JEE Main 2024 — 31 Jan Shift 1 (Previous Year Paper)

JEE Main · 2024 · with answers and explanations

questions
90
Total marks
300
Duration
180 minutes
Negative marking
−1

Subjects: Mathematics · Physics · Chemistry

Question 1

Mathematics · 4 marks · −1

Let g(x)g(x) be a linear function and f(x)={g(x),x≤0(1+x2+x)1x,x>0f(x)=\begin{cases}g(x), & x\le0\\ \left(\frac{1+x}{2+x}\right)^{\frac1x}, & x>0\end{cases}, is continuous at x=0x=0. If f′(1)=f(−1)f'(1)=f(-1), then the value g(3)g(3) is:

  1. A.13log⁡e(49e1/3)\frac13\log_e\left(\frac{4}{9e^{1/3}}\right)
  2. B.log⁡e(49)−1\log_e\left(\frac49\right)-1
  3. C.log⁡e(49e1/3)\log_e\left(\frac{4}{9e^{1/3}}\right)
  4. D.13log⁡e(49)+1\frac13\log_e\left(\frac49\right)+1

Correct answer: C

Explanation: f(0+)=lim⁡(1/2)1/x=0f(0^+)=\lim(1/2)^{1/x}=0, so g(x)=kxg(x)=kx. f′(1)=23(ln⁡32+16)=f(−1)=−kf'(1)=\frac23\left(\ln\frac32+\frac16\right)=f(-1)=-k; g(3)=3k=ln⁡49−13g(3)=3k=\ln\frac49-\frac13.

Question 2

Mathematics · 4 marks · −1

Two marbles are drawn in succession from a box containing 10 red, 30 white, 20 blue and 15 orange marbles, with replacement being made after each drawing. Then the probability, that first drawn marble is red and second drawn marble is white, is:

  1. A.425\frac4{25}
  2. B.225\frac2{25}
  3. C.475\frac4{75}
  4. D.23\frac23

Correct answer: C

Explanation: 1075⋅3075=475\frac{10}{75}\cdot\frac{30}{75}=\frac{4}{75}.

Question 3

Mathematics · 4 marks · −1

Let α,β,γ,δ∈Z\alpha,\beta,\gamma,\delta\in\mathbb{Z} and let A(α,β)A(\alpha,\beta), B(1,0)B(1,0), C(γ,δ)C(\gamma,\delta) and D(1,2)D(1,2) be the vertices of a parallelogram ABCD. If AB=10AB=\sqrt{10} and the points A and C lie on the line 3y=2x+13y=2x+1, then 2(α+β+γ+δ)2(\alpha+\beta+\gamma+\delta) is equal to:

  1. A.10
  2. B.5
  3. C.12
  4. D.8

Correct answer: D

Explanation: Diagonals bisect at (1, 1); integer point on the line with AB=10AB=\sqrt{10} is A(−2,−1)A(-2,-1), so C(4,3)C(4,3); 2(−2−1+4+3)=82(-2-1+4+3)=8.

Question 4

Mathematics · 4 marks · −1

Let SS be the set of positive integral values of aa for which ax2+2(a+1)x+9a+4x2−8x+32<0\frac{ax^2+2(a+1)x+9a+4}{x^2-8x+32}<0, ∀x∈R\forall x\in\mathbb{R}. Then, the number of elements in SS is:

  1. A.3
  2. B.0
  3. C.1
  4. D.∞

Correct answer: B

Explanation: The denominator is always positive; the numerator can be negative for all xx only if a<0a<0.

Question 5

Mathematics · 4 marks · −1

For 0<c<b<a0<c<b<a, let (a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0(a+b-2c)x^2+(b+c-2a)x+(c+a-2b)=0 and α≠1\alpha\ne1 be one of its root. Then, among the two statements: (I) If α∈(−1,0)\alpha\in(-1,0), then bb cannot be the geometric mean of aa and cc (II) If α∈(0,1)\alpha\in(0,1), then bb may be the geometric mean of aa and cc

  1. A.Only (II) is true
  2. B.Both (I) and (II) are true
  3. C.Only (I) is true
  4. D.Neither (I) nor (II) is true

Correct answer: B

Explanation: Coefficients sum to 0, so α=a+c−2ba+b−2c\alpha=\frac{a+c-2b}{a+b-2c}. If b=acb=\sqrt{ac} the numerator is (a−c)2>0(\sqrt a-\sqrt c)^2>0, so α>0\alpha>0; and α<1\alpha<1 always since b>cb>c.

Question 6

Mathematics · 4 marks · −1

For α,β,γ≠0\alpha,\beta,\gamma\ne0, if sin⁡−1α+sin⁡−1β+sin⁡−1γ=π\sin^{-1}\alpha+\sin^{-1}\beta+\sin^{-1}\gamma=\pi and (α+β+γ)(α−γ+β)=3αβ(\alpha+\beta+\gamma)(\alpha-\gamma+\beta)=3\alpha\beta, then γ\gamma equals:

  1. A.3\sqrt3
  2. B.32\frac{\sqrt3}{2}
  3. C.12\frac1{\sqrt2}
  4. D.3−122\frac{\sqrt3-1}{2\sqrt2}

Correct answer: B

Explanation: Treat α,β,γ\alpha,\beta,\gamma as sines of angles of a triangle: α2+β2−γ2=αβ\alpha^2+\beta^2-\gamma^2=\alpha\beta gives cos⁡C=12\cos C=\frac12, γ=sin⁡π3\gamma=\sin\frac\pi3.

Question 7

Mathematics · 4 marks · −1

Let y=y(x)y=y(x) be the solution of the differential equation dydx=(tan⁡x)+ysin⁡x(sec⁡x−sin⁡xtan⁡x)\frac{dy}{dx}=\frac{(\tan x)+y}{\sin x(\sec x-\sin x\tan x)}, x∈(0,π2)x\in\left(0,\frac\pi2\right) satisfying the condition y(π4)=2y\left(\frac\pi4\right)=2. Then, y(π3)y\left(\frac\pi3\right) is:

  1. A.32(2+log⁡e3)\frac{\sqrt3}{2}(2+\log_e3)
  2. B.3(2+log⁡e3)\sqrt3(2+\log_e\sqrt3)
  3. C.3(1+2log⁡e3)\sqrt3(1+2\log_e3)
  4. D.3(2+log⁡e3)\sqrt3(2+\log_e3)

Correct answer: B

Explanation: The equation is y′−ysin⁡xcos⁡x=sec⁡2xy'-\frac{y}{\sin x\cos x}=\sec^2x; with IF cot⁡x\cot x: ycot⁡x=ln⁡tan⁡x+2y\cot x=\ln\tan x+2.

