JEE Main 2025 — 28 Jan Shift 1 (Previous Year Paper)

JEE Main · 2025 · with answers and explanations

questions
74
Total marks
296
Duration
180 minutes
Negative marking
−1

Subjects: Mathematics · Physics · Chemistry

Question 1

Mathematics · 4 marks · −1

If f(x)=2x2x+2f(x)=\frac{2^x}{2^x+\sqrt{2}}, x∈Rx\in\mathbf{R}, then ∑k=181f(k82)\sum_{k=1}^{81}f\left(\frac{k}{82}\right) is equal to

  1. A.812\frac{81}{2}
  2. B.41
  3. C.82
  4. D.81281\sqrt{2}

Correct answer: A

Explanation: f(x)+f(1−x)=1f(x)+f(1-x)=1: 40 pairs + f(12)=12f(\frac12)=\frac12 → 81/2.

Question 2

Mathematics · 4 marks · −1

If ∫−π/2π/296x2cos⁡2x(1+ex)dx=π(απ2+β)\int_{-\pi/2}^{\pi/2}\frac{96x^2\cos^2x}{(1+e^x)}dx=\pi(\alpha\pi^2+\beta), α,β∈Z\alpha, \beta\in\mathbf{Z}, then (α+β)2(\alpha+\beta)^2 equals

  1. A.144
  2. B.100
  3. C.196
  4. D.64

Correct answer: B

Explanation: =∫0π/296x2cos⁡2x dx=48(π324−π4)=π(2π2−12)=\int_0^{\pi/2}96x^2\cos^2x\,dx=48\left(\frac{\pi^3}{24}-\frac{\pi}{4}\right)=\pi(2\pi^2-12): (2−12)2=100(2-12)^2=100.

Question 3

Mathematics · 4 marks · −1

Let the equation of the circle, which touches x-axis at the point (a, 0), a > 0 and cuts off an intercept of length b on y-axis be x2+y2−αx+βy+γ=0x^2+y^2-\alpha x+\beta y+\gamma=0. If the circle lies below x-axis, then the ordered pair (2a,b2)(2a, b^2) is equal to

  1. A.(α,β2−4γ)(\alpha, \beta^2-4\gamma)
  2. B.(γ,β2+4α)(\gamma, \beta^2+4\alpha)
  3. C.(γ,β2−4α)(\gamma, \beta^2-4\alpha)
  4. D.(α,β2+4γ)(\alpha, \beta^2+4\gamma)

Correct answer: A

Explanation: Centre (a,−r)(a,-r): α = 2a; y-intercept b2=β2−4γb^2=\beta^2-4\gamma.

Question 4

Mathematics · 4 marks · −1

Let for some function y=f(x)y=f(x), ∫0xtf(t)dt=x2f(x)\int_0^xtf(t)dt=x^2f(x), x > 0 and f(2) = 3. Then f(6) is equal to

  1. A.6
  2. B.1
  3. C.3
  4. D.2

Correct answer: B

Explanation: xf=2xf+x2f′xf=2xf+x^2f' ⇒ f′/f=−1/xf'/f=-1/x ⇒ f=c/xf=c/x: f(6) = 1.

Question 5

Mathematics · 4 marks · −1

Let A (x, y, z) be a point in xy- plane, which is equidistant from three points (0, 3, 2), (2, 0, 3) and (0, 0, 1). Let B = (1, 4, −1) and C = (2, 0, −2). Then among the statements (S1) : △ABC\triangle ABC is an isosceles right angled triangle, and (S2) : the area of △ABC\triangle ABC is 922\frac{9\sqrt{2}}{2},

  1. A.both are true
  2. B.only (S1) is true
  3. C.only (S2) is true
  4. D.both are false

Correct answer: B

Question 6

Mathematics · 4 marks · −1

The relation R = {(x, y) : x, y ∈ Z and x + y is even} is:

  1. A.an equivalence relation
  2. B.symmetric and transitive but not reflexive
  3. C.reflexive and symmetric but not transitive
  4. D.reflexive and transitive but not symmetric

Correct answer: A

Question 7

Mathematics · 4 marks · −1

cos⁡(sin⁡−135+sin⁡−1513+sin⁡−13365)\cos\left(\sin^{-1}\frac{3}{5}+\sin^{-1}\frac{5}{13}+\sin^{-1}\frac{33}{65}\right) is equal to:

  1. A.1
  2. B.3365\frac{33}{65}
  3. C.0
  4. D.3265\frac{32}{65}

Correct answer: C

Explanation: sin⁡−135+sin⁡−1513=sin⁡−15665=cos⁡−13365\sin^{-1}\frac35+\sin^{-1}\frac{5}{13}=\sin^{-1}\frac{56}{65}=\cos^{-1}\frac{33}{65}, which with sin⁡−13365\sin^{-1}\frac{33}{65} sums to π2\frac\pi2: cos = 0.

Question 8

Mathematics · 4 marks · −1

The sum of all local minimum values of the function f(x)={1−2x,x<−113(7+2∣x∣),−1≤x≤21118(x−4)(x−5),x>2f(x)=\begin{cases}1-2x, & x<-1\\ \frac{1}{3}(7+2|x|), & -1\le x\le2\\ \frac{11}{18}(x-4)(x-5), & x>2\end{cases} is

  1. A.13172\frac{131}{72}
  2. B.16772\frac{167}{72}
  3. C.15772\frac{157}{72}
  4. D.17172\frac{171}{72}

Correct answer: C

Explanation: Local minima: f(0) = 7/3 and f(4.5) = −11/72: sum 168−1172=15772\frac{168-11}{72}=\frac{157}{72}.

Question 9

Mathematics · 4 marks · −1

The sum, of the squares of all the roots of the equation x2+∣2x−3∣−4=0x^2+|2x-3|-4=0, is

  1. A.3(2−2)3(2-\sqrt{2})
  2. B.6(2−2)6(2-\sqrt{2})
  3. C.6(3−2)6(3-\sqrt{2})
  4. D.3(3−2)3(3-\sqrt{2})

Correct answer: B

Explanation: x≥32x\ge\frac32: x2+2x−7=0x^2+2x-7=0 ⇒ x=−1+22x=-1+2\sqrt2; x<32x<\frac32: x2−2x−1=0x^2-2x-1=0 ⇒ x=1−2x=1-\sqrt2. Squares: 9−42+3−22=6(2−2)9-4\sqrt2+3-2\sqrt2=6(2-\sqrt2).

