2/3}2
  4. D.log⁡34\log_3 4

Correct answer: A

Explanation: x=2e−atx=2e^{-at}, y=e−bty=e^{-bt}; ea−b=4/3e^{a-b}=4/3; x=y⇒(4/3)t=2x=y\Rightarrow(4/3)^t=2.

Question 20

Mathematics · 4 marks · −1

If S={z∈C:∣z−i∣=∣z+i∣=∣z−1∣}S=\{z\in\mathbb{C}:|z-i|=|z+i|=|z-1|\}, then, n(S)n(S) is:

  1. A.3
  2. B.0
  3. C.1
  4. D.2

Correct answer: C

Explanation: ∣z−i∣=∣z+i∣|z-i|=|z+i| gives the real axis; ∣z−i∣=∣z−1∣|z-i|=|z-1| gives y=xy=x; only z=0z=0.

Question 21

Mathematics · 4 marks · −1

If 8=3+14(3+p)+142(3+2p)+143(3+3p)+…∞8=3+\frac14(3+p)+\frac{1}{4^2}(3+2p)+\frac{1}{4^3}(3+3p)+\ldots\infty, then the value of pp is ______.

Correct answer: 9

Explanation: ∑3/4k=1\sum 3/4^k=1 and ∑kp/4k=4p9\sum kp/4^k=\frac{4p}{9}, so 8=4+4p98=4+\frac{4p}{9}, p=9p=9.

Question 22

Mathematics · 4 marks · −1

If α\alpha satisfies the equation x2+x+1=0x^2+x+1=0 and (1+α)7=A+Bα+Cα2(1+\alpha)^7=A+B\alpha+C\alpha^2, A,B,C≥0A,B,C\ge0, then 5(3A−2B−C)5(3A-2B-C) is equal to ______.

Correct answer: 5

Explanation: (1+α)7=(−α2)7=−α2=1+α(1+\alpha)^7=(-\alpha^2)^7=-\alpha^2=1+\alpha, so A=B=1A=B=1, C=0C=0; 5(3−2)=55(3-2)=5.

Question 23

Mathematics · 4 marks · −1

A fair die is tossed repeatedly until a six is obtained. Let XX denote the number of tosses required and let a=P(X=3)a=P(X=3), b=P(X≥3)b=P(X\ge3) and c=P(X≥6∣X>3)c=P(X\ge6\mid X>3). Then b+ca\frac{b+c}{a} is equal to ______.

Correct answer: 12

Explanation: a=25216a=\frac{25}{216}, b=2536b=\frac{25}{36}, c=(56)2=2536c=\left(\frac56\right)^2=\frac{25}{36}; b+ca=12\frac{b+c}{a}=12.

Question 24

Mathematics · 4 marks · −1

If the solution of the differential equation (2x+3y−2)dx+(4x+6y−7)dy=0(2x+3y-2)dx+(4x+6y-7)dy=0, y(0)=3y(0)=3, is αx+βy+3log⁡e∣2x+3y−γ∣=6\alpha x+\beta y+3\log_e|2x+3y-\gamma|=6, then α+2β+3γ\alpha+2\beta+3\gamma is equal to ______.

Correct answer: 29

Question 25

Mathematics · 4 marks · −1

Let for a differentiable function f:(0,∞)→Rf:(0,\infty)\to\mathbb{R}, f(x)−f(y)≥log⁡e(xy)+x−yf(x)-f(y)\ge\log_e\left(\frac{x}{y}\right)+x-y, ∀ x,y∈(0,∞)\forall\,x,y\in(0,\infty). Then ∑n=120f′(1n2)\sum_{n=1}^{20}f'\left(\frac{1}{n^2}\right) is equal to ______.

Correct answer: 2890

Explanation: Swapping x,yx,y gives equality, so f(x)=ln⁡x+x+cf(x)=\ln x+x+c, f′(x)=1x+1f'(x)=\frac1x+1; ∑(n2+1)=2870+20=2890\sum(n^2+1)=2870+20=2890.

Question 26

Mathematics · 4 marks · −1

The least positive integral value of α\alpha, for which the angle between the vectors αi^−2j^+2k^\alpha\hat i-2\hat j+2\hat k and αi^+2αj^−2k^\alpha\hat i+2\alpha\hat j-2\hat k is acute, is ______.

Correct answer: 5

Explanation: Dot product α2−4α−4>0⇒α>2+22≈4.83\alpha^2-4\alpha-4>0\Rightarrow\alpha>2+2\sqrt2\approx4.83; least integer 5.