Question 8

Mathematics · 4 marks · −1

The area of the region {(x,y):y2≤4x, x<4, xy(x−1)(x−2)(x−3)(x−4)>0, x≠3}\left\{(x,y):y^2\le4x,\ x<4,\ \frac{xy(x-1)(x-2)}{(x-3)(x-4)}>0,\ x\ne3\right\} is:

  1. A.83\frac83
  2. B.643\frac{64}{3}
  3. C.323\frac{32}{3}
  4. D.163\frac{16}{3}

Correct answer: C

Explanation: On each of (0,1), (1,2), (2,3), (3,4) exactly one half (y>0y>0 or y<0y<0) of the parabola qualifies: area =∫042x dx=323=\int_0^42\sqrt x\,dx=\frac{32}{3}.

Question 9

Mathematics · 4 marks · −1

Let a be the sum of all coefficients in the expansion of (1−2x+2x2)2023(3−4x2+2x3)2024(1-2x+2x^2)^{2023}(3-4x^2+2x^3)^{2024} and b=lim⁡x→0(∫0xlog⁡(1+t)t2024+1dtx2)b=\lim_{x\to0}\left(\frac{\int_0^x\frac{\log(1+t)}{t^{2024}+1}dt}{x^2}\right). If the equations cx2+dx+e=0cx^2+dx+e=0 and 2bx2+ax+4=02bx^2+ax+4=0 have a common root, where c,d,e∈Rc,d,e\in\mathbb{R}, then d:c:ed:c:e equals:

  1. A.4 : 1 : 4
  2. B.1 : 1 : 4
  3. C.1 : 2 : 4
  4. D.2 : 1 : 4

Correct answer: B

Explanation: a=1a=1, b=12b=\frac12; x2+x+4=0x^2+x+4=0 has non-real roots, so the equations are proportional.

Question 10

Mathematics · 4 marks · −1

Three rotten apples are accidently mixed with fifteen good apples. Assuming the random variable xx to be the number of rotten apples in a draw of two apples, the variance of xx is:

  1. A.40153\frac{40}{153}
  2. B.37153\frac{37}{153}
  3. C.47153\frac{47}{153}
  4. D.57153\frac{57}{153}

Correct answer: A

Explanation: P(0)=105153P(0)=\frac{105}{153}, P(1)=45153P(1)=\frac{45}{153}, P(2)=3153P(2)=\frac{3}{153}; E=13E=\frac13, E(x2)=57153E(x^2)=\frac{57}{153}; Var =57153−19=40153=\frac{57}{153}-\frac19=\frac{40}{153}.

Question 11

Mathematics · 4 marks · −1

If one of the diameters of the circle x2+y2−10x+4y+13=0x^2+y^2-10x+4y+13=0 is a chord of another circle C, whose centre is the point of intersection of the lines 2x+3y=122x+3y=12 and 3x−2y=53x-2y=5, then the radius of the circle C is:

  1. A.6
  2. B.323\sqrt2
  3. C.20\sqrt{20}
  4. D.4

Correct answer: A

Explanation: Radius 4, centre (5, −2); C's centre (3, 2) at distance 20\sqrt{20}: R2=16+20R^2=16+20.

Question 12

Mathematics · 4 marks · −1

Let a⃗=3i^+j^−2k^\vec a=3\hat i+\hat j-2\hat k, b⃗=4i^+j^+7k^\vec b=4\hat i+\hat j+7\hat k and c⃗=i^−3j^+4k^\vec c=\hat i-3\hat j+4\hat k be three vectors. If a vectors p⃗\vec p satisfies p⃗×b⃗=c⃗×b⃗\vec p\times\vec b=\vec c\times\vec b and p⃗⋅a⃗=0\vec p\cdot\vec a=0, then p⃗⋅(i^−j^−k^)\vec p\cdot(\hat i-\hat j-\hat k) is equal to:

  1. A.28
  2. B.24
  3. C.32
  4. D.36

Correct answer: C

Explanation: p⃗=c⃗+λb⃗\vec p=\vec c+\lambda\vec b with −8−λ=0-8-\lambda=0: p⃗=(−31,−11,−52)\vec p=(-31,-11,-52).

Question 13

Mathematics · 4 marks · −1

The sum of the series 11−3⋅12+14+21−3⋅22+24+31−3⋅32+34+…\frac{1}{1-3\cdot1^2+1^4}+\frac{2}{1-3\cdot2^2+2^4}+\frac{3}{1-3\cdot3^2+3^4}+\ldots up to 10 terms is:

  1. A.55109\frac{55}{109}
  2. B.−45109-\frac{45}{109}
  3. C.−55109-\frac{55}{109}
  4. D.45109\frac{45}{109}

Correct answer: C

Explanation: k(k2−k−1)(k2+k−1)=12[1k2−k−1−1k2+k−1]\frac{k}{(k^2-k-1)(k^2+k-1)}=\frac12\left[\frac1{k^2-k-1}-\frac1{k^2+k-1}\right] telescopes to 12(−1−1109)\frac12\left(-1-\frac1{109}\right).

Question 14

Mathematics · 4 marks · −1

The solution curve of the differential equation ydxdy=x(log⁡ex−log⁡ey+1)y\frac{dx}{dy}=x(\log_ex-\log_ey+1), x>0,y>0x>0,y>0 passing through the point (e,1)(e,1) is:

  1. A.2∣log⁡exy∣=y+12\left|\log_e\frac xy\right|=y+1
  2. B.∣log⁡eyx∣=x\left|\log_e\frac yx\right|=x
  3. C.∣log⁡exy∣=y\left|\log_e\frac xy\right|=y
  4. D.∣log⁡eyx∣=y2\left|\log_e\frac yx\right|=y^2

Correct answer: C

Explanation: x=vyx=vy gives dvvln⁡v=dyy\frac{dv}{v\ln v}=\frac{dy}{y}, so ln⁡xy=Ky\ln\frac xy=Ky with K=1K=1.

Question 15

Mathematics · 4 marks · −1

lim⁡x→0e2∣sin⁡x∣−2∣sin⁡x∣−1x2\lim_{x\to0}\frac{e^{2|\sin x|}-2|\sin x|-1}{x^2}

  1. A.is equal to −1
  2. B.is equal to 1
  3. C.does not exist
  4. D.is equal to 2

Correct answer: D

Explanation: eu−u−1≈u22e^u-u-1\approx\frac{u^2}{2} with u=2∣sin⁡x∣u=2|\sin x|.