Question 10

Mathematics · 4 marks · −1

Let nCr−1=28{}^nC_{r-1}=28, nCr=56{}^nC_r=56 and nCr+1=70{}^nC_{r+1}=70. Let A (4cost, 4sint), B (2sint, −2cost) and C (3r−n,r2−n−1)(3r-n, r^2-n-1) be the vertices of a triangle ABC, where t is a parameter. If (3x−1)2+(3y)2=α(3x-1)^2+(3y)^2=\alpha, is the locus of the centroid of triangle ABC, then α\alpha equals

  1. A.20
  2. B.8
  3. C.6
  4. D.18

Correct answer: A

Explanation: n = 8, r = 3: C = (1, 0); 3x−1=4cos⁡t+2sin⁡t3x-1=4\cos t+2\sin t, 3y=4sin⁡t−2cos⁡t3y=4\sin t-2\cos t ⇒ α = 20.

Question 11

Mathematics · 4 marks · −1

Three defective oranges are accidently mixed with seven good ones and on looking at them, it is not possible to differentiate between them. Two oranges are drawn at random from the lot. If x denote the number of defective oranges, then the variance of x is

  1. A.14/25
  2. B.18/25
  3. C.26/75
  4. D.28/75

Correct answer: D

Question 12

Mathematics · 4 marks · −1

Let f:R→Rf:\mathbf{R}\to\mathbf{R} be a function defined by f(x)=(2+3a)x2+(a+2a−1)x+bf(x)=(2+3a)x^2+\left(\frac{a+2}{a-1}\right)x+b, a≠1a\neq1. If f(x+y)=f(x)+f(y)+1−27xyf(x+y)=f(x)+f(y)+1-\frac{2}{7}xy, then the value of 28∑i=15∣f(i)∣28\sum_{i=1}^{5}|f(i)| is

  1. A.545
  2. B.675
  3. C.715
  4. D.735

Correct answer: B

Question 13

Mathematics · 4 marks · −1

Two number k1k_1 and k2k_2 are randomly chosen from the set of natural numbers. Then, the probability that the value of ik1+ik2i^{k_1}+i^{k_2}, (i=−1)(i=\sqrt{-1}) is non-zero, equals

  1. A.34\frac{3}{4}
  2. B.14\frac{1}{4}
  3. C.12\frac{1}{2}
  4. D.23\frac{2}{3}

Correct answer: A

Explanation: Zero only when the residues differ by 2 mod 4 (4 of 16 pairs): 3/4.

Question 14

Mathematics · 4 marks · −1

If the image of the point (4, 4, 3) in the line x−12=y−21=z−13\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-1}{3} is (α,β,γ)(\alpha, \beta, \gamma), then α+β+γ\alpha+\beta+\gamma is equal to

  1. A.9
  2. B.7
  3. C.12
  4. D.8

Correct answer: A

Question 15

Mathematics · 4 marks · −1

The area (in sq. units) of the region {(x,y):0≤y≤2∣x∣+1,0≤y≤x2+1,∣x∣≤3}\{(x, y): 0\le y\le2|x|+1, 0\le y\le x^2+1, |x|\le3\} is

  1. A.803\frac{80}{3}
  2. B.643\frac{64}{3}
  3. C.323\frac{32}{3}
  4. D.173\frac{17}{3}

Correct answer: B

Explanation: By symmetry 2[∫02(x2+1)dx+∫23(2x+1)dx]=2[143+6]=6432\left[\int_0^2(x^2+1)dx+\int_2^3(2x+1)dx\right]=2\left[\frac{14}{3}+6\right]=\frac{64}{3}.

Question 16

Mathematics · 4 marks · −1

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is

  1. A.4608
  2. B.5719
  3. C.4607
  4. D.5720

Correct answer: C

Question 17

Mathematics · 4 marks · −1

Let TrT_r be the rthr^{th} term of an A.P. If for some m, Tm=125T_m=\frac{1}{25}, T25=120T_{25}=\frac{1}{20}, and 20∑r=125Tr=1320\sum_{r=1}^{25}T_r=13, then 5m∑r=m2mTr5m\sum_{r=m}^{2m}T_r is equal to

  1. A.126
  2. B.98
  3. C.142
  4. D.112

Correct answer: A

Question 18

Mathematics · 4 marks · −1

Let ⟨an⟩\langle a_n\rangle be a sequence such that a0=0a_0=0, a1=12a_1=\frac{1}{2} and 2an+2=5an+1−3an2a_{n+2}=5a_{n+1}-3a_n, n = 0, 1, 2, 3, .... Then ∑k=1100ak\sum_{k=1}^{100}a_k is equal to

  1. A.3a99−1003a_{99}-100
  2. B.3a100−1003a_{100}-100
  3. C.3a100+1003a_{100}+100
  4. D.3a99+1003a_{99}+100

Correct answer: B

Explanation: an=(32)n−1a_n=\left(\frac32\right)^n-1; ∑1100ak=3((32)100−1)−100=3a100−100\sum_1^{100}a_k=3\left(\left(\tfrac32\right)^{100}-1\right)-100=3a_{100}-100.