Question 27

Mathematics · 4 marks · −1

Let the area of the region {(x,y):x−2y+4≥0, x+2y2≥0, x+4y2≤8, y≥0}\{(x,y):x-2y+4\ge0,\ x+2y^2\ge0,\ x+4y^2\le8,\ y\ge0\} be mn\frac{m}{n}, where mm and nn are coprime numbers. Then m+nm+n is equal to ______.

Correct answer: 119

Question 28

Mathematics · 4 marks · −1

Let f(x)=x3+x2f′(1)+xf′′(2)+f′′′(3)f(x)=x^3+x^2f'(1)+xf''(2)+f'''(3), x∈Rx\in\mathbb{R}. Then f′(10)f'(10) is equal to ______.

Correct answer: 202

Explanation: f′′′=6f'''=6; f′′(x)=6x+2f′(1)f''(x)=6x+2f'(1), f′(x)=3x2+2xf′(1)+f′′(2)f'(x)=3x^2+2xf'(1)+f''(2). Solving: f′(1)=−5f'(1)=-5, f′′(2)=2f''(2)=2; f′(10)=300−100+2=202f'(10)=300-100+2=202.

Question 29

Mathematics · 4 marks · −1

Let A=[201110101]A=\begin{bmatrix}2&0&1\\1&1&0\\1&0&1\end{bmatrix}, B=[B1,B2,B3]B=[B_1,B_2,B_3], where B1,B2,B3B_1,B_2,B_3 are column matrices, and AB1=[100]AB_1=\begin{bmatrix}1\\0\\0\end{bmatrix}, AB2=[230]AB_2=\begin{bmatrix}2\\3\\0\end{bmatrix}, AB3=[321]AB_3=\begin{bmatrix}3\\2\\1\end{bmatrix}. If α=∣B∣\alpha=|B| and β\beta is the sum of all the diagonal elements of BB, then α3+β3\alpha^3+\beta^3 is equal to ______.

Correct answer: 28

Question 30

Mathematics · 4 marks · −1

Let the set of all a∈Ra\in\mathbb{R} such that the equation cos⁡2x+asin⁡x=2a−7\cos2x+a\sin x=2a-7 has a solution be [p,q][p,q] and r=tan⁡9∘−tan⁡27∘−1cot⁡63∘+tan⁡81∘r=\tan9^\circ-\tan27^\circ-\frac{1}{\cot63^\circ}+\tan81^\circ, then pqrpqr is equal to ______.

Correct answer: 48

Question 31

Physics · 4 marks · −1

A plane electromagnetic wave propagating in xx-direction is described by Ey=(200 V m−1)sin⁡[1.5×107t−0.05x]E_y=(200\ \text{V m}^{-1})\sin[1.5\times10^7t-0.05x]; The intensity of the wave is : (Use ϵ0=8.85×10−12 C2N−1m−2\epsilon_0=8.85\times10^{-12}\ \text{C}^2\text{N}^{-1}\text{m}^{-2})

  1. A.106.2 W m−2106.2\ \text{W m}^{-2}
  2. B.53.1 W m−253.1\ \text{W m}^{-2}
  3. C.35.4 W m−235.4\ \text{W m}^{-2}
  4. D.26.6 W m−226.6\ \text{W m}^{-2}

Correct answer: B

Explanation: I=12cϵ0E02=12(3×108)(8.85×10−12)(4×104)=53.1I=\frac12c\epsilon_0E_0^2=\frac12(3\times10^8)(8.85\times10^{-12})(4\times10^4)=53.1 W m−2^{-2}.

Question 32

Physics · 4 marks · −1

The radius of third stationary orbit of electron for Bohr's atom is R. The radius of fourth stationary orbit will be:

  1. A.34R\frac34R
  2. B.916R\frac{9}{16}R
  3. C.43R\frac43R
  4. D.169R\frac{16}{9}R

Correct answer: D

Explanation: r∝n2r\propto n^2: r4=169Rr_4=\frac{16}{9}R.

Question 33

Physics · 4 marks · −1

0.08 kg air is heated at constant volume through 5°C. The specific heat of air at constant volume is 0.17 kcal/kg°C and J = 4.18 joule/cal. The change in its internal energy is approximately.

  1. A.298 J
  2. B.318 J
  3. C.284 J
  4. D.142 J

Correct answer: C

Explanation: ΔU=mcvΔT=0.08×0.17×5=0.068\Delta U=mc_v\Delta T=0.08\times0.17\times5=0.068 kcal ≈284\approx284 J.