Question 16

Mathematics · 4 marks · −1

If the system of linear equations x−2y+z=−4x-2y+z=-4 2x+αy+3z=52x+\alpha y+3z=5 3x−y+βz=33x-y+\beta z=3 has infinitely many solutions, then 12α+13β12\alpha+13\beta is equal to:

  1. A.60
  2. B.54
  3. C.64
  4. D.58

Correct answer: D

Explanation: Eliminating xx: (α+4)y+z=13(\alpha+4)y+z=13 and 5y+(β−3)z=155y+(\beta-3)z=15 must be proportional: α=13\alpha=\frac13, β=5413\beta=\frac{54}{13}.

Question 17

Mathematics · 4 marks · −1

If f(x)=4x+36x−4f(x)=\frac{4x+3}{6x-4}, x≠23x\ne\frac23 and (f∘f)(x)=g(x)(f\circ f)(x)=g(x), where g:R−{23}→R−{23}g:\mathbb{R}-\left\{\frac23\right\}\to\mathbb{R}-\left\{\frac23\right\}, (g∘g∘g)(4)(g\circ g\circ g)(4) is equal to:

  1. A.−1920-\frac{19}{20}
  2. B.4
  3. C.−4
  4. D.1920\frac{19}{20}

Correct answer: B

Explanation: f(f(x))=xf(f(x))=x, so gg is the identity.

Question 18

Mathematics · 4 marks · −1

if f(x)=∣x32x2+11+3x3x2+22xx3+6x3−x4x2−2∣f(x)=\begin{vmatrix}x^3&2x^2+1&1+3x\\3x^2+2&2x&x^3+6\\x^3-x&4&x^2-2\end{vmatrix} for all x∈Rx\in\mathbb{R}, then 2f(0)+f′(0)2f(0)+f'(0) is equal to:

  1. A.48
  2. B.18
  3. C.42
  4. D.24

Correct answer: C

Explanation: f(0)=12f(0)=12; differentiating row by row at 0 gives 24+0−6=1824+0-6=18; 24+18=4224+18=42.

Question 19

Mathematics · 4 marks · −1

The distance of the point Q(0, 2, −2) from the line passing through the point P(5, −4, 3) and perpendicular to the lines r⃗=(−3i^+2k^)+λ(2i^+3j^+5k^)\vec r=(-3\hat i+2\hat k)+\lambda(2\hat i+3\hat j+5\hat k), λ∈R\lambda\in\mathbb{R} and r⃗=(i^−2j^+k^)+μ(−i^+3j^+2k^)\vec r=(\hat i-2\hat j+\hat k)+\mu(-\hat i+3\hat j+2\hat k), μ∈R\mu\in\mathbb{R} is:

  1. A.54\sqrt{54}
  2. B.86\sqrt{86}
  3. C.74\sqrt{74}
  4. D.20\sqrt{20}

Correct answer: C

Explanation: Direction ∝(1,1,−1)\propto(1,1,-1); ∣PQ∣2=86|PQ|^2=86, projection2=12^2=12; distance 74\sqrt{74}.

Question 20

Mathematics · 4 marks · −1

If the foci of a hyperbola are same as that of the ellipse x29+y225=1\frac{x^2}{9}+\frac{y^2}{25}=1 and eccentricity of the hyperbola is 158\frac{15}{8} times the eccentricity of the ellipse, then the smaller focal distance of the point (2,14325)\left(\sqrt2,\frac{14}{3}\sqrt{\frac25}\right) on the hyperbola, is equal to:

  1. A.1425−4314\sqrt{\frac25}-\frac43
  2. B.1425−16314\sqrt{\frac25}-\frac{16}{3}
  3. C.725−837\sqrt{\frac25}-\frac83
  4. D.725+837\sqrt{\frac25}+\frac83

Correct answer: C

Explanation: Foci (0,±4)(0,\pm4), e=32e=\frac32, transverse semi-axis 83\frac83; smaller focal distance ey−83=725−83ey-\frac83=7\sqrt{\frac25}-\frac83.

Question 21

Mathematics · 4 marks · −1

If the integral 525∫0π/2sin⁡2xcos⁡112x(1+cos⁡52x)12dx525\int_0^{\pi/2}\sin2x\cos^{\frac{11}{2}}x\left(1+\cos^{\frac52}x\right)^{\frac12}dx is equal to (n2−64)(n\sqrt2-64), then nn is equal to ______.

Correct answer: 176

Question 22

Mathematics · 4 marks · −1

Let a⃗\vec a and b⃗\vec b be two vectors such that ∣a⃗∣=1|\vec a|=1, ∣b⃗∣=4|\vec b|=4, and a⃗⋅b⃗=2\vec a\cdot\vec b=2. If c⃗=(2a⃗×b⃗)−3b⃗\vec c=(2\vec a\times\vec b)-3\vec b and the angle between b⃗\vec b and c⃗\vec c is α\alpha, then 192sin⁡2α192\sin^2\alpha is equal to ______.

Correct answer: 48

Explanation: cos⁡α=−32\cos\alpha=-\frac{\sqrt3}{2} (as ∣c⃗∣=83|\vec c|=8\sqrt3, b⃗⋅c⃗=−48\vec b\cdot\vec c=-48), so 192⋅14=48192\cdot\frac14=48.

Question 23

Mathematics · 4 marks · −1

Let S=(−1,∞)S=(-1,\infty) and f:S→Rf:S\to\mathbb{R} be defined as f(x)=∫−1x(et−1)11(2t−1)5(t−3)12(2t−10)61dtf(x)=\int_{-1}^{x}(e^t-1)^{11}(2t-1)^5(t-3)^{12}(2t-10)^{61}dt. Let pp = Sum of squares of the values of xx, where f(x)f(x) attains local maxima on SS, and qq = Sum of the values of xx, where f(x)f(x) attains local minima on SS. Then, the value of p2+2qp^2+2q is ______.

Correct answer: 27

Question 24

Mathematics · 4 marks · −1

The total number of words (with or without meaning) that can be formed out of the letters of the word 'DISTRIBUTION' taken four at a time, is equal to ______.