Question 19

Mathematics · 4 marks · −1

Let ABCD be a trapezium whose vertices lie on the parabola y2=4xy^2=4x. Let the sides AD and BC of the trapezium be parallel to y-axis. If the diagonal AC is of length 254\frac{25}{4} and it passes through the point (1, 0), then the area of ABCD is

  1. A.758\frac{75}{8}
  2. B.252\frac{25}{2}
  3. C.1258\frac{125}{8}
  4. D.754\frac{75}{4}

Correct answer: D

Question 20

Mathematics · 4 marks · −1

Let O be the origin, the point A be z1=3+22iz_1=\sqrt{3}+2\sqrt{2}i, the point B (z2z_2) be such that 3∣z2∣=∣z1∣\sqrt{3}|z_2|=|z_1| and arg⁡(z2)=arg⁡(z1)+π6\arg(z_2)=\arg(z_1)+\frac{\pi}{6}. Then

  1. A.area of triangle ABO is 114\frac{11}{4}
  2. B.ABO is a scalene triangle
  3. C.area of triangle ABO is 113\frac{11}{\sqrt{3}}
  4. D.ABO is an obtuse angled isosceles triangle

Correct answer: D

Explanation: ∣z1∣=11|z_1|=\sqrt{11}, ∣z2∣=11/3|z_2|=\sqrt{11/3}; area =121111/3sin⁡30∘=1143=\frac12\sqrt{11}\sqrt{11/3}\sin30^\circ=\frac{11}{4\sqrt3}; sides 11\sqrt{11}, 11/3\sqrt{11/3}, 11/3\sqrt{11/3} → isosceles with 120° at B.

Question 21

Mathematics · 4 marks · −1

Let f(x)={3x,x<0min⁡{1+x+[x],x+2[x]},0≤x≤25,x>2f(x)=\begin{cases}3x, & x<0\\ \min\{1+x+[x], x+2[x]\}, & 0\le x\le2\\ 5, & x>2\end{cases}, where [.] denotes greatest integer function. If α\alpha and β\beta are the number of points, where f is not continuous and is not differentiable, respectively, then α+β\alpha+\beta equals ______.

Correct answer: 5

Question 22

Mathematics · 4 marks · −1

Let a⃗=i^+j^+k^\vec{a}=\hat{i}+\hat{j}+\hat{k}, b⃗=2i^+2j^+k^\vec{b}=2\hat{i}+2\hat{j}+\hat{k} and d⃗=a⃗×b⃗\vec{d}=\vec{a}\times\vec{b}. If c⃗\vec{c} is a vector such that a⃗⋅c⃗=∣c⃗∣\vec{a}\cdot\vec{c}=|\vec{c}|, ∣c⃗−2a⃗∣2=8|\vec{c}-2\vec{a}|^2=8 and the angle between d⃗\vec{d} and c⃗\vec{c} is π4\frac{\pi}{4}, then ∣10−3b⃗⋅c⃗∣+∣d⃗×c⃗∣2|10-3\vec{b}\cdot\vec{c}|+|\vec{d}\times\vec{c}|^2 is equal to ______.

Correct answer: 6

Question 23

Mathematics · 4 marks · −1

Let E1E_1: x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=1 be an ellipse. Ellipses EiE_i's are constructed such that their centres and eccentricities are same as that of E1E_1, and the length of minor axis of EiE_i is the length of major axis of Ei+1E_{i+1} (i≥1i\ge1). If AiA_i is the area of the ellipse EiE_i, then 5π(∑i=1∞Ai)\frac{5}{\pi}\left(\sum_{i=1}^{\infty}A_i\right), is equal to ______.

Correct answer: 54

Explanation: Scale ratio 2/3 each step: areas GP with ratio 4/9: ∑A=6π5/9=54π5\sum A=\frac{6\pi}{5/9}=\frac{54\pi}{5}; answer 54.

Question 24

Mathematics · 4 marks · −1

If α=1+∑r=16(−3)r−1 12C2r−1\alpha=1+\sum_{r=1}^{6}(-3)^{r-1}\,{}^{12}C_{2r-1}, then the distance of the point (12,3)(12, \sqrt{3}) from the line αx−3y+1=0\alpha x-\sqrt{3}y+1=0 is ______.

Correct answer: 5

Question 25

Mathematics · 4 marks · −1

Let M denote the set of all real matrices of order 3 × 3 and let S = {−3, −2, −1, 1, 2}. Let S1={A=[aij]∈M:A=ATS_1=\{A=[a_{ij}]\in M: A=A^T and aij∈S,∀i,j}a_{ij}\in S, \forall i, j\}, S2={A=[aij]∈M:A=−ATS_2=\{A=[a_{ij}]\in M: A=-A^T and aij∈S,∀i,j}a_{ij}\in S, \forall i, j\}, S3={A=[aij]∈M:a11+a22+a33=0S_3=\{A=[a_{ij}]\in M: a_{11}+a_{22}+a_{33}=0 and aij∈S,∀i,j}a_{ij}\in S, \forall i, j\}. If n(S1∪S2∪S3)=125αn(S_1\cup S_2\cup S_3)=125\alpha, then α\alpha equals ______.

Correct answer: 1613

Question 26

Physics · 4 marks · −1

Due to presence of an em-wave whose electric component is given by E=100sin⁡(ωt−kx)E=100\sin(\omega t-kx) NC−1C^{-1}, a cylinder of length 200 cm holds certain amount of em-energy inside it. If another cylinder of same length but half diameter than previous one holds same amount of em-energy, the magnitude of the electric field of the corresponding em-wave should be modified as

  1. A.25 sin(ωt\omega t−kx) NC−1C^{-1}
  2. B.50 sin(ωt\omega t−kx) NC−1C^{-1}
  3. C.400 sin(ωt\omega t−kx) NC−1C^{-1}
  4. D.200 sin(ωt\omega t−kx) NC−1C^{-1}

Correct answer: D

Explanation: Volume 1/4 ⇒ energy density ×4 ⇒ E × 2 = 200.

Question 27

Physics · 4 marks · −1

In the experiment for measurement of viscosity 'η\eta' of given liquid with a ball having radius R, consider following statements. A. Graph between terminal velocity V and R will be a parabola. B. The terminal velocities of different diameter balls are constant for a given liquid. C. Measurement of terminal velocity is dependent on the temperature. D. This experiment can be utilized to assess the density of a given liquid. E. If balls are dropped with some initial speed, the value of η\eta will change. Choose the correct answer from the options given below:

  1. A.C, D and E Only
  2. B.B, D and E Only
  3. C.A, C and D Only
  4. D.A, B and E Only

Correct answer: C

Question 28

Physics · 4 marks · −1

For a particular ideal gas which of the following graphs represents the variation of mean squared velocity of the gas molecules with temperature?