Question 34

Physics · 4 marks · −1

Position of an ant (S in metres) moving in Y-Z plane is given by S⃗=2t2j^+5k^\vec S=2t^2\hat j+5\hat k (where t is in second). The magnitude and direction of velocity of the ant at t = 1 s will be :

  1. A.16 m/s in y-direction
  2. B.4 m/s in y-direction
  3. C.4 m/s in x-direction
  4. D.9 m/s in z-direction

Correct answer: B

Explanation: v⃗=4tj^\vec v=4t\hat j; at t=1t=1 s, 4 m/s along yy.

Question 35

Physics · 4 marks · −1

Given below are two statements : Statement (I) : Planck's constant and angular momentum have same dimensions. Statement (II) : Linear momentum and moment of force have same dimensions. In the light of the above statements, choose the correct answer from the options given below :

  1. A.Both Statement I and Statement II are true
  2. B.Statement I is false but Statement II is true
  3. C.Both Statement I and Statement II are false
  4. D.Statement I is true but Statement II is false

Correct answer: D

Explanation: hh and LL are both [ML2^2T−1^{-1}]; momentum [MLT−1^{-1}] differs from torque [ML2^2T−2^{-2}].

Question 36

Physics · 4 marks · −1

A body of mass 1000 kg is moving horizontally with a velocity 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is :

  1. A.3
  2. B.5
  3. C.6
  4. D.2

Correct answer: B

Explanation: 1000×6=1200v⇒v=51000\times6=1200v\Rightarrow v=5 m/s.

Question 37

Physics · 4 marks · −1

Which of the following circuits is reverse - biased ?

Figure for question 37
  1. A.Circuit (1): ground — diode (anode at ground) — resistor — −5-5 V
  2. B.Circuit (2): +2+2 V — resistor — diode (anode towards +2 V) — ground
  3. C.Circuit (3): +2+2 V — diode (anode at +2 V) — resistor — +4+4 V
  4. D.Circuit (4): +2+2 V — diode (anode side) — resistor R — −10-10 V

Correct answer: C

Explanation: Only in (3) is the cathode (+4 V) at a higher potential than the anode (+2 V).

Question 38

Physics · 4 marks · −1

A wire of length 10 cm and radius 7×10−4\sqrt7\times10^{-4} m connected across the right gap of a meter bridge. When a resistance of 4.5 Ω is connected on the left gap by using a resistance box, the balance length is found to be at 60 cm from the left end. If the resistivity of the wire is R×10−7R\times10^{-7} Ω m, then value of R is :

  1. A.66
  2. B.70
  3. C.63
  4. D.35

Correct answer: A

Explanation: X=4.5×4060=3 ΩX=4.5\times\frac{40}{60}=3\ \Omega; ρ=XAL=3π(7×10−8)0.1=66×10−7\rho=\frac{XA}{L}=\frac{3\pi(7\times10^{-8})}{0.1}=66\times10^{-7} Ω m.

Question 39

Physics · 4 marks · −1

A convex lens of focal length 40 cm forms an image of an extended source of light on a photo electric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length 20 cm. The photoelectric current now is :

  1. A.I2\frac{I}{2}
  2. B.II
  3. C.2I2I
  4. D.4I4I

Correct answer: B

Explanation: Same aperture collects the same light power, so the photocurrent is unchanged.

Question 40

Physics · 4 marks · −1

Given below are two statements : Statement (I) : Viscosity of gases is greater than that of liquids. Statement (II) : Surface tension of a liquid decreases due to the presence of insoluble impurities. In the light of the above statements, choose the most appropriate answer from the options given below :

  1. A.Both Statement I and Statement II are incorrect
  2. B.Both Statement I and Statement II are correct
  3. C.Statement I is correct but Statement II is incorrect
  4. D.Statement I is incorrect but Statement II is correct

Correct answer: D

Question 41

Physics · 4 marks · −1

A wire of resistance R and length L is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be :

  1. A.15R\frac15R
  2. B.125R\frac{1}{25}R
  3. C.5R5R
  4. D.25R25R

Correct answer: B

Explanation: Each part R/5R/5; five in parallel give R/25R/25.

Question 42

Physics · 4 marks · −1

If the refractive index of the material of a prism is cot⁡(A2)\cot\left(\frac{A}{2}\right) where AA is the angle of prism then the angle of minimum deviation will be :

  1. A.π2−2A\frac{\pi}{2}-2A
  2. B.π−2A\pi-2A
  3. C.π−A\pi-A
  4. D.π2−A\frac{\pi}{2}-A

Correct answer: B

Explanation: sin⁡A+δ2=cos⁡A2⇒A+δ2=π2−A2⇒δ=π−2A\sin\frac{A+\delta}{2}=\cos\frac A2\Rightarrow\frac{A+\delta}{2}=\frac\pi2-\frac A2\Rightarrow\delta=\pi-2A.