Correct answer: 3734

Question 25

Mathematics · 4 marks · −1

Let the foci and length of the latus rectum of an ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>ba>b be (±5,0)(\pm5,0) and 50\sqrt{50}, respectively. Then, the square of the eccentricity of the hyperbola x2b2−y2a2b2=1\frac{x^2}{b^2}-\frac{y^2}{a^2b^2}=1 equals:

Correct answer: 51

Question 26

Mathematics · 4 marks · −1

Let f:R→Rf:\mathbb{R}\to\mathbb{R} be a function defined by f(x)=4x4x+2f(x)=\frac{4^x}{4^x+2} and M=∫f(a)f(1−a)xsin⁡4(x(1−x))dxM=\int_{f(a)}^{f(1-a)}x\sin^4(x(1-x))dx, N=∫f(a)f(1−a)sin⁡4(x(1−x))dxN=\int_{f(a)}^{f(1-a)}\sin^4(x(1-x))dx; a≠12a\ne\frac12. If αM=βN\alpha M=\beta N, α,β∈N\alpha,\beta\in\mathbb{N}, then the least value of α2+β2\alpha^2+\beta^2 is equal to ______.

Correct answer: 5

Explanation: f(a)+f(1−a)=1f(a)+f(1-a)=1, so by symmetry M=12NM=\frac12N; 2M=N2M=N, least α2+β2=4+1=5\alpha^2+\beta^2=4+1=5.

Question 27

Mathematics · 4 marks · −1

In the expansion of (1+x)(1−x2)(1+3x+3x2+1x3)5(1+x)(1-x^2)\left(1+\frac3x+\frac3{x^2}+\frac1{x^3}\right)^5, x≠0x\ne0, the sum of the coefficients of x3x^3 and x−13x^{-13} is equal to ______.

Correct answer: 118

Question 28

Mathematics · 4 marks · −1

Let A={1,2,3,4}A=\{1,2,3,4\} and R={(1,2),(2,3),(1,4)}R=\{(1,2),(2,3),(1,4)\} be a relation on A. Let S be the equivalence relation on A such that R⊂SR\subset S and the number of elements in S is n. Then, the minimum value of nn is:

Correct answer: 16

Explanation: All four elements fall into one class: 42=164^2=16.

Question 29

Mathematics · 4 marks · −1

Let Q and R be the feet of perpendiculars from the point P(a,a,a)P(a,a,a) on the lines x=y,z=1x=y,z=1 and x=−y,z=−1x=-y,z=-1 respectively. If ∠QPR\angle QPR is a right angle, then 12a212a^2 is equal to:

Correct answer: 12

Question 30

Mathematics · 4 marks · −1

If α\alpha denotes the number of solutions of ∣1−i∣x=2x|1-i|^x=2^x and β=(∣z∣arg⁡(z))\beta=\left(\frac{|z|}{\arg(z)}\right), where z=π4(1+i)4[1−πiπ+i+π−i1+πi]z=\frac\pi4(1+i)^4\left[\frac{1-\sqrt\pi i}{\sqrt\pi+i}+\frac{\sqrt\pi-i}{1+\sqrt\pi i}\right], i=−1i=\sqrt{-1}, then the distance of the point (α,β)(\alpha,\beta) from the line 4x−3y=74x-3y=7 is ______.

Correct answer: 3

Question 31

Physics · 4 marks · −1

In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5×10105\times10^{10} Hz and an amplitude of 50 V m−1^{-1}. The total average energy density of the electromagnetic field of the wave is: [Use ϵ0=8.85×10−12\epsilon_0=8.85\times10^{-12} C²/N m²]

  1. A.4.425×10−84.425\times10^{-8} J m−3^{-3}
  2. B.2.212×10−82.212\times10^{-8} J m−3^{-3}
  3. C.1.106×10−81.106\times10^{-8} J m−3^{-3}
  4. D.2.212×10−102.212\times10^{-10} J m−3^{-3}

Correct answer: C

Explanation: u=12ϵ0E02=1.106×10−8u=\frac12\epsilon_0E_0^2=1.106\times10^{-8} J m−3^{-3}.

Question 32

Physics · 4 marks · −1

The parameter that remains the same for molecules of all gases at a given temperature is:

  1. A.kinetic energy
  2. B.momentum
  3. C.mass
  4. D.speed

Correct answer: A

Question 33

Physics · 4 marks · −1

The given figure represents two isobaric processes for the same mass of an ideal gas, then:

Figure for question 33
  1. A.P1=P2P_1=P_2
  2. B.P2>P1P_2>P_1
  3. C.P2≥P1P_2\ge P_1
  4. D.P1>P2P_1>P_2

Correct answer: D

Explanation: V=nRPTV=\frac{nR}{P}T: larger slope means lower pressure.

Question 34

Physics · 4 marks · −1

The refractive index of a prism with apex angle A is cot⁡A/2\cot A/2. The angle of minimum deviation is:

  1. A.δm=180∘−2A\delta_m=180^\circ-2A
  2. B.δm=180∘−A\delta_m=180^\circ-A
  3. C.δm=180∘−3A\delta_m=180^\circ-3A
  4. D.δm=180∘−4A\delta_m=180^\circ-4A

Correct answer: A

Question 35

Physics · 4 marks · −1

The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60 cm, the length of the closed pipe will be:

  1. A.45 cm
  2. B.15 cm
  3. C.60 cm
  4. D.30 cm

Correct answer: B

Explanation: v4L=2v2(0.6)⇒L=15\frac{v}{4L}=\frac{2v}{2(0.6)}\Rightarrow L=15 cm.

Question 36

Physics · 4 marks · −1

A coil is placed perpendicular to a magnetic field of 5000 T. When the field is changed to 3000 T in 2s, an induced emf of 22 V is produced in the coil. If the diameter of the coil is 0.02 m, then the number of turns is the coil is:

  1. A.7
  2. B.35
  3. C.70
  4. D.140

Correct answer: C

Explanation: 22=Nπ(0.01)2×100022=N\pi(0.01)^2\times1000.

Question 37

Physics · 4 marks · −1

A rigid wire consists of a semicircular position of radius R and two straight sections. The wire is partially immerged in a perpendicular magnetic field B=B0k^B=B_0\hat k as shown in figure. The magnetic force on the wire if it has current ii is:

Figure for question 37
  1. A.2iBRj^2iBR\hat j
  2. B.−iBRj^-iBR\hat j
  3. C.iBRj^iBR\hat j
  4. D.−2iBRj^-2iBR\hat j

Correct answer: D

Explanation: Effective length between the legs is 2Ri^2R\hat i; F⃗=i(2Ri^)×B0k^=−2iRB0j^\vec F=i(2R\hat i)\times B_0\hat k=-2iRB_0\hat j.

Question 38

Physics · 4 marks · −1

When a metal surface is illuminated by light of wavelength λ, the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ, stopping potential is 2V. The threshold wavelength for this surface is:

  1. A.9λ
  2. B.3λ
  3. C.5λ
  4. D.4.5λ

Correct answer: A

Explanation: E−ϕ=8E-\phi=8, E3−ϕ=2\frac E3-\phi=2: E=9E=9, ϕ=1\phi=1 eV; λ0=9λ\lambda_0=9\lambda.