Figure for question 28
  1. A.Concave-down increasing curve
  2. B.Curve rising to a peak then falling
  3. C.Concave-up increasing curve
  4. D.Straight line through the origin

Correct answer: D

Explanation: v2‾=3RT/M\overline{v^2}=3RT/M ∝ T.

Question 29

Physics · 4 marks · −1

A hemispherical vessel is completely filled with a liquid of refractive index μ\mu. A small coin is kept at the lowest point (O) of the vessel as shown in figure. The minimum value of the refractive index of the liquid so that a person can see the coin from point E (at the level of the vessel) is ______.

Figure for question 29
  1. A.2\sqrt{2}
  2. B.32\frac{\sqrt{3}}{2}
  3. C.32\frac{3}{2}
  4. D.3\sqrt{3}

Correct answer: A

Explanation: The ray from O reaching E must graze the surface at B; at B the ray OB makes 45° with the normal: μsin⁡45∘=sin⁡90∘\mu\sin45^\circ=\sin90^\circ ⇒ μ=2\mu=\sqrt2.

Question 30

Physics · 4 marks · −1

Find the equivalent resistance between two ends of the following circuit

Figure for question 30
  1. A.r3\frac{r}{3}
  2. B.r
  3. C.r9\frac{r}{9}
  4. D.r6\frac{r}{6}

Correct answer: C

Explanation: All three r/3 resistors are in parallel: r/9.

Question 31

Physics · 4 marks · −1

The center of mass of a thin rectangular plate (fig - x) with sides of length a and b, whose mass per unit area (σ\sigma) varies as σ=σ0xab\sigma=\frac{\sigma_0x}{ab} (where σ0\sigma_0 is a constant), would be ______

Figure for question 31
  1. A.(13a,b2)\left(\frac{1}{3}a, \frac{b}{2}\right)
  2. B.(23a,23b)\left(\frac{2}{3}a, \frac{2}{3}b\right)
  3. C.(a2,b2)\left(\frac{a}{2}, \frac{b}{2}\right)
  4. D.(23a,b2)\left(\frac{2}{3}a, \frac{b}{2}\right)

Correct answer: D

Explanation: xcm=∫x2∫x=2a3x_{cm}=\frac{\int x^2}{\int x}=\frac{2a}{3}; ycm=b/2y_{cm}=b/2.

Question 32

Physics · 4 marks · −1

Choose the correct nuclear process from the below options [p: proton, n: neutron, e−e^-: electron, e+e^+: positron, ν\nu : neutrino, νˉ\bar{\nu} : antineutrino]

  1. A.n→p+e++νˉn\to p+e^++\bar{\nu}
  2. B.n→p+e++νn\to p+e^++\nu
  3. C.n→p+e−+νˉn\to p+e^-+\bar{\nu}
  4. D.n→p+e−+νn\to p+e^-+\nu

Correct answer: C

Question 33

Physics · 4 marks · −1

Three infinitely long wires with linear charge density λ\lambda are placed along the x–axis, y–axis and z–axis respectively. Which of the following denotes an equipotential surface?

  1. A.(x + y) (y + z) (z + x) = constant
  2. B.xyz = constant
  3. C.xy + yz + zx = constant
  4. D.(x2+y2)(y2+z2)(z2+x2)(x^2+y^2)(y^2+z^2)(z^2+x^2) = constant

Correct answer: D

Explanation: V=−λ4πϵ0ln⁡[(y2+z2)(z2+x2)(x2+y2)]V=-\frac{\lambda}{4\pi\epsilon_0}\ln[(y^2+z^2)(z^2+x^2)(x^2+y^2)] + const.

Question 34

Physics · 4 marks · −1

A wire of resistance R is bent into an equilateral triangle and an identical wire is bent into a square. The ratio of resistance between the two end points of an edge of the triangle to that of the square is

  1. A.32/27
  2. B.27/32
  3. C.9/8
  4. D.8/9

Correct answer: A

Explanation: Triangle: (R/3)(2R/3)R=2R9\frac{(R/3)(2R/3)}{R}=\frac{2R}{9}; square: (R/4)(3R/4)R=3R16\frac{(R/4)(3R/4)}{R}=\frac{3R}{16}; ratio 32/27.

Question 35

Physics · 4 marks · −1

Consider a long thin conducting wire carrying a uniform current I. A particle having mass "M" and charge "q" is released at a distance "a" from the wire with a speed v0v_0 along the direction of current in the wire. The particle gets attracted to the wire due to magnetic force. The particle turns round when it is at distance x from the wire. The value of x is [μ0\mu_0 is vacuum permeability]

  1. A.a[1−mv02qμ0I]a\left[1-\frac{mv_0}{2q\mu_0I}\right]
  2. B.a2\frac{a}{2}
  3. C.ae−4πmv0qμ0Iae^{-\frac{4\pi mv_0}{q\mu_0I}}
  4. D.a[1−mv0qμ0I]a\left[1-\frac{mv_0}{q\mu_0I}\right]

Correct answer: C

Explanation: m dvx=−qB dym\,dv_x=-qB\,dy with B=μ0I2πrB=\frac{\mu_0I}{2\pi r}; speed constant: at turning point vx=−v0v_x=-v_0: 2mv0=qμ0I2πln⁡ax2mv_0=\frac{q\mu_0I}{2\pi}\ln\frac ax ⇒ x=ae−4πmv0/(qμ0I)x=ae^{-4\pi mv_0/(q\mu_0I)}.