Question 43

Physics · 4 marks · −1

A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 s. The average emf induced in the loop during this time is :

  1. A.−2 V
  2. B.−1 V
  3. C.+2 V
  4. D.+1 V

Correct answer: D

Explanation: Φ=BAcos⁡60∘=4×5×12=10\Phi=BA\cos60^\circ=4\times5\times\frac12=10 Wb; ε=−ΔΦ/Δt=+1\varepsilon=-\Delta\Phi/\Delta t=+1 V.

Question 44

Physics · 4 marks · −1

The acceleration due to gravity on the surface of earth is g. If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :

  1. A.4g4g
  2. B.2g2g
  3. C.g4\frac g4
  4. D.g2\frac g2

Correct answer: A

Explanation: g∝1/R2g\propto1/R^2; halving RR gives 4g4g.

Question 45

Physics · 4 marks · −1

An electric charge 10−6 μC10^{-6}\ \mu C is placed at origin (0, 0) m of X — Y co-ordinate system. Two points P and Q are situated at (3,3)(\sqrt3,\sqrt3) m and (6,0)(\sqrt6,0) m respectively. The potential difference between the points P and Q will be :

  1. A.6\sqrt6 V
  2. B.0 V
  3. C.3 V
  4. D.3\sqrt3 V

Correct answer: B

Explanation: Both points are 6\sqrt6 m from the charge, so they are equipotential.

Question 46

Physics · 4 marks · −1

Two bodies of mass 4 g and 25 g are moving with equal kinetic energies. The ratio of magnitude of their linear momentum is :

  1. A.3 : 5
  2. B.4 : 5
  3. C.5 : 4
  4. D.2 : 5

Correct answer: D

Explanation: p=2mK∝mp=\sqrt{2mK}\propto\sqrt m: 4:25=2:5\sqrt4:\sqrt{25}=2:5.

Question 47

Physics · 4 marks · −1

A train is moving with a speed of 12 m/s on rails which are 1.5 m apart. To negotiate a curve of radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is: (Given, g = 10 m/s²)

  1. A.5.4 cm
  2. B.4.8 cm
  3. C.4.2 cm
  4. D.6.0 cm

Correct answer: A

Explanation: h=v2drg=144×1.54000=0.054h=\frac{v^2d}{rg}=\frac{144\times1.5}{4000}=0.054 m.

Question 48

Physics · 4 marks · −1

A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E⃗\vec E and B⃗\vec B represent the electric and magnetic fields respectively, then the region of space may have : (A) E = 0, B = 0 (B) E = 0, B ≠ 0 (C) E ≠ 0, B = 0 (D) E ≠ 0, B ≠ 0 Choose the most appropriate answer from the options given below :

  1. A.(A), (B) and (C) only
  2. B.(A), (B) and (D) only
  3. C.(B), (C) and (D) only
  4. D.(A), (C) and (D) only

Correct answer: B

Explanation: (B) works with v⃗∥B⃗\vec v\parallel\vec B, (D) with crossed fields (qE=qvBqE=qvB); (C) always deflects.

Question 49

Physics · 4 marks · −1

Identify the physical quantity that cannot be measured using spherometer :

  1. A.Thickness of thin plates
  2. B.Radius of curvature of concave surface
  3. C.Radius of curvature of convex surface
  4. D.Specific rotation of liquids

Correct answer: D

Question 50

Physics · 4 marks · −1

The average kinetic energy of a monoatomic molecule is 0.414 eV at temperature: (Use KB=1.38×10−23K_B=1.38\times10^{-23} J/mol-K)

  1. A.1500 K
  2. B.3000 K
  3. C.3200 K
  4. D.1600 K

Correct answer: C

Explanation: 32kBT=0.414×1.6×10−19\frac32k_BT=0.414\times1.6\times10^{-19} J ⇒T=3200\Rightarrow T=3200 K.

Question 51

Physics · 4 marks · −1

If average depth of an ocean is 4000 m and the bulk modulus of water is 2×1092\times10^9 N m−2^{-2}, then fractional compression ΔVV\frac{\Delta V}{V} of water at the bottom of ocean is α×10−2\alpha\times10^{-2}. The value of α\alpha is ______. (Given, g=10g=10 m s−2^{-2}, ρ=1000\rho=1000 kg m−3^{-3})

Correct answer: 2

Explanation: ΔVV=ρghB=4×1072×109=2×10−2\frac{\Delta V}{V}=\frac{\rho gh}{B}=\frac{4\times10^7}{2\times10^9}=2\times10^{-2}.