Question 39

Physics · 4 marks · −1

Four identical particles of mass m are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is (22+132)Gm2L2\left(\frac{2\sqrt2+1}{32}\right)\frac{Gm^2}{L^2}, the length of the sides of the square is:

  1. A.2L
  2. B.4L
  3. C.3L
  4. D.L2\frac L2

Correct answer: B

Explanation: Net force =(22+1)Gm22a2=\frac{(2\sqrt2+1)Gm^2}{2a^2}; equate: a=4La=4L.

Question 40

Physics · 4 marks · −1

Identify the logic operation performed by the given circuit.

Figure for question 40
  1. A.AND
  2. B.NAND
  3. C.OR
  4. D.NOR

Correct answer: C

Explanation: Y=AˉBˉ‾=A+BY=\overline{\bar A\bar B}=A+B.

Question 41

Physics · 4 marks · −1

If the percentage errors in measuring the length and the diameter of a wire are 0.1% each. The percentage error in measuring its resistance will be:

  1. A.0.2%
  2. B.0.1%
  3. C.0.144%
  4. D.0.3%

Correct answer: D

Explanation: R∝L/d2R\propto L/d^2: 0.1 + 0.2.

Question 42

Physics · 4 marks · −1

A small steel ball is dropped into a long cylinder containing glycerine. Which one of the following is the correct representation of the velocity time graph for the transit of the ball?

Figure for question 42
  1. A.v rises linearly then falls linearly (triangle)
  2. B.v increases linearly with t (straight line)
  3. C.v rises and levels off asymptotically (concave curve approaching terminal velocity)
  4. D.v constant then decreasing

Correct answer: C

Question 43

Physics · 4 marks · −1

A coin is placed on a disc. The coefficient of friction between the coin and the disc is μ. If the distance of the coin from the center of the disc is r, the maximum angular velocity which can be given to the disc, so that the coin does not slip away, is:

  1. A.rμg\sqrt{\frac{r}{\mu g}}
  2. B.μrg\frac{\mu}{\sqrt{rg}}
  3. C.μgr\frac{\mu g}{r}
  4. D.μgr\sqrt{\frac{\mu g}{r}}

Correct answer: D

Question 44

Physics · 4 marks · −1

A force is represented by F=ax2+bt12F=ax^2+bt^{\frac12} where xx = distance and tt = time. The dimensions of b2/ab^2/a are:

  1. A.[MLT−2][MLT^{-2}]
  2. B.[ML3T−3][ML^3T^{-3}]
  3. C.[ML−1T−1][ML^{-1}T^{-1}]
  4. D.[ML2T−3][ML^2T^{-3}]

Correct answer: B

Explanation: [a]=ML−1T−2[a]=ML^{-1}T^{-2}, [b]=MLT−5/2[b]=MLT^{-5/2}.

Question 45

Physics · 4 marks · −1

Two conductors have the same resistance at 0°C but their temperature coefficients of resistance are α1\alpha_1 and α2\alpha_2. The respective temperature coefficients for their series and parallel combinations are:

  1. A.α1+α2, α1α2α1+α2\alpha_1+\alpha_2,\ \frac{\alpha_1\alpha_2}{\alpha_1+\alpha_2}
  2. B.α1+α22, α1+α22\frac{\alpha_1+\alpha_2}{2},\ \frac{\alpha_1+\alpha_2}{2}
  3. C.α1+α22, α1+α2\frac{\alpha_1+\alpha_2}{2},\ \alpha_1+\alpha_2
  4. D.α1+α2, α1+α22\alpha_1+\alpha_2,\ \frac{\alpha_1+\alpha_2}{2}

Correct answer: B

Question 46

Physics · 4 marks · −1

Two charges q and 3q are separated by a distance 'r' in air. At a distance x from charge q, the resultant electric field is zero. The value of x is:

  1. A.r3(1+3)\frac{r}{3(1+\sqrt3)}
  2. B.r(1+3)\frac{r}{(1+\sqrt3)}
  3. C.(1+3)r\frac{(1+\sqrt3)}{r}
  4. D.r(1+3)r(1+\sqrt3)

Correct answer: B

Explanation: qx2=3q(r−x)2⇒r−x=3x\frac{q}{x^2}=\frac{3q}{(r-x)^2}\Rightarrow r-x=\sqrt3x.

Question 47

Physics · 4 marks · −1

The relation between time 't' and distance 'x' is t=αx2+βxt=\alpha x^2+\beta x, where α and β are constants. The relation between acceleration (a) and velocity (v) is:

  1. A.a=−5αv5a=-5\alpha v^5
  2. B.a=−4αv4a=-4\alpha v^4
  3. C.a=−3αv2a=-3\alpha v^2
  4. D.a=−2αv3a=-2\alpha v^3

Correct answer: D

Explanation: 1v=2αx+β\frac1v=2\alpha x+\beta; differentiating, −av2=2αv-\frac{a}{v^2}=2\alpha v.

Question 48

Physics · 4 marks · −1

If the wavelength of the first member of Lyman series of hydrogen is λ. The wavelength of the second member will be:

  1. A.527λ\frac5{27}\lambda
  2. B.3227λ\frac{32}{27}\lambda
  3. C.2732λ\frac{27}{32}\lambda
  4. D.275λ\frac{27}{5}\lambda

Correct answer: C

Explanation: λ2λ1=3/48/9=2732\frac{\lambda_2}{\lambda_1}=\frac{3/4}{8/9}=\frac{27}{32}.

Question 49

Physics · 4 marks · −1

In the given arrangement of a doubly inclined plane two blocks of masses M and m are placed. The blocks are connected by a light string passing over an ideal pulley as shown. The coefficient of friction between the surface of the plane and the blocks is 0.25. The value of m, for which M = 10 kg will move down with an acceleration of 2 m/s², is: (take g=10g=10 m/s² and tan⁡37∘=3/4\tan37^\circ=3/4)

Figure for question 49
  1. A.9 kg
  2. B.2.25 kg
  3. C.6.5 kg
  4. D.4.5 kg

Correct answer: D

Explanation: 80−15−T=20⇒T=4580-15-T=20\Rightarrow T=45 N; 45−6m−2m=2m⇒m=4.545-6m-2m=2m\Rightarrow m=4.5 kg.

Question 50

Physics · 4 marks · −1

An artillery piece of mass M1M_1 fires a shell of mass M2M_2 horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is:

  1. A.M2/(M1+M2)M_2/(M_1+M_2)
  2. B.M1/(M1+M2)M_1/(M_1+M_2)
  3. C.M2M1\frac{M_2}{M_1}
  4. D.M1M2\frac{M_1}{M_2}

Correct answer: C

Explanation: Equal momenta: K∝1MK\propto\frac1M.