Question 36

Physics · 4 marks · −1

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: A sound wave has higher speed in solids than gases. Reason R: Gases have higher value of Bulk modulus than solids. In the light of the above statements, choose the correct answer from the options given below

  1. A.A is false but R is true
  2. B.Both A and R are true and R is the correct explanation of A
  3. C.A is true but R is false
  4. D.Both A and R are true but R is NOT the correct explanation of A

Correct answer: C

Question 37

Physics · 4 marks · −1

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: In a central force field, the work done is independent of the path chosen. Reason R: Every force encountered in mechanics does not have an associated potential energy. In the light of the above statements, choose the most appropriate answer from the options given below

  1. A.A is true but R is false
  2. B.Both A and R are true and R is the correct explanation of A
  3. C.Both A and R are true but R is NOT the correct explanation of A
  4. D.A is false but R is true

Correct answer: C

Question 38

Physics · 4 marks · −1

A bead of mass 'm' slides without friction on the wall of a vertical circular hoop of radius 'R' as shown in figure. The bead moves under the combined action of gravity and a massless spring (k) attached to the bottom of the hoop. The equilibrium length of the spring is 'R'. If the bead is released from top of the hoop with (negligible) zero initial speed, velocity of bead, when the length of spring becomes 'R', would be (spring constant is 'k', g is accleration due to gravity)

Figure for question 38
  1. A.2gR+kR2m2\sqrt{gR+\frac{kR^2}{m}}
  2. B.2Rg+4kR2m\sqrt{2Rg+\frac{4kR^2}{m}}
  3. C.2Rg+kR2m\sqrt{2Rg+\frac{kR^2}{m}}
  4. D.3Rg+kR2m\sqrt{3Rg+\frac{kR^2}{m}}

Correct answer: D

Explanation: The spring (natural length R, fixed at the bottom of the hoop) has length R when the bead is at 60° from the bottom point, i.e. 3R/2 below the top. Energy: 12kR2+mg3R2=12mv2\frac12kR^2+mg\frac{3R}{2}=\frac12mv^2 (spring initially stretched to 2R) ⇒ v=3gR+kR2mv=\sqrt{3gR+\frac{kR^2}{m}}.

Question 39

Physics · 4 marks · −1

Which of the following circuits has the same outpur as that of the given circuit? [A and NOT(B) feed an AND gate; A and B feed a second AND gate; the two AND outputs feed a NOR gate giving Y]

Figure for question 39
  1. A.B alone into a NOT (drawn as AND-with-bubble with one input) giving Y
  2. B.A and B into an AND gate giving Y
  3. C.A and B into an AND gate followed by a NOT giving Y
  4. D.A alone into a NOT gate giving Y

Correct answer: D

Explanation: Y=ABˉ+AB‾=AˉY=\overline{A\bar B+AB}=\bar A.

Question 40

Physics · 4 marks · −1

A particle of mass 'm' and charge 'q' is fastened to one end 'A' of a massless string having equilibrium length ll, whose other end is fixed at point 'O'. The whole system is placed on a frictionless horizontal plane and is initially at rest. If uniform electric field is switched on along the direction as shown in figure, then the speed of the particle when it crosses the x–axis is

Figure for question 40
  1. A.qElm\sqrt{\frac{qEl}{m}}
  2. B.qEl2m\sqrt{\frac{qEl}{2m}}
  3. C.qEl4m\sqrt{\frac{qEl}{4m}}
  4. D.2qElm\sqrt{\frac{2qEl}{m}}

Correct answer: A

Explanation: Work =qEl(1−cos⁡60∘)=qEl2=qEl(1-\cos60^\circ)=\frac{qEl}{2} ⇒ v=qEl/mv=\sqrt{qEl/m}.

Question 41

Physics · 4 marks · −1

A proton of mass 'mpm_p' has same energy as that of a photon of wavelength 'λ\lambda'. If the proton is moving at non-relativistic speed, then ratio of its de Broglie wavelength to the wavelength of photon is.

  1. A.1cE2mp\frac{1}{c}\sqrt{\frac{E}{2m_p}}
  2. B.1c2Emp\frac{1}{c}\sqrt{\frac{2E}{m_p}}
  3. C.12cEmp\frac{1}{2c}\sqrt{\frac{E}{m_p}}
  4. D.1cEmp\frac{1}{c}\sqrt{\frac{E}{m_p}}

Correct answer: A

Explanation: h/2mpEhc/E=1cE2mp\frac{h/\sqrt{2m_pE}}{hc/E}=\frac1c\sqrt{\frac{E}{2m_p}}.

Question 42

Physics · 4 marks · −1

A thin prism P1P_1 with angle 4° made of glass having refractive index 1.54, is combined with another thin prism P2P_2 made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism P2P_2 in degrees is

  1. A.16/3
  2. B.1.5
  3. C.3
  4. D.4

Correct answer: C

Explanation: 0.54×4=0.72A0.54\times4=0.72A ⇒ A = 3°.

Question 43

Physics · 4 marks · −1

A Carnot engine (E) is working between two temperatures 473K and 273K. In a new system two engines - engine E1E_1 works between 473K to 373K and engine E2E_2 works between 373K to 273K. If η12\eta_{12}, η1\eta_1 and η2\eta_2 are the efficiencies of the engines E, E1E_1 and E2E_2, respectively, then

  1. A.η12≥η1+η2\eta_{12}\ge\eta_1+\eta_2
  2. B.η12=η1+η2\eta_{12}=\eta_1+\eta_2
  3. C.η12=η1η2\eta_{12}=\eta_1\eta_2
  4. D.η12<η1+η2\eta_{12}<\eta_1+\eta_2

Correct answer: D

Explanation: 1−η=(1−η1)(1−η2)1-\eta=(1-\eta_1)(1-\eta_2) ⇒ η=η1+η2−η1η2<η1+η2\eta=\eta_1+\eta_2-\eta_1\eta_2<\eta_1+\eta_2.

Question 44

Physics · 4 marks · −1

Two capacitors C1C_1 and C2C_2 are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are U1U_1 and U2U_2, respectively. Which of the given statements is true?

Figure for question 44
  1. A.C2>C1C_2>C_1, U2<U1U_2<U_1
  2. B.C1>C2C_1>C_2, U1<U2U_1<U_2
  3. C.C2>C1C_2>C_1, U2>U1U_2>U_1
  4. D.C1>C2C_1>C_2, U1>U2U_1>U_2

Correct answer: C

Explanation: Same V; C2 saturates at the higher charge ⇒ C2 > C1 and U2 > U1.