Question 52

Physics · 4 marks · −1

A particle starts from origin at t=0t=0 with a velocity 5i^5\hat i m/s and moves in x-y plane under action of a force which produces a constant acceleration of (3i^+2j^)(3\hat i+2\hat j) m/s². If the x-coordinate of the particle at that instant is 84 m, then the speed of the particle at this time is α\sqrt\alpha m/s. The value of α\alpha is ______.

Correct answer: 673

Explanation: 5t+1.5t2=84⇒t=65t+1.5t^2=84\Rightarrow t=6 s; v=(23,12)v=(23,12); α=529+144=673\alpha=529+144=673.

Question 53

Physics · 4 marks · −1

Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is 5.0 cm. The magnitude of the magnetic field at a point P midway between the wires is ___ μT. (Given : μ0=4π×10−7\mu_0=4\pi\times10^{-7} T m A−1^{-1})

Figure for question 53

Correct answer: 160

Explanation: Each wire gives μ0I2π(0.025)=80 μ\frac{\mu_0I}{2\pi(0.025)}=80\ \muT in the same direction; total 160 μT.

Question 54

Physics · 4 marks · −1

The charge accumulated on the capacitor connected in the following circuit is ______ μC. (given C=150 μFC=150\ \mu F)

Figure for question 54

Correct answer: 400

Explanation: Branch A: VA=10×23V_A=10\times\frac{2}{3} above the bottom =6.67=6.67 V; branch B: VB=10×410=4V_B=10\times\frac{4}{10}=4 V; ΔV=8/3\Delta V=8/3 V; Q=150×83=400 μQ=150\times\frac83=400\ \muC.

Question 55

Physics · 4 marks · −1

Two immiscible liquids of refractive indices 85\frac85 and 32\frac32 respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is α4\frac{\alpha}{4} cm. The value of α\alpha is ______.

Figure for question 55

Correct answer: 31

Explanation: Apparent depth =63/2+68/5=4+3.75=314=\frac{6}{3/2}+\frac{6}{8/5}=4+3.75=\frac{31}{4} cm.

Question 56

Physics · 4 marks · −1

Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i=i0sin⁡ωti=i_0\sin\omega t, where i0=5i_0=5 A and ω=50π\omega=50\pi rad/s. The maximum value of emf in the second coil is πα\frac{\pi}{\alpha} V. The value of α\alpha is ______.

Correct answer: 2

Explanation: εmax=Mi0ω=0.002×5×50π=π2\varepsilon_{max}=Mi_0\omega=0.002\times5\times50\pi=\frac\pi2.

Question 57

Physics · 4 marks · −1

Four particles each of mass 1 kg are placed at four corners of a square of side 2 m. Moment of inertia of system about an axis perpendicular to its plane and passing through one of its vertex is ______ kg m².

Correct answer: 16

Explanation: I=0+4+4+8=16I=0+4+4+8=16 kg m².

Question 58

Physics · 4 marks · −1

A thin metallic wire having cross sectional area of 10−410^{-4} m² is used to make a ring of radius 30 cm. A positive charge of 2π2\pi C is uniformly distributed over the ring, while another positive charge of 30 pC is kept at the centre of the ring. The tension in the ring is ______ N; provided that the ring does not get deformed (neglect the influence of gravity). (given, 14πϵ0=9×109\frac{1}{4\pi\epsilon_0}=9\times10^9 SI units)

Correct answer: 3

Explanation: T=kQq2πR2=9×109×2π×30×10−122π×0.09=3T=\frac{kQq}{2\pi R^2}=\frac{9\times10^9\times2\pi\times30\times10^{-12}}{2\pi\times0.09}=3 N.

Question 59

Physics · 4 marks · −1

A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is α\sqrt\alpha cm, where α=\alpha= ______.

Correct answer: 12

Explanation: ω=2.5\omega=2.5 s−1^{-1}; 5=2.516−x2⇒x2=125=2.5\sqrt{16-x^2}\Rightarrow x^2=12.

Question 60

Physics · 4 marks · −1

In a nuclear fission process, a high mass nuclide (A≈236)(A\approx236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A≈118)(A\approx118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be ______ MeV.

Correct answer: 236

Explanation: 236×(8.6−7.6)=236236\times(8.6-7.6)=236 MeV.

Question 61

Chemistry · 4 marks · −1

Yellow compound of lead chromate gets dissolved on treatment with hot NaOH solution. The product of lead formed is a :

  1. A.Dianionic complex with coordination number six
  2. B.Tetraanionic complex with coordination number six
  3. C.Neutral complex with coordination number four
  4. D.Dianionic complex with coordination number four

Correct answer: D

Explanation: PbCrO4\text{PbCrO}_4 dissolves as [Pb(OH)4]2−[\text{Pb(OH)}_4]^{2-}: dianionic, CN 4.