Question 51

Physics · 4 marks · −1

Equivalent resistance of the following network is ______ Ω.

Figure for question 51

Correct answer: 1

Question 52

Physics · 4 marks · −1

Two waves of intensity ratio 1:9 cross each other at a point. The resultant intensites at that point, when (a) Waves are incoherent is I1I_1 (b) Waves are coherent is I2I_2 and differ in phase by 60°. If I1I2=10x\frac{I_1}{I_2}=\frac{10}{x} then x=x= ______.

Correct answer: 13

Explanation: I1=10II_1=10I; I2=I+9I+2⋅3Icos⁡60∘=13II_2=I+9I+2\cdot3I\cos60^\circ=13I.

Question 53

Physics · 4 marks · −1

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02% is ______ m. (Take density of sea water = 10310^3 kg m−3^{-3}, Bulk modulus of rubber = 9×1089\times10^8 N m−2^{-2}, and g=10g=10 m s−2^{-2})

Correct answer: 18

Explanation: h=B(ΔV/V)ρg=9×108×2×10−4104=18h=\frac{B(\Delta V/V)}{\rho g}=\frac{9\times10^8\times2\times10^{-4}}{10^4}=18 m.

Question 54

Physics · 4 marks · −1

A particle performs simple harmonic motion with amplitude A. Its speed is increased to three times at an instant when its displacement is 2A3\frac{2A}{3}. The new amplitude of motion is nA3\frac{nA}{3}. The value of n is ______.

Correct answer: 7

Explanation: v2=ω25A29v^2=\omega^2\frac{5A^2}{9}; new A′2=4A29+9⋅5A29=49A29A'^2=\frac{4A^2}{9}+9\cdot\frac{5A^2}{9}=\frac{49A^2}{9}.

Question 55

Physics · 4 marks · −1

A small square loop of wire of side l is placed inside a large square loop of wire of side L(L=l2)L(L=l^2). The loops are coplanar and their centers coincide. The value of the mutual inductance of the system is x×10−7\sqrt x\times10^{-7} H, where x=x= ______.

Correct answer: 128

Explanation: Bcentre=22μ0IπLB_{centre}=\frac{2\sqrt2\mu_0I}{\pi L}; M=22μ0l2πL=82×10−7=128×10−7M=\frac{2\sqrt2\mu_0l^2}{\pi L}=8\sqrt2\times10^{-7}=\sqrt{128}\times10^{-7}.

Question 56

Physics · 4 marks · −1

A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of Hh\frac Hh for which the body will take the maximum time to reach the ground is ______.

Correct answer: 2

Explanation: Total time 2(H−h)g+2hg\sqrt{\frac{2(H-h)}{g}}+\sqrt{\frac{2h}{g}} is maximum at h=H2h=\frac H2.

Question 57

Physics · 4 marks · −1

The mass defect in a particular reaction is 0.4g. The amount of energy liberated is n×107n\times10^7 kWh, where n=n= ______. (speed of light = 3×1083\times10^8 m/s)

Correct answer: 1

Explanation: E=4×10−4×9×1016=3.6×1013E=4\times10^{-4}\times9\times10^{16}=3.6\times10^{13} J =107=10^7 kWh.

Question 58

Physics · 4 marks · −1

A parallel plate capacitor with plate separation 5 mm is charged up by a battery. It is found that on introducing a dielectric sheet of thickness 2 mm, while keeping the battery connections intact, the capacitor draws 25% more charge from the battery than before. The dielectric constant of the sheet is ______.

Correct answer: 2

Explanation: 53+2/K=1.25⇒K=2\frac{5}{3+2/K}=1.25\Rightarrow K=2.

Question 59

Physics · 4 marks · −1

A solid circular disc of mass 50 kg rolls along a horizontal floor so that its center of mass has a speed of 0.4 m/s. The absolute value of work done on the disc to stop it is:

Correct answer: 6

Explanation: K=34mv2=34(50)(0.16)=6K=\frac34mv^2=\frac34(50)(0.16)=6 J.

Question 60

Physics · 4 marks · −1

An electron moves through a uniform magnetic field B⃗=B0i^+2B0j^\vec B=B_0\hat i+2B_0\hat j T. At a particular instant of time, the velocity of electron is u⃗=3i^+5j^\vec u=3\hat i+5\hat j m/s. If the magnetic force acting on electron is F⃗=5ek^\vec F=5e\hat k N, where e is the charge of electron, then the value of B0B_0 is ______ T.

Correct answer: 5

Explanation: u⃗×B⃗=(6−5)B0k^\vec u\times\vec B=(6-5)B_0\hat k; F⃗=−e(B0k^)=5ek^⇒∣B0∣=5\vec F=-e(B_0\hat k)=5e\hat k\Rightarrow|B_0|=5.

Question 61

Chemistry · 4 marks · −1

The correct statements from following are: A. The strength of anionic ligands can be explained by crystal field theory. B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds. C. The hybridization involved in formation of [Ni(CN)4]2−[\text{Ni(CN)}_4]^{2-} complex is dsp2dsp^2. D. The number of possible isomer(s) of cis-[PtCl2(en)2]2+[\text{PtCl}_2(\text{en})_2]^{2+} is one Choose the correct answer from the options given below:

  1. A.B, C only
  2. B.B, D only
  3. C.A, C only
  4. D.A, D only

Correct answer: A

Explanation: CFT cannot explain why anionic ligands are weak; the cis complex is chiral (two isomers).

Question 62

Chemistry · 4 marks · −1

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A: Alcohols react both as nucleophiles and electrophiles. Reason R: Alcohols reacts with active metals such as sodium, potassium and aluminium to yield corresponding alkoxides and liberate hydrogen. In the light of the above statements, choose the correct answer from the options given below:

  1. A.A is false but R is true.
  2. B.Both A and R are true but R is NOT the correct explanation of A.
  3. C.Both A and R are true and R is the correct explanation of A.
  4. D.A is true but R is false.

Correct answer: B

Question 63

Chemistry · 4 marks · −1

Given below are two statements: Statement I: IUPAC name of HO-CH2-(CH2)3-CH2-COCH3\text{HO-CH}_2\text{-(CH}_2)_3\text{-CH}_2\text{-COCH}_3 is 7-hydroxyheptan-2-one. Statement II: 2-oxoheptan-7-ol is the correct IUPAC name for above compound. In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Statement I is incorrect but Statement II is correct.
  2. B.Both Statement I and Statement II are correct.
  3. C.Statement I is correct but Statement II is incorrect.
  4. D.Both Statement I and Statement II are incorrect.