Question 45

Physics · 4 marks · −1

Consider following statements: A. Surface tension arises due to extra energy of the molecules at the interior as compared to the molecules at the surface, of a liquid. B. As the temperature of liquid rises, the coefficient of viscosity increases. C. As the temperature of gas increases, the coefficient of viscosity increases D. The onset of turbulence is determined by Reynold's number. E. In a steady flow two stream lines never intersect. Choose the correct answer from the options given below:

  1. A.A, B, C Only
  2. B.C, D, E Only
  3. C.B, C, D Only
  4. D.A, D, E Only

Correct answer: B

Question 46

Physics · 4 marks · −1

In a measurement, it is asked to find modulus of elasticity per unit torque applied on the system. The measured quantity has dimension of [MaLbTc][M^aL^bT^c]. If b = 3, the value of c is ______

Correct answer: 0

Explanation: ML−1T−2ML2T−2=L−3\frac{ML^{-1}T^{-2}}{ML^2T^{-2}}=L^{-3}, so a = 0, b = −3, c = 0.

Question 47

Physics · 4 marks · −1

A double slit interference experiment performed with a light of wavelength 600 nm forms an interference fringe pattern on a screen with 10th bright fringe having its centre at a distance of 10 mm from the central maximum. Distance of the centre of the same 10th bright fringe from the central maximum when the source of light is replaced by another source of wavelength 660 nm would be ______ mm.

Correct answer: 11

Explanation: y ∝ λ: 11 mm.

Question 48

Physics · 4 marks · −1

A tiny metallic rectangular sheet has length and breadth of 5 mm and 2.5 mm, respectively. Using a specially designed screw gauge which has pitch of 0.75 mm and 15 divisions in the circular scale, you are asked to find the area of the sheet. In this measurement, the maximum fractional error will be x100\frac{x}{100} where x is ______.

Correct answer: 3

Explanation: LC = 0.05 mm: 0.055+0.052.5=0.03\frac{0.05}{5}+\frac{0.05}{2.5}=0.03, x = 3.

Question 49

Physics · 4 marks · −1

Two iron solid discs of negligible thickness have radii R1R_1 and R2R_2 and moment of intertia I1I_1 and I2I_2, respectively. For R2=2R1R_2=2R_1, the ratio of I1I_1 and I2I_2 would be 1/x, where x = ______.

Correct answer: 16

Explanation: Same thickness and material: m∝R2m\propto R^2, I∝R4I\propto R^4: x = 16.

Question 50

Physics · 4 marks · −1

The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in similar way. The moment of inertia of a solid sphere which has same radius as the disc and rotating in similar way, is n times higher than the moment of inertia of the given ring. Here, n = ______. Consider all the bodies have equal masses.

Correct answer: 4

Explanation: Disc about diameter MRd24=2.5⋅MRr22\frac{MR_d^2}{4}=2.5\cdot\frac{MR_r^2}{2} ⇒ Rd2=5Rr2R_d^2=5R_r^2; sphere 25MRd2=2MRr2=4×MRr22\frac25MR_d^2=2MR_r^2=4\times\frac{MR_r^2}{2}: n = 4.

Question 51

Chemistry · 4 marks · −1

Given below are two statements: Statement I: In the oxalic acid vs KMnO4KMnO_4 (in the presence of dil H2SO4H_2SO_4) titration the solution needs to be heated initially to 60°C, but no heating is required in Ferrous ammonium sulphate (FAS) vs KMnO4KMnO_4 titration (in the presence of dil H2SO4H_2SO_4) Statement II: In oxalic acid vs KMnO4KMnO_4 titration, the initial formation of MnSO4MnSO_4 takes place at high temperature, which then acts as catalyst for further reaction. In the case of FAS vs KMnO4KMnO_4, heating oxidizes Fe2+Fe^{2+} into Fe3+Fe^{3+} by oxygen of air and error may be introduced in the experiment. In the light of the above statements, choose the correct answer from the options given below

  1. A.Both Statement I and Statement II are true
  2. B.Statement I is true but Statement II is false
  3. C.Both Statement I and Statement II are false
  4. D.Statement I is false but Statement II is true

Correct answer: A

Question 52

Chemistry · 4 marks · −1

Both acetaldehyde and acetone (individually) undergo which of the following reactions? A. Iodoform Reaction B. Cannizaro Reaction C. Aldol Condensation D. Tollen's Test E. Clemmensen Reduction. Choose the correct answer from the options given below:

  1. A.B, C and D Only
  2. B.A, C and E Only
  3. C.A, B and D Only
  4. D.C and E Only

Correct answer: B

Question 53

Chemistry · 4 marks · −1

Given below are two statements: Statement I : D-glucose pentaacetate reacts with 2, 4 – dinitrophenylhydrazine Statement II : Starch, on heating with concentrated sulfuric acid at 100°C and 2 - 3 atmosphere pressure produces glucose. In the light of the above statements, choose the correct answer from the options given below

  1. A.Both Statement I and Statement II are true
  2. B.Statement I is true but Statement II is false
  3. C.Statement I is false but Statement II is true
  4. D.Both Statement I and Statement II are false

Correct answer: C

Question 54

Chemistry · 4 marks · −1

The metal ion whose electronic configuration is not affected by the nature of the ligand and which gives a violet colour in non-luminous flame under hot condition in borax bead test is

  1. A.Ni2+Ni^{2+}
  2. B.Mn2+Mn^{2+}
  3. C.Cr3+Cr^{3+}
  4. D.Ti3+Ti^{3+}

Correct answer: A

Explanation: Ni2+Ni^{2+} (d8d^8) has the same t2g6eg2t_{2g}^6e_g^2 configuration for any ligand and gives a violet bead (hot, oxidising flame).

Question 55

Chemistry · 4 marks · −1

Consider the following elements In, Tl, Al, Pb, Sn and Ge. The most stable oxidation states of elements with highest and lowest first ionisation enthalpies, respectively, are

  1. A.+2 and +3
  2. B.+4 and +1
  3. C.+1 and +4
  4. D.+4 and +3

Correct answer: D

Explanation: Highest IE: Ge (most stable +4); lowest IE: In (most stable +3).

Question 56

Chemistry · 4 marks · −1

In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields? A. n = 1, l = 0, mlm_l = 0 B. n = 2, l = 0, mlm_l = 0 C. n = 2, l = 1, mlm_l = 1 D. n = 3, l = 2, mlm_l = 1 E. n = 3, l = 2, mlm_l = 0. Choose the correct answer from the options given below:

  1. A.B and C Only
  2. B.A and B Only
  3. C.D and E Only
  4. D.C and D Only

Correct answer: C

Question 57

Chemistry · 4 marks · −1

A weak acid HA has degree of dissociation x. Which option gives the correct expression of (pH − pKaK_a)?