Question 62

Chemistry · 4 marks · −1

Consider the following complex ions P=[FeF6]3−P=[\text{FeF}_6]^{3-} Q=[V(H2O)6]2+Q=[\text{V(H}_2\text{O)}_6]^{2+} R=[Fe(H2O)6]2+R=[\text{Fe(H}_2\text{O)}_6]^{2+} The correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is:

  1. A.Q < P < R
  2. B.R < Q < P
  3. C.Q < R < P
  4. D.R < P < Q

Correct answer: C

Explanation: Unpaired electrons: P (Fe3+^{3+}, high spin d5^5) 5, Q (V2+^{2+}, d3^3) 3, R (Fe2+^{2+}, high spin d6^6) 4.

Question 63

Chemistry · 4 marks · −1

The electronic configuration for Neodymium is : [Atomic Number for Neodymium 60]

  1. A.[Xe] 4f1 5d1 6s2[\text{Xe}]\,4f^1\,5d^1\,6s^2
  2. B.[Xe] 4f6 6s2[\text{Xe}]\,4f^6\,6s^2
  3. C.[Xe] 4f4 6s2[\text{Xe}]\,4f^4\,6s^2
  4. D.[Xe] 5f7 7s2[\text{Xe}]\,5f^7\,7s^2

Correct answer: C

Question 64

Chemistry · 4 marks · −1

Given below are two statements : Statement (I) : Aqueous solution of ammonium carbonate is basic. Statement (II) : Acidic/basic nature of salt solution of a salt of weak acid and weak base depends on KaK_a and KbK_b value of acid and the base forming it. In the light of the above statements, choose the most appropriate answer from the options given below :

  1. A.Statement I is incorrect but Statement II is correct
  2. B.Both Statement I and Statement II are correct
  3. C.Both Statement I and Statement II are incorrect
  4. D.Statement I is correct but Statement II is incorrect

Correct answer: B

Question 65

Chemistry · 4 marks · −1

Given below are two statements : Statement (I) : p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol. Statement (II) : Ethanol will give immediate turbidity with Lucas reagent. In the light of the above statements, choose the correct answer from the options given below :

  1. A.Statement I is false but Statement II is true
  2. B.Both Statement I and Statement II are false
  3. C.Both Statement I and Statement II are true
  4. D.Statement I is true but Statement II is false

Correct answer: D

Explanation: p-Nitrophenol is the most acidic of the three; primary alcohols do not give immediate turbidity with Lucas reagent.

Question 66

Chemistry · 4 marks · −1

Given below are two statements : Statement (I) : The 4f and 5f - series of elements are placed separately in the Periodic table to preserve the principle of classification. Statement (II) : s-block elements can be found in pure form in nature. In the light of the above statements, choose the most appropriate answer from the options given below :

  1. A.Statement I is false but Statement II is true
  2. B.Both Statement I and Statement II are false
  3. C.Both Statement I and Statement II are true
  4. D.Statement I is true but Statement II is false

Correct answer: D

Question 67

Chemistry · 4 marks · −1

Choose the polar molecule from the following :

  1. A.CO2\text{CO}_2
  2. B.CCl4\text{CCl}_4
  3. C.CH2=CH2\text{CH}_2=\text{CH}_2
  4. D.CHCl3\text{CHCl}_3

Correct answer: D

Question 68

Chemistry · 4 marks · −1

Which of the following electronic configuration would be associated with the highest magnetic moment ?

  1. A.[Ar] 3d8[\text{Ar}]\,3d^8
  2. B.[Ar] 3d7[\text{Ar}]\,3d^7
  3. C.[Ar] 3d6[\text{Ar}]\,3d^6
  4. D.[Ar] 3d3[\text{Ar}]\,3d^3

Correct answer: C

Explanation: Unpaired electrons: 2, 3, 4, 3.