Correct answer: C

Question 64

Chemistry · 4 marks · −1

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A: pKapK_a value of phenol is 10.0 while that of ethanol is 15.9. Reason R: Ethanol is stronger acid than phenol. In the light of the above statements, choose the correct answer from the options given below:

  1. A.A is false but R is true.
  2. B.A is true but R is false.
  3. C.Both A and R are true but R is NOT the correct explanation of A.
  4. D.Both A and R are true and R is the correct explanation of A.

Correct answer: B

Question 65

Chemistry · 4 marks · −1

Match List I with List II List I: A. Glucose/NaHCO3/Δ\text{NaHCO}_3/\Delta; B. Glucose/HNO3\text{HNO}_3; C. Glucose/HI/Δ; D. Glucose/Bromine water List II: I. Gluconic acid; II. No reaction; III. n-hexane; IV. Saccharic acid Choose the correct answer from the options given below:

  1. A.A-IV, B-I, C-III, D-II
  2. B.A-I, B-IV, C-III, D-II
  3. C.A-III, B-II, C-I, D-IV
  4. D.A-II, B-IV, C-III, D-I

Correct answer: D

Question 66

Chemistry · 4 marks · −1

Identify the mixture that shows positive deviations from Raoult's Law :

  1. A.(CH3)2CO+CS2(\text{CH}_3)_2\text{CO}+\text{CS}_2
  2. B.CHCl3+C6H6\text{CHCl}_3+\text{C}_6\text{H}_6
  3. C.CHCl3+(CH3)2CO\text{CHCl}_3+(\text{CH}_3)_2\text{CO}
  4. D.(CH3)2CO+C6H5NH2(\text{CH}_3)_2\text{CO}+\text{C}_6\text{H}_5\text{NH}_2

Correct answer: A

Question 67

Chemistry · 4 marks · −1

For the given reaction, choose the correct expression of KCK_C from the following :- Fe(aq)3++SCN(aq)−⇌(FeSCN)(aq)2+\text{Fe}^{3+}_{(aq)}+\text{SCN}^-_{(aq)}\rightleftharpoons(\text{FeSCN})^{2+}_{(aq)}

  1. A.KC=[FeSCN2+]2[Fe3+][SCN−]K_C=\frac{[\text{FeSCN}^{2+}]^2}{[\text{Fe}^{3+}][\text{SCN}^-]}
  2. B.KC=[FeSCN2+][Fe3+][SCN−]K_C=\frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}][\text{SCN}^-]}
  3. C.KC=[FeSCN2+][Fe3+]2[SCN−]2K_C=\frac{[\text{FeSCN}^{2+}]}{[\text{Fe}^{3+}]^2[\text{SCN}^-]^2}
  4. D.KC=[Fe3+][SCN−][FeSCN2+]K_C=\frac{[\text{Fe}^{3+}][\text{SCN}^-]}{[\text{FeSCN}^{2+}]}

Correct answer: B

Question 68

Chemistry · 4 marks · −1

The correct sequence of electron gain enthalpy of the elements listed below is A. Ar B. Br C. F D. S Choose the most appropriate from the options given below:

  1. A.D > C > B > A
  2. B.A > D > B > C
  3. C.A > D > C > B
  4. D.C > B > D > A

Correct answer: B

Explanation: Algebraic values: Ar (+96) > S (−200) > Br (−325) > F (−328) kJ/mol.

Question 69

Chemistry · 4 marks · −1

The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:

  1. A.B and D only
  2. B.B, C, D only
  3. C.A and C only
  4. D.A, B, C only

Correct answer: C

Question 70

Chemistry · 4 marks · −1

The product (C) in the below mentioned reaction is: CH3-CH2-CH2-Br→KOH(alc), ΔA→HBrB→KOH(aq), ΔC\text{CH}_3\text{-CH}_2\text{-CH}_2\text{-Br}\xrightarrow{\text{KOH(alc)},\ \Delta}A\xrightarrow{\text{HBr}}B\xrightarrow{\text{KOH(aq)},\ \Delta}C

  1. A.Propan-1-ol
  2. B.Propyne
  3. C.Propene
  4. D.Propan-2-ol

Correct answer: D

Explanation: Propene → 2-bromopropane (Markovnikov) → propan-2-ol.

Question 71

Chemistry · 4 marks · −1

Identify the factor from the following that does not affect electrolytic conductance of a solution.

  1. A.The nature of solvent used
  2. B.Concentration of the electrolyte
  3. C.The nature of the electrolyte added
  4. D.The nature of the electrode used

Correct answer: D

Question 72

Chemistry · 4 marks · −1

Match List I with List II List I (Technique): A. Distillation; B. Fractional distillation; C. Steam distillation; D. Distillation under reduced pressure List II (Application): I. Separation of glycerol from spent-lye; II. Aniline – Water mixture; III. Separation of crude oil fractions; IV. Chloroform - Aniline Choose the correct answer from the options given below:

  1. A.A-IV, B-I, C-II, D-III
  2. B.A-I, B-II, C-IV, D-III
  3. C.A-II, B-III, C-I, D-IV
  4. D.A-IV, B-III, C-II, D-I

Correct answer: D

Question 73

Chemistry · 4 marks · −1

Identify correct statements from below: A. The chromate ion is square planar. B. Dichromates are generally prepared from chromates. C. The green manganate ion is diamagnetic. D. Dark green coloured K2MnO4\text{K}_2\text{MnO}_4 disproportionates in a neutral or acidic medium to give permanganate. E. With increasing oxidation number of transition metal, ionic character of the oxides decreases. Choose the correct answer from the options given below:

  1. A.A, B, C only
  2. B.A, D, E only
  3. C.B, D, E only
  4. D.B, C, D only

Correct answer: C

Explanation: Chromate is tetrahedral; manganate (d1^1) is paramagnetic.

Question 74

Chemistry · 4 marks · −1

The compound that is white in color is:

  1. A.ammonium arsinomolybdate
  2. B.ammonium sulphide
  3. C.lead iodide
  4. D.lead sulphate

Correct answer: D

Question 75

Chemistry · 4 marks · −1

Give below are two statements: Statement -I: Noble gases have very high boiling points. Statement -II: Noble gases are monoatomic gases. They are held together by strong dispersion forces. Because of this they are liquefied at very low temperature. Hence, they have very high boiling points. In the light of the above statements, choose the correct answer from the options given below:

  1. A.Statement I is true but Statement II is false.
  2. B.Both Statement I and Statement II are true.
  3. C.Both Statement I and Statement II are false.
  4. D.Statement I is false but Statement II is true.