  1. A.log (1 + 2x)
  2. B.log⁡(1−xx)\log\left(\frac{1-x}{x}\right)
  3. C.log⁡(x1−x)\log\left(\frac{x}{1-x}\right)
  4. D.0

Correct answer: C

Question 58

Chemistry · 4 marks · −1

The products A and B in the following reactions, respectively are: A ←Ag−NO2\xleftarrow{Ag-NO_2} CH3−CH2−CH2−BrCH_3-CH_2-CH_2-Br →AgCN\xrightarrow{AgCN} B

  1. A.CH3−CH2−CH2−NO2CH_3-CH_2-CH_2-NO_2, CH3−CH2−CH2−NCCH_3-CH_2-CH_2-NC
  2. B.CH3−CH2−CH2−NO2CH_3-CH_2-CH_2-NO_2, CH3−CH2−CH2−CNCH_3-CH_2-CH_2-CN
  3. C.CH3−CH2−CH2−ONOCH_3-CH_2-CH_2-ONO, CH3−CH2−CH2−CNCH_3-CH_2-CH_2-CN
  4. D.CH3−CH2−CH2−ONOCH_3-CH_2-CH_2-ONO, CH3−CH2−CH2−NCCH_3-CH_2-CH_2-NC

Correct answer: A

Question 59

Chemistry · 4 marks · −1

Which of the following oxidation reactions are carried out by both K2Cr2O7K_2Cr_2O_7 and KMnO4KMnO_4 in acidic medium? A. I−→I2I^-\to I_2 B. S2−→SS^{2-}\to S C. Fe2+→Fe3+Fe^{2+}\to Fe^{3+} D. I−→IO3−I^-\to IO_3^- E. S2O32−→SO42−S_2O_3^{2-}\to SO_4^{2-}. Choose the correct answer from the options given below:

  1. A.A, B and C Only
  2. B.C, D and E Only
  3. C.B, C and D Only
  4. D.A, D and E Only

Correct answer: A

Question 60

Chemistry · 4 marks · −1

The compounds that produce CO2CO_2 with aqueous NaHCO3NaHCO_3 solution are: A. benzoic acid B. phenol C. 2,4,6-trinitrophenol (picric acid) D. cyclohexanecarboxylic acid E. 3-methoxyphenol. Choose the correct answer from the options given below:

Figure for question 60
  1. A.A and B Only
  2. B.A, B and E Only
  3. C.A and C Only
  4. D.A, C and D Only

Correct answer: D

Question 61

Chemistry · 4 marks · −1

Consider 'n' is the number of lone pair of electrons present in the equatorial position of the most stable structure of ClF3ClF_3. The ions from the following with 'n' number of unpaired electrons are A. V3+V^{3+} B. Ti3+Ti^{3+} C. Cu2+Cu^{2+} D. Ni2+Ni^{2+} E. Ti2+Ti^{2+}. Choose the correct answer from the options given below:

  1. A.B and D Only
  2. B.A and C Only
  3. C.B and C Only
  4. D.A, D and E Only

Correct answer: D

Explanation: ClF3ClF_3: both lone pairs equatorial, n = 2. Two unpaired: V3+V^{3+} (d2d^2), Ni2+Ni^{2+} (d8d^8), Ti2+Ti^{2+} (d2d^2).

Question 62

Chemistry · 4 marks · −1

The molecules having square pyramidal geometry are

  1. A.SbF5SbF_5 & PCl5PCl_5
  2. B.SbF5SbF_5 & XeOF4XeOF_4
  3. C.BrF5BrF_5 & PCl5PCl_5
  4. D.BrF5BrF_5 & XeOF4XeOF_4

Correct answer: D

Question 63

Chemistry · 4 marks · −1

Match the LIST-I with LIST-II. LIST-I (Redox Reaction): A. CH4(g)+2O2(g)→ΔCO2(g)+2H2O(l)CH_4(g)+2O_2(g)\xrightarrow{\Delta}CO_2(g)+2H_2O(l) B. 2NaH(s)→Δ2Na(s)+H2(g)2NaH(s)\xrightarrow{\Delta}2Na(s)+H_2(g) C. V2O5(s)+5Ca(s)→Δ2V(s)+5CaO(s)V_2O_5(s)+5Ca(s)\xrightarrow{\Delta}2V(s)+5CaO(s) D. 2H2O2(aq)→Δ2H2O(l)+O2(g)2H_2O_2(aq)\xrightarrow{\Delta}2H_2O(l)+O_2(g). LIST-II (Type of Redox Reaction): I. Disproportionation reaction II. Combination reaction III. Decomposition reaction IV. Displacement reaction. Choose the correct answer from the options given below:

  1. A.A-II, B-III, C-I, D-IV
  2. B.A-III, B-IV, C-I, D-II
  3. C.A-II, B-III, C-IV, D-I
  4. D.A-IV, B-I, C-II, D-III

Correct answer: C

Question 64

Chemistry · 4 marks · −1

Given below are two statements: Statement I: Et2N−CH2CH2−ClEt_2N-CH_2CH_2-Cl will undergo alkaline hydrolysis at a faster rate than Et2CH−CH2CH2−ClEt_2CH-CH_2CH_2-Cl. Statement II: In Et2N−CH2CH2−ClEt_2N-CH_2CH_2-Cl, intramolecular substitution takes place first by involving lone pair of electrons on nitrogen. In the light of the above statements, choose the most appropriate answer from the options given below

  1. A.Both Statement I and Statement II are incorrect
  2. B.Both Statement I and Statement II are correct
  3. C.Statement I is incorrect but Statement II is correct
  4. D.Statement I is correct but Statement II is incorrect

Correct answer: B

Question 65

Chemistry · 4 marks · −1

Ice and water are placed in a closed container at a pressure of 1 atm and temperature 273.15K. If pressure of the system is increased 2 times, keeping temperature constant, then identify correct observation from following

  1. A.The amount of ice decreases.
  2. B.The solid phase (ice) disappears completely.
  3. C.Volume of system increases .
  4. D.Liquid phase disappears completely.