Question 69

Chemistry · 4 marks · −1

Two nucleotides are joined together by a linkage known as :

  1. A.Glycosidic linkage
  2. B.Phosphodiester linkage
  3. C.Peptide linkage
  4. D.Disulphide linkage

Correct answer: B

Question 70

Chemistry · 4 marks · −1

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Melting point of Boron (2453 K) is unusually high in group 13 elements. Reason (R) : Solid Boron has very strong crystalline lattice. In the light of the above statements, choose the most appropriate answer from the options given below :

  1. A.(A) is false but (R) is true
  2. B.Both (A) and (R) are correct and (R) is the correct explanation of (A)
  3. C.(A) is true but (R) is false
  4. D.Both (A) and (R) are correct but (R) is not the correct explanation of (A)

Correct answer: B

Question 71

Chemistry · 4 marks · −1

The correct statement regarding nucleophilic substitution reaction in a chiral alkyl halide is :

  1. A.Retention occurs in SN1S_N1 reaction and inversion occurs in SN2S_N2 reaction.
  2. B.Racemisation occurs in SN1S_N1 reaction and inversion occurs in SN2S_N2 reaction.
  3. C.Racemisation occurs in SN1S_N1 reaction and retention occurs in SN2S_N2 reaction.
  4. D.Racemisation occurs in both SN1S_N1 and SN2S_N2 reactions.

Correct answer: B

Question 72

Chemistry · 4 marks · −1

Which of the following has highly acidic hydrogen?

Figure for question 72
  1. A.H3C-CO-CH2-CO-CH2CH3\text{H}_3\text{C-CO-CH}_2\text{-CO-CH}_2\text{CH}_3 (hexane-2,4-dione)
  2. B.CH3CH2CH2-CO-CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{-CO-CH}_2\text{CH}_3 (a hexan-3-one skeletal structure with one C=O)
  3. C.H3C-CO-CO-CH2CH2CH3\text{H}_3\text{C-CO-CO-CH}_2\text{CH}_2\text{CH}_3 (hexane-2,3-dione)
  4. D.H3C-CO-CH2CH2-CO-CH3\text{H}_3\text{C-CO-CH}_2\text{CH}_2\text{-CO-CH}_3 (hexane-2,5-dione)

Correct answer: A

Explanation: The CH2_2 flanked by two C=O groups in the 1,3-diketone gives the most stabilised enolate.

Question 73

Chemistry · 4 marks · −1

Highest enol content will be shown by :

Figure for question 73
  1. A.Cyclohexane-1,2,3-trione
  2. B.Cyclohexane-1,4-dione
  3. C.Cyclohexane-1,3,5-trione
  4. D.Cyclohexane-1,3-dione

Correct answer: C

Explanation: Cyclohexane-1,3,5-trione enolises completely to aromatic phloroglucinol (1,3,5-trihydroxybenzene).

Question 74

Chemistry · 4 marks · −1

The ascending order of acidity of —OH group in the following compounds is : (A) Bu – OH (B) 4-nitrophenol (O2N-C6H4-OH\text{O}_2\text{N-C}_6\text{H}_4\text{-OH}, para) (C) 4-methoxyphenol (MeO-C6H4-OH\text{MeO-C}_6\text{H}_4\text{-OH}, para) (D) phenol (E) 2,4-dinitrophenol Choose the correct answer from the options given below :

Figure for question 74
  1. A.(A) < (C) < (D) < (B) < (E)
  2. B.(C) < (D) < (B) < (A) < (E)
  3. C.(A) < (D) < (C) < (B) < (E)
  4. D.(C) < (A) < (D) < (B) < (E)

Correct answer: A

Explanation: Alcohol is least acidic; +R methoxy lowers, nitro groups raise phenol acidity.

Question 75

Chemistry · 4 marks · −1

Which of the following is strongest Bronsted base ?

Figure for question 75
  1. A.Aniline
  2. B.Pyrrolidine
  3. C.Diphenylamine
  4. D.Pyrrole

Correct answer: B

Explanation: Pyrrolidine is a saturated secondary amine whose lone pair is localised; the others delocalise it.

Question 76

Chemistry · 4 marks · −1

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

  1. A.decreased vapour pressure, decreased boiling point
  2. B.increased vapour pressure, decreased boiling point
  3. C.decreased vapour pressure, increased boiling point
  4. D.increased vapour pressure, increased boiling point

Correct answer: C

Question 77

Chemistry · 4 marks · −1

NaCl reacts with conc. H2SO4\text{H}_2\text{SO}_4 and K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7 to give reddish fumes (B), which react with NaOH to give yellow solution (C). (B) and (C) respectively are :

  1. A.Na2CrO4\text{Na}_2\text{CrO}_4, CrO2Cl2\text{CrO}_2\text{Cl}_2
  2. B.CrO2Cl2\text{CrO}_2\text{Cl}_2, KHSO4\text{KHSO}_4
  3. C.CrO2Cl2\text{CrO}_2\text{Cl}_2, Na2Cr2O7\text{Na}_2\text{Cr}_2\text{O}_7
  4. D.CrO2Cl2\text{CrO}_2\text{Cl}_2, Na2CrO4\text{Na}_2\text{CrO}_4