Correct answer: C

Question 76

Chemistry · 4 marks · −1

Consider the oxides of group 14 elements SiO2\text{SiO}_2, GeO2\text{GeO}_2, SnO2\text{SnO}_2, PbO2\text{PbO}_2, CO and GeO. The amphoteric oxides are :

  1. A.GeO, GeO2\text{GeO}_2
  2. B.SnO2\text{SnO}_2, PbO2\text{PbO}_2
  3. C.SnO2\text{SnO}_2, CO
  4. D.SiO2\text{SiO}_2, GeO2\text{GeO}_2

Correct answer: B

Question 77

Chemistry · 4 marks · −1

A species having carbon with sextet of electrons and can act as electrophile is called:

  1. A.carbocation
  2. B.pentavalent carbon
  3. C.carbanion
  4. D.carbon free radical

Correct answer: A

Question 78

Chemistry · 4 marks · −1

'Adsorption' principle is used for which of the following purification method?

  1. A.Distillation
  2. B.Sublimation
  3. C.Chromatography
  4. D.Extraction

Correct answer: C

Question 79

Chemistry · 4 marks · −1

The metals that are employed in the battery industries are: A. Fe B. Mn C. Ni D. Cr E. Cd Choose the correct answer from the options given below:

  1. A.A, B, C, D and E
  2. B.A, B, C and D only
  3. C.B, D and E only
  4. D.B, C and E only

Correct answer: D

Question 80

Chemistry · 4 marks · −1

Integrated rate law equation for a first order gas phase reaction is given by (where PiP_i is initial pressure and PtP_t is total pressure at time t)

  1. A.k=2.303t×Pi(2Pi−Pt)k=\frac{2.303}{t}\times\frac{P_i}{(2P_i-P_t)}
  2. B.k=2.303t×log⁡(2Pi−Pt)Pik=\frac{2.303}{t}\times\log\frac{(2P_i-P_t)}{P_i}
  3. C.k=2.303t×log⁡Pi(2Pi−Pt)k=\frac{2.303}{t}\times\log\frac{P_i}{(2P_i-P_t)}
  4. D.k=2.303t×2Pi(2Pi−Pt)k=\frac{2.303}{t}\times\frac{2P_i}{(2P_i-P_t)}

Correct answer: C

Explanation: For A → B + C, reactant pressure at time t is 2Pi−Pt2P_i-P_t.

Question 81

Chemistry · 4 marks · −1

The product of the following reaction is P. 4-Hydroxybenzaldehyde →(i) PhMgBr (1 equiv.) (ii) aq. NH4Cl\xrightarrow{\text{(i) PhMgBr (1 equiv.)}\ \text{(ii) aq. NH}_4\text{Cl}} P The number of hydroxyl groups present in the product P is ______.

Figure for question 81

Correct answer: 0

Question 82

Chemistry · 4 marks · −1

CH3CH2Br+NaOH\text{CH}_3\text{CH}_2\text{Br}+\text{NaOH}: in C2H5OH\text{C}_2\text{H}_5\text{OH} → Product A; in H2O\text{H}_2\text{O} → Product B The total number of hydrogen atoms in product A and product B is ______.

Correct answer: 10

Explanation: A = ethene (4 H), B = ethanol (6 H).

Question 83

Chemistry · 4 marks · −1

Molar mass of the salt from NaBr, NaNO3\text{NaNO}_3, KI and CaF2\text{CaF}_2 which does not evolve coloured vapours on heating with concentrated H2SO4\text{H}_2\text{SO}_4 is ______ g mol−1^{-1}. (Molar mass in g mol−1^{-1} : Na : 23, N : 14, K : 39, O : 16, Br : 80, I : 127, F : 19, Ca : 40)

Correct answer: 78

Explanation: CaF2_2 gives colourless HF: 78.

Question 84

Chemistry · 4 marks · −1

Number of moles of methane required to produce 22g CO2(g)\text{CO}_{2(g)} after combustion is x×10−2x\times10^{-2} moles. The value of x is ______.

Correct answer: 50

Explanation: 0.5 mol.

Question 85

Chemistry · 4 marks · −1

The 'Spin only' Magnetic moment for [Ni(NH3)6]2+[\text{Ni(NH}_3)_6]^{2+} is ______ ×10−1\times10^{-1} BM. (given = Atomic number of Ni : 28)

Correct answer: 28

Explanation: Ni2+^{2+}, two unpaired electrons: 8=2.83\sqrt8=2.83 BM.

Question 86

Chemistry · 4 marks · −1

Number of alkanes obtained on electrolysis of a mixture of CH3COONa\text{CH}_3\text{COONa} and C2H5COONa\text{C}_2\text{H}_5\text{COONa} is ______.

Correct answer: 3

Explanation: Ethane, propane, butane.

Question 87

Chemistry · 4 marks · −1

One Faraday of electricity liberates x×10−1x\times10^{-1} gram atom of copper from copper sulphate. x is ______.

Correct answer: 5

Explanation: 0.5 gram atom.

Question 88

Chemistry · 4 marks · −1

The ionization energy of sodium in kJ mol−1^{-1}, if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is ______.

Correct answer: 494

Explanation: hcNAλ=0.1196242×10−9\frac{hcN_A}{\lambda}=\frac{0.1196}{242\times10^{-9}} J/mol ≈ 494 kJ/mol.

Question 89

Chemistry · 4 marks · −1

The number of species from the following in which the central atom uses sp3sp^3 hybrid orbitals in its bonding is ______. NH3\text{NH}_3, SO2\text{SO}_2, SiO2\text{SiO}_2, BeCl2\text{BeCl}_2, CO2\text{CO}_2, H2O\text{H}_2\text{O}, CH4\text{CH}_4, BF3\text{BF}_3

Correct answer: 4

Explanation: NH3_3, SiO2_2, H2_2O, CH4_4.

Question 90

Chemistry · 4 marks · −1

Consider the following reaction at 298 K. 32O2(g)⇌O3(g)\frac32\text{O}_{2(g)}\rightleftharpoons\text{O}_{3(g)}, KP=2.47×10−29K_P=2.47\times10^{-29}. ΔrG∘\Delta_rG^\circ for the reaction is ______ kJ. (Given R = 8.314 J K−1^{-1} mol−1^{-1})

Correct answer: 163

Explanation: ΔG∘=−RTln⁡K=−8.314×298×(−65.87)≈163\Delta G^\circ=-RT\ln K=-8.314\times298\times(-65.87)\approx163 kJ.

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