Correct answer: B

Explanation: At 2 atm the melting point of ice is below 273.15 K, so at constant 273.15 K the ice phase cannot persist: it melts completely.

Question 66

Chemistry · 4 marks · −1

For a given reaction R → P, t1/2t_{1/2} is related to [A]0[A]_0 as given in table: [A]0[A]_0 = 0.100 mol L−1L^{-1}, t1/2t_{1/2} = 200 min; [A]0[A]_0 = 0.025 mol L−1L^{-1}, t1/2t_{1/2} = 100 min. Given: log 2 = 0.30. Which of the following is true? A. The order of the reaction is 1/2. B. If [A]0[A]_0 is 1M, then t1/2t_{1/2} is 20010200\sqrt{10} min C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M. D. t1/2t_{1/2} is 800 min for [A]0[A]_0 = 1.6 M. Choose the correct answer from the options given below:

  1. A.C and D Only
  2. B.A, B and D Only
  3. C.A and C Only
  4. D.A and B Only

Correct answer: B

Explanation: t1/2∝[A]01−nt_{1/2}\propto[A]_0^{1-n}: 4× conc gives 2× time ⇒ n = 1/2; B: 20010200\sqrt{10} ✓; D: 1.6/0.1 = 16 → 4 × 200 = 800 ✓.

Question 67

Chemistry · 4 marks · −1

What is the freezing point depression constant of a solvent, 50 g of which contain 1 g non volatile solute (molar mass 256 g mol−1mol^{-1}) and the decrease in freezing point is 0.40 K ?

  1. A.5.12 K kg mol−1mol^{-1}
  2. B.3.72 K kg mol−1mol^{-1}
  3. C.1.86 K kg mol−1mol^{-1}
  4. D.4.43 K kg mol−1mol^{-1}

Correct answer: A

Explanation: Kf=0.40×256×501000=5.12K_f=\frac{0.40\times256\times50}{1000}=5.12.

Question 68

Chemistry · 4 marks · −1

The correct order of stability of following carbocations is : A: triphenylmethyl cation Ph3C+Ph_3C^+; B: diphenylmethyl cation Ph2CH+Ph_2CH^+; C: cycloheptatrienyl (tropylium) cation; D: sec-butyl cation CH3CH2C+HCH3CH_3CH_2\overset{+}{C}HCH_3.

Figure for question 68
  1. A.C > B > A > D
  2. B.A > B > C > D
  3. C.C > A > B > D
  4. D.B > C > A > D

Correct answer: C

Question 69

Chemistry · 4 marks · −1

The incorrect decreasing order of atomic radii is

  1. A.Mg > Al > C > O
  2. B.Si > P > Cl > F
  3. C.Al > B > N > F
  4. D.Be > Mg > Al > Si

Correct answer: D

Explanation: Be is smaller than Mg.

Question 70

Chemistry · 4 marks · −1

Given below is the plot of the molar conductivity vs concentration\sqrt{\text{concentration}} for KCl in aqueous solution. If, for the higher concentration of KCl solution, the resistance of the conductivity cell is 100 Ω\Omega, then the resistance of the same cell with the dilute solution is \'x\' Ω\Omega. The value of x is ______ (Nearest integer)

Figure for question 70

Correct answer: 150

Explanation: κ=Λc\kappa=\Lambda c: dilute 150×0.01=1.5150\times0.01=1.5, concentrated 100×0.0225=2.25100\times0.0225=2.25; R∝1/κR\propto1/\kappa: x=100×2.251.5=150x=100\times\frac{2.25}{1.5}=150.

Question 71

Chemistry · 4 marks · −1

The formation enthalpies, ΔHf⊖\Delta H_f^\ominus for H(g)H_{(g)} and O(g)O_{(g)} are 220.0 and 250.0 kJ mol−1mol^{-1}, respectively, at 298.15 K, and ΔHf⊖\Delta H_f^\ominus for H2O(g)H_2O_{(g)} is −242.0 kJ mol−1mol^{-1} at the same temperature. The average bond enthalpy of the O–H bond in water at 298.15 K is ______ kJ mol−1mol^{-1} (nearest integer).

Correct answer: 466

Explanation: 2(O−H)=2(220)+250+242=9322(O-H)=2(220)+250+242=932 ⇒ 466.

Question 72

Chemistry · 4 marks · −1

Consider the following sequence of reactions: Chlorobenzene →i) Mg, dry ether; ii) CO2,H3O+; iii) NH3,Δ\xrightarrow{\text{i) Mg, dry ether; ii) } CO_2, H_3O^+;\ \text{iii) } NH_3, \Delta} A →Br2,NaOH\xrightarrow{Br_2, NaOH} B. 11.25 mg of chlorobenzene will produce ______ ×10−1\times10^{-1} mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol−1mol^{-1} respectively]

Correct answer: 93

Explanation: 0.1 mmol → benzamide → aniline (93): 9.3 mg = 93 × 10⁻¹.

Question 73

Chemistry · 4 marks · −1

The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is ______ ×10−1\times10^{-1} M (Nearest integer) [Given: Density of aqueous solution of (X) is 1.25 g mL−1mL^{-1}, Molar mass of the acid is 70 g mol−1mol^{-1}]

Correct answer: 125

Explanation: M=70×1.25×1070=12.5M=\frac{70\times1.25\times10}{70}=12.5 → 125.

Question 74

Chemistry · 4 marks · −1

Quantitative analysis of an organic compound (X) shows following % composition. C : 14.5 %, Cl : 64.46 %, H : 1.8 %. (Empirical formula mass of the compound (X) is ______ ×10−1\times10^{-1} (Given molar mass in g mol−1mol^{-1} of C : 12, H : 1, O : 16, Cl : 35.5)

Correct answer: 1655

Explanation: O = 19.24%; ratio C 1.21 : H 1.8 : Cl 1.82 : O 1.2 ≈ 2 : 3 : 3 : 2 → C2H3Cl3O2C_2H_3Cl_3O_2 = 165.5 → 1655.

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