Correct answer: D

Question 78

Chemistry · 4 marks · −1

IUPAC name of following compound (P) is :

Figure for question 78
  1. A.3-Ethyl-1,1-dimethylcyclohexane
  2. B.1-Ethyl-5,5-dimethylcyclohexane
  3. C.1-Ethyl-3,3-dimethylcyclohexane
  4. D.1,1-Dimethyl-3-ethylcyclohexane

Correct answer: A

Question 79

Chemistry · 4 marks · −1

Element not showing variable oxidation state is :

  1. A.Iodine
  2. B.Bromine
  3. C.Fluorine
  4. D.Chlorine

Correct answer: C

Question 80

Chemistry · 4 marks · −1

Among the given organic compounds, the total number of aromatic compounds is ______.

Figure for question 80

Correct answer: 3

Question 81

Chemistry · 4 marks · −1

Mass of methane required to produce 22 g of CO₂ after complete combustion is ______ g. (Given Molar mass in g mol⁻¹, C = 12.0, H = 1.0, O = 16.0)

Correct answer: 8

Explanation: 0.5 mol CO2_2 needs 0.5 mol CH4_4 = 8 g.

Question 82

Chemistry · 4 marks · −1

The mass of silver (Molar mass of Ag : 108 g mol⁻¹) displaced by a quantity of electricity which displaces 5600 mL of O₂ at S.T.P. will be ______ g.

Correct answer: 108

Explanation: 0.25 mol O2_2 = 1 F, which deposits 1 mol Ag = 108 g.

Question 83

Chemistry · 4 marks · −1

3-Methylhex-2-ene on reaction with HBr in presence of peroxide forms an addition product (A). The number of possible stereoisomers for 'A' is ______.

Correct answer: 4

Explanation: Anti-Markovnikov product 2-bromo-3-methylhexane has two stereocentres: 4 stereoisomers.

Question 84

Chemistry · 4 marks · −1

The number of electrons present in all the completely filled subshells having n=4n=4 and s=+12s=+\frac12 is ______. (Where n = principal quantum number and s = spin quantum number)

Correct answer: 16

Explanation: 4s, 4p, 4d, 4f have 1+3+5+7 = 16 orbitals, one +12+\frac12 electron each.

Question 85

Chemistry · 4 marks · −1

From the given list, the number of compounds with +4 oxidation state of Sulphur is ______. SO₃, H₂SO₃, SOCl₂, SF₄, BaSO₄, H₂S₂O₇

Correct answer: 3

Explanation: H2SO3\text{H}_2\text{SO}_3, SOCl2\text{SOCl}_2, SF4\text{SF}_4.

Question 86

Chemistry · 4 marks · −1

Sum of bond order of CO and NO⁺ is ______.

Correct answer: 6

Explanation: Both are isoelectronic with N2_2: 3 + 3 = 6.

Question 87

Chemistry · 4 marks · −1

Consider the following data for the given reaction 2HI(g)→H2(g)+I2(g)2\text{HI}_{(g)}\to\text{H}_{2(g)}+\text{I}_{2(g)} | | 1 | 2 | 3 | | HI (mol L⁻¹) | 0.005 | 0.01 | 0.02 | | Rate (mol L⁻¹ s⁻¹) | 7.5×10−47.5\times10^{-4} | 3.0×10−33.0\times10^{-3} | 1.2×10−21.2\times10^{-2} | The order of the reaction is ______.

Correct answer: 2

Explanation: Doubling [HI] quadruples the rate: second order.

Question 88

Chemistry · 4 marks · −1

Among the following, total number of meta directing functional groups is ______. (Integer based) −OCH3-\text{OCH}_3, −NO2-\text{NO}_2, −CN-\text{CN}, −CH3-\text{CH}_3, −NHCOCH3-\text{NHCOCH}_3, −COR-\text{COR}, −OH-\text{OH}, −COOH-\text{COOH}, −Cl-\text{Cl}

Correct answer: 4

Explanation: −NO2-\text{NO}_2, −CN-\text{CN}, −COR-\text{COR}, −COOH-\text{COOH}.

Question 89

Chemistry · 4 marks · −1

If three moles of an ideal gas at 300 K expand isothermally from 30 dm³ to 45 dm³ against a constant opposing pressure of 80 kPa, then the amount of heat transferred is ______ J.

Correct answer: 1200

Explanation: Isothermal: q=−w=PextΔV=80×103×15×10−3=1200q=-w=P_{ext}\Delta V=80\times10^3\times15\times10^{-3}=1200 J.